A student prepares a solution of Potassium Nitrate (KNO3) containing 95g at 40 C. This solution is -


A.) Saturated

B.) Unsaturated

C.) Supersaturated

D.) None of the Above

The mass of butane gas at the given volume and Standard temperature and pressure is 0.0022g.

The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.

It is expressed as;

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )

Given the data in the question;

PV = nRT

n = PV / RT

n = ( 1.0atm × 3.00L ) / ( 0.08206 Latm/molK × 273.15K )

n = 3.00Latm / 22.41 Latm/mol

n = 0.13mol

Now, since Molar mass of brutane gas is 58.12 g/mol.

Mass = n × Molar mass

Mass = 0.13mol × 58.12 g/mol

Mass = 0.0022g

Therefore, the mass of butane gas at the given volume and Standard temperature and pressure is 0.0022g.

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Answer:

Formula-Q = W /V

Explanation:

*hope it's help*

Answer:

[tex]3+[/tex]

Explanation:

[tex]\text{X}_2\text{O}_3 \leftrightharpoons 2\text{X}^{3+}+3\text{O}^{2-}[/tex]

The 4 ways to increase the concentration of chlorine molecules is listed below and the reaction will go into reverse if cooled.

Le Châtelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish an equilibrium.

Energy + HCl (g) + ClNO₃ ⇄  Cl₂  + HNO₃

a. So in this reaction when at equilibrium , To increase the concentration of Chlorine molecules

1. An increase in Temperature will favour the formation of Chlorine molecules.

2. Decrease in concentration of Chlorine , or partial removal of Chlorine will result the equation to go in forward direction.

3.An Increase in the concentration of HCl will favour formation of Chlorine molecules.

4.An Increase in the concentration of  CINO₃ will also favour formation of Chlorine molecules.

b. The cooling would shift the reaction into backward direction as it is an endothermic reaction in forward state.

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Answer:

0.264moles

Explanation:

number of moles= given mass/molar mass.

Molar mass of Cu2SO4= 63.5+32+4(16)=159.5

moles(n)=42.2/159.5= 0.264moles

Answer:

a)CaCO 3→CaO+CO 2CaCO3→CaO+CO2

b) Moles of CaCO3=4.37moles

c) I) Mass of calcium oxide =28g

ii)Mass of carbon dioxide=16.7g

iii)Volume=203cm3

The amount of time of contact, the area of contact, and the specific heats of the substances. Hence, option A is correct.

The heat in calories is required to raise the temperature of one gram of a substance one degree Celsius.

Factors that affect the rate of heat flow include the conductivity of the material, the temperature difference across the material, the thickness of the material, and the area of the material.

Different materials have greater or lesser resistance to heat transfer, making them better insulators or better conductors.

The amount of time of contact, the area of contact, and the specific heats of the substances.

Hence, option A is correct.

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Answer: The answer is C and D

B: If a substance undergoes a physical change, then it will retain most of its original properties because no new substance is formed.

C: If a substance undergoes a chemical change, then it will not retain its original properties because a new substance is formed.

Explanation: I took the test on edg

Answer:

5.40

Explanation:

you set up the equation with the given value first which is 97.3grams, and grams also goes on the bottom of the equation since the grams have to cancel out to make a mol. calculate the grams of H20 which is 18.016, then put it on the bottom of the equation, then put 1 mol on top.

97.3g x 1mol/18.016

Answer:

5.4 moles

Explanation:

H2 O    mole weight     1.008 * 2   + 16 = 18.016 gm/mole

97.3 gm / 18.016 gm/mole   = 5.4 moles

The practical work inside the lab includes lab equipments, chemicals, and the practical outside a laboratory is more about conservation of nature and practicals include natural things in their living areas.

What are lab practicals?

Practicals are set up stations with lab equipments and  chemicals and where students learn practical of the theoretical statements.

The exams of practicals are done to test the leaning of chemistry of the students.

Thus, the practical work inside the lab includes lab equipments, chemicals, and the practical outside a laboratory is more about conservation of nature and practicals include natural things in their living areas.

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Answer:

Ideal Solution: An ideal solution is a solution where interactions between molecules are identical between all the molecules in the solution. Non ideal Solution: A non ideal solution is a solution that has differences in the interactions between molecules of different components in the solution.

Explanation:

Answer:

Ideal solutions obey Raoult's law over entire range of concentrations. Nonideal solutions do not obey Raoult's law over the entire range of concentrations. 2. The vapour pressure of ideal solution always lies between vapour pressures of pure components.

Answer:

I believe it is useful as it shows how electrons are distributed in the shells (energy levels) of an iron atom. An atom is the smallest particle of an element that can take part in a chemical reaction. It contains the nucleus and the shells (energy levels). the nucleus contains protons and neutrons while the shells contain electrons.

Explanation:

The molar mass of the protein from the calculation is 1667 g/mol.

The osmotic pressure can be determined using the formula;

π=icRT

i = Van't Hoff factor = 1

c = concentration = ?

R = gas constant = 0.082 atmLK-1mol-1

T = temperature = 298 K

π= 2.24 torr or 0.029 atm

Now;

0.029 = 1 * c * 0.082 * 298

c = 0.029/1 * 0.082 * 298

c = 0.0012 M

Now;

2.00×10-3 g/MM = 0.0012 M *  1.00/1000L

MM = 2.00×10-3 g/0.0012 M *  1.00/1000L

MM = 1667 g/mol

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Answer:

ecosystem diversity

Explanation:

hope this helped

Answer:

The sun is important to Earth because it helps regulate the climate, is the main source of energy for producers in the ecosystems and it keeps the oceans from freezing, along with providing light. If just one of these factors changed dramatically, it would impact all life on Earth. Without the sun, the planet’s oceans would freeze, temperatures would drop and all life would die off without light or food.

The sun is important to every single aspect of life on the planet. Human life could not exist without it because it would cause all of the water and food sources to cease to exist. The sun is in no danger of disappearing any time soon. Scientists estimate the sun has at least another 5 billion years before it turns into a red giant and swallows up Mercury and Venus. It will also destroy all life on Earth because it will be close to the planet once that change occurs. The temperature of the sun will also increase tenfold from 18 million to 180 million degrees Fahrenheit. The increase in the sun’s size when it finally begins to change will be due to the heat increase causing expansion.

Without the sun, we would no energy to live, no plants to eat, no trees to give us oxygen or animals to roam. We would not have gravity to keep the earth in orbit. Without the sun, the earth would be dark and cold and life would quickly disappear.

[tex]\huge\tt{SOLUTION:}[/tex]

━┈─────────────────────┈━

→(-23.0)-(0.0_

→-23.0 degrees C

→ -23=1.86 * Cm

→ 12.37= Cm.

→i* molality

→i= 1

→12.37= 1*m

→12.37= m

12.37m= moles C2H6O2/ 10.0kg water

123.7= moles of C2H6O2

123.7moles C2H6O2 * 62.26g C2H6O2

━┈─────────────────────┈━

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“Work smarter not harder”

To calculate the density of an object, you would need to know the mass and volume of the object.

The density of an object is the ratio of the mass of the object to that of its volume.

In other words, density = mass/volume.

Thus, in order to calculate the density of an object, both its mass and its volume must be known or given.

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A negative enthalpy (ΔH)for a molecule means energy was released when the molecule went through a phase change.

The enthalpy change of a reaction is the amount of heat absorbed or released as the reaction takes place.

Also, the amount of energy required to change the phase of a material is known as the enthalpy,

A negative enthalpy entails the amount of energy released during an exothermic reaction.

Thus, a negative enthalpy (ΔH)for a molecule means energy was released when the molecule went through a phase change.

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See below~

[tex] [OH^{-}] = 0.001 \\ = 10^{-3} M \Longrightarrow pOH = 3 \\ pH + pOH = 14 \Longrightarrow pH = 14-3 = 11[/tex]

The pH of a 0.0010 M NaOH solution is approximately 11.

To calculate the pH of a solution, you need to determine the concentration of hydrogen ions ([H+]). In the case of a strong base like NaOH, the concentration of hydroxide ions ([OH-]) can be used to calculate the concentration of hydrogen ions.

Given that NaOH is a strong base, it dissociates completely in water to form Na+ and OH- ions. The concentration of hydroxide ions can be assumed to be the same as the concentration of NaOH.

In this case, the concentration of NaOH is given as 0.0010 M.

Since [OH-] = 0.0010 M, we can use the Kw (ionization constant of water) to calculate [H+].

Kw = [H+][OH-] = 1.0 x [tex]10^{-14}[/tex]

[H+] = Kw / [OH-]

[H+] = (1.0 x [tex]10^{-14}[/tex]) / (0.0010)

[H+] = 1.0 x [tex]10^{-11}[/tex]M

To calculate the pH, we use the formula: pH = -log[H+]

pH = -log(1.0 x [tex]10^{-11}[/tex])

pH ≈ 11

Therefore, the pH of a 0.0010 M NaOH solution is approximately 11.

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Answer:

Sodium has one valence electron. Valence electrons are electrons found in the outermost shell of an atom. The shell number representing the valence shell will differ depending on the atom in question. For sodium, which is in the 3rd row of the periodic table, the valence electrons will be found in the 3rd shell.

Answer:

D. What to produce?

Explanation:

A 62.2 g sample of aluminum sulfide has 2.49  * 10²³ formula units.

A mole is defined as  6.022 * 10²³  of atoms , molecules , ions or others.

It is given in the question to find the number of formula units in 62.2 g sample of Aluminum Sulfide.

To determine no. of formula units , No. of mole needs to be determined

Molecular Weight of Aluminum Sulfide is 150.158 gm

150.158 g of Aluminum Sulfide makes 1 mole

62.2 g will make 62.2 * 1 / 150.158 = 0.414 moles

1 mole = 6.022 * 10²³ formula units.

0.414 moles = 0.414 *  6.022 * 10²³

= 2.49  * 10²³ formula units.

Therefore , a 62.2 g sample of aluminum sulfide has 2.49  * 10²³ formula units.

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Answer:

A. Clear and Sunny

Explanation:

The answer would be A. Clear and Sunny. A high pressure system occurs where the air mass above the Earth is denser than in surrounding areas, and therefore exerts a higher force or pressure. They usually happen with li9ght winds. Using process of elimination, it could not be D. Warm and Stormy, C. Cloudy and Rainy, or B. Cold and Stormy because all have wet climates.

The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

BF3 molecule is a stable molecule because all the electrons present in the outermost shell of boron are covalently bonded with fluorine. Boron in BF3, three bonds is the maximum possible because boron only has 3 electrons to share.

So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

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An unsaturated solution is formed when 25g of NaCI are dissolved in 100g of water at 30 degrees Celsius.

A solution is formed as a result of the dissolution of a solute in a solvent.

However, based on the capacity of the solvent to take in more solute, a solution can be of three types namely;

An unsaturated solution is a solution whose solvent can dissolve more solute at a particular temperature.

According to this question, 25g of NaCI are dissolved in 100g of water at 30°C, hence, the solvent can take in more solute at 30°C.

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Answer: Chemistry is the study of matter and the changes it undergoes.

An example of chemistry being used in the real world is how an ECG works. Chemistry is also sometimes considered the "central science". I hope this answer helped!! :)

Answer: 3. Mass is lost due to the conversion of mass to energy.

The last statement is correct

They both have seven protons in the nucleus.

it's wrong because they have six protons in the nuclear

They both have the same mass number.

it's wrong because Carbon-12 has mass number 12 but Carbon-13 has mass number 13

They both have seven neutrons in the nucleus.

it's wrong because Carbon-12 has six  in the nucleus but Carbon-13 has seven  in the nucleus

They both have the same atomic number.

It's true. They have the atomic number - 6

Answer:

D. They both have the same atomic number.

Explanation:

ed22

There are three number of electrons lost by 1 mole of aluminium because aluminum has +3 charge on it.

When an atom loses electron, positive charge appears on the atom this is called cation. In this reaction we can see that aluminium has +3 charge which means that it loses 3 electrons.

So we can conclude that There are three number of electrons lost by 1 mole of aluminium because aluminum has +3 charge on it.

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Answer:

0.82 moles CO₂

Explanation:

To convert from grams to moles, you need to find the molar mass of CO₂. This conversion is a ratio stating the amount of grams CO₂ per 1 mole. The molar mass is calculated using the molar mass of each element (in CO₂) from the periodic table.

Molar Mass (Carbon): 12.011 g/mol

Molar Mass (Oxygen): 15.998 g/mol

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

36 grams CO₂               1 mole
----------------------  x  --------------------------  = 0.82 moles CO₂
                                 44.007 grams

Answer:

1940K and 1939K Isotopes are two forms of the same element that have different numbers of neutrons in the nucleus. This means same symbol, and same atomic number (subscript), but different mass number (superscript).