Hi there!
[tex]\large\boxed{KE =1.245 J}}[/tex]
The equation of angular kinetic energy is:
[tex]KE = \frac{1}{2}Iw^2[/tex]
Where:
I = moment of inertia (kgm²/s)
ω = angular speed (rad/sec)
A rod rotated about one of its endpoints has a standard moment of inertia of 1/3mR², so:
[tex]KE = \frac{1}{2}(\frac{1}{3}mL^2w^2)[/tex]
[tex]KE = \frac{1}{6}mL^2w^2[/tex]
Plug in the given values:
[tex]KE = \frac{1}{6}(0.63)(0.82^2)(4.2^2) = 1.245 J[/tex]
Ryder is testing the change in motion for an object that weighs 25 kg and an object that weighs 30 kg. He will push each object with the same force. Ryder predicts the object that weighs 25 kg will have a greater change in motion. Is this correct?
Yes, the object with the smaller mass will have a greater change in motion.
No, the change in motion for both objects will be the same.
Yes, the mass is greater, and the object will have a greater change of motion.
No, neither of the objects will have a change in motion.
Ryder is testing the change in motion for an object that weighs 25 kg and an object that weighs 30 kg. Then, the greater change in motion is due to the greater mass of the object, and the object will have a greater change of motion. Thus, the correct option is C.
Motion is the phenomenon in which an object changes its position with respect to the time taken. Motion of an object is mathematically described in terms of the displacement covered by the object, the distance, velocity, acceleration, speed and the frame of reference to an observer and measurement of the change in the position of the body of an object relative to that particular frame with the change in time taken.
The motion of an object is proportional to the mass of the object. The mass is greater in this case, and therefore the objects will have a greater change of motion.
Therefore, the correct option is C.
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What will be the speed of these waves (in terms of V) if we increase M by a factor of 18.0, which stretches the wire to double its original length
The speed of the chord wave allows finding a new speed when the mass is increased and the chord length is:
The velocity is: v = [tex]\frac{v_o}{3}[/tex]
A wave is a periodic movement of the particles that carries energy, but not matter, the speed of the waves is related to the properties of the medium by the relationship.
[tex]v = \sqrt{\frac{T}{\mu } }[/tex]
Where v is the speed of the wave, T the force and μ is the linear density.
Indicates that the applied mass increases by a factor of 18.0 and the length of the head is increased to twice the original.
The linear density of the cable is
[tex]\mu = \frac{m}{l}[/tex]
Where m is the mass of the cable and l is the length.
Let's use the subscript "o" for the initial conditions.
M = 18.0 m₀
l = 2 l₀
We look for the density.
[tex]\mu = \frac{18.0 m_o}{2.0 l_o}[/tex]mu = 18.0 mo / 2 lo
[tex]\mu = 9.0 \mu_o[/tex]
We substitute in the expression for the velocity assuming that the tension is kept constant.
[tex]v= \sqrt{\frac{T}{9.0 \mu} }[/tex]
[tex]v= \frac{v_o}{3}[/tex]
In conclusion, using the speed of the chord wave we can find a new speed when the mass is increased and the chord length is:
The velocity is: v = [tex]\frac{v_o}{3}[/tex]
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Harriet is practicing archery. As she draws back an arrow, the arrow has LaTeX: 34.3 J of elastic potnetial energy, and LaTeX: 0.40 J of gravitational potential energy. How much kinetic energy will the arrow have when it is about to hit the ground?
The kinetic energy of the arrow when it is about to hit the ground is 34.7 J.
The given parameters;
elastic potential energy of the arrow, Ux = 34.3 Jgravitational potential energy, P.E = 0.4 JAccording the principle of conservation of energy, the total potential energy of the arrow will be converted to maximum kinetic energy when the arrow is about to hit the ground.
[tex]K.E = P.E + U_x\\\\K.E = 34.3 \ J \ + \ 0.4 \ J\\\\K.E = 34.7 \ J[/tex]
Thus, the kinetic energy of the arrow when it is about to hit the ground is 34.7 J.
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What are some physical factors we deal with for sleeping?
Answer:
we deal our body movement during sleeping
Entra vapor a una tobera adiabática con un flujo másico de 250 kg/h. Al entrar el vapor
tiene una energía interna específica de 2510 kJ/kg, una presión de 1378 kPa, un
volumen específico de 0.147 m3
/kg y una velocidad de 5 m/s. Las condiciones de salida
son P= 138.7 kPa, volumen específico de 1.099 m3
/kg y energía interna específica de
2263 kJ/kg. Determine la velocidad de salida.
Este problema describe el funcionamiento de una tobera adiabática (sin flujo de calor), la cual tiene una corriente de entrada que difiere de la de salida espacial y energéticamente, pero que conservan el mismo flujo másico de 250 kg/h. De este modo, usamos un balance de energía con el fin the determinar la velocidad a la que sale el fluido, según es requerido en el problema:
[tex]mu_1+mP_1v_1+mgh_1+\frac{1}{2} mv_1^2=mu_2+mP_2v_2+mgh_2+\frac{1}{2} mv_2^2[/tex]
En la que se tiene que la incógnita es la velocidad de salida, [tex]v_2[/tex], y es posible simplificar el flujo másico, [tex]m[/tex], al estar como factor común en ambos lados y despreciar la energía potencial (mgh), ya que no hay diferencia de altura significativa entre la entrada y salida de la tobera.
De este modo, es posible reemplazar los valores dados para obtener la siguiente expresión:
[tex]2510\frac{kJ}{kg} +1378kPa*0.147\frac{m^3}{kg} +\frac{1}{2} (5\frac{m}{s} )^2=2263\frac{kJ}{kg}+138.7kPa*1.099\frac{m^3}{kg} +\frac{1}{2} v_2^2[/tex]
Y así, hallar la velocidad de salida como sigue:
[tex]2725.066\frac{kJ}{kg}=2415.431\frac{kJ}{kg} +\frac{1}{2} v_2^2\\\\v_2=\sqrt{2(2725.066\frac{kJ}{kg}-2415.431\frac{kJ}{kg} )} \\\\v_2=24.9\frac{m}{s}[/tex]
Para revisar:
https://brainly.com/question/23265263https://brainly.com/question/14279777. If the frequency of a system undergoing simple harmonic motion doubles, by what factor does the maximum value of acceleration change
Answer:
a1 = -w^2 A sin w t where w is the angular frequency
a2 = - (2 w)^2 A sin 2 w t where w2 = 2 w1
a2 / a1 = 4 sin 2 w t / sin w t
Since sin 2 w t / sin w t = 2 sin w t will change twice as fast
a2 / a1 = 8 the max acceleration must change 8 tims as fast
when an object is immersed in liquid at rest,why is the net force on the object is the horizontal direction equal to zero?
Based on Newton's third law, the pressure is the same on points that are at the same level but on opposite sides.
Why is the net force in the horizontal direction on an object immersed in a liquid at rest equal to zero?When an object is immersed in a fluid at rest,
the fluid exerts a force on its surface which always normal to the object's surfacethe pressure is the same on points that are at the same level but on opposite sides.Therefore, the net force along horizontal firection is equal to zero.
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Jimmy walks to school by traveling 2.0 miles east and 3.0 miles north from his starting point. What are the magnitude and direction of Jimmy's displacement with respect to his original position?
Answer:
3.6 miles at 56.3 degrees north of east.
Explanation:
If you draw a diagram to calculate Jimmy's displacement, you end up with a triangle.
To solve for the magnitude of Jimmy's displacement with respect to his original position, we need to use the Pythagorean Theorem formula.
Pythagorean Theorem Formula = a^2 + b^2 = c^2
Step by Step to solve for the magnitude of Jimmy's displacement:
1) a^2 + b^2 = c^2
2) 2.0^2 + 3^2 = c^2
3) 4 + 9 = c^2
4) 13 = c^2
5) To find what "c" equals to we need to find the square root of 13.
6) √13 = 3.6 | c = 3.6 miles
To solve for the direction of Jimmy's displacement with respect to his original position, we need to use the following formula:
tan^-1 ∅ (3/2)
tan^-1 ∅ (1.5)
∅ = 56.309° north of east
Therefore, your answer is 3.6 miles at 56.3 degrees north of east.
HOW DO U FEEL WHEN U PLAY OR WATCH BADMINTON?
Answer:
I feel exited and happy I enjoy it with my friend
HELP ASAP!!!!! Choose all the answers that apply. Technology A)influences science
B)helps scientists observe fast phenomena
C)is the same as science
D) influences history
E)helps scientists observe slow phenomena
A 220 g mass is on a frictionless horizontal surface at the end of a spring that has force constant of 7.0
Nm-1. The mass is displaced 5.2 cm from its equilibrium position and then released to undergo simple
harmonic motion.
At what displacement from the equilibrium position is the potential energy equal to the kinetic energy
The concept of conservation of energy and harmonic motion allows to find the result for the power where the kinetic and potential energy are equal is:
x = 0.135 cm
Given parameters
The mass m = 220 g = 0.220 kg The spring cosntnate3 k = 7.0 N / m Initial displacement A = 5.2 cm = 5.2 10-2 mTo find
The position where the kinetic and potential energy are equal
A simple harmonic movement is a movement where the restoring force is proportional to the displacement, the result of this movement is described by the expression.
x = A cos wt + fi
w² = [tex]\frac{k}{m}[/tex]
Where x is the displacement from the equilibrium position, A the initial amplitude of the system, w the angular velocity t the time, fi a phase constant determined by the initial conditions, k the spring constant and m the mass.
The speed is defined by the variation of the position with respect to time.
v = [tex]\frac{dx}{dt}[/tex]
let's evaluate
v = - A w sin (wt + Ф)
Since the body releases for a time t = 0 the velocity is zero, therefore the expression remains.
0 = - A w sin Ф
For the equality to be correct, the sine function must be zero, this implies that the phase constant is zero
x = A cos wt
Let's find the point where the kinetic and potential energy are equal.
K = U
½ m v² = m g x
we substitute
½ A² w² sin² wt = g A cos wt
sin² wt = [tex]\frac{2g}{A}[/tex] cos wt
let's calculate
w = [tex]\sqrt{\frac{7}{0.220} }[/tex]
w = 5.64 rad / s
sin² 5.64t = 2 9.8 / 0.052 cos 5.64t
sin² 5.64t = 376.92 cos 5.64 t
1 - cos² 5.64t = 376.92 cos 5.64t
cos² 5.64t -376.92 cos564t -1 = 0
we make the change of variable
x = cos 5.64t
x²- 376.92 x - 1 = 0
x = 0.026
cos 5.64t = 0.026
Let's find the displacement for this time
x = 5.2 10-2 0.026
x = 1.35 10-3 m
In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:
x = 0.135 cm
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what is the specific latent heat of fusion of water?
Answer:
334
Explanation:
How are the two types of power plants similar how are they different
Answer:
iIn a nuclear plant, the heat source is from the nuclear reaction whereas in a thermal power plant it is from the combustion of coal. The difference is in the inlet steam parameters to the turbine in a nuclear plant. Thermal power plants use steam at superheated conditions. ... The nuclear plant uses a 'wet steam turbine'.
Explanation:
The heat source in a nuclear power plant is the nuclear reaction, whereas the heat source in a thermal power plant is coal combustion. The difference is in the turbine's input steam characteristics.
What is a power plant?Power plant is an industrial structure that generates electricity. The majority of power plants are linked to the electrical grid.
Nuclear power bare a form of thermal power plant. You have a reactor where fission takes place and heat is generated, a heat exchanger that transports this heat to where it is needed.
Thermal power plant equipment converts this heat into electric energy, usually via a steam turbine.
The reactor, heat exchanger, and thermal conversion technology all have different designs and technologies, but the overall architecture is quite similar to other types of thermal power plants.
The heat source in a nuclear power plant is the nuclear reaction, whereas the heat source in a thermal power plant is coal combustion. The difference is in the turbine's input steam characteristics.
Hence, the two types of power plants differ in difference is in the turbine's input steam characteristics.
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A and E are wrong i think please solve this thank you.
Answer:
I think number 3.
Explanation:
Which term describes one kind of movement of Earth?
eclipse
revolution
tilted orbit
lunar cycle
Answer:
revolution
Explanation:
the earth revolves around the sun
Answer: B, revolution
Explanation:
A merry-go-round rotates from rest with an angular acceleration of 1.08 rad/s2. How long does it take to rotate through (a) the first 3.74 rev and (b) the next 3.74 rev
Answer:
Let ω1 be the initial angular speed and ω2 the final angular speed:
α = (ω2- α1) / t
corresponding to a = (v2 - v1) / t
S (distance corresponds to theta)
1 rev = 2 pi and 3.74 rev = 7.48 pi = 23.5 radians
S = 1/2 a t^2 linear or S = 1/2 α t^2 angular acceleration
23.5 = 1/2 * 1.08 t^2 and t = 6.60 sec for first 3.84 rev
b) ω1 = 1.08 * 6.6 = 7.13 rad/sec initial speed for second 3.74
23.5 = 7.13 t + .54 t^2 compare to S = v1 t + 1/2 a t^2
.54 t^2 + 7.13 t - 23.5 = 0
t^2 + 13.2 t - 43.5 = 0
t = 2.7 sec for next 3.74
Check:
7.13 * 2.7 + .54 * 2.7^2 = 23.2 rad = 3.7 rad
Comparing energy resources
Which statement about reversible reactions is correct?(1 point)
They are always at equilibrium.
They are always at equilibrium.
The forward and reverse reactions must happen at the same rate.
The forward and reverse reactions must happen at the same rate.
They can occur in either direction.
They can occur in either direction.
They always involve gases.
They always involve gases.
Answer:
I think the answer would be C
C = They can occur in either direction.
Explanation:
the answer is C. They can occur in either directions
A projectile is launched with a horizontal velocity of 20 m/s and an initial vertical velocity of 20 m/s. What is the projectile's acceleration in the Horizontal direction? Verticle direction?
Answer:
Vertical acceleration 9.8 m/s² downward
Horizontal acceleration 0.0 m/s²
assuming no air resistance.
convert -40⁰ c to Fahrenheit scale
Answer:
104f
Explanation:
(40°C × 9/5) + 32 = 104°F
Calculate the following
Earth's mass: Man's Mass
Earth's Radiusi man Radius
Earth's Density: mon Density
Farth's granty: man granty
There is a uniform magnetic field of magnitude B, pervading all space, perpendicular to the plane of rod and rails. The rod is released from rest, and it is observed that it accelerates to the left. In what direction does the magnetic field point?
The right hand rule to find the direction of the magnetic field for a falling bar is:
The charge is positive the magnetic field is outgoing, horizontally and towards us. The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.
The magnetic force is given by the vector product of the velocity and the magnetic field.
F = q v x B
Where the bolds indicate vectors, F is the force, q the charge on the particle, v the velocity and B the magnetic field.
In the vector product, the vectors are perpendicular, which is why the right-hand rule has been established, see attached:
The thumb points in the direction of speed. Fingers extended in the direction of the magnetic field. The palm is in the direction of the force if the charge is positive and in the opposite direction if the charge is negative.
They indicate that the bar is dropped, therefore its speed is vertical and downwards, it moves to the left therefore this is the direction of the force, we use the right hand rule, the magnetic field must be horizontal, we have two possibilities:
If the charge is positive the magnetic field is outgoing, horizontally and towards us. If the charge of the bar is negative, the magnetic field is incoming, that is, horizontal away from us
In conclusion using the right hand rule we can find the direction of the magnetic field for a falling bar is:
The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.The charge is positive the magnetic field is outgoing, horizontally and towards us.
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Work is required to lift a barbell. How many times more work is required to lift the barbell 2 times as high?
Answer:
2 times more work
Explanation:
Work is a force times distance
W = Fd
The barbell does not change mass so its weight (force) is constant.
That means work is directly proportional to the distance traveled.
twice the distance means twice the work.
Youssef and Sophia are driving in two different cars and not paying attention to their surroundings. Youssef approaches an intersection moving 11 m/s East while Sophia approaches the same intersection moving 13.5 m/s North. Both speeds are measured relative to the ground. When Youssef is 220 m from the intersection, Sophia is 275 m from the intersection. Do the two cars collide when they reach the intersection
Answer:
I think E--
Explanation:
(Fill the blank)
the ________ g____ makes saliva that make your food wet and easy to swallow
Answer:
What make saliva that make your food wet and easy to swallow?
enzyme amylase
Explanation:
The digestive functions of saliva include moistening food, and helping to create a food bolus, so it can be swallowed easily. Saliva contains the enzyme amylase that breaks some starches down into maltose and dextrin. Thus, digestion of food occurs within the mouth, even before food reaches the stomach.
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Yan na baby
A Projectile of mass 0.277 kf is shot from a cannon. The end of the cannon's barrel is at heiht 6.8 m. The initial velocity of the projectile has a horizontal component of 6.1 m/s. The projectile rises to a maximum height above the end of the cannon's barrel and strikes th ground a horizontal distance past the end of the cannon;s barrel. What is the time it takes for the projectile to reach its maximm height? The acceleration of gravity is 9.8 m/s^2.
The time taken by the projectile to reach its maximum height is 0.62 second.
Given parameters:
Horizontal component of initial velocity of the projectile: [tex]u_x[/tex] = 6.1 m/s.
To reach maximum height, the projectile should be throwed in 45 degree. So, vertical component of initial velocity of the projectile: [tex]u_y[/tex] = 6.1 m/s.
Given, The acceleration of gravity is 9.8 m/s².
At maximum height the vertical component of velocity of the projectile becomes zero due to acceleration due to gravity acts downwards.
So, from formula [tex]v_y[/tex] = [tex]u_y[/tex] - gt; we can write:
0 = 6.1 - 9.8t
⇒ t = 6.1/9.8 = 0.62 s.
Hence, the time taken by the projectile to reach its maximum height is 0.62 second.
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8.92 A 45.0 kg woman stands up in a 60.0 kg canoe 5.00 m long. She walks from a point 1.00 m from one end to a point I .00 m from the other end (Fig. P8.92). If you ignore resistance to motion Of the canoe in the water, how far does the canoe move during fis process
The distance that the canoe moves in this process is 1.29 meters.
We first have to find the center of mass
[tex]X = \frac{MsXs+McXc}{Mw+Mc} \\\\[/tex]
Where
Ms = Woman's mass = 45
Mc = Canoe's mass = 60kg
Xs = position from left= 1 cm
Xc = position from left end of canoe's mass = 2.5cm
When we put these values into the equation we have:
[tex]X=\frac{45*1+60*2.5}{45+60} \\\\= 1.857\\[/tex]
The center of gravity lies at the center of this boat. Therefore,
[tex]Xc = \frac{L}{2} \\\\L = 5 m long\\\\\frac{5}{2} =2.5[/tex]
5.00 - 1. 00 = 4 meters
[tex]\frac{45*4+60*2.5}{45+60} = 3.14meters\\\\[/tex]
To get the distance that is moved by this canoe
distance = 3.143-1.857
= 1.286
≈ 1.29 meters
The distance that the canoe moves in this process is 1.29 meters.
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What is First Aid.
I mark u brainliest answer
Answer:
First aid refers to the emergency or immediate care you should provide when a person is injured or ill until full medical treatment is available.
Explanation:
In an oscillating LC circuit, when 81.0% of the total energy is stored in the inductor's magnetic field, (a) what multiple of the maximum charge is on the capacitor and (b) what multiple of the maximum current is in the inductor
Answer:
21
Explanation:
9+10=21
An ambulance is currently traveling at 25 m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is attempting to pass a car which is moving at a constant velocity of 50 m/s. How far must the ambulance travel until it matches the car’s velocity?
Answer:
PLEASE MARK ME BRAINLIEST!!!
Explanation:
Given initial velocity of ambulance
v0=18m/s , acceleration a=5m/s2
To find distance, x=?
First we need to calculate the time for which it acquires 30\,m/s. For that use equation
v=v0+at
30=18+5×t
⇒t=30−185=125seconds
Distance travelled by the ambulance
x=v0t+12at2
x=(18×125)+12×5×(125)2
x=43.2+2.5×5.76=43.2+14.4
x=57.6m
Therefore the ambulance has to travel 57.6 m to match the velocity of car.