a study of the effects of exercis used rats bred to have high or low capacity for exercise. The 8 high capacity rats had mean blood pressure 89 mm Hg and variance 81; the 8 low-capacity rats had mean blood pressure 105 mm Hg with variance 169. What is the value of the two-sample t statistic for comapring the two population means

Answer:

[tex]t=-2.86[/tex]

Step-by-step explanation:

From the question we are told that:

Sample 1 [tex]n_1=8[/tex]

Sample 1 mean blood pressure [tex]\=x_1=89mmHg[/tex]

Sample 1 variance [tex]\sigma_1=81[/tex]

Sample 2 [tex]n_2=8[/tex]

Sample 2 mean blood pressure [tex]\=x_2=105mmHg[/tex]

Sample 2 variance [tex]\sigma_2=169[/tex]

Generally the equation for the test of statistic is mathematically given by

[tex]t=\frac{\=x_1-\=x_2}{\sqrt{\frac{\sigma_2}{n_1}+\frac{\sigma_2}{n_2} } }[/tex]

[tex]t=\frac{89-105}{\sqrt{\frac{81}{8}+\frac{169}{8} } }[/tex]

[tex]t=-2.86[/tex]

therefore the samples test for comparing the two population means

[tex]t=-2.86[/tex]

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