Answer:
8 vehicles
Step-by-step explanation:
Given: Monthly salary of salesperson is $2400
Incentive of salesperson is $250 per vehicle sold.
First, lets compute income to earned apart from salary.
∴ Deduct salary from the target amount
$2000 need to be earned only through incentive, which is $250 per vehicle sold.
Now, solving to get number vehicles to be sold to earn $2000 as incentive.
Number of vehicle=
8 vehicles need to be sold by salesperson to get total earning as $4400.
Need help with this...pronto..please
g(n) = 2n + 3
h(n)=n-1
Find (g•h)(n)
Answer:
Step-by-step explanation:
g(n) = 2n + 3
h(n) = n − 1
(g * h)(n) = g(h(n))
= g(n − 1)
= 2(n − 1) + 3
= 2n − 2 + 3
= 2n + 1
A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If the height of the bounce follows geometric progression, find the general term that represent the situation in term of k. [2 marks] Hence, if the ball dropped from a height of 235ft, determine i. the highest height achieved by the ball after six bounces ii. the total distance travelled by the ball when it strikes the ground for 12th time [2 marks] [3 marks b) The number of cell double after each process of cell division every 2 hours. If there are 120 bacteria initially, how many bacteria will be there after one and half day? [4 marks]
The movement of the ping pong ball follows a exponential progression.
The expression for the k-th bounce is: [tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]The height after the 6th bounce is 41.82 ftThe total distance after the 12th bounce is 1584.84ft.There will be 31457280 bacteria after a day and a half.1. Ping pong ball
The given parameters are:
[tex]\mathbf{a = 235}[/tex] --- the initial height
[tex]\mathbf{r = 75\%}[/tex] --- the common ratio
(a) The expression after bouncing k times
To do this, we make use of
[tex]\mathbf{T_n = a \times r^n}[/tex]
So, we have:
[tex]\mathbf{T_n = 235 \times (0.75)^n}[/tex]
In this case; k = n.
So, the equation becomes
[tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]
Hence, the expression for the k-th bounce is: [tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]
(b) The height after bouncing 6 times
This means that k = 6.
So, we have:
[tex]\mathbf{T_k = 235 \times (0.75)^k}[/tex]
[tex]\mathbf{T_6 = 235 \times (0.75)^6}[/tex]
[tex]\mathbf{T_6 = 41.82}[/tex]
Hence, the height after the 6th bounce is 41.82 ft
(c) The total distance after the 12th bounce
First, we calculate the total height after the 12th bounce using:
[tex]\mathbf{S_k = \frac{a(1 - r^k)}{1 - r}}[/tex]
So, we have:
[tex]\mathbf{S_k = \frac{235 \times (1 - 0.75^{12})}{1 - 0.75}}[/tex]
[tex]\mathbf{S_k = \frac{235 \times (0.968)}{0.25}}[/tex]
[tex]\mathbf{S_k = 909.92}[/tex]
So, the total distance is:
[tex]\mathbf{Distance = 2 \times S_k - a}[/tex]
[tex]\mathbf{Distance = 2 \times 909.92 - 235}[/tex]
[tex]\mathbf{Distance = 1584.84}[/tex]
Hence, the total distance after the 12th bounce is 1584.84ft.
(2) Cell division
The given parameters are:
[tex]\mathbf{r = 2/2hr}[/tex] --- rate
[tex]\mathbf{a = 120}[/tex] --- initial number of cells
[tex]\mathbf{t = 18}[/tex] --- number of 2 hours is a day and a half
So, the number of bacteria is:
[tex]\mathbf{T_t = ar^t}[/tex]
This gives
[tex]\mathbf{T_t = 120 \times 2^{18}}[/tex]
[tex]\mathbf{T_t = 31457280}[/tex]
Hence, there will be 31457280 bacteria after a day and a half.
Read more about exponential functions at:
https://brainly.com/question/11487261
What do you already know about credit cards?
Answer:
A credit card is a payment card issued to users to enable the cardholder to pay a merchant for goods and services based on the cardholder's accrued debt.
Step-by-step explanation:
help pls don't get it wrong I have an election tmr to see if I have good grades pls help
BTW,,
[tex]join \: bunny \: squad[/tex]
[tex]just \: comment \: if \: you \: want[/tex]
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Answer:
pls mark my brainliest because you didn't wriitten coorect question
Step-by-step explanation:
Kiran has 27 nickels and quarters in his pocket, worth a total of $2.75.
a. Write a system of equations to represent the relationships between the
number of nickels n, the number of dimes d, and the dollar amount in
this situation.
Answer:
[tex]\begin{cases}n+d = 27\\0.05n+0.10d = 2.75\\\end{cases}[/tex]
====================================================
Explanation:
n = number of nickels
d = number of dimes
The n and d are placeholders for positive whole numbers.
Since we have 27 coins, we know that n+d = 27. The two subcounts must add to the grand total of 27. That explains how the first equation is set up.
The second equation is set up by looking at the dollar amount each group of coin brings in.
0.05n = amount of money in dollars the nickels bring in
0.10d = amount of money in dollars the dimes bring in
0.05n+0.10d = total amount of money in dollars = 2.75
The single curly brace to the left of the equations tells the reader we're dealing with a system of equations. The equations are tied together.
Parallelogram A and B are similar. What is the scale factor from rectangle A to B? 12 2 5 А B 4.8
Answer:
i dont get it
Step-by-step explanation:
In Example 2 we saw that Airbus A330-300s seat 330 passengers and cost $250 million each, Boeing 767-300ERs seat 270 passengers and cost $200 million each, while Boeing Dreamliner 787-9s seat 240 passengers and cost $250 million each. You are the purchasing manager of an airline company and have a spending goal of $4950 million for the purchase of new aircraft to seat a total of 5850 passengers. Your company has a policy of supporting U.S. industries, and you have been instructed to buy twice as many Boeings as Airbuses. Given the selection of three aircraft, how many of each should you order?
The number of order of each aircraft is an illustration of simultaneous equations.
You should order 7 Airbus A330-300s, 5 Boeing 767-300ERs and 9 Boeing Dreamliner 787-9s
To do this, we make use of the following representations:
A represents Airbus A330-300sB represents Boeing 767-300ERsC represents Boeing Dreamliner 787-9sFrom the question, we have the following equations
[tex]\mathbf{330A + 270B + 240C = 5850}[/tex] ----the number of passengers
[tex]\mathbf{B + C = 2A}[/tex] --- the relationship between the number of planes
[tex]\mathbf{250A + 200B + 240C =4950 }[/tex] --- the budget
Make A the subject in [tex]\mathbf{B + C = 2A}[/tex]
[tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex]
Substitute [tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex] in [tex]\mathbf{330A + 270B + 240C = 5850}[/tex]
[tex]\mathbf{330 \times \frac{1}{2}(B + C) + 270B + 240C = 5850}[/tex]
[tex]\mathbf{165B + 165C + 270B + 240C = 5850}[/tex]
[tex]\mathbf{435B + 405C = 5850}[/tex]
Divide through by 15
[tex]\mathbf{29B + 27C = 390}[/tex]
Make C the subject
[tex]\mathbf{C = \frac{390 - 29B}{27}}[/tex]
Substitute [tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex] in [tex]\mathbf{250A + 200B + 240C =4950 }[/tex]
[tex]\mathbf{250 \times \frac{1}{2}(B + C) + 200B + 240C =4950 }[/tex]
[tex]\mathbf{125B + 125C + 200B + 240C =4950 }[/tex]
[tex]\mathbf{325B + 365C =4950 }[/tex]
Divide through by 5
[tex]\mathbf{65B + 73C =990}[/tex]
Substitute [tex]\mathbf{C = \frac{390 - 29B}{27}}[/tex]
[tex]\mathbf{65B + 73\times\frac{390 - 29B}{27} =990}[/tex]
Multiply through by 27
[tex]\mathbf{65B \times 27+ 73\times(390 - 29B) =990 \times 27}[/tex]
[tex]\mathbf{1755B+ 28470 - 2117B =26730}[/tex]
Collect like terms
[tex]\mathbf{1755B- 2117B =26730 - 28470}[/tex]
[tex]\mathbf{-362B =-1740}[/tex]
Solve for B
[tex]\mathbf{B =\frac{1740}{362}}[/tex]
[tex]\mathbf{B =5}[/tex] --- approximated
Substitute [tex]\mathbf{B =5}[/tex] in [tex]\mathbf{C = \frac{390 - 29B}{27}}[/tex]
[tex]\mathbf{C = \frac{390 - 29 \times 5}{27}}}[/tex]
[tex]\mathbf{C = \frac{245}{27}}}[/tex]
[tex]\mathbf{C = 9}[/tex] --- approximated
Recall that: [tex]\mathbf{A=\frac{1}{2}(B + C)}[/tex]
So, we have:
[tex]\mathbf{A = \frac{1}{2} \times (5 + 9)}[/tex]
[tex]\mathbf{A = \frac{1}{2} \times 14}[/tex]
[tex]\mathbf{A = 7}[/tex]
Hence, you should order 7 Airbus A330-300s, 5 Boeing 767-300ERs and 9 Boeing Dreamliner 787-9s
Read more about simultaneous equations at:
https://brainly.com/question/16763389
Can someone please show me their working on these on how to work out?
To rationalize essentially means to get rid of the radical.
The trick to all of these it to multiply the top and bottom by a radical that will turn the radical you have into the square root of a perfect square.
Part a: [tex]\dfrac{1}{2\sqrt{5}}[/tex]
One approach that will always work, but not be the smallest radical, is to just multiply by the radical that is already there.
In the case of [tex]\dfrac{1}{2\sqrt{5}}[/tex], you can multiply the top and bottom by [tex]\sqrt{5}[/tex], so you'll really do this:
[tex]\dfrac{1}{2\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}} = \dfrac{1\cdot\sqrt{5}}{2\sqrt{5}\sqrt{5}}[/tex]
But in the bottom, [tex]\sqrt{5}\cdot\sqrt{5} = \sqrt{25}=5[/tex], so your work finishes out like this:
[tex]\dfrac{1\cdot\sqrt{5}}{2\sqrt{5}\sqrt{5}} = \dfrac{\sqrt{5}}{2\sqrt{25}} = \dfrac{\sqrt{5}}{2\cdot5} = \dfrac{\sqrt{5}}{10}[/tex]
Part b: [tex]\dfrac{4}{5\sqrt{2}}[/tex]
In the case of [tex]\dfrac{4}{5\sqrt{2}}[/tex], you can multiply the top and bottom by [tex]\sqrt{2}[/tex], so you'll really do this:
[tex]\dfrac{4}{5\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}[/tex]
But in the bottom, [tex]\sqrt{2}\cdot\sqrt{2} = \sqrt{4}=2[/tex], so your work finishes out like this:
[tex]\dfrac{4}{5\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{4\sqrt{2}}{5\sqrt{4}}=\dfrac{4\sqrt{2}}{5\cdot{2}}=\dfrac{4\sqrt{2}}{10}[/tex]
Sometimes the fraction can be reduced, so this should be reduced to [tex]\dfrac{2\sqrt{2}}{5}[/tex].
Looking at all the others, they'll follow this same approach and they will all reduce at the end.
Here's part c, for one more example.
Part c: [tex]\dfrac{3}{3\sqrt{2}}[/tex]
In the case of [tex]\dfrac{3}{3\sqrt{2}}[/tex], you can multiply the top and bottom by [tex]\sqrt{2}[/tex], but you should also reduce the initial fraction first.
[tex]\dfrac{3}{3\sqrt{2}} = \dfrac{1}{1\cdot\sqrt{2}} = \dfrac{1}{\sqrt{2}}[/tex]
And now proceed with rationalizing:
[tex]\dfrac{1}{\sqrt{2}} \cdot\dfrac{\sqrt{2}}{\sqrt{2}}[/tex]
But in the bottom, [tex]\sqrt{2}\cdot\sqrt{2} = \sqrt{4}=2[/tex], so your work finishes out like this:
[tex]\dfrac{1}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{1\cdot\sqrt{2}}{\sqrt{4}}=\dfrac{\sqrt{2}}{{2}}[/tex]
And you're done.
Hopefully that helps you finish the rest of those.
To check your answers, here is the answer key for the rest:
part d:[tex]\dfrac{2\sqrt{6}}{5}[/tex]
part e:[tex]\dfrac{4\sqrt{2}}{3}[/tex]
part f:[tex]\dfrac{4\sqrt{5}}{7}[/tex]
part g:[tex]\dfrac{5\sqrt{10}}{3}[/tex]
part d:[tex]\dfrac{5\sqrt{2}}{3}[/tex]
Answer:
Step-by-step explanation:
(a) 1/(2 sqrt5) x (sqrt 5)/(sqrt5) = (sqrt 5)/10
(b) 4/(5bsqrt2) x (sqrt2)/(sqrt2) = (4sqrt2)/10 = (2sqrt2)/5
(c) 3/(3 sqrt2) x (sqrt2)/(sqrt2) =(sqrt2)/2
(d) 12 /(5 sqrt6) x (sqrt6)/(sqrt6) = (12sqrt6)/30 = (2sqrt6)5
(e) 8/(3 sqrt2) x (sqrt2)/(sqrt2) = (8 sqrt2)/6 = (4 sqrt2)/3
(f) 20/(7 sqrt5) x (sqrt5)/(sqrt5) = (20 sqrt5)/35 = (4 sqrt5)/7
(g) 50/(3 sqrt10) x (sqrt10)(sqrt10) = (50 sqrt10)/30 = (5sqrt10)/3
(h) 10/(3 sqrt2) x (sqrt2)/(sqrt2) = (10 sqrt2)6 = (5 sqrt2)/3
Please help do # 2 hurry!!! Will give brainliest
Answer:
2a) because they are continuous lines that don't intercept
Step-by-step explanation:
Answer:
2a) They all have the slope of 2x.
2b) R) y = 2x-3
2c) R is the lowest line because the b value (-3) has the least value out of the 3 choices.
On Friday, 0.325 of the students in
Keisha's math class were absent. What
percent of the students were absent?
Look at picture for choices!! Quick!!
Answer:
The answer is A
Step-by-step explanation:
A is equal to the amount of students that were absent.
NEEDS HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
3
Step-by-step explanation:
find the value of 3x^3y-2xy^2 when x=3 and y=-2
Answer:
sorry I don't remember bye I will try to remember
SHOW WORK. Algebra question. 100 POINTS. Easy
Answer:
D. -1 < x < 3Step-by-step explanation:
The given function is negative between the x - intercepts -1 and 3.Your choice is correct.Answer:
D. -1 < x < 3
Step-by-step explanation:
The given function is negative between the x - intercepts -1 and 3.
Your choice is correct.
Choose the system of inequality's that matches the graph
16. Mr. Cho owes the bank $120. He borrows money to buy 12 coffees at
$1.25 each for the all the math teachers. How much does he owe now? *
Answer:
$135
Step-by-step explanation:
120+(12*1.25)
120+15
135
HELP!?!?!?! I can't figure this out
Answer:
So, I believe n/2 may be even and 3n+1 is odd. They succumb to 3n if that helps.
Step-by-step explanation:
I'm not certain on what to do but I hope this helps some what.
Ratio from boys to girls is 2:3. There are 300 fatal kids in the school. How many boys are in the school?
Answer:
180
Step-by-step explanation:
2:3 = 300
2x +3x = 300
5x = 300
x = 300/5
x= 60
2X60= 120 (girls)
3X60= 180 (boys)
if u want to to check whether the ans is correct then try adding your outcomes 120+180 that is = 300 . so the correct ans is 180.
y"+y'-6y = 12e^3t+12e^-2t
Answer
yc(T)=y"+y'-6y=0
Step-by-step explanation:
A stadium has 10,500 seats and 8 VIP boxes. The stadium is divided into 12 equal
sections: 2 premium sections and 10 standard sections. A seat at the premium section
costs $48 per game. A seat at the standard section costs $27 per game.
1. How many seats are there in each section?
2.
If there are 35 seats in each row, how many rows are in each section?
3.
If all the seats in the premium section are sold out for a game, how much will the
stadium get from those ticket sales?
Answer:
omg so many Q's
Step-by-step explanation:
[tex]\sqrt{72x^{7} q^{8} }[/tex]
How much of the circle is shaded? Write your answer as a fraction in simplest form.
Answer:
5/28
Step-by-step explanation:
[tex] \frac{1}{4} + \frac{4}{7} = \frac{7 + 16}{28} = \frac{23}{28} \\ 1 - \frac{23}{28} = \frac{5}{28} [/tex]
Find the inverse function in slope-intercept form (mx+b)
f (x) = x - 16
f^-1 (x) =
Answer:
[tex] \rm y = x + 16 [/tex]
Step-by-step explanation:
A function is given to us and we need to write the inverse of the function in slope intercept form . The given function is ,
[tex]\rm\implies f(x) = x - 16 [/tex]
Let ,
[tex]\rm\implies y = f(x)[/tex]
So that ,
[tex]\rm\implies y = x - 16 [/tex]
Interchange x and y ,
[tex]\rm\implies x = y - 16 [/tex]
Solve for y ,
[tex]\rm\implies y = x + 16[/tex]
Now replace ,
[tex]\rm\implies y = f^{-1}(x) [/tex]
We have ,
[tex]\rm\implies f^{-1}(x) = x+16 [/tex]
And in slope intercept form ,
[tex]\rm\implies \boxed{\pink{\frak {y = x +16}}}[/tex]
Find the difference.
678-595.8
Answer:
82.2
Step-by-step explanation:
The difference is subtracting:
678 - 595.8 = 82.2
Answer:
82.2
Step-by-step explanation:
Check the image below.
I have no idea how to draw the last one … any help plz
Answer:
The intersection of the x and y axis is one point one the line, another one is (1, 1). The range of y<x is below the line I just described.
Step-by-step explanation:
6. Find the missing lengths of the sides.
Answer: D
30 60 90 trinagle rules
a=8
b=a sqaure root of 3 or 8square root of 3
c=2a or 2*8 or c=16
Step-by-step explanation:
Step-by-step explanation:
sin30°=8/c
1/2=8/c
8×2=c
16=c
tan30°=8/b
[tex] \frac{1}{ \sqrt{3} } = \frac{8}{b} \\ 8 \sqrt{3} = b[/tex]
option. d
Okay very important question.
When your doing pemdas , will you get a different answer then just calculating the problem on a calculator.
For example,
11x10-12 divided by 3
Calculated is 106
What’s the answer using pemdas?
Answer: It depends on how you put it in the calculator
Step-by-step explanation:
11x10=110
110-12=98
93/3 = 32.66
fill in the blank (Geometry B)
Step-by-step explanation:
ratio
to
sind = d/e
sinf = f/e
8/3 * (-2 1/2) the product is
Answer:
-28
Step-by-step explanation:
You have to do the parenthesis 1st, then the [tex]\frac{8}{3}[/tex], and multiply the result :D
=
Find the slope of the graph of — 4x + 2y = 10 by
rewriting the equation in slope-intercept form.
Answer:
multiply by -1
Step-by-step explanation:
Slope intercept form : y = mx + b
-4x + 2y = 10 Solve the equation for y
+4x = +4x
2y = 4x + 10
y = 4x/2 + 10/2 Divide all terms by 2
multiply by -1 Simply