A steam engine delivers 5.4×10^8 J of work per minute and services 3.6×10^9 J of heat per minute from its boiler.
i) What is the efficiency of the engine?
ii) How much heat is wasted per minute?
Answers
Work shown down.
The 15% is the efficiency and the energy wasted is the second part.
Related Questions
if a buffer solution is 0.210 m in a weak acid ( a=6.7×10−5) and 0.470 m in its conjugate base, what is the ph?
Answers
If a buffer solution is 0.210 m in a weak acid and 0.470 m in its conjugate base. The pH of the buffer solution is approximately 4.53.
To determine the pH of a buffer solution, we can use the Henderson-Hasselbalch equation, which is given by
pH = pKa + log ([A-] / [HA])
Where:
pH is the logarithmic measure of the hydrogen ion concentration in the solution.
pKa is the negative logarithm of the acid dissociation constant (Ka) of the weak acid.
[A-] is the concentration of the conjugate base.
[HA] is the concentration of the weak acid.
In this case, the concentration of the weak acid ([HA]) is 0.210 M, and the concentration of the conjugate base ([A-]) is 0.470 M. The acid dissociation constant (Ka) is given as 6.7 × [tex]10^{-5}[/tex].
First, let's calculate the pKa
pKa = -log(Ka) = -log(6.7 × [tex]10^{-5}[/tex]) = 4.18
Next, substitute the given values into the Henderson-Hasselbalch equation:
pH = 4.18 + log(0.470 / 0.210) = 4.18 + log(2.238) = 4.18 + 0.35
pH = 4.53
Therefore, the pH of the buffer solution is 4.53.
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Explain why locations near the North Pole experience weeks of sunlight in June with no sunsets.
Answers
Answer:
It happens because the Earth is tilted on its axis around 23 degrees therefore the sun normally never sets at north Pole in summers. The sun doesn't set at Arctic Circle on North pole from about April 19 to August 23 each year due to this phenomenon.
Table is in the picture. and will mark brainstest.
Here is the question
Based on the information in the table, which combination of materials would make the most conductive and best insulated wire?
A) A zinc wire with glass insulation
B) A copper wire with rubber insulation
C) A plastic wire with plastic insulation
D) An aluminum wire with plastic insulation
Answers
Does Direction matter when you are measuring momentum
Answers
Answer:
Yes
Momentum is a vector quantity
Explanation:
A vector quantity is a quantity that has both magnitude and direction
So definitely direction matters
Answer:
no on edge 2021
Explanation:
a car moving south speeds up from 10 m/s to 40 m/s in 15 seconds. what is the car’s acceleration?2 m/s215 m/s230 m/s250 m/s2
Answers
The acceleration of this car include the following: A. 2 m/s².
How to calculate the acceleration of this car?In Science, the acceleration of a car can be calculated by using this mathematical expression:
a = (V - U)/t
Where:
a represents the acceleration measured in meters per seconds square (m/s²).V represents the final velocity measured in meters per seconds (m/s).U represents the initial velocity measured in meters per seconds (m/s).t represents the time measured in seconds.By substituting the given parameters into the acceleration formula, we have;
Acceleration, a = (40 - 10)/15
Acceleration, a = 30/15
Acceleration, a = 2 m/s².
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when heating a sample of liquid water, which of the following best describes the point at which boiling begins?when heating a sample of liquid water, which of the following best describes the point at which boiling begins?
Answers
When heating a sample of liquid water, the point at which boiling begins is best described as the temperature at which the vapor pressure of the liquid equals the atmospheric pressure.
The point at which boiling begins is when the vapor pressure of the liquid equals the atmospheric pressure. At this point, the liquid can no longer hold any more vapor and bubbles of vapor form and rise to the surface. The temperature at which this occurs is called the boiling point.
For water at sea level, the boiling point is 100°C (212°F). However, the boiling point of water can vary depending on the atmospheric pressure. At higher altitudes, the atmospheric pressure is lower, so the boiling point of water is lower. For example, at the top of Mount Everest, the boiling point of water is about 70°C (160°F).
The boiling point of a liquid can also be affected by the presence of impurities. For example, salt water has a higher boiling point than pure water. This is because the salt molecules interfere with the formation of water vapor.
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In a particular photoelectric effect experiment, photons with an energy of 4.00 eV are incident on a metal surface, producing photoelectrons with a maximum kinetic energy of 2.00 eV.
a) What is the work function of the metal? (in eV)
b) If the photon energy is adjusted to 6.10 eV, what will be the maximum kinetic energy of the photoelectrons? (answer in eV)
Answers
a) The work function of the metal is 2.00 eV.
b) When the photon energy is adjusted to 6.10 eV, the maximum kinetic energy of the photoelectrons will be 4.10 eV.
a) The work function (Φ) of the metal can be determined by subtracting the maximum kinetic energy (KEmax) of the photoelectrons from the energy of the incident photons (Ephoton).
Given:
The energy of incident photons (Ephoton) = 4.00 eV
The maximum kinetic energy of photoelectrons (KEmax) = 2.00 eV
To find the work function (Φ):
Φ = Ephoton - KEmax
Φ = 4.00 eV - 2.00 eV
Φ = 2.00 eV
Therefore, the work function of the metal is 2.00 eV.
b) To calculate the maximum kinetic energy of photoelectrons when the photon energy is adjusted to 6.10 eV, we use the same formula as in part (a).
Given:
The energy of incident photons (Ephoton) = 6.10 eV
To find the maximum kinetic energy of photoelectrons (KEmax):
KEmax = Ephoton - Φ
Using the previously determined work function (Φ) of 2.00 eV:
KEmax = 6.10 eV - 2.00 eV
KEmax = 4.10 eV
Therefore, when the photon energy is adjusted to 6.10 eV, the maximum kinetic energy of the photoelectrons will be 4.10 eV.
a) The work function of the metal is 2.00 eV.
b) When the photon energy is adjusted to 6.10 eV, the maximum kinetic energy of the photoelectrons will be 4.10 eV.
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A softball player is running at 4.88 m/sec when she slides into second base coming to a stop in .872 seconds. How far did she slide, and what was her acceleration?
Answers
Answer:
d=v1t - .5at^2
d=4.88 x .872 - 0.5 x (4.88/0.872) x 0.872^2
d=4.255 - 2.12
d= 2.135m
Explanation:
acceleration is negative because she is slowing down.
A force of 2 lb stretches a spring 1 ft. An 8-lb weight is attached to the end of the spring and released 4in. above the equilibrium position from rest. If the medium offers a resistance to the motion of the weight numerically equal to 3/2 times the instantaneous velocity, find the equation of motion. Determine if the system is underdamped, overdamped, or critically damped.
Answers
The solution to the differential equation is then:
x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t)
And the system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.
The force required to stretch a spring is directly proportional to the amount the spring is stretched. This relationship is known as Hooke’s Law. It can be expressed mathematically as:
F = -kx
Where F is the force applied to the spring, x is the displacement of the spring from its equilibrium position, and k is the spring constant.
For a mass-spring system under the influence of a damping force, the differential equation governing the system is:
m(d2x/dt2) + c(dx/dt) + kx = 0
where m is the mass of the object attached to the spring, c is the damping coefficient, and k is the spring constant.
The given force of 2 lb stretches the spring by 1 ft, so the spring constant is given by k = F/x = 2/1 = 2 lb/ft.
The 8-lb weight is released 4 in. above the equilibrium position, which is 0.25 ft. The initial displacement is therefore x(0) = 0.25 ft, and the initial velocity is v(0) = 0. The damping force is given by f_d = -3/2v. Using the values given, the differential equation for the system is:
m(d2x/dt2) + c(dx/dt) + kx = 0 (1)
The values of m, k, and c are given by
m = 8/g = 8/32.2 = 0.248 kg
k = 2/lb/ft * 0.4536 kg/lb * 0.3048 m/ft = 0.294 kg/sm = 0.248 kgc = 3/2
The equation of motion is then:
d2x/dt2 + 12.05dx/dt + 1.186x = 0 (2)
where we have substituted the values of m, c, and k into equation (1).
The characteristic equation is:
r2 + 12.05r + 1.186 = 0 (3)
Solving for the roots of the characteristic equation, we find:
r = (-12.05 ± √(12.052 - 4(1.186)))/2= -6.025 ± 2.181i
The roots are complex conjugates, so the solution to the differential equation can be written as:
x(t) = e⁽⁻⁶·⁰²⁵t⁾(C₁ cos(2.181t) + C₂ sin(2.181t)) (4)
The initial displacement and velocity are given by x(0) = 0.25 and v(0) = 0.
Substituting these values into equation (4) and taking the derivative, we get:
x(0) = C₁ = 0.25dx/dt|t=0 = -6.025
C₂ = 0
Solving for C₁ and C₂, we get:
C₁ = 0.25C2 = 0
The solution to the differential equation is then:
x(t) = 0.25e⁽⁻⁶·⁰²⁵t⁾ cos(2.181t) (5)
The system is underdamped because the roots of the characteristic equation have a non-zero imaginary part.
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In your own words, tell me how an element, molecule, and compound are used to make different substances. All three must be mentioned in order to receive full credit.
Answers
Answer:
When atoms from different elements are joined together in groups, they form molecules. The atoms in molecules bind together chemically, which means that the atoms cannot be separated again by physical means, such as filtration. The molecule has different properties from the elements from which is was made.
Explanation:
Calculate the magnitude of the electric field at one corner of a square 2.12 m on a side if the other three corners are occupied by 4.75×10−6 C charges. Express your answer to three significant figures and include the appropriate units.
What is the direction of the electric field at the corner?
What is the direction of the electric field at the corner?
along the side of the square between the corner and one of the charges toward the charge
along the side of the square between the corner and one of the charges outward of the charge
along the line between the corner and the center of the square toward the center
along the line between the corner and the center of the square outward of the center
Answers
The direction of the electric field at the corner is along the line between the corner and the center of the square, outward of the center.
The formula to calculate the electric field at a point due to a point charge is given by: Electric field = (k * |q|) / r^2
Given that the charge at each corner is 4.75×10−6 C and the side length of the square is 2.12 m, we can calculate the electric field due to each charge at the corner. Since the charges are at the corners, the distance (r) between each charge and the corner is equal to the side length of the square (2.12 m). Calculating the electric field due to each charge and summing them up, we have:Electric field = (k * |q|) / r^2 + (k * |q|) / r^2 + (k * |q|) / r^2
Electric field = (3 * k * |q|) / r^2
Substituting the values, we get:
Electric field = (3 * 9 x 10^9 N m^2/C^2 * 4.75×10−6 C) / (2.12 m)^2
Electric field ≈ 2.526 x 10^6 N/C
Therefore, the magnitude of the electric field at one corner of the square is approximately 2.526 x 10^6 N/C. Now, let's determine the direction of the electric field at the corner. Since the other charges are positive, the electric field vectors due to these charges will point away from them. Considering the symmetry of the square, the electric field vectors at the corner will be directed along the line between the corner and the center of the square, outward of the center.Therefore, the direction of the electric field at the corner is along the line between the corner and the center of the square, outward of the center.
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Explain why is the temperature of a hot tea higher than the temperature of iced tea?
Answers
Answer:
Because the hot tea is hot from a microwave or coffee machine when iced tea is cold from ice in the tea.
Explanation:
A force of 355 N is applied to an object that accelerates at a rate of 7.8 m/sec2 . What is the mass of the object ?
Answers
Answer:
A force of 355 N is applied to an object that accelerates at a rate of 7.8 m/sec2 . What is the mass of the object ?
Explanation:
what is the minimum possible coefficient of static friction between thebike tires and the ground?
Answers
The minimum possible coefficient of static friction between bike tires and the ground is zero. This means that there is no requirement for static friction to exist in order for the bike to remain stationary or in motion.
Static friction is the force that prevents two surfaces from sliding against each other when there is no relative motion between them. It depends on the nature of the surfaces in contact and the force pressing them together. In the case of bike tires and the ground, the coefficient of static friction measures the ratio of the maximum static frictional force to the normal force between the tire and the ground.
If the coefficient of static friction were zero, it would imply that there is no need for static friction to keep the bike tires from slipping. This situation can occur when the surfaces are extremely smooth or when other forces, such as rolling resistance or air resistance, provide enough stability to maintain traction.
However, it's important to note that a zero coefficient of static friction can also indicate a lack of friction altogether, which could make it impossible for the bike tires to maintain contact with the ground and result in sliding or loss of control.
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A laptop battery has an emf of 11.4 V. The laptop uses 0.80 A while running. Part A How much charge moves through the battery each second? Express your answer with the appropriate units. By how much does the electric potential energy of this charge increase as it moves through the battery? Express your answer with the appropriate units.
Answers
(a) The charge moving through the battery each second is 0.80 Coulombs. (b) The electric potential energy of the charge increases by 9.12 Joules as it moves through the battery.
Part A:
The charge moving through the battery each second can be calculated using the formula:
Q = I * t
Where Q is the charge, I is the current, and t is the time.
Given that the laptop uses 0.80 A while running, the charge moving through the battery each second can be calculated as:
Q = (0.80 A) * (1 s)
Calculating this expression gives us:
Q = 0.80 C
Therefore, the charge moving through the battery each second is 0.80 Coulombs.
Part B:
The change in electric potential energy as the charge moves through the battery can be calculated using the formula:
ΔPE = Q * ΔV
Where ΔPE is the change in electric potential energy, Q is the charge, and ΔV is the change in voltage.
In this case, since the battery has an emf (electromotive force) of 11.4 V, the change in voltage is equal to the emf. Therefore, we have:
ΔPE = Q * emf
Substituting the known values, we have:
ΔPE = (0.80 C) * (11.4 V)
Calculating this expression gives us:
ΔPE = 9.12 J
Therefore, the electric potential energy of the charge increases by 9.12 Joules as it moves through the battery.
(a) The charge moving through the battery each second is 0.80 Coulombs.
(b) The electric potential energy of the charge increases by 9.12 Joules as it moves through the battery.
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A shopper standing 3.00 m from a convex security mirror sees his image with a magnification of 0.250. How far is his image from the mirror's surface and is it real or virtual?
o 8.33 cm, virtual o 8.33 cm, real o 75.0 cm, virtual o 75.0 cm. real
Answers
The image of the shopper is 75.0 cm from the mirror's surface, and it is virtual.
The magnification (m) of an image formed by a convex mirror is given by the formula:
m = -d_i / d_o,
where d_i is the distance of the image from the mirror's surface and d_o is the distance of the object from the mirror's surface. In this case, the magnification is given as 0.250.
Given that the shopper is standing 3.00 m from the convex mirror (d_o = 3.00 m) and the magnification is 0.250, we can rearrange the formula to solve for d_i:
d_i = -m * d_o.
Substituting the values into the formula:
d_i = -0.250 * 3.00,
= -0.75 m.
The negative sign indicates that the image is virtual, meaning it cannot be projected onto a screen. Taking the absolute value, the image is 0.75 m from the mirror's surface.
Converting 0.75 m to centimeters, we get 75.0 cm.
The image of the shopper is located 75.0 cm from the convex mirror's surface, and it is a virtual image. This calculation utilizes the magnification formula for a convex mirror to determine the distance of the image based on the given magnification and object distance.
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A. 180Ω resistor is in series with a 0.150H inductor and a 0.600μF capactor. Part A
Compute the impedance of the circuit at a frequency of f1=500 Hz and at a frequency of f2 =1000 Hz. Enter your answer in ohms separated by comma
Z1, Z2 = ____Ω. Part B In each case; compule the phase angle of the source voltage with respect to the current. Enter your answer in degrees separated by comma.
Answers
At a frequency of 500 Hz, the impedance of the circuit is approximately 180.026Ω, and the phase angle of the source voltage with respect to the current is approximately 0.637°.
A) To compute the impedance of the circuit, we use the formula:
Z = √(R² + (XL - XC)²)
Where Z is the impedance, R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.
Given:
Resistance (R) = 180Ω
Inductance (L) = 0.150H
Capacitance (C) = 0.600μF
= 0.600 × 10⁻⁶ F
At frequency f1 = 500 Hz:
XL = 2πf1L
XC = 1/(2πf1C)
Calculating XL and XC:
XL = 2π(500 Hz)(0.150 H)
= 471 Ω
XC = 1/(2π(500 Hz)(0.600 × 10⁻⁶ F))
≈ 5307 Ω
Using the formula for impedance:
Z1 = √(R² + (XL - XC)²)
= √(180² + (471 - 5307)²)
≈ 180.026 Ω
At frequency f2 = 1000 Hz:
XL = 2πf2L
XC = 1/(2πf2C)
Calculating XL and XC:
XL = 2π(1000 Hz)(0.150 H)
= 942 Ω
XC = 1/(2π(1000 Hz)(0.600 × 10⁻⁶ F))
≈ 2653 Ω
Using the formula for impedance:
Z2 = √(R² + (XL - XC)²)
= √(180² + (942 - 2653)²)
≈ 180.134 Ω
B) The phase angle (θ) of the source voltage with respect to the current can be calculated using the formula:
θ = atan((XL - XC)/R)
At frequency f1:
θ1 = atan((XL - XC)/R)
= atan((471 - 5307)/180)
≈ 0.637°
At frequency f2:
θ2 = atan((XL - XC)/R)
= atan((942 - 2653)/180)
≈ 0.318°
At a frequency of 500 Hz, the impedance of the circuit is approximately 180.026Ω, and the phase angle of the source voltage with respect to the current is approximately 0.637°. At a frequency of 1000 Hz, the impedance of the circuit is approximately 180.134Ω, and the phase angle is approximately 0.318°.
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How far apart would two 100 kg persons need to be so that the force they exert on each other is equal to 1N? You can assume they are point masses, having mass but no size. Q1: A1m B6.672x10-7 m 8.17x10-4 m D100 nm
Answers
The distance between the two 100 kg persons needs to be approximately 8.17 x 10^-4 meters (or 0.817 mm) in order for the force they exert on each other to be equal to 1 N.
To calculate the distance between two 100 kg persons so that the force they exert on each other is equal to 1 N, we can use Newton's law of universal gravitation.
The formula for gravitational force (F) between two objects is:
F = (G * m1 * m2) / r^2
where G is the gravitational constant (approximately 6.672 x 10^-11 N·m^2/kg^2), m1 and m2 are the masses of the objects, and r is the distance between the centers of the objects.
In this case, we want the force to be 1 N, and both persons have a mass of 100 kg. Substituting these values into the formula, we get:
1 N = (6.672 x 10^-11 N·m^2/kg^2 * 100 kg * 100 kg) / r^2
Simplifying the equation:
1 N = (6.672 x 10^-7 N·m^2) / r^2
Rearranging the equation to solve for the distance (r):
r^2 = (6.672 x 10^-7 N·m^2) / 1 N
r^2 = 6.672 x 10^-7 m^2
Taking the square root of both sides:
r ≈ 8.17 x 10^-4 m
Therefore, the distance between the two 100 kg persons needs to be approximately 8.17 x 10^-4 meters (or 0.817 mm) in order for the force they exert on each other to be equal to 1 N. Option B, 6.672 x 10^-7 m, appears to be a typographical error as it corresponds to the value of the gravitational constant rather than the distance.
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The greater the mass of an object being moved, the greater amount of force needed to move the object,
Answers
Answer:
It's often called the law of inertia. Acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object). ... A more massive object has a greater tendency to resist changes in its state of motion.
Explanation:
Answer: It's often called the law of inertia. Acceleration is produced when a force acts on a mass. The greater the mass (of the object being accelerated) the greater the amount of force needed (to accelerate the object). ... A more massive object has a greater tendency to resist changes in its state of motion.
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a particular can of soda has an internal absolute pressure of 3.0 atm. 11. if the can were located at sea level, what is the gauge pressure, in atm, that someone would measure for the can?
Answers
The gauge pressure that someone would measure for the can of soda located at sea level is 2.0 atm.
Gauge pressure is the pressure measured relative to atmospheric pressure. At sea level, the atmospheric pressure is approximately 1.0 atm. To find the gauge pressure, we subtract the atmospheric pressure from the internal absolute pressure.
Gauge pressure = Internal absolute pressure - Atmospheric pressure
Given that the internal absolute pressure is 3.0 atm and the atmospheric pressure is 1.0 atm, we can substitute these values into the equation:
Gauge pressure = 3.0 atm - 1.0 atm = 2.0 atm
If the can of soda is located at sea level, someone would measure a gauge pressure of 2.0 atm. Gauge pressure represents the pressure above or below atmospheric pressure, and in this case, the can has an internal pressure that is 2.0 atm higher than the atmospheric pressure at sea level.
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Which answer below is not a statement of the second law of thermodynamics? a. Real processes proceed in a preferred direction. b. In theory, heat engines working in a cycle employ reversible processes. c. The entropy of the universe increases in all natural processes d. Energy does not flow spontancously by heat from a cold to a hot reservoir. You cannot construct a heat engine operating in a cycle that does nothing but take heat from a reservoir and perform an equal amount of work
Answers
The answer that is not a statement of the second law of thermodynamics is d. Energy does not flow spontaneously by heat from a cold to a hot reservoir.
Options a, b, and c all reflect different aspects of the second law of thermodynamics, such as the preferential direction of real processes, the increase of entropy in natural processes, and the limitation on constructing a heat engine that only performs work without rejecting any heat to a colder reservoir.
However, option d contradicts the second law by suggesting the spontaneous flow of heat from a cold to a hot reservoir, making it the answer that is not a statement of the second law of thermodynamics.
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Red light has a wavelength of 650 nm. Green light has a wavelength of 550 nm. The speed of light is 3×108 m/s
Frequency of the red light = 4.615*10^14 s^-1
Frequency of the green light = 5.455*10^14 s^-1
You are driving to school and approach a red light. How fast would you need to be going to make the light appear to be green? Give your answer in m/s. It will also need scientific notation.
Answers
To make the red light appear green, you would need to be traveling at a speed of approximately 2.727×10⁸ m/s.
How to make the red light appear green?The color of light is determined by its wavelength. Red light has a longer wavelength than green light, with the given values of 650 nm and 550 nm, respectively.
The frequency of light is inversely proportional to its wavelength, so we can use the formula:
frequency = speed of light / wavelength
Given that the speed of light is 3×10⁸ m/s, we can calculate the frequencies of red and green light:
Frequency of red light = (3×10⁸ m/s) / (650×10⁻⁹ m) = 4.615×10¹⁴ s⁻¹
Frequency of green light = (3×10⁸ m/s) / (550×10⁻⁹ m) = 5.455×10¹⁴ s⁻¹
To perceive the red light as green, we need to match the frequencies. Since the speed of light remains constant, we can equate the two frequencies:
(3×10⁸ m/s) / (λ_red) = (3×10⁸ m/s) / (λ_green)
Simplifying the equation, we find:
λ_red = λ_green
From this, we can determine the speed required to make the red light appear green:
v = (λ_red - λ_green) / λ_green = (650×10⁻⁹ m - 550×10⁻⁹ m) / 550×10⁻⁹ m = 100×10⁻⁹ m / 550×10⁻⁹ m
v ≈ 2.727×10⁸ m/s
Therefore, in order for the red light to appear green, you would need to be moving at a velocity of approximately 2.727×10⁸ m/s.
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Windows having double glass panes with some space between them is called double glazing. Why do windows in cold countries have double glazing?
options:
For the conduction of heat
For the convection of heat
For the radiation of heat
For the insulation of heat
Answers
Answer: for insulation of heat
Explanation:
Windows in cold countries have double glazing windows to provide a barrier against the outside temperature by creating a buffer zone between two glasses.
The air or any other gas-filled between the glasses act as an insulator and offer great resistance to outside temperature thereby maintaining the inside temperature intact.
calculate the magnetic flux if the magnetic field vector is b=(-20 t)i (10 t)k and the area vector is a=(-50 m2)j (8 m2) k.
Answers
The magnetic flux if the magnetic field vector is b=(-20 t)i (10 t)k and the area vector is a=(-50 m2)j (8 m2) k is 1000 t j + 80 t k.
The magnetic flux is calculated as follows:
[tex]\phi = \vec{B} \cdot \vec{A}[/tex]
where
B is the magnetic field vector,
A is the area vector, and ϕ is the magnetic flux.
In this case, we have:
[tex]\vec{B} = (-20 t)i + (10 t)k[/tex]
and
[tex]\vec{A} = (-50 m^2)j + (8 m^2) k[/tex]
Substituting these values into the equation for magnetic flux, we get:
[tex]\begin{aligned}\phi &= (-20 t)i + (10 t)k \cdot (-50 m^2)j + (8 m^2) k \\&= -20 t \cdot (-50 m^2)j + 10 t \cdot 8 m^2 k \\&= 1000 t j + 80 t k\end{aligned}[/tex]
Therefore, the magnetic flux is a vector with a magnitude of 1000t and a direction of j+k. Note that the magnetic flux is a scalar quantity, so the vector notation is only used to indicate the direction of the flux.
The magnetic flux can also be calculated as follows:
[tex]\phi = \int_A \vec{B} \cdot d\vec{S}[/tex]
where A is the area of the surface, and d
S is a small element of surface area. In this case, the area of the surface is a rectangle with dimensions 50×8 meters. The magnetic field is uniform, so we can calculate the magnetic flux as follows:
[tex]\begin{aligned}\phi &= \int_A \vec{B} \cdot d\vec{S} \\&= \int_{-50}^{50} \int_{-8}^8 (-20 t)i + (10 t)k \cdot dx dy \\&= \int_{-50}^{50} (-20 t) \cdot dy + \int_{-8}^8 (10 t) \cdot dx \\&= 1000 t j + 80 t k\end{aligned}[/tex]
The answer is: 1000 t j + 80 t k
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the force on a loop of wire in a magnetic field shown in the figure can be used to measure the field strength. the field is uniform, and the plane of the loop is perpendicular to the field.
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The force experienced by the loop can be utilized to measure the field strength of the uniform magnetic field.
This force is known as the magnetic force or the Lorentz force.
The magnetic force (F) on a current-carrying loop of wire in a magnetic field is given by the equation:
[tex]F = I * B * A * sin(\theta)[/tex]
Where:
F is the magnetic force,
I is the current flowing through the loop,
B is the magnetic field strength,
A is the area of the loop, and
θ is the angle between the magnetic field and the normal to the loop.
In this case, the loop is placed perpendicular to the magnetic field, so θ = 90 degrees, and sin(θ) = 1. Therefore, the equation simplifies to:
F = I * B * A
By adjusting the current and measuring the resulting force, we can calculate the magnetic field strength (B) using the equation:
B = F / (I * A)
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--The complete question is, How the force on a loop of wire in a magnetic field can be used to measure the field strength? the field is uniform, and the plane of the loop is perpendicular to the field.--
How are wavelength, pitch, frequency, and energy all related?
Answers
Answer:
he word that musicians use for frequency is pitch. The shorter the wavelength, the higher the frequency, and the higher the pitch, of the sound. In other words, short waves sound high; long waves sound low. ... In other words, it sounds higher
Explanation:
derive the error propagation equation for δk (the kinetic energy).
Answers
The error propagation equation for δk (the kinetic energy) is:
δk = √((1/4v^4) * δm² + m²v² * δv²).
To derive the error propagation equation for δk (the kinetic energy), we first need to understand what error propagation is.
Error propagation is a method used to estimate the uncertainty of a quantity that is derived from several other measured quantities that have uncertainties. In other words, it is a way to determine how the errors of the input quantities affect the error of the output quantity.
Now let's derive the error propagation equation for δk (the kinetic energy):
The kinetic energy (k) of an object can be calculated using the following equation:
k = 1/2mv^2
Where m is the mass of the object and v is its velocity.
We can use the standard error propagation formula to find the uncertainty in k.
This formula is given as:
δk = √((∂k/∂m)² * δm² + (∂k/∂v)² * δv²)
where δm and δv are the uncertainties in the measured values of m and v, respectively.
To find ∂k/∂m and ∂k/∂v, we need to take the partial derivatives of k with respect to m and v.
∂k/∂m = 1/2v²
∂k/∂v = mv
Now we can substitute these values in the error propagation equation:
δk = √((1/2v²)² * δm² + (mv)² * δv²)
Therefore, the error propagation equation for δk (the kinetic energy) is:
δk = √((1/4v^4) * δm² + m²v² * δv²)
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_______ are considered to be fluids.
Solids
Liquids only
Gases only
Liquids and gases
Answers
Answer:
liquids and gases
Explanation:
Liquids and gases are considered to be fluids because they yield to shearing forces, whereas solids resist them.
You throw a baseball with a mass of 0.5 kg. The ball leaves your hand with a speed of 35 m/s. Calculate the kinetic energy. (SHOW ALL WORK)
Answers
Answer:
The kinetic energy of the baseball is 306.25 joules.
Explanation:
SInce the baseball can be considered a particle, that is, that effects from geometry can be neglected, the kinetic energy ([tex]K[/tex]), in joules, is entirely translational, whose formula is:
[tex]K = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)
Where:
[tex]m[/tex] - Mass, in kilograms.
[tex]v[/tex] - Speed, in meters per second.
If we know that [tex]m = 0.5\,kg[/tex] and [tex]v = 35\,\frac{m}{s}[/tex], then the kinetic energy of the baseball thrown by the player is:
[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex]
[tex]K = 306.25\,J[/tex]
The kinetic energy of the baseball is 306.25 joules.
A point source emits electromagnetic radiation uniformly in all directions If the power output of the source is 960 W what are the amplitudes of the electric and magnetic fields in the wave at a distance of 15.0 m from the source? (The surface area of a sphere that has radius Ris 4nR? e0 = 8.854x10 C? /(N-m') . #to 4tx10 T-mA .) Ans. electric field amplitude_LbQNlc_ 2 magnetic field amplitude _5_3.3XLO
Answers
The electric and magnetic field amplitudes of an electromagnetic wave can be calculated using the power output of the source and the distance from the source. We can use the formula:
P = (1/2)ε₀cE₀²A,
where P is the power output, ε₀ is the permittivity of free space (8.854x10⁻¹² C²/(N·m²)), c is the speed of light (3x10⁸ m/s), E₀ is the electric field amplitude, and A is the surface area of a sphere with radius R.
First, let's calculate the surface area of the sphere at a distance of 15.0 m:
A = 4πR² = 4π(15.0 m)² ≈ 2827.43 m².
Now, rearranging the formula, we can solve for E₀:
E₀² = (2P) / (ε₀cA) = (2 * 960 W) / (8.854x10⁻¹² C²/(N·m²) * 3x10⁸ m/s * 2827.43 m²).
Calculating this expression gives us E₀² ≈ 8.76x10⁻⁶ N²/C².
Taking the square root, we find:
E₀ ≈ 9.36x10⁻⁴ N/C.
Finally, we can use the relationship between the electric and magnetic field amplitudes in an electromagnetic wave:
B₀ = E₀ / c,
where B₀ is the magnetic field amplitude.
Substituting the values, we get:
B₀ ≈ (9.36x10⁻⁴ N/C) / (3x10⁸ m/s) ≈ 3.12x10⁻¹² T.
Therefore, the electric field amplitude at a distance of 15.0 m from the source is approximately 9.36x10⁻⁴ N/C, and the magnetic field amplitude is approximately 3.12x10⁻¹² T.
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