Answer is 47.14 v
by the relation
[tex]\frac{V out}{V in } = \frac{N secondary}{N primary }[/tex]
Horticulture 120 pts (HURRY)
Auto-steer technology is dependent on the use of
tracking relayed from satellites to receivers and transmitters in the farm equipment.
Answer: GPS
Explanation:
I took the test 2021
Answer:
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True or False. The Magnitude of the induced voltage in a coil of wire depends on how quickly the magnetic flux through the coil of wire changes.
Answer:
Yes, its true
Explanation:
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Answer: yes its true
Explanation:
nmo
where would a car traveling on a roller coaster have the most kinetic energy ? and why?
Answer:
As the car travels up the coaster it is gaining potential energy.
Explanation:
Because It has the greatest in amount of potential energy at the top of the coaster. when the car travels down the roller coaster it obtains speed and kinetic energy.
What formula should I use?
The density of the atmosphere on a certain planet is found to decrease as altitude increases (as measured from the planet's surface). What is the graphical relationship between altitude and atmospheric density on this planet? Altitude (km) Almospheric Density (km/mº)
Α.inverse plot B. quadratic plot C. velocity plot D. acceleration plot E.parabolic plot
Answer:I think it’s Velocity plot.
Explanation:
I hope i can help you, have a great day and good like with everything.
Answer: inverse plot
Explanation: lucky guess lmk if its right
An electron and a proton are held on an x axis, with the electron at x = + 1.000 m
and the proton at x = - 1.000 m . If a second electron is initially at x = + 20.00 m on the x axis and is given an initial velocity of 450 m/s towards the origin, will it reach and origin? And how close will it get to the origin if it doesn't?
Answer:
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
Explanation:
For this exercise we must use conservation of energy
the electric potential energy is
U = [tex]k \frac{q_1q_2}{r_{12}}[/tex]
for the proton at x = -1 m
U₁ =[tex]- k \frac{e^2 }{r+1}[/tex]
for the electron at x = 1 m
U₂ = [tex]k \frac{e^2 }{r-1}[/tex]
starting point.
Em₀ = K + U₁ + U₂
Em₀ = [tex]\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1}[/tex]
final point
Em_f = [tex]k e^2 ( -\frac{1}{r_2 +1} + \frac{1}{r_2 -1})[/tex]
energy is conserved
Em₀ = Em_f
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e^2 (- \frac{1}{r_2 +1} + \frac{1}{r_2 -1})
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e²( [tex]\frac{2}{(r_2+1)(r_2-1)}[/tex] )
we substitute the values
½ 9.1 10⁻³¹ 450 + 9 10⁹ (1.6 10⁻¹⁹)² [ [tex]- \frac{1}{20+1} + \frac{1}{20-1}[/tex] ) = 9 109 (1.6 10-19) ²( [tex]\frac{2}{r_2^2 -1}[/tex] )
2.0475 10⁻²⁸ + 2.304 10⁻³⁷ (5.0125 10⁻³) = 4.608 10⁻³⁷ ( [tex]\frac{1}{r_2^2 -1}[/tex] )
2.0475 10⁻²⁸ + 1.1549 10⁻³⁹ = 4.608 10⁻³⁷ [tex]\frac{1}{r_2^2 -1}[/tex]
[tex]\frac{2.0475 \ 10^{-28} }{1.1549 \ 10^{-37} } = \frac{1}{r_2^2 -1}[/tex]
r₂² -1 = (4.443 10⁸)⁻¹
r2 = [tex]\sqrt{1 + 2.25 10^{-9}}[/tex]
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
A specified volume of space contains an electric field for which the magnitude is given by E=E0cos(ωt). Suppose that E0 = 20 V/m and ω = 1.0 × 107 s−1. What is the maximum displacement current through a 0.40 m2 cross-sectional area of this volume?
Answer: [tex]0.708\ mA[/tex]
Explanation:
Given
[tex]E_o=20\ V/m[/tex]
[tex]\omega =10^7\ s^{-1}[/tex]
Cross-sectional area [tex]A=0.40\ m^2[/tex]
Current density is given by
[tex]J=\epsilon_o \dfrac{dE}{dt}[/tex]
Displacement current
[tex]\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A[/tex]
The required value of the maximum displacement current of the given space is [tex]7.08 \times 10^{-4} \;\rm A[/tex].
Given data:
The intensity of electric field is, [tex]E_{0}=20 \;\rm V/m[/tex].
The angular frequency of electric field is, [tex]\omega=1.0 \times 10^{7} \;\rm s^{-1}[/tex].
The cross-sectional area of space is, [tex]A =0.40 \;\rm m^{2}[/tex].
In the given problem, the instantaneous electric field is given by [tex]E = E_{0} \times cos(\omega t)[/tex]
So, the expression for the current density is,
[tex]J= \epsilon_{0} \times \dfrac{dE}{dt}[/tex]
Here, [tex]\epsilon_{0}[/tex] is the permittivity of free space. Solving as,
[tex]J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)[/tex]
And the expression for the maximum displacement current is,
[tex]I = J \times A[/tex]
And the maximum displacement current is possible only when, J is positive and J will be positive for [tex]sin(\omega t)=-1[/tex].
Then solving as,
[tex]I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A[/tex]
Thus, we can conclude that the required value of the maximum displacement current of the given space is [tex]7.08 \times 10^{-4} \;\rm A[/tex].
Learn more about the displacement current here:
https://brainly.com/question/20344850
PLEASE HEEELLLPPPPP
Two ice skaters on ice push away from each other. The friend on the left is 45 kg and the friend on the right is
40 kg. The right skater gets pushed and moves with an acceleration 2 m/s". Based on this scenario what will
happen to the left skater?
Can someone please help me with history.
Answer:
Yes my name is Axelrod I can help you
What different forms of energy are present when an egg crashes into the egg catcher?
Answer:
An egg raised above the ground has potential energy due to the force of gravity. When dropped, the egg's potential energy is converted into the kinetic energy of motion. :)
Explanation:
What type of reaction results in the formation of a salt?
Two resistors, R1 and R2, are connected
in series to a 5.00 V battery. R1 is
12.0 Ohm. A current of 0.167 A flows
through the circuit.
What is resistance of R2?
Answer:
18 ohms
Explanation:
V = I(R1 + R2)
5V = (0.167A)(12 ohms + R2)
Solving for R2
R2 = 18 ohms
An ocean wave travels at 2.2m/s if the wavelength is 11 meters what’s the frequency of the wave in Hz
Answer:
0.2 Hz
Explanation:
f = v / λ.
Where f = frequency,
v = velocity/speed,
λ = wavelength.
f = v / λ →
f = 2.2m/s / 11 m
f = 2.2 / 11 [1 / s]
f = 1 / 5 [Hz]
f = 0.2 Hz
- Determine the speed of a 350 Hz sound wave with a wavelength of 0.971 m
adio wave transmitted to the moon through snace by
Explanation:
[tex]from \: the \: wave \: equation \\ Speed \: \: V = f \lambda \\ = 350 \times 0.971 \\ = 339 850 \: {ms}^{ - 1} [/tex]
Simple harmonic motion occurs when an object is displaced from its stable equilibrium position and the force or torque pushing it back toward equilibrium is ______ in displacement. Group of answer choices exponential sinusoidal quadratic linear
Answer:
force is of the LINEAR type
Explanation:
In simple harmonic movements the restoring force is of the Hooke e-force type, which has the form
F = - k (x-x₀)
where x₀ is the initial length of the spring.
Therefore we can see this force is of the LINEAR type
Can anyone help me!!!
I need this really soon!!!!
Q. Rama's weight is 40kg . She is carrying a load of 20 kg up to a height of 20 metres. What work does she do? Also mention the type of work
No links!!!!
No spams!!!!
Answer:
3920 N.
Explanation:
that's what the answer is..
A friend insists that electric current is the same as electrical energy. Work with a partner to develop a rebuttal
against your friend's misconception.
Answer: The electrons flowing through the wire are referred to as a quantity of electricity, and the flow of electricity is referred to as “an electric current.”
Explanation: Hope it Helps have a blessed day
Shown below is a 10 kg block being pushed by a horizontal force F of magnitude 200N. The coefficient of kinetic friction between the two surface is 0.50. Find the acceleration of the block.
Answer:
15.1 m/s²
Explanation:
Step 1: Calculate the force exerted by the friction
Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.
Ff = μ × m × g
where,
μ: coefficient of kinetic friction
m: mass of the block
g: gravity
Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N
Step 2: Calculate the resulting force
The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.
R = F - Ff = R = 200 N - 49 N = 151 N
Step 3: Calculate the acceleration of the block
We will use Newton's second law of motion.
R = m × a
a = R/m
a = 151 N/10 kg = 15.1 m/s²
While traveling along a highway a driver slows from 31 m/s to 15 m/s in 8 seconds. What is the automobile’s acceleration? (Remember that a negative value indicates a slowing down or deceleration.)
Answer:
The automobile's acceleration in that time interval is -2 m/s^2
Explanation:
The acceleration is defined as the rate of change of the velocity.
The average acceleration in a given lapse of time is calculated as:
A = (final velocity - initial velocity)/time.
In this case, we have:
initial velocity = 31 m/s
final velocity = 15 m/s
time = 8 seconds.
Then the average acceleration is:
A = (15m/s - 31m/s)/8s = -2 m/s^2
Can someone help me with this please
how do we calculate the value of work?
Answer:
Work = Force × Distance
Explanation:
Work = Force × Distance
The SI unit of work is Joule
-TheUnknownScientist
the distance between the sun and moon is 480 light second. convert the distance into meter
Answer:
1.439 × 10¹¹ m is the answer.
Explanation:
1 light-second = 2.998 × 10⁸m
480 light-seconds = 480 × 2.998 × 10⁸
= 1439.04 × 10⁸
= 1.439 × 10¹¹
∴ 1.439 × 10¹¹ m is the answer.
The distance converted into the meter will be 1.439×10¹¹ m.In one light second, there are 2.998 ×10⁸ m.
What is the distance?Distance is a numerical representation of the distance between two objects or locations.
The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
The given data in the problem is;
The distance between the sun and moon is,d= 480 light second
[tex]\rm d_m[/tex] is the distance in meter
As we know,
[tex]\rm 1\ light\ second = 2.998 \times 10^8m \\\\ 480\ light\ seconds = 480 \times 2.998 \times 10^8\ m \\\\ d_m= 1439.04 \times 10^8 \\\\ d_m = 1.439 \times 10^{11}[/tex]
Hence the distance converted into the meter will be 1.439×10¹¹ m.
To learn more about the distance refer to the link;
https://brainly.com/question/26711747
How has modern safety equipment found in automobiles helped to counteract Newton’s First Law of Motion?
Answer:
Well. the law says "an object in motion stays in motion" So seatbelts could be one. they stop us humans from continuing to move when the car stops.
PLS HELP ME!!!
The engine cars that pull high-speed trains usually taper to a point in front, as shown in the illustration. How does this shape change the forces acting on the moving engine car?
Which would result in an increase in the magnetic field strength produced by an electromagnet? A) increasing the space between the turns in the coil B) increasing the number of turns in the coil C) decreasing the current in the coil D) decreasing the voltage in the coil
Answer:
B) increasing the number of turns in the
Explanation:
A) Increasing the space between the turns in the coil will decrease the number of coils. It will result in a decrease in the strength of the magnetic field because the strength of the magnetic field of an electromagnet is directly proportional to the number of coils.
B) Increasing the no. of turns in the coil will result in an increase in the strength of the magnetic field.
C) Strength of magnetic field is directly proportional to the magnitude of current passing through the electromagnet. Therefore, decreasing the current will decrease the strength of the magnetic field.
D) Decreasing the voltage will decrease the current and as a result, the strength of the magnetic field will also be decreased.
Hence, the correct option is:
B) increasing the number of turns in the
The downward force acting on an object in free fall is the force of ___________
100 points!!! Please help!!!
In the system shown above, the pulley is a uniform disk with a mass of .75 kg and a radius of 6.5 cm. The coefficient of friction between the 5.8 kg mass and the horizontal surface is .25, and the ropes does not slip on the pulley. They system is released from rest. Use work-energy principles to determine the kinetic energy of the (a) 2.8 kg mass and (b) the pulley after the 5.8 kg mass has moved 2.2 meters.
Answer:
please find the answer in the attached image, divided in 2 parts.
Convertir 0.3 Hm en cm.
Answer:
3000 cm
Explanation:
What is the driving force behind the movement of Earth's plates?
Convection currents in the mantle are slowly causing the plates to move.
The magnetic pull of the poles are pulling the plates apart.
The inertia of the rotation of the Earth causes the plates to move.
The aliens are playing with the Earth like a puzzle.
Convection currents in the mantle are slowly causing the plates to move.
How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it during condensation in the atmosphere Water gains energy during evaporation and condensation in the lithosphere. Water gains energy in condensation and releases it in evaporation. Water releases energy during evaporation and condensation.
Answer:
Water gains energy during evaporation and releases it during condensation in the atmosphere
Explanation:
In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.
In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.
In condensation, the molecules of gaseous water looses energy and becomes liquid.
Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.
Answer:
K12 HE HE
Explanation: