Answer:
T = 0.084 Nm
Explanation:
First, we will calculate the angular acceleration:
[tex]\alpha = \frac{\omega_f - \omega_i}{t}[/tex]
where,
α = angular acceleration = ?
ωf = final angular speed = (10 RPM)(2π rad/1 rev)(1 min/60 s) = 1.05 rad/s
ωi = initial angular speed = (2 RPM)(2π rad/1 rev)(1 min/60 s) = 0.21 rad/s
t = time = 5 s
Therefore,
[tex]\alpha = \frac{1.05\rad/s - 0.21\ rad/s}{5\ s}\\\\\alpha = 0.168\ rad/s^2[/tex]
Now, for the torque:
[tex]T = I\alpha[/tex]
where,
T = torque = ?
I = moment of inertia = 0.5 kg.m²
Therefore,
[tex]T = (0.5\ kg.m^2)(0.168\ rad/s^2)\\[/tex]
T = 0.084 Nm
As you change the amplitude, does the wavelength change?
Answer:
Explanation:
Amplitude does not affect wavelength. It also does not affect wave speed. Amplitude is the energy of the wave measured from the rest position to the top of the crest.
Hope this Helped!!!
Answer:
False
Explanation:
Amplitude does not affect wavelength. It also does not affect wave speed.
Amplitude is the energy of the wave measured from the rest position to the top of the crest. A wave with more energy has a higher up crest/ higher amplitude.
4. Coloca las partes en orden para formar una frase.
Se – La – se – transforma – sólo – no – ni – destruye – energía – crea – se
La energía no se crea ni se destruye solo se transforma
Explanation:
espero y te ayude
can someone pls help with the last one
Answer:
ummmmmmmmmmmm ask your teacher or perant for help
Explanation:
so umm ask an adult or teen figure and maybe you will get it write not sure do
Of the 5000 species of mammals, 250 species are carnivorous. What is the ratio of carnivorous to mammals?
Answer: The ratio of carnivorous species to all mammal species is 1:20
Explanation:
250:5000 = 250/250 = 1
250:5000 = 5000/250 = 20
Answer = 1:20
PLEASE NEED AN ANSWER SO I CAN SUBMIT IT!!! THANK YOU IN ADVANCE (will give brainliest)
For the circuit shown with a 12.0 V battery, what are the currents through each resistor and the voltage drops across each resistor?
Answer:
Im only 12 and i need the points so ima try my best.
Explanation:
574.780616 m6 kg3 s-6 K-3 mol-3
2. A block of mass 1.2 kg lies on a frictionless surface. A man slides the block
against a spring, compressing it .15m. When the man lets go of the spring, the
block moves at 5 m/s. What is the spring constant of the spring?
mm
.
Answer:
The spring constant will be "1333.33 N/m".
Explanation:
The given values are:
Mass,
m = 1.2 kg
Displacement compression,
x = 0.15 m
Block's velocity,
[tex]v_i=5 \ m/s[/tex]
As we know,
⇒ [tex]E_i=E_f[/tex]
or,
⇒ [tex]K_i+v_i=K_f+v_f[/tex]
⇒ [tex]\frac{1}{2}mv_i^2+0=0+ \frac{1}{2}Kx^2[/tex]
So,
⇒ [tex]K=\frac{mv_i^2}{x_2}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{1.2\times 5\times 5}{0.15\times 0.15}[/tex]
⇒ [tex]=\frac{30}{0.0225}[/tex]
⇒ [tex]=1333.33 \ N/m[/tex]
The following diagram shows one positively charged metal egg and one negatively charged metal egg.
What occurs as the eggs come closer to each other without touching?
→ a) The magnitude of the electrostatic force between the eggs increases, and they repel each other.
→ b) The magnitude of the electrostatic force between the eggs decreases, and they repel each other.
→c) The magnitude of the electrostatic force between the eggs decreases, and they attract each other.
→d) The magnitude of the electrostatic force between the eggs increases, and they attract each other.
Answer:
I think the answer is C but I'm probably wrong.
According to Coloum's law, when two charged eggs are brought closer, the magnitude of the electrostatic force between the eggs increases, and they attract each other. Hence, option D is correct.
What is Coloumb's law?Coloumb's law equals the magnitude of charges and distance of charges. It gives force of attraction or repulsion between the charged bodies. Like charges repel each other and unlike charges attract each other.
Coloumb's law states that the force of attraction or repulsion between charged bodies is directly proportional to the product of charges and inversely proportional to the square of distance between them.
The force of attraction or repulsion is given by,F = q₁×q₂ / r². q₁,q₂ is the product of charges and r is the distance of seperation of charges. The force decreases with increase of distance as distance and force are inversely proportional to each other.
From the given, two metal egg is given, one is with positive and other is negatively charged metal egg. When two metal eggs are brought closer, they attract each other as the metal eggs are oppositively charged.
When two oppositvely charged metals are brought closer, the distance of seperation of two metal eggs decreased. When distance of seperation decreases, electrostatic force increases.
Hence, as the metal eggs come closer to each other without touching the distance decreases with increase of electrostatic force and they are unlike charges, thus they attract each other. Hence, the correct option is D.
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Diagram in photo, 50 points
The given diagram represents a DC circuit. Each resistor has a value of 100 Ω.
What is the total power used in the circuit?
(A) 0.06 w (B) 0.08 w (C) 0.40 w (D) 0.96 w
4. For the same circuit as the previous question, if resistor R2 was removed from
the circuit, then how much total current will flow through the circuit?
(A) 0.06 A (B) 0.08 A (C) 0.40 A (D) 0.96 A
Answer:
b
Explanation:
A trained eye in the dark for an extended period of time may pick up a light stimulus from a light source, at the lowest radiated power of 1,2*10* (- 17) W. Determine how many photons of light with a wavelength of 500nm fall on the retina of the eye every second
Answer:
#_photons = 30 photons / s
Explanation:
Let's start by finding the energy of a photon of light, let's use the Planck relation
E = h f
the speed of light is related to wavelength and frequency
c = λ f
we substitute
E = h c /λ
E₀ = 6.63 10⁻³⁴ 3 10⁸/500 10⁻⁹
E₀ = 3.978 10⁻¹⁹ J
now let's use a direct proportion rule. If the energy of a photon is Eo, how many fornes has an energy E = 1.2 10⁻¹⁷ J in a second
#_photons = 1 photon (E / Eo)
#_photons = 1 1.2 10⁻¹⁷ /3.978 10⁻¹⁹
#_photons = 3.0 10¹
#_photons = 30 photons / s
How do you calculate the total resistance in a series circuit with more than one resistor
Answer:
You add up all the individual resistances of the resistors in the series circuit to get the total resistance of the circuit
Explanation:
A series circuit is a circuit that has most of its components connected end-to-end
following what was stated above, in a series circuit, the resistors are connected end to end. This means that the current that flows out from one of the resistors flows into the next one. As a result of this, the current through all the resistors is the same.
To get the total equivalent resistance in a series circuit, you add up all the individual resistances of the resistors in the series circuit. This should give you the total resistance in the circuit.
i.e
Total resistance = R1 + R2 + R3 ....
The force of gravity between you and Earth is greater than the force of gravity between you and a car because Earth has more __________ than the car.
Answer:Earth has more mass than the car.
in the question
Unbalanced forces acting on an object produce a change in the object's __________
An unbalanced force acting on an object results in the object's motion changing. The object may change its speed (speed up or slow down), or it may change its direction. Friction is a force that resists the motion or the tendency toward motion between two objects in contact with each other.
motion
Answer:
motion. FILLER FILLER FILLER
A chart showing the type of reproduction that occurs in several organisms is shown below. Organism Type of Reproduction Bacteria Asexual Salmon Sexual Oak Trees Both Bears Sexual Asexual Flatworms Based on the information on the chart, which organisms are able to produce genetically diverse offspring? A Bacteria, oak trees, and flatworms B Salmon, oak trees, and bears C Salmon and bears only D Bacteria and flatworms only
Answer:
C
Explanation:
Answer:
B
Explanation:
Because it’s asking about sexual
Activities that can help reduce the stress level in a family include A. exercising B. reading C. going for a walk D. all of the above Please select the best answer from the choices provided. A B. ОС
Answer:
D. all the above
Explanation:
Took the quiz.
Answer: D) all the above
Explanation: :)
What do diffraction and refraction have in common? They both involve interference. They both involve wave interactions. They both involve reflection. They both involve construction.
Answer:
They both involve wave interactions.
Explanation:
Diffraction is defined as the bending of waves around obstacles. Refraction can be defined as the bending of the light when it transfers from one substance to another. The main similarity between the diffraction and refraction is that both involves the interaction of the waves with the substance and also causes the waves to bend and change their direction. Hence, they both involve wave interaction is the correct option.
What diffraction and refraction have in common is that they both involve wave interactions. This is further explained below.
What are diffraction and refraction?When waves travel from one medium to another and refract, This causes them to change direction. while Diffraction is simply defined as the bending of waves around barriers.
In conclusion, diffraction and refraction are properties of waves.
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1. Which object is farthest from the origin at t=2sec
A.a B. b
C. they are the same location at t=2sec
D. they are the same distance from the origin , but in opposite direction
2. Which object moves with constant non-zero acceleration
A. A C. both a and b
B. B. D. neither A and B
3. Which object is in its initial position at t=2sec?
A. A C. both a and b
B. B D. neither A and B
Help me ppppppppp
Answer:
that one i know only pe not that sorry again
1. Jen is stepping out of a boat on to a dock. She has one foot on the dock and one foot in
the boat. No one holds on to the boat. It begins to move away from the dock. Jen's legs
split wider and wider. Which law applies?
you tend to push off with the foot still on the boat.
Newtons 3rd law of motion hold that every action has an equal and opposite reaction.
So, the amount of force you use on your back foot to push yourself onto the dock, has an equal end opposite amount of force going the other way from your sole of your foot, which pushes the boat the other way.
The same principle applies when you fire a cannon - in the pirate films, you see the body of the cannon forced back as it is fired.
Take it one step further, Henry VIII flagship, “Mary Rose fired all its cannons together one day in a broad side, the opposite force rolled the ship over and sank it.
A stereo speaker is made of a flexible cone-shaped material that vibrates, creating a sound wave. A sound wave formed be a speaker travels through air to your ear as a series of compressions and rarefactions of air molecules.
Which statement classifies the sound wave?
transverse wave in which the particles of the wave move in a direction parallel to the wave motion
longitudinal wave in which the particles of the wave move in a direction parallel to the wave motion
transverse wave in which the particles of the wave move in a direction perpendicular to the wave motion
O longitudinal wave in which the particles of the wave move in a direction perpendicular to the wave motion
Answer: longitudinal wave in which the particles of the wave move in a direction parallel to the wave motion
The sound wave is a longitudinal wave in which the particles of the wave move in a direction parallel to the wave motion.
What is a wave of sound?A sound wave can be described as the pattern of distribution caused by the movement of energy that is traveling through a medium, such as air, water, or any liquid or solid matter, etc, as it is traveling away from the source of the sound. There are two types of sound waves:
Longitudinal wave: When the particles of the medium move in a direction parallel to the direction that the wave moves then the wave is known as the longitudinal wave.
Transverse Wave: When the particles of the medium move in a direction perpendicular to the direction that the wave moves then the wave are known as the transverse wave.
As it is given that the sound wave formed by the speaker travels through the air to your ear as a series of compressions and rarefactions of air molecules, therefore, the particles of the medium move in a direction parallel to the direction that the wave.
Hence, the sound wave is a longitudinal wave in which the particles of the wave move in a direction parallel to the wave motion.
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please explain application of Stephan boltzmann law
Answer:
This law is used to find the luminosity (the rate of energy released), for an object given its surface temperature. This law assumes the body acts as a black-body radiator (an object that emits energy from the entire EM spectrum)
For a given object with a constant surface area, the Stefan-Boltzmann law says that luminosity is proportional to the temperature raised to the fourth power.
Explanation:
Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 0,92 = -5.00 x 10-6 C,
and q3 = -5.00 x 10-6 C. Particles qı and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.500 m. What is net force on q3?
Answer:
1.12
Explanation:
it is correct on Acellus
The total force on charge q(3) is 1125 x [tex]10^{-3}[/tex] Newton
We have three charges in a straight line.
We have to find the force on charge q3 due to charge q1 and q2.
State Coulomb's law.The force between two point charges is directly proportional to the product of the magnitude of two point charges and inversely proportional to the square of the distance between them. Mathematically-
[tex]F = \frac{1}{4\pi\epsilon_{o}}{\frac{qQ}{r^{2} } } }[/tex]
We have -
[tex]q_{1} =q_{2} =q_{3} = -5 \times 10^{-6} C[/tex]
The distance between -
[tex]q_{1}\;and\;q_{2} = q_{2} \;and\;q{3}[/tex] = 0.5 m
Now, Force on charge q(3) due to charge q(1) -
F(1 → 3) = [tex]\frac{1}{4\pi\epsilon_{o}}{\frac{5\times 10^{-6} \times 5\times 10^{-6} }{1^{2} } } } = 9\times 10^{9} \times 25 \times 10^{-12} = 225\times 10^{-3}[/tex] N (repelling force)
Force on charge q(3) due to charge q(2) can be calculate similarly as -
F(2 → 3) = 900 x [tex]10^{-3}[/tex] N(repelling force)
Now, both the forces are in same direction, so we can add them algebraically -
[tex]F_{net}[/tex] = F(1 → 3) + F(2 → 3) = 1125 x [tex]10^{-3}[/tex] N
Hence, the total force on charge q(3) is 1125 x [tex]10^{-3}[/tex] Newton
Hence, the wavelength of light in nano meters is 0.0177 x nm.
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A 1,000 kg ball traveling at 5 m/s would have kinetic energy. A 10 kg ball traveling at 5 m/s would have kinetic energy. A 100 kg person falling at 5 m/s would have kinetic energy.
Question : 1
mass (m) = 1000 kgvelocity (v) = 5 m/s=》
[tex]k.e = \dfrac{1}{2}mv {}^{2} [/tex]
=》
[tex]k.e = \dfrac{1}{2} \times 1000 \times (5) {}^{2} [/tex]
=》
[tex]k.e = 500 \times 25[/tex]
=》
[tex]k.e = 12500 \: joules[/tex]
kinetic energy = 12500 joules
Question : 2
mass (m) = 10 kgvelocity (v) = 5 m/s=》
[tex]k.e = \dfrac{1}{2} mv {}^{2} [/tex]
=》
[tex]k.e = \dfrac{1}{2} \times 10 \times ({5})^{2} [/tex]
=》
[tex]k.e = 5 \times 25[/tex]
=》
[tex]k.e = 125 \: joules[/tex]
kinetic energy = 125 joules
Question : 3
mass = 100 kgvelocity = 5 m/s=》
[tex]k.e = \dfrac{1}{2} mv {}^{2} [/tex]
=》
[tex]k.e = \frac{1}{2} \times 100 \times (5) {}^{2} [/tex]
=》
[tex]k.e = 50 \times 25[/tex]
=》
[tex]k.e = 1250 \: joules[/tex]
kinetic energy = 1250 joules
En una feria, se gana una jirafa de peluche lanzando una moneda a un platito, el cual está sobre una repisa más arriba del punto en que la moneda sale de la mano y a una distancia horizontal de 2.1 m desde ese punto (figura 3.41). Si lanza la moneda con velocidad de 6.4 m>s, a un ángulo de 60° sobre la horizontal, la moneda caerá en el platito. Ignore la resistencia del aire. A) ¿A qué altura está la repisa sobre el punto donde se lanza la moneda? B) ¿Qué componente vertical tiene la velocidad de la moneda justo antes de caer en el platito?
Answer:
A) La altura de la repisa sobre el punto donde se lanza la moneda es de aproximadamente 0,42 m
B) La velocidad de la moneda justo antes de que golpee el platillo es de aproximadamente 0,895 m/s hacia abajo
Explanation:
A) Los parámetros dados son;
La distancia horizontal del plato desde donde se lanza la moneda = 2,1 m
La velocidad con la que se lanza la moneda, u = 6,4 m / s
El ángulo al que se lanza la moneda, θ = 60 °
La componente horizontal de la velocidad, vₓ = 6.4 m / s × cos (60°) = 3.2 m/s
El tiempo que tarda la moneda en recorrer una distancia horizontal de 2,1 m, 't' se calcula de la siguiente manera;
t = 2,1 m/(3,2 m/s) = 0,65625 segundos
Por tanto, la altura de la moneda a 0,65625 segundos se da de la siguiente manera;
y = u × sin (θ) × t - (1/2) × g × t²
En t = 0,65625 segundos, obtenemos;
y = 6,4 × sin (60°) × 0,65625 - (1/2) × 9,81 × (0,65625) = 0,41840044589
La altura de la repisa sobre el punto donde se lanza la moneda, y ≈ 0.42 m
B) La velocidad vertical de la moneda justo antes de que golpee el platillo, [tex]v_y[/tex], se da como sigue;
[tex]v_y[/tex] = u × sin(θ) - g·t
∴ [tex]v_y[/tex] = 6.4 × sin(60°) - 9.81 × 0.65625 ≈ -0.895
La velocidad de la moneda justo antes de golpear el platillo, [tex]v_y[/tex] ≈ 0.895 m/s (hacia abajo)
A harmonic oscillator is described by the function
x(t) = (0.290 m) cos(0.390t).
Find the oscillator's maximum velocity and maximum acceleration. Find the oscillator's position, velocity, and acceleration when t = 2.50 s.
(a)
oscillator's maximum velocity (in m/s)
m/s
(b)
oscillator's maximum acceleration (m/s2)
m/s2
(c)
oscillator's position (in m) when t = 2.50 s
m
(d)
oscillator's velocity (in m/s) when t = 2.50 s
m/s
(e)
oscillator's acceleration (in m/s2) when t = 2.50 s
m/s2
8. Jay drives his truck to football practice. He gives Jen a ride. The truck stalls in the parking
lot. He gets out and pushes it, but it won't budge. He tells Jen to get out and help him
push. They manage to push the truck into a parking space. (Thank goodness he is a
tackle!) Which law applies?
Answer:
Action Reaction
Explanation:
Linear vectore F
A drop of oil of volume 10 ^-10 m3 spreads out on water to make a circular film radius 10^-1m what is the thickness of the film
Answer:
The thickness of the film is = 3.183e-9m
Explanation:
It will help us if we understand that the shape of the circular film can be approximated to be a cylinder. The height of this cylinder, or its thickness, in this case, will be very small.
Since we can approximate the shape of the drop of oil to be a cylinder, after it has spread out on the surface of the water, we can use the cylindrical geometric formulas to find out how thick the film is.
The volume of a cylinder = [tex]\pi r^2 h[/tex]
our radius is given as [tex]10^{-1}m = 0.1m[/tex]
the volume is [tex]10 ^{-10} m^3=1e-10m^3[/tex]
Remember that our task is to find the height of the cylinder. We can do this by making the height the subject of the formula.
[tex]h = \frac{Volume}{\pi r^2} = \\\\\frac{1e-10}{\pi \times 0.1^2} = 3.183e-9m[/tex]
Therefore, the thickness of the film is = 3.183e-9m
How does refraction allow thin convex lenses to work?
Answer:
https://www.khanacademy.org/science/physics/geometric-optics/lenses/v/convex-lenses
Explanation:
Here is a link to a video to tell you about this.
A man drags his suitcase for a 2.00m with a force of 10.0n. Determine the work done on the suitcase if, it is inclined at an angle of 30°
Answer:
17.32 J
Explanation:
Work = Fcos(theta)x
Work = (10cos30°)(2)
Work = 17.32 J
During a phase change, such as when an ice cube melts, its temperature —
Answer:
Will start to decrease until it reaches the room temperature where it transforms from solid to liquid as the bonds are weakening and thus water has a low melting point also known as h20
Explanation:
A 74.2 kg teenager slides down a frictionless slide that has an angle of inclination of 38˚. What is the magnitude of the acceleration of the teenager down the slide?
Answer:
Explanation:
This is one-dimensional motion on an incline which makes it so much more funner :/
The equation for this is
w*sinθ - f = ma which is just a fancy version of Newton's second law that says that the sum of the forces acting on an object are equal to that object's mass times its acceleration.
w is the weight of the teen which is also the normal force, [tex]F_n[/tex]. Therefore,
[tex]w=F_n=mg[/tex] where m is mass and g is gravity:
[tex]w=F_n=(74.2)(9.8)[/tex] and we need 2 sig figs for this since there are 2 in 9.8:
w = 730N
Since there is no friction in this problem, the value for f, frictional force, is 0, making our job a bit shorter. Filling in the main equation:
730sin38 - 0 = 74.2a
Since the left side is subtraction and we will eventually have to divide, and the rules for subtraction/addition are different from those for multiplication/division, we will have to subtract first, get the correct number of sig figs for that difference, and then divide, following the rules for division.
730sin38 will have 2 sig figs which is 450. Now
450 - 0 = 74.2a and
450 = 74.2a and divide to 2 sig figs:
a = 6.1 m/s/s
how freezing could be used to remove sugar from a mixture of sugar and water.