A theater group made appearances in two cities. The hotel charge before tax in the second city was $ 1500 higher than in the first. The tax in the first city was
3%, and the tax in the second city was 9.5%. The total hotel tax paid for the two cities was $580. How much was the hotel charge in each city before tax?
First city:
si
Х
5
?
Second city: 0
I’m
Answers
9514 1404 393
Answer:
first city: $3500second city: $5000Step-by-step explanation:
Let x and y represent the hotel charges in the two cities. The relations we are given are ...
x - y = -1500 . . . . . . second city hotel charge was 1500 more
0.03x +0.095y = 580 . . . . . total tax paid was 580
Using the first equation, we can write an expression for x:
x = y -1500
Substituting that into the second equation gives ...
0.03(y -1500) +0.095y = 580
0.125y = 625 . . . . . . . add 45 to both sides and simplify
y = 5000 . . . . . . . . . . multiply by 8
x = 5000 -1500 = 3500
The hotel charges were ...
First city: $3500
Second city: $5000
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