A town recently dismissed 88 employees in order to meet their new budget reductions. The town had 77 employees over 5050 years of age and 1717 under 5050. If the dismissed employees were selected at random, what is the probability that at least 66 employees were over 5050? Express your answer as a fraction or a decimal number rounded to four decimal places.

Step-by-step explanation:

DAG = DG

120=120°

DHG + DG =360°

DHG +120° =360°

DHG+120°-120°=360°-120°

DHG°=240°

Answer:

Root of 65

Step-by-step explanation:

8^2 is equal to 64, so the sqrt of 64 would equal 8 exactly. The question is asking for which of the sqrts would be closest to 8, so sqrt of 65 is the number that is closest to 64, so it is the answer.

Answer:

[tex] \sqrt{65} [/tex]

as

[tex] \sqrt{64} = 8[/tex]

so it's the closest value to 8

and also

[tex] \sqrt{65} = 8.06[/tex]

via calculator

Answer:

[tex]P(81)=56.16[/tex]

Step-by-step explanation:

From the question we are told that:

Mean [tex]\mu=50[/tex]

Standard Deviation [tex]\sigma=7[/tex]

Percentile 81st

Generally Probability of 81st Percentile

 [tex]P(Z<x)=81\%[/tex]

Using Standard normal Table

 [tex]P(Z<0.88)=81\%[/tex]

Therefore the 81st percentile is given as

 [tex]P(81)=z*\sigma *\mu[/tex]

 [tex]P(81)=0.88*7*50[/tex]

 [tex]P(81)=56.16[/tex]

Answer:

C = 19.9 ft

Step-by-step explanation:

Your question isn't properly constructed. However, I'll attempt in providing a possible way of finding one of the sides of a given triangle.

Generally, the Pythagorean theorem is used to find the side of a triangle when two of its sides are known or provided.

Assuming the following data;

Let the length of sides of the triangle be;

Opposite side = a = 15 ft

Adjacent side = b = 13 ft

Hypotenuse side = c

From Pythagorean theorem;

Mathematically, Pythagorean theorem is given by the formula;

C² = a² + b²

C² = 15² + 13²

C² = 225 + 169

C² = 394

Taking the square root of both sides, we have;

C = √394

C = 19.9 ft

Answer:

emm who exactly is chipo bcause i literally have no idea

Answer:

N=115

Step-by-step explanation:

n=.25(2.5715/.12)^2 =114.8 so round up to 115. Hope that help you

Answer:

[tex]x=73[/tex]

Answer:

The 85% confidence interval for the mean number of toys purchased each year is (6.7, 6.9).

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.85}{2} = 0.075[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.075 = 0.925[/tex], so Z = 1.44.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.44\frac{2.1}{\sqrt{686}} = 0.1[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 6.8 - 0.1 = 6.7

The upper end of the interval is the sample mean added to M. So it is 6.8 + 0.1 = 6.9

The 85% confidence interval for the mean number of toys purchased each year is (6.7, 6.9).

Answer:

x= 0.22947

Step-by-step explanation:

Step-by-step explanation:

x=0 22 im not sure though ok

Answer:

1.(a) 25.3

(b) 3.49

(c) 14.44

2.(a) 86.64

(b) 59.85

(c) 27.92

3. 5.92

4.(a) 13.96

(b) 43.32

(c) 101.12

5.(a) 59.85

(b) 10.47

(c) 50.6

6. 5.56

Answer:

m=4

2y/2=y

8x/2=4x

4/2=2

so

y=4x+4

Answer:

17

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

[tex]d = \sqrt{(x_{2} -x_{1})^{2} + (y_{2} - x_{1})^{2} }[/tex]

d = distance

[tex](x_{1}, y_{1})[/tex] = coordinates of the first point

[tex](x_{2}, y_{2})[/tex] = coordinates of the second point

Answer: The distance between the points (6,-7)(-2,8) is 17.

Step-by-step explanation:

To calculate the distance between two points, we apply the following formula:

[tex]\boldsymbol{\sf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 } }}[/tex]

The points are:

We substitute in the formula and solve:

[tex]\boldsymbol{\sf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 } }}\\ \\ \boldsymbol{\sf{d=\sqrt{(-2-6)^2+(8-(-7))^2 } }}\\ \\ \boldsymbol{\sf{d=\sqrt{(-8)^2+15^2}=\sqrt{64+225 } }}\\ \\ \boldsymbol{\sf{d=\sqrt{289}=17 }}[/tex]

The distance between the points (6,-7)(-2,8) is 17.

Answer:

2/36 or 1/18 simplified

Step-by-step explanation:

you have all the combinations listed which is good.

probability = number of successful events / number of total events

there are

m<1=130°[alternate angle are equal again]

m<1+m<2180°[linear pair]

m<2=180°-130°

====================================

If you have any questions feel free to ask me^^

Have a nice and great day!

#PilipinasAngBayanKo

Answer:

Rhoda, whose ACT has a z-score of 1, scored in the 84th percentile in the ACT, compared to Bill, whose SAT has a z-score of -2, who scored in the 2nd percentile on the SAT. Due to the higher percentile(higher z-score)  on her test, Rhoda did better on her respective test than Bill, and thus, his logic is wrong.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Bill:

Scored 300, so [tex]X = 300[/tex]

SAT has a μ of 500 and a σ of 100.

His z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{300 - 500}{100}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.02.

This means that Bill, whose SAT score has Z = -2, scored in the 2nd percentile.

Rhoda

Scored 25, so [tex]X = 25[/tex].

ACT has a μ of 20 and a σ of 5

Her z-score:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{25 - 20}{5}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a p-value of 0.84

This means that Rhoda, whose ACT score has Z = 1, scored in the 84th percentile.

What is wrong with Bill’s logic ?

Rhoda, whose ACT has a z-score of 1, scored in the 84th percentile in the ACT, compared to Bill, whose SAT has a z-score of -2, who scored in the 2nd percentile on the SAT. Due to the higher percentile(higher z-score)  on her test, Rhoda did better on her respective test than Bill, and thus, his logic is wrong.

Answer:

A) John

Answer:

john

Step-by-step explanation:

Answer:

180

Step-by-step explanation:

volume= (6*5)/2*12 =180 in

Answer: 3 pounds

Step-by-step explanation: 12 - 4.50 = 7.50 7.50/2.50=3

Answer:

You need to show the statements or I can't help.

Answer:

105.6

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

(17/12)π radians

Step-by-step explanation:

π radians = 180º

255 * (π/180) = (17/12)π

Answer:

x = 9

Step-by-step explanation:

The triangle given is an isosceles triangle because it has two equal sides. By implication, the two base angles that are opposite the two equal sides are equal to each other.

Therefore,

80° + 2(m<2) = 180° (sum of triangle theorem)

80 + 2(5x + 5) = 180

80 + 10x + 10 = 180

Add like terms

90 + 10x = 180

90 + 10x - 90 = 180 - 90 (substraction property of equality)

10x = 90

10x/10 = 90/10 (division property of equality)

x = 9

Answer:

7.3

Step-by-step explanation:

Biggest value = 8.9

smallest value = 1.6

range = 8.9-1.6 = 7.3

Step-by-step explanation:

range=highest number - lowest number

= 8.9 - 1.6

=7.3

Answer:

[tex]A + B + E = 32[/tex]

Step-by-step explanation:

Given

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

Required

Find [tex]A +B + E[/tex]

We have:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

Using integration by parts

[tex]\int {u} \, dv = uv - \int vdu[/tex]

Where

[tex]u = x^2[/tex] and [tex]dv = e^{-4x}dx[/tex]

Solve for du (differentiate u)

[tex]du = 2x\ dx[/tex]

Solve for v (integrate dv)

[tex]v = -\frac{1}{4}e^{-4x}[/tex]

So, we have:

[tex]\int {u} \, dv = uv - \int vdu[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]

-----------------------------------------------------------------------

Solving

[tex]\int xe^{-4x} dx[/tex]

Integration by parts

[tex]u = x[/tex] ---- [tex]du = dx[/tex]

[tex]dv = e^{-4x}dx[/tex] ---------- [tex]v = -\frac{1}{4}e^{-4x}[/tex]

So:

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx[/tex]

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx[/tex]

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}[/tex]

So, we have:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}][/tex]

Open bracket

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x} -\frac{1}{8}e^{-4x}[/tex]

Factor out [tex]e^{-4x}[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}[/tex]

Rewrite as:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}[/tex]

Recall that:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}[/tex]

By comparison:

[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]

[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]

[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]

Solve A, B and C

[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]

Divide by [tex]-x^2[/tex]

[tex]\frac{1}{4} = \frac{1}{64}A[/tex]

Multiply by 64

[tex]64 * \frac{1}{4} = A[/tex]

[tex]A =16[/tex]

[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]

Divide by [tex]-x[/tex]

[tex]\frac{1}{8} = \frac{1}{64}B[/tex]

Multiply by 64

[tex]64 * \frac{1}{8} = \frac{1}{64}B*64[/tex]

[tex]B = 8[/tex]

[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]

Multiply by -64

[tex]-64 * -\frac{1}{8} = -\frac{1}{64}E * -64[/tex]

[tex]E = 8[/tex]

So:

[tex]A + B + E = 16 +8+8[/tex]

[tex]A + B + E = 32[/tex]

Answer:

[tex]area = \frac{1}{2} \times 11 \times 18 \\ = 99 \: {ft}^{2} [/tex]

Step-by-step explanation:

angle ABE=angle EBC

Answer:

a = 32,37

b=99

Step-by-step explanation:

a = 32,369

The third decimal place is greater (or equal) than 5, so we need to add one unit to the second place.

= 32,37

b = 99,004

The third decimal place is lesser than 5, so we can simply delete it.

= 99,00

Since only zero in every decimal places are not relevant, we can remove them:

= 99

Answer:

340

Step-by-step explanation:

2(10*8)=160

2(8*5)=80

2(5*10)=100

160+80+100=340

Answer:

7 C

Step-by-step explanation:

We want to find the y value for an x value of -9

The y value for the x value of -9 is 7

Answer:

[tex]C=252.2ft[/tex]

Step-by-step explanation:

From the question we are told that:

First Kite Distance [tex]A=450ft[/tex]

Second Kite Distance [tex]B=390ft[/tex]

Angle [tex]\theta=34\textdegree[/tex]

Generally the equation for Distance X between the kites is mathematically given by

Using Cosine Rule

 [tex]C^2=A^2+B^2-2abCos \theta[/tex]

Therefore

 [tex]C^2=(450)^2+(390)^2-2(450)(390)Cos 34[/tex]

 [tex]C^2=63607.81[/tex]

 [tex]C=\sqrt(63607.81)[/tex]

 [tex]C=252.2ft[/tex]