A town has a population of 14000 and grows at 3% every year. What will be the population after 6 years, to the nearest whole number?

Answer:

The answer would be Y= 1/4X -3

Step-by-step explanation:

Hope it was helpful .

Good luck ^.^

Step-by-step explanation:

True

false

false

true

i think its that I'm sorry if its wrong

Answer: $27.65

Step-by-step explanation:

0.18 = 6.3

Discount = $6.3

0.03 = 1.05

Tax = 1.05

35 - 6.3 - 1.05 = 27.65

Answer:

it's just a angle that is 3D

Step-by-step explanation:

Answer:

each glass will have 0.75 of a cup or 3/4 of a cup * 0.75 and 3/4 is the same*

Answer:

-4 + -6 = -10

Step-by-step explanation:

From the line at negative 4 it goes to negative 10 you need to add six to four to make ten. Though since it is negative numbers we add a negative 6

The calculated product of the vectors a and b is 17

From the question, we have the following parameters that can be used in our computation:

a = (4, 1, 1/5) and b = (6,-4, -15)

The product of the vectors can be calculated using

a * b = Sum of products of each position

Using the above as a guide, we have the following:

a * b = 4 * 6 + 1 * -4 + 1/5 * -15

Evaluate the expression

a * b = 17

Hence, the product of the vectors a and b is 17

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Answer:

D

Step-by-step explanation:

Answer:

It's A I think. I did the math on math.way and it was differeten the the answers you have.

Step-by-step explanation:

Answer:

Step-by-step explanation:

a. annual premium: 79.35

b. monthly premium: 7.14

Marcie Ann Weber, age 32, takes out $15,000 of a term insurance for a ten-year term. Annual premium = $1,500 per year and monthly premium = $125 per month.

One type of operation is division in mathematics. In this procedure, the phrases or numbers are divided into the same number of components.

Given: Marcie Ann Weber,

insured amount of term insurance plan = $15,000.

Number of year = 10 year

To find the amount of annual premium:

Divide the total insured amount by number of years.

Annual premium = Insured amount of term insurance plan / Number of year

Annual premium = $15,000 / 10

Annual premium = $1,500 per year

To find the amount of monthly premium:

Monthly premium = Insured amount of term insurance plan / Number of month in 10 year

Monthly premium = 15,000 / (10 x 12)

Monthly premium = 15,000 / 120

Monthly premium = $125 per month.

Therefore, annual premium = $1,500 per year and monthly premium = $125 per month.

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Answer:

y = 10

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = [tex]\frac{1}{2}[/tex] , then

sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{y}{20}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )

2y = 20 ( divide both sides by 2 )

y = 10

Answer:

Number of different ways of filling the position is   8961115245946500

Step-by-step explanation:

There are total of 4 positions which can be arranged in 4! Ways  

Like wise there are 12 positions. Hence the number of arrangements for these 12 positions would be 12!

Overall there are 12+4 = 16 positions in which 50 people needs to be arranged

Number of different ways of filling the position is  

50P16 /(12! *4!)

= 8961115245946500

The number of different ways of filling the position is,  8961115245946500

There are total of 4 positions can be arranged in 4! Ways  

Similarly  there are 12 positions.

Therefore, the number of arrangements for these 12 positions is  12!

If there is an arrangement of the data then we use the permutation

Therefore we can say that there are 12+4 = 16 positions in which 50 people needs to be arranged.

The number of different ways of filling the position is,

[tex]50P16 /(12! *4!)[/tex]

By using the calculater you can find,

= 8961115245946500

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Answer:

I think! 3.5 feet wide

Step-by-step explanation:

the area of the pool is 240 square feet. divide by 68 square feet gives you 3.539= 3.5 feet wide. dont shoot me if I'm wrong lol

The width of the deck is approximately 2.65 feet.

To solve the problem, we need to first find the total area of the pool and deck combined, and then subtract the area of the pool to find the area of the deck.

The total area of the pool and deck can be represented as follows:

(12 + 2x) x (20 + 2x)

where x is the width of the deck.

The area of the pool is:

12 x 20 = 240

So, the area of the deck can be found by subtracting the area of the pool from the total area:

(12 + 2x) x  (20 + 2x) - 240 = 68

Expanding the left side and simplifying, we get:

4x²+ 64x - 208 = 0

Dividing both sides by 4, we get:

x²+ 16x - 52 = 0

Using the quadratic formula, we get:

x = (-b ± √(b² - 4ac)) / 2a

Where a = 1, b = 16, and c = -52.

Plugging in these values, we get:

x = (-16 ± √(16² - 4(1)(-52))) / 2(1)

x = (-16 ± √(960)) / 2

x = (-16 ± 4√(15)) / 2

x = -8 ± 2√(15)

Since the width of the deck cannot be negative, we can discard the negative solution, and we are left with:

x = -8 + 2√(15)

So, the width of the deck is approximately 2.65 feet.

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The new mAs should be approximately 45 mAs.
The intensity of radiation at a given distance can be calculated using the inverse square law:

Intensity2 = Intensity1 × (Distance1/Distance2)^2

Given:
Intensity1 = 100 mR
Distance1 = 100 cm
Distance2 = 200 cm

Using the above formula, we can calculate the new intensity at 200 cm:

Intensity2 = 100 mR × (100 cm/200 cm)^2
Intensity2 = 100 mR × (1/4)
Intensity2 = 25 mR

To maintain the same exposure at the new distance, the new mAs needs to be adjusted accordingly. We can use the exposure maintenance formula:

mAs2/mAs1 = (kVp2/kVp1) × (Distance1/Distance2)^2 × (Gridratio2/Gridratio1)^2

Given:
mAs1 = 30 mAs
kVp1 = 120 kV
kVp2 = 138 kV
Gridratio1 = 5:1
Gridratio2 = 10:1

Substituting the given values into the formula, we can solve for mAs2:

mAs2/30 mAs = (138 kV/120 kV) × (100 cm/200 cm)^2 × (10/5)^2
mAs2/30 mAs = (1.15) × (0.5)^2 × (4)
mAs2/30 mAs = 1.15 × 0.25 × 4
mAs2/30 mAs = 0.115

Simplifying, we find:
mAs2 = 30 mAs × 0.115
mAs2 ≈ 3.45 mAs

Therefore, the new mAs should be approximately 45 mAs (rounded to the nearest whole number) to maintain exposure at 200 cm with a 10:1 grid and 138 kV.

To maintain exposure at a new distance of 200 cm with a 10:1 grid and 138 kV, the radiograph technician should set the new mAs to approximately 45 mAs. This adjustment takes into account the changes in distance, kV, and grid ratio while ensuring that the radiation intensity remains consistent.

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A code with distance 2t + 1 can correct t or fewer errors using the minimum distance decoding criteria.

When considering the minimum distance decoding criteria, a code with a minimum distance of 2t + 1 can correct t or fewer transmission errors.

The minimum distance of a code refers to the smallest number of bit flips or symbol errors needed to transform one valid codeword into another. In this case, the distance is 2t + 1, which means that any two valid codewords in the code will have a minimum Hamming distance of at least 2t + 1.

By choosing the minimum distance decoding criteria, the decoder can identify and correct up to t or fewer transmission errors. This is because if the received codeword differs from the transmitted codeword by t or fewer errors, it will still be closer to the intended codeword than any other codeword in the code.

Therefore, the decoder can successfully correct these errors and recover the original transmitted message.

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Answer: 40% i think

Step-by-step explanation:

Answer:

The factors of x²-64 is equal to (x-8)(x+8).

Step-by-step explanation:

The given expression is:

x²-64

we know that, 8² = 64

So,

(x²-8²) = (x-8)(x+8) [As (a-b)(a+b) = a²-b²]

So, the factors of x²-64 i equal to (x-8)(x+8).

Answer:

Any number below 3

(2, negative infinity)

Answer:

here's the answer with steps

x + 2 < 5

-2 -2

x < 3

The statement is False.

(a) Let x be an integer. If 4x² + 3x + 7 is odd, then x must be even.Statement (a) is false.

Here is the explanation:We know that an integer is odd if and only if it can be represented in the form of 2k + 1, where k is any integer.Let us assume that x is an odd integer. Then, we can write x as 2k + 1, where k is any integer.Substituting the value of x in 4x² + 3x + 7, we get;4x² + 3x + 7 = 4(2k + 1)² + 3(2k + 1) + 7= 4(4k² + 4k + 1) + 6k + 3 + 7= 16k² + 16k + 4 + 6k + 10= 16k² + 22k + 14= 2(8k² + 11k + 7)which is an even integer as it is a multiple of 2.

Therefore, we have proven that if x is odd, then 4x² + 3x + 7 is even.So, we have disproved the statement as it is not true for all integers. It's only true for odd integers only. Therefore, statement (a) is false.

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Given that X₁, X₂, ..., Xₙ are iid according to a uniform continuous distribution over the open interval (0,0+1).

Now, we have to find a sufficient statistics for 8.Let T = ∑Xᵢ, then T ~ U(n*0,n).Thus, T is a sufficient statistic for θ.Hence, T is a sufficient statistics for 8.

Given that X₁, X₂, ..., Xₙ are iid according to a uniform continuous distribution over the open interval (0,0+1).

We have to find a minimally sufficient statistics for

Let T = (X(n), X(1)), where X(n) = max{X₁,X₂, .... Xₙ} and X(1) = min{X₁,X₂, .... Xₙ}.As Xᵢ follows uniform distribution, so T can take any value in [0, 1].

Let Y = nX(n)/(1-X(n)), thenY = (nX(n))/(1-X(n)) = (nX(n))/(X(n)-X(1)) = 1/[(X(n)-X(1))/n].Now, 0 < X(1) ≤ X(n) < 1. Therefore, 0 < (X(n)-X(1))/n ≤ 1/n. Then, Y takes values in [0,∞).Thus, Y is a one-to-one function of T.

Hence, T is a minimally sufficient statistics for 8.

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The equation that states (x, y) is equidistant from (4, 1) and the x-axis is -8x - 2y + 17 = 0.

To express that the point (x, y) is equidistant from both the point (4, 1) and the x-axis, we can set up an equation using the distance formula.

The distance formula states that the distance between two points (x₁, y₁) and (x₂, y₂) is given by:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

In this case, we want the distance from (x, y) to (4, 1) to be equal to the distance from (x, y) to the x-axis. The x-axis can be represented by the equation y = 0.

Let's set up the equation:

√((x - 4)² + (y - 1)²) = √((x - x)² + (y - 0)²)

Simplifying, we get:

√((x - 4)² + (y - 1)²) = √(x² + y²)

To remove the square roots, we can square both sides of the equation:

((x - 4)² + (y - 1)²) = (x² + y²)

Expanding and simplifying further, we have:

x² - 8x + 16 + y² - 2y + 1 = x² + y²

Combining like terms, we obtain:

-8x - 2y + 17 = 0

Therefore, the equation that states (x, y) is equidistant from (4, 1) and the x-axis is -8x - 2y + 17 = 0.

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Answer:

[tex]g \: y = 2x - 3 \\ [/tex]

if you insert x and y values in equation you can find the exact equation

If a critical point at x=2, an inflection point at (1,4), and a leading coefficient of 1, the final formula for the cubic polynomial is f(x) = x³ - 3x² + 12x - 6.

To find the formula for a cubic polynomial with specific properties, we can start by considering the critical point and the inflection point.

Given that the critical point is at x = 2, we know that the derivative of the cubic polynomial should be equal to zero at x = 2. This means that the slope of the polynomial at x = 2 is zero. Taking the derivative of the cubic polynomial, we have:

f'(x) = 3ax² + 2bx + c.

Setting this equal to zero and substituting x = 2, we get:

3a(2)² + 2b(2) + c = 0.

12a + 4b + c = 0.

Now, let's consider the inflection point at (1,4). We know that the second derivative of the cubic polynomial should be zero at x = 1. Taking the second derivative, we have:

f''(x) = 6ax + 2b.

Setting this equal to zero and substituting x = 1, we get:

6a(1) + 2b = 0.

6a + 2b = 0.

Solving the system of equations consisting of 12a + 4b + c = 0 and 6a + 2b = 0, we find a = -1/2, b = 3/2, and c = -6.

Therefore, the formula for the cubic polynomial is:

f(x) = -1/2x³ + 3/2x² - 6x + d.

The leading coefficient is 1, so we have:

f(x) = x³ - 3x² + 12x + d.

To determine the value of d, we can use the fact that the inflection point is (1,4). Substituting x = 1 and y = 4 into the equation, we get:

4 = 1 - 3 + 12 + d.

4 = 10 + d.

d = -6.

Therefore, the final formula for the cubic polynomial is:

f(x) = x³ - 3x² + 12x - 6.

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Complete question is:

Find the formula for a cubic polynomial, ax³+bx²+cx+d,  with a critical point at x=2, an inflection point at (1,4), and a leading coefficient of 1.

Answer:

P'(0, -4)

Step-by-step explanation:

when a coordinate (x, y) is rotated by 180 degrees, the resulting coordinate will be (-x, -y). Note that each coordinate is negated when rotated about 180 degrees

Given the coordinate P (0, 4). When rotated by 180 degrees, the resulting coordinate will be at P'(0, -4)

Answer:

x^3+3x^2-46

Step-by-step explanation:

Answer:

Step-by-step explanation:

(48x^2)(y) + (16x)(y^2).

This is addition, so the distributive property applies. [(48x^2)(y) + (16x)(y^2)]/8xy = (48x^2)(y)/8xy+(16x)(y^2)/8xy = 6x+2y.

Division rules are explained below.

I included the parentheses to emphasize the difference between x^2y, which means x to the 2y, and (x^2)(y), which is x^2 times y.

TELL ME IF THIS IS CONFUSING<,BECAUSE I DON'T THINK I EXPLAINED VERY WELL.

Alex and Jack work for a computer software company. Alex can write a computer program in 24 hours, while

Jack can write it in 16 hours. How long will it take them to write the program together?

Answer: 9.6 hours

The statement is true that:

When the data are interval, the parameters of interest are the population mean μ and the population variance σ² .

Given,

Mean and standard variance .

Here,

An interval estimator provides a range of values as an estimate of a parameter, considering uncertainty, while a point estimator provides a single value estimate. The Student's t-distribution is used when the population standard deviation is unknown, and the z-distribution is used when it is known.

Support for the statement:

True: When the data are interval, the parameters of interest are the population mean (μ) and the population variance (σ^2). The population mean represents the average value of the variable of interest in the population, while the population variance measures the variability or spread of the variable in the population.

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The pizza is divided into 6 equal pieces in total: 3 initial slices, each further divided into 2 equal pieces.

A pizza is cut into 3 equal slices. Each slice is then cut into 2 equal pieces. How many pieces of pizza are there in total?

To solve this problem, we can use our definition of multiplication. Multiplication is repeated addition. In this case, we are repeatedly adding 2 to itself 3 times. This gives us 2 + 2 + 2 = 6. Therefore, there are 6 pieces of pizza in total.

We can also use math drawings to solve this problem. Here is a math drawing that shows how to find the product of 1/3 * 2/3:

The first row of the math drawing shows 1/3 of a pizza. The second row shows 2/3 of a pizza. The third row shows the product of 1/3 * 2/3. As you can see, the product is 6 pieces of pizza.

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