a sample of gas at 25.0 c has a volume of 11.0 L and exerts a pressure of 660.0 mmHg. how many moles of gas are in the sample​

Answer:

24,000 years

Explanation:

If the scientist intends to apply the combined gas law to determine various attributes, the following statement is accurate: (A) The pressure must remain at 200 kPa, but the volume, temperature, and amount can change.

Among the statements provided:

A. The statement "The pressure must stay at 200 kPa, but the volume, temperature, and amount can change" is true regarding the remainder of the experiment if the scientist wants to use the combined gas law to calculate different properties. In the combined gas law, the pressure is a constant value, while the volume, temperature, and amount of gas can vary.

B. The statement "The volume must stay at 300 mL, but the pressure, temperature, and amount can change" is not true regarding the remainder of the experiment if the scientist wants to use the combined gas law. The combined gas law allows for changes in all four variables: pressure, volume, temperature, and amount of gas.

C. The statement "The temperature must stay at 900 K, but the pressure, temperature, and amount can change" is not true regarding the remainder of the experiment if the scientist wants to use the combined gas law. The combined gas law considers variations in temperature along with other variables.

D. The statement "The amount must stay at 0.008 mol CO₂, but the temperature, pressure, and volume can change" is not true regarding the remainder of the experiment if the scientist wants to use the combined gas law. The combined gas law takes into account changes in all four variables, including the amount of gas.

In summary, only statement A is true regarding the remainder of the experiment if the scientist wants to use the combined gas law.

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Complete question :

Which of the following statements are true regarding the remainder of the experiment if the scientist wants to use the combined gas law to calculate different properties?

A. The pressure must stay at 200 kPa, but the volume, temperature, and amount can change.

B. The volume must stay at 300 mL, but the pressure, temperature, and amount can change.

C. The temperature must stay at 900 K, but the pressure, temperature, and amount can change.

D. The amount must stay at 0.008 mol CO2, but the temperature, pressure. and volume can change. are filled with comcsodiocodec

Answer:

The power plants

are inexpensive to build

The amphiprotic substances among the options provided are HS⁻ and NH₃.

The term "amphiprotic" refers to substances that can act as both acids and bases, depending on the reaction conditions.

a. H₂SO₄ (sulfuric acid) is not considered amphiprotic. It is a strong acid that readily donates a proton (H+) but does not accept protons in typical acid-base reactions.

b. HS⁻ (hydrogen sulfide ion) is amphiprotic. It can act as a base by accepting a proton to form H₂S (hydrogen sulfide), and it can also act as an acid by donating a proton to form S²⁻ (sulfide ion).

c. PO₄³⁻ (phosphate ion) is not considered amphiprotic. It is a polyprotic base that can donate multiple protons, but it does not accept protons in typical acid-base reactions.

d. NH₃ (ammonia) is amphiprotic. It acts as a base by accepting a proton to form NH₄⁺ (ammonium ion), and it can also act as an acid by donating a proton to form NH₂⁻ (amide ion).

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Compound A is likely a compound containing a central carbon atom bonded to two methyl groups, followed by a carbon chain of three carbons ending with a carbonyl group.

Based on the given reaction of oxidative cleavage with KMnO₄ in an acidic solution, the products formed are:

Compound A → (CH₃)₂C=O + CH₃CH₂CH₂CO₂H

From this, we can deduce that Compound A must be a compound that, upon oxidative cleavage, yields acetone [(CH₃)₂C=O] and a carboxylic acid (CH₃CH₂CH₂CO₂H).

To propose a structure for Compound A, we need to consider the functional groups and the products formed.

1. Acetone (CH₃)₂C=O: This is a ketone functional group, consisting of a carbon double-bonded to an oxygen atom, with two methyl groups attached to the same carbon atom.

2. Carboxylic acid (CH₃CH₂CH₂CO₂H): This is a carboxylic acid functional group, consisting of a carbon double-bonded to an oxygen atom (carbonyl group) and a hydroxyl group (-OH) attached to the same carbon atom. The carbon atom is further bonded to an ethyl group (CH₂CH₂) and a hydrogen atom (H).

Based on these products, a possible structure for Compound A is:

In this structure, the central carbon atom is bonded to two methyl groups (CH₃) and is connected to an ethyl group (CH₂CH₂) and a carboxylic acid group (COOH).

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In the given energy chain, the energy is created in the fire when it heats up the pot. When the pot heats up, it cooks the food that fuels the body. As the food fuels the body, the body releases heat during activity. Therefore, the energy is created in the initial stage of the chain, i.e., when the fire heats up the pot.

The given energy chain is as follows:

Fire heats up a pot → Pot cooks food → Food fuels body → Body releases heat during activity

In the given energy chain, the energy is created in the first step when the fire heats up the pot. As the fire heats up the pot, the pot becomes hot and cooks the food that is in it. This cooking of food releases energy, which can be used by the body.The energy is then transferred to the body as it consumes the cooked food. The food fuels the body and provides it with the necessary energy to carry out activities. As the body uses this energy, it also releases heat during activity, which can be measured in the form of sweat or an increase in body temperature.Therefore, the energy is created in the fire heats up the pot step of the energy chain.

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The concentration of OH- for a 0.0545 M solution of hydrochloric acid (HCl) is 7.21 x 10^-13 M.

Let's first understand the concepts of acids and bases and strong acids and bases.

Acids are proton donors, and bases are proton acceptors. The strength of an acid or a base is determined by the extent to which it donates or accepts protons. Strong acids and bases dissociate completely in water, while weak acids and bases dissociate only partially.

Thus, a strong acid or base has a high concentration of H+ or OH-, respectively.
Now let's solve the problem. We are given a 0.0545 M solution of hydrochloric acid (HCl).

Since HCl is a strong acid, it dissociates completely in water according to the equation:

HCl → H+ + Cl-

The concentration of H+ in the solution will be equal to the concentration of HCl, which is 0.0545 M.
Since we know that

pOH + pH = 14,

we can calculate the pOH of the solution using the pH:

pH = -log[H+]

pH = -log(0.0545)

pH = 1.2648
Now,

pOH + pH = 14

can be rewritten as:

pOH = 14 - pH

pOH = 14 - 1.2648

pOH = 12.7352
The concentration of OH- can be calculated using the pOH:

pOH = -log[OH-]

12.7352 = -log[OH-]

[OH-] = 7.21 x 10^-13
Therefore, the concentration of OH- for a 0.0545 M solution of hydrochloric acid (HCl) is 7.21 x 10^-13 M.

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Answer:chain reaction

Explanation:

Answer:

0.68 M

Explanation:

The concentration of a solute refers to Molarity= [tex]\frac{moles}{Liter}[/tex]

We need to find moles, we can do that by using stoichiometry to convert 6g > moles using molar mass.

Molar mass of C6H8O6= 176 g/mol; this is our key to converting the amount we have to moles.

6g C6H8O6 x [tex]\frac{1 mol}{176 g}[/tex]C6H8O6 = 0.034 mol C6H8O6

Now we need our volume per drop.

We know 1000 mL=1 L

We have 20 drops per 1 mL, so 1 mL / 20 = 0.05 mL per drop. But we need Liters, so we'll convert it to Liters.

0.05 mL x [tex]\frac{1 L}{1000mL}[/tex] = 0.00005L

Now we can solve for Molarity.

Molarity of C6H8O6 = [tex]\frac{0.034 mols}{0.00005 L}[/tex] = 0.068M of C6H8O6

For the reaction 2H2S(g) ⇌ 2H2(g) + S2(g), the effect of a volume change on this reaction at equilibrium can be considered. It can be predicted whether increasing the reaction volume will cause the reaction to shift to the right, shift to the left, or have no effect on the reaction.

In this reaction, two moles of gaseous reactants are being converted into two moles of gaseous products. Therefore, this is a reaction that involves a change in volume. According to Le Chatelier's principle, the equilibrium will shift in such a way as to counteract the effect of the volume change.

If the reaction volume is increased by adding inert gas (i.e., a gas that doesn't react with the reactants), then the total pressure of the system will increase, but the partial pressures of the reactants and products will remain the same. Since the partial pressures remain unchanged, the equilibrium will not shift in either direction.

However, if the reaction volume is decreased by removing some of the gaseous products, then the partial pressure of the products will decrease. In order to counteract this decrease, the equilibrium will shift to the right to produce more gaseous products (i.e., more H2 and S2). Therefore, decreasing the volume will cause the reaction to shift to the right.

Therefore, increasing the reaction volume will have no effect on this reaction at equilibrium.

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Diffusion is the process by which particles (such as molecules, ions, or atoms) move from an area of higher concentration to an area of lower concentration, driven by the concentration gradient.

A concentration gradient refers to the difference in concentration between two regions. In diffusion, particles move randomly and collide with each other, causing them to spread out and distribute themselves evenly.

As particles move from higher concentration to lower concentration, the concentration gradient decreases, resulting in the equalization of concentrations over time. This movement occurs due to the natural tendency of particles to achieve a state of equilibrium, where there is no net movement of particles across the concentration gradient.

Diffusion plays a crucial role in various biological, physical, and chemical processes, such as gas exchange in the lungs, the transport of nutrients across cell membranes, and the mixing of substances in solutions.

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To calculate the percent recovery for each component (basic, acidic, and neutral) and the percent error for the melting point of each component in Experiment 4C, specific formulas and calculations are required. The percent recovery is calculated by dividing the mass of the recovered component by the initial mass and multiplying by 100. The percent error for the melting point is calculated by comparing the experimental melting point to the accepted literature value and expressing the difference as a percentage of the accepted value.

To calculate the percent recovery for each component, you need to divide the mass of the recovered component by the initial mass and multiply by 100. Let's perform the calculations for each component:

a. Basic (Ethyl-4-amino benzoate):

Percent Recovery = (Recovered mass of basic component / Initial mass of basic component) x 100

Percent Recovery = (0.0137 g / 0.0498 g) x 100 = 27.51%

b. Acidic (Benzoic Acid):

Percent Recovery = (Recovered mass of acidic component / Initial mass of acidic component) x 100

Percent Recovery = (0.0322 g / 0.0588 g) x 100 = 54.76%

c. Neutral (9-fluorenone):

Percent Recovery = (Recovered mass of neutral component / Initial mass of neutral component) x 100

Percent Recovery = (0.0422 g / 0.0508 g) x 100 = 83.07%

To calculate the percent error for the melting point of each component, you need to compare the experimental melting point to the accepted literature value. The percent error is calculated using the formula:

Percent Error = ((Experimental melting point - Accepted melting point) / Accepted melting point) x 100

Let's perform the calculations for each component:

a. Basic (Ethyl-4-amino benzoate):

Percent Error = ((84.0°C - Accepted melting point) / Accepted melting point) x 100

b. Acidic (Benzoic Acid):

Percent Error = ((121.5°C - Accepted melting point) / Accepted melting point) x 100

c. Neutral (9-fluorenone):

Percent Error = ((82.0°C - Accepted melting point) / Accepted melting point) x 100

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The critical angle is given by sin ic = n2 / n1, where n1 and n2 are the indices of refraction for the media.

Using the formula sin ic = n2 / n1 for the critical angle for a liquid-air surface, we can calculate the index of refraction of the liquid.47.7° = sin⁡ic = n2 / n1, where n1 is the index of refraction of air, which is 1.00. The index of refraction of the liquid is therefore 1.33.

When light travels from a medium with a high refractive index (n1) to a medium with a low refractive index (n2), total internal reflection occurs if the angle of incidence is greater than the critical angle (ic).

The critical angle (ic) can be calculated using the formula sin ic = n2 / n1, where n1 and n2 are the indices of refraction of the media. The angle of incidence that causes total internal reflection is the critical angle.

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Answer: Balanced forces

Explanation: Equal forces acting in opposite directions are called balanced forces. Balanced forces acting on an object will not change the object's motion.

In 0.750 moles of aluminum oxide (Al2O3), there are 2.25 moles of O2- ions. This is determined by the balanced chemical equation for the formation of aluminum oxide, which states that for every 1 mole of Al2O3, there are 3 moles of O2- ions.

By using a simple mole-to-mole conversion, we can calculate the number of moles of O2- ions present. Thus, with 0.750 moles of Al2O3, multiplying by the ratio of 3 moles O2- ions to 1 mole Al2O3 yields 2.25 moles of O2- ions. To determine the number of moles of O2- ions in 0.750 moles of aluminum oxide (Al2O3), we need to consider the balanced chemical equation for the formation of aluminum oxide. The formula for aluminum oxide indicates that for every 1 mole of Al2O3, there are 3 moles of O2- ions. Therefore, if we have 0.750 moles of Al2O3, we can calculate the number of moles of O2- ions as follows:

0.750 moles Al2O3 × (3 moles O2- ions / 1 mole Al2O3) = 2.25 moles O2- ions

Therefore, there are 2.25 moles of O2- ions in 0.750 moles of aluminum oxide, Al2O3.

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Answer:

9.05 g

Explanation:

PV=nRT

Use the ideal gas equation. Substitute values.

P = 5 atm

V = 1.50 L

n = ?

R (gas constant) = 0.08206 L-atm/mol-K

T = 20.0°C

*Always convert °C to K.

T = 20.0° + 273 = 293K

Substitute values.

(5 atm)(1.50 L) = n(0.08206 L-atm/mol-K)(293K)

n = (5 atm)(1.50 L) / (0.08206 L-atm/mol-K)(293K)

n = 0.3119335... mol

Convert to grams with the given average mass of air.

0.3119335... mol x (29.0 g/1 mol) = 9.05 g

Answer:

Explanation:

true.                        

Answer:

True. why?

Because the fluid that is lost through the blood vessels is restored but with no central pump or heart, this device releases and collects fluid.

Answer:

Because both the bonding electrons come from the oxygen atom. Explanation: A coordinate covalent bond is formed when both the bonding electrons are coming from the same atom

Explanation:

The mass (mm) of glucose in 195 mL of a 5.50% (m/v) glucose solution is 10.725 grams (g).

The mass (mm) of glucose in 195 mL of a 5.50% (m/v) glucose solution is 10.725 grams (g).Explanation:The formula used to calculate the mass (mm) of glucose in 195 mL of a 5.50% (m/v) glucose solution is given as follows:Firstly, we need to know the formula of the percentage by mass/volume:%(m/v) = (mass of solute / volume of solution) × 100where,(mass of solute / volume of solution) is the concentration of the solution (C) and can be represented as:C = (mass of solute / volume of solution)Now, using the above formula we can find out the mass (mm) of glucose in 195 mL of a 5.50% (m/v) glucose solution:Given,Volume of solution (V) = 195 mLConcentration of solution (C) = 5.50% (m/v)The concentration of solution (C) is 5.50% (m/v)So, it means in 100 mL of the glucose solution, 5.50 g of glucose is present. Hence, in 195 mL of glucose solution, the mass of glucose is given as:Mass of glucose = (mass/volume) × volumeMass of glucose = (5.50 g/100 mL) × 195 mL= 0.055 g/mL × 195 mL= 10.725 gTherefore, the mass (mm) of glucose in 195 mL of a 5.50% (m/v) glucose solution is 10.725 grams (g).

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Answer:

The first one is correct.

Explanation: Eh Are you cheating on quiz?

Part A: [tex]Fe(OH)_{3} (s)[/tex] + 3H+(aq) → [tex]Fe^3+(aq)[/tex]+ [tex]3H_{2}O(l)[/tex](solid [tex]Fe(OH)_{2}[/tex] reacts with aqueous H+ to form [tex]Fe^3+[/tex] ions and water). Part B: H+(aq) + [tex]ClO_{3}^-[/tex](aq) + Na+(aq) +[tex]OH^-(aq)[/tex]→ Na+(aq) + [tex]ClO_{3}^-(aq)[/tex] + [tex]H_{2}O(l)[/tex](H+ reacts with [tex]OH^-[/tex] to form water in the presence of Na+ and [tex]ClO_{3}^-[/tex] ions).

Part A:

The balanced net ionic equation for the reaction between solid [tex]Fe(OH)_{3}[/tex] and aqueous [tex]H_{2}SO_{4}[/tex]is:

[tex]Fe(OH)_{3} (s)[/tex] + 3H+(aq) + [tex]3SO_{4}^2-(aq)[/tex] → [tex]Fe^3+(aq)[/tex] + [tex]3SO_{4}^2-(aq)[/tex] +[tex]3H_{2}O(l)[/tex].

In this reaction, the [tex]Fe(OH)_{3}[/tex] solid reacts with the H+ ions from [tex]H_{2}SO_{4}[/tex]to form[tex]Fe^3+[/tex] ions and water molecules. The sulfate ions [tex](SO_{4}^2-)[/tex]are spectator ions and do not participate in the net reaction. The phases are indicated by (s) for solid, (aq) for aqueous, and (l) for liquid.

Part B:

The balanced net ionic equation for the reaction between [tex]HClO_{3}(aq)[/tex] and NaOH(aq) is:

H+(aq) + [tex]ClO_{3}^-(aq)[/tex]+ Na+(aq) + [tex]OH^-(aq)[/tex] → Na+(aq) + [tex]ClO_{3}^-(aq)[/tex] + [tex]H_{2}O(l)[/tex].

Here, the H+ ion from [tex]HClO_{3}[/tex] reacts with the [tex]OH^-[/tex] ion from NaOH to form water molecules. Sodium ion (Na+) and chlorate ion ([tex]ClO_{3}^-[/tex]) are spectator ions. The phases are indicated by (aq) for aqueous and (l) for liquid.

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Answer:

I only

last answer

Explanation:

Answer:

Hi

Explanation:

Decomposition reactions are really the opposite of combination reactions. In decomposition reactions, a single compound breaks down into two or more simpler substances (elements and/or compounds).

Explanation:

Decomposition chemical reactions

Decomposition reactions are really the opposite of combination reactions. In decomposition reactions, a single compound breaks down into two or more simpler substances (elements and/or compounds).

The decomposition of water into hydrogen and oxygen gases

and the decomposition of hydrogen peroxide t form oxygen gas and water

are examples of decomposition reactions.

Answer:

carbon dioxide and oxygen

Explanation:

Answer:

This process produces methane and hydrogen

Explanation:

The addition of 0.183 moles of hydrobromic acid to a 1 liter solution containing 0.487 M acetic acid and 0.365 M sodium acetate will lower the pH slightly. On the other hand, the addition of 0.391 moles of nitric acid to a 1 liter solution containing 0.474 M hydrocyanic acid and 0.356 M potassium cyanide will lower the pH by several units.

In the first case, the acetic acid and sodium acetate form a buffer solution, which helps maintain a relatively stable pH. The acetic acid acts as a weak acid, while the sodium acetate is its conjugate base. When a small amount of hydrobromic acid is added, it reacts with the acetate ions in the buffer system, shifting the equilibrium towards the formation of more acetic acid and water. This results in an increase in the concentration of hydronium ions (H3O+), leading to a slight decrease in pH.

In the second case, the hydrocyanic acid and potassium cyanide also form a buffer solution. However, nitric acid is a strong acid that completely ionizes in water. The addition of nitric acid increases the concentration of hydronium ions significantly, overpowering the buffer system and causing a substantial decrease in pH.

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f < cl < se < as (fluorine, chlorine, selenium, arsenic), which arranges the elements in increasing order of electronegativity.

Hence, the correct option is C.

Electronegativity is a measure of an atom's ability to attract electrons towards itself when it is part of a chemical bond. It generally increases as you move across a period from left to right and decreases as you move down a group in the periodic table.

A. cl < f < se < as (chlorine, fluorine, selenium, arsenic):

Chlorine (Cl) has a higher electronegativity than fluorine (F), selenium (Se), and arsenic (As). Therefore, it is arranged correctly that chlorine has the highest electronegativity, followed by fluorine, selenium, and then arsenic.

B. se < f < as < cl (selenium, fluorine, arsenic, chlorine):

This arrangement is not in increasing order of electronegativity. Fluorine (F) has the highest electronegativity among these elements, followed by chlorine (Cl), then arsenic (As), and selenium (Se) has the lowest electronegativity.

C. f < cl < se < as (fluorine, chlorine, selenium, arsenic):

This arrangement is correct. Fluorine (F) has the highest electronegativity, followed by chlorine (Cl), then selenium (Se), and arsenic (As) has the lowest electronegativity.

D. as < se < cl < f (arsenic, selenium, chlorine, fluorine):

This arrangement is not in increasing order of electronegativity. Fluorine (F) has the highest electronegativity among these elements, followed by chlorine (Cl), then selenium (Se), and arsenic (As) has the lowest electronegativity.

Therefore, the correct answer is option C: f < cl < se < as (fluorine, chlorine, selenium, arsenic), which arranges the elements in increasing order of electronegativity.

Hence, the correct option is C.

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Answer:

A. 1147.44 grams

Explanation:

Multiply volume by molarity to get the moles of solution.

5.85 M = mol/2.0 L

mol = (5.85 M)(2.0 L)

mol = 11.7

There is 11.7 moles of H2SO4.

Convert to grams with molar mass.

11.7 mol H2SO4 x (98.076 g/1 mol) = 1147.49 g

Closest answer is A, 1147.44 g.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

net force = 2400 × 3.6

We have the final answer as

Hope this helps you