A new apartment complex with 90 one bedroom apartment units and 100 two bedrooms apartment units was built near a lake. Rental prices that will provide full occupancy are estimated as $1200 for one bedroom unit and $1800 for two bedrooms unit. A market survey suggests that for every $20 increase in price of one bedroom unit one less customer will sign a lease and for every $60 increase in price of two bedrooms unit two less customers will sign a lease. What rental price should the manager charge to maximize revenue?

Rental Price for One bedroom ____
Rental Price for Two bedroom ____

Answer:

(4, -3)

(-28,-11)

Step-by-step explanation:

y = [tex]\frac{1}{4}[/tex] x - 4  Substitute 4 for x

y = [tex]\frac{1}{4}[/tex][tex](\frac{4}{1})[/tex] - 4  another name of 4 is [tex]\frac{4}{1}[/tex]

y = 1 - 4

y = -3

(4,-3)

y = [tex]\frac{1}{4}[/tex] x - 4  Substitute -11 for y

-11 = [tex]\frac{1}{4}[/tex] x - 4  Add 4 to both sides

-11 + 4 = [tex]\frac{1}{4}[/tex]x - 4 + 4

-7 = [tex]\frac{1}{4}[/tex]x  Multiply both sides by 4

-7(4) = [tex]\frac{1}{4}[/tex][tex](\frac{4}{1})[/tex]x

-28 = x

(-28,-11)

Helping in the name of Jesus.

I am pretty sure the answer is b. emplyee 2# but im not 100% sure since your graph is really weird and hard to uunderstand

Step-by-step explanation:

Charlie's monthly pay, P, can be represented as a linear function of the number of items sold, q. The monthly salary of $2,000 represents the y-intercept of the line, and the commission of $100 per item sold represents the slope of the line.

Thus, the model for Charlie's monthly pay, P(q), can be expressed as:

P(q) = 100q + 2000

where q is the number of items sold in a month, and P(q) is Charlie's monthly pay in dollars.

Answer: it will take approximately 14.62 years for the initial investment to double at an interest rate of 4.75% per year, compounded continuously.

Step-by-step explanation: Given an investment of $2000 at a continuously compounded interest rate of 4.75%, the balance in the account can be calculated using the following mathematical expression after t years:

The aforementioned equation, A = P * e^(rt), denotes the relationship between the accrued amount (A) and the principal amount (P), compounded continuously at a fixed annual rate of interest (r) over a specific time period (t), as governed by the mathematical constant "e."

In the context of financial calculations, the symbol 'P' denotes the initial capital investment. The interest rate, represented by the variable 'r', is expressed in the form of a decimal. Additionally, 'e' is the mathematical constant, roughly equivalent to 2.71828. Finally, 't' refers to the duration of the investment, measured in years.

In order to determine the duration of time required for the investment to achieve a twofold increase, it is necessary to solve the corresponding equation:

The equation expressed as 2P = P * e^(rt) can be restated more formally as follows. Given a principal investment amount represented by P and a rate of return indicated by r, compounded over time t, the equation can be expressed as the product of P and the exponential function of e^(rt), yielding twice the initial investment amount.

The variable 2P represents the monetary value acquired through doubling the initial investment.

Upon division of both sides by P, the resulting expression is as follows:

The equation 2 equals the exponential function of the base e raised to the power of the product of r and t.

By applying the natural logarithm function to both expressions, the resultant outcome is:

The natural logarithm of 2 can be represented as rt, where r denotes the logarithmic base and t denotes the logarithm of the argument, in accordance with the conventions of academic mathematical writing.

Upon resolving for the variable t, an outcome is yielded:

The mathematical expression t = ln(2) / r can be written in a formal academic style as follows: The equation determines the relationship between time t and the rate of decay r, where t is equal to the natural logarithm of 2 divided by r.

Upon substitution of the provided values, the resultant output is:

The calculated value of the variable t, representing the length of time in years, is approximately equal to 14.62 years, obtained through the algebraic manipulation of the natural logarithmic function of 2 divided by the constant value of 0.0475.

Answer:

The first and second one

Step-by-step explanation:

Since they are one-to-one functions, the first table and the first graph (under the table) are the answers.

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Answer: The first one and second one.

Step-by-step explanation:

It's a bit cut-off but for the very first function, each x-value has a corresponding y-value so it is a function. For the second one (the graph), if we do the vertical line test, it will pass it (vertical line touches only one point of the function). The third one (the loop graph) , however, will not pass the vertical line test as there's a point on the graph where if we were to draw a vertical line, it would be touch 2 or 3 points of the function.

Answer:

x = -1

Step-by-step explanation:

You will plug in 8 for y then solve for x:

[tex]\frac{12}{3} = (x-1)^2\\4 = (x-1)^2\\\frac{+}{-}2 = x-1 \\ x= +3, and -1[/tex]

Then the answer is -1 because the graph shows the point in the 2nd quadrant meaning x is negative

the more extreme height was the case for the shortest living man (13.38 standard deviation units below the population's mean) compare with the tallest man that was 9.21 standard deviation units above the population's mean.

To answer this question, we need to use standardized values, and we can obtain them using the formula:

z = (x - μ)σ  ..  [1]  

Where,

x is the raw score we want to standardize.

μ is the population's mean.

σ is the population standard deviation.

A z-score "tells us" the distance from  in standard deviation units, and a positive value indicates that the raw score is above the mean and a negative that the raw score is below the mean.

In a normal distribution, the more extreme values are those with bigger z-scores, above and below the mean. We also need to remember that the normal distribution is symmetrical.

Heights of men at that time had:

μ = 171.59 cm

σ  = 5.47 cm.

Let us see the z-score for each case:

Case 1: The tallest living man at that time

The tallest man had a height of 222 cm.

Using [1], we have (without using units):

z = (x - μ)σ

z = (222 - 171.59)/5.47

z = 50.41 / 5.47

z = 9.21

That is, the tallest living man was 9.21 standard deviation units above the population's mean.

Case 2: The shortest living man at that time

The shortest man had a height of 98.4 cm.

Following the same procedure as before, we have:

z = (x - μ)σ

z = (98.4 - 171.59)/5.47

z = - 13.38

That is, the shortest living man was 13.38 standard deviation units below the population's mean (because of the negative value for the standardized value.)

The normal distribution is symmetrical (as we previously told). The height for the shortest man was at the other extreme of the normal distribution in  standard deviation units more than the tallest man.

Then, the more extreme height was the case for the shortest living man (13.38 standard deviation units below the population's mean) compare with the tallest man that was 9.21 standard deviation units above the population's mean.

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Answer:

x = -16/7 and y = 38/7.

Step-by-step explanation:

To solve the system of equations:

x + 3y - 22 = 0 --- equation (1)

2x - y + 42 = 0 --- equation (2)

x - 11y + 142 = 0 --- equation (3)

We will use the method of substitution to find the values of x and y that satisfy all three equations.

From equation (1), we can express x in terms of y:

x = 22 - 3y --- equation (4)

We can substitute equation (4) into equation (2) and simplify:

2(22 - 3y) - y + 42 = 0

44 - 6y - y + 42 = 0

-7y = -38

y = 38/7

Now, we can substitute the value of y into equation (4) to find x:

x = 22 - 3(38/7)

x = -16/7

Therefore, the solution to the system of equations is:

x = -16/7 and y = 38/7.

Result:

The weight of the pumpkin in November = 71 ounces more than in October.

How to compare the weights?

To compare the weights, we need to convert both weights to the same unit of measurement, either pounds or ounces.

Let's convert the first weight, which is 3 pounds and 11 ounces, to ounces:

3 pounds = 3 x 16 = 48 ounces

11 ounces = 11

So the first weight is 48 + 11 = 59 ounces.

Now, let's convert the second weight, which is 8 pounds and 2 ounces, to ounces:

8 pounds = 8 x 16 = 128 ounces

2 ounces = 2

So the second weight is 128 + 2 = 130 ounces.

To find how many more ounces the pumpkin weighed in November, we subtract the October weight from the November weight:

130 - 59 = 71

Therefore, the pumpkin weighed 71 more ounces in November than it did in October.

The mean is 4746
The median wage is #4618

The wages for the five local government trainees are

#4,166, #4,618, #3,742, #5,838 and #5,366

= 4166+ 4618+ 3742+5838+5366/5

= 23,730/5

Mean = 4,746

The median wage is

Arrange the wages orderly

3,742, 4166, 4618, 5366, 5838

The median wage is #4618

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Answer: the slope is 6

Step-by-step explanation: the line y=6x-3

The solution to the system of equations is x = 6 and  y = -5, which is the same as we obtained using the elimination method.

A system of equations is a collection of one or more equations that are considered together. The system can consist of linear or nonlinear equations and may have one or more variables. The solution to a system of equations is the set of values that satisfy all of the equations in the system simultaneously. The given system of equations is:

2x + y = 7 ---(1)

x + y = 1 ---(2)

To solve this system, we can use the method of elimination or substitution.

Method 1: Elimination

In this method, we eliminate one of the variables by adding or subtracting the two equations. To do this, we need to multiply one or both equations by a suitable constant so that the coefficients of one of the variables become equal in magnitude but opposite in sign.

Let's multiply equation (2) by -2, so that the coefficient of y in both equations becomes equal in magnitude but opposite in sign:

-2(x + y) = -2(1) --

Multiplying equation

(2) by -2-2x - 2y = -2

Now we can add the two equations (1) and (-2x - 2y = -2) to eliminate y:

2x + y = 7(-2x - 2y = -2)0x - y = 5

We now have a new equation in which y is isolated.

To solve for y, we can multiply both sides by -1:

-1(-y) = -1(5)y = -5

Now that we know y = -5, we can substitute this value into equation (2) to find x:x + y = 1x + (-5) = 1x = 6

Therefore, the solution to the system of equations is (x,y) = (6,-5).

Method 2: Substitution

In this method, we solve one of the equations for one variable in terms of the other variable and substitute this expression into the other equation to get an equation with only one variable.

From equation (2), we can solve for y in terms of x:y = 1 - x

We can then substitute this expression for y into equation (1):2x + y = 72x + (1 - x) = 7 --Substituting y = 1 - xx + 1 = 7x = 6

Now that we know x = 6, we can substitute this value into equation (2) to find y:x + y = 16 + y = 1 --Substituting x = 6y = -5

Therefore, the solution to the system of equations is (x,y) = (6,-5), which is the same as we obtained using the elimination method.

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2/7

Assuming I know what standard deviation is, it is there is a 3 ounce "range" that the machine can give, based on that 24 oz mean. So there can be 21,22,23,24,25,26, and 27. Out of those 7, 2 are the numbers we are looking for, so it is 2/7.

The value of the square root 3 6/25 is 1⅘

The square root of a number is a value that can be multiplied by itself to give the original number. For example the square root of 225 is 15.

Another example is the square of 16, which can be gotten by finding the prime product of 16

16 = 2×2×2×2. we can group the 2s into two i.e (2×2) × (2×2) . We can now take one out of 2 .

= 2 × 2 = 4. Therefore the the square root of 16 is 4.

Therefore the square root of 3 6/25 can be found by converting the fraction into improper fraction.

= 81/25

therefore the √81/25 = 9/5 = 1⅘.

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Based ont he the function y = - 2x + 5 + 2x - 5 is given ,

if  x < -2.5, y = 0

i f  x > 2.5, y = 0

if -2.5 ≤  x  ≤ 2.5 = 0

Without the absolute value symbols

y = -2x + 5 + 2x - 5

Where x < - 2.5

y = -2 (-2.5) + 5 + 2 (-2.5 ) - 5

y =  5 + 5 + (-5)-5

y = 0

Where x > 2.5

y = -2 (2.5) + 5 + 2(2.5) - 5

y = 0

Where -2.5 ≤ x ≤ 2.5

y = -2x + 5 + 2x -5

grouping like terms we have

-2x + 2x +5 -5
y = 0

thus, Where -2.5 ≤ x ≤ 2.5

y = 0

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For a standard normal distribution, the approximate value of

P(-0.41) ≤ z ≤ (0.73) is 43%.

Option A is the correct answer.

We have,

To find the approximate value of P(-0.41) ≤ z ≤ (0.73) for a standard normal distribution, we need to use the standard normal table.

Looking at the table,

The value of P(Z ≤ 0.73) = 0.7673.

The value of P(Z ≤ -0.41) = 0.3409.

To find the value of P(-0.41) ≤ Z ≤ (0.73),

We need to subtract P(Z ≤ -0.41) from P(Z ≤ 0.73):

P(-0.41) ≤ Z ≤ (0.73) = P(Z ≤ 0.73) - P(Z ≤ -0.41)

P(-0.41) ≤ Z ≤ (0.73) = 0.7673 - 0.3409

P(-0.41) ≤ Z ≤ (0.73) = 0.4264

Rounding this value to the nearest whole percent, we get 43%.

Therefore,

For a standard normal distribution, the approximate value of

P(-0.41) ≤ z ≤ (0.73) is 43%.

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With a p-value of 0.022, there is convincing evidence of a difference in the proportion of men and women who intended to vote for Trump in the city. Type I error could have been made. No, there is not convincing evidence to support the claim that a greater proportion of women than men intended to vote for Trump. Increasing the significance level would increase power, but would also increase the likelihood of making a Type I error.

We can use a two-sample z-test to test for the difference in proportions between men and women who intended to vote for Trump.

Let p1 be the proportion of men who intended to vote for Trump and p2 be the proportion of women who intended to vote for Trump. Then the null and alternative hypotheses are

H0: p₁ = p₂

Ha: p₁ ≠ p₂

We can calculate the pooled sample proportion

p = (x₁ +  x₂) / (n₁ +  n₂)

= (120 + 132) / (250 + 240)

= 0.508

where x₁ = 120, x₂ = 132, n₁ = 250, and n₂ = 240.

We can calculate the test statistic

z = (p₁ - p₂) / √(p * (1 - p) * (1/n₁ + 1/n₂))

= (0.48 - 0.55) / √(0.508 * 0.492 * (1/250 + 1/240))

= -2.29

Using a standard normal distribution table, the p-value for a two-tailed test with a test statistic of -2.29 is 0.022. Since the p-value is less than 0.05, we reject the null hypothesis and conclude that there is convincing evidence that there is a difference in the proportion of all men and the proportion of all women in this city who intended to vote for Trump at the 0.05 significance level.

The mistake we could have made is a type I error, which is rejecting the null hypothesis when it is actually true. In this case, it would mean concluding that there is a difference in proportions between men and women who intended to vote for Trump when there is actually no difference.

The confidence interval for the difference in proportions is (-0.158, 0.018), which includes 0. Since 0 is in the interval, we cannot reject the null hypothesis that there is no difference in proportions between men and women who intended to vote for Trump.

Therefore, based on the interval, there is not convincing evidence to support the claim that a greater proportion of women than men intended to vote for Trump.

One way to increase the power of the test is to decrease the significance level (i.e., increase the alpha level). This would allow us to reject the null hypothesis more easily and increase the chance of detecting a true difference in proportions.

However, the drawback of making this change is that it increases the chance of making a type I error, which means rejecting the null hypothesis when it is actually true.

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a) The probability of picking a sweet tea on the first draw is 8/12. Since we did not replace the first tea, the probability of picking another sweet tea on the second draw is 7/11. Similarly, the probability of picking a sweet tea on the third draw is 6/10. Therefore, the probability of picking 3 sweet teas in a row is:

(8/12) * (7/11) * (6/10) = 0.2545 or 127/500

b) There are 3 ways to pick exactly one sweet tea: S U U, U S U, U U S, where S represents a sweet tea and U represents an unsweetened tea. The probability of picking a sweet tea on the first draw is 8/12, and the probability of picking an unsweetened tea is 4/12. Therefore, the probability of picking exactly one sweet tea is:

(8/12) * (4/11) * (3/10) + (4/12) * (8/11) * (3/10) + (4/12) * (3/11) * (8/10) = 0.4364 or 48/110

An elephant weighs 110 pounds more on Day 60 than it does on Day 5

Here, function w = 2d +200 represents the weight w of an elephant on a given day during his first year.

From above function , the weight of an elephant on Day 60 would be,

w₆₀ = 2(60) + 200

w₆₀ = 120 + 200

w₆₀ = 320 pounds

and the weight of an elephant on Day 5 would be,

w₅ = 2(5) + 200

w₅ = 10 + 200

w₅ = 210

The difference between these weights is:

w = w₆₀ - w₅

w = 320 - 210

w = 110 pounds

Therefore, an elephant weighs 110 pounds more on Day 60 than on Day 5

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The volume of the cube will be 5.832 cubic inches.

The volume of a cube is given by the formula V = s³, where s is the length of one of its edges.

In this case, the length of one edge is given as 1.8 inches.

So, substituting s = 1.8 inches in the formula, we get:

V = s³ = 1.8³ = 5.832 cubic inches

Therefore, the volume of the cube is 5.832 cubic inches.

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Note that where the above events are described, the probablity of A occurring given that B occurrs is 6/25.

We can use Bayes' theorem to find the conditional probability

P  (A| B) = P(A and B ) / P( B)

From the problem statement, we know that P(A) = 1/3,

P(B) = 5/6, and

P (A and B) = 1/5.

Substituting to get .....

P(A | B) =  (1/5) / (5/6)

= 1/5 x (6 /5)

= 6/25

Hence, we are corect to state that the probability of A occurring given that B occurs is 6/25.

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Step-by-step explanation:

supposedly

A=3

B= -2

C=2

(3-(-2)×2=(3×2)-(-2×2)

5×2=6-(-4)

10=6+4

10=10

The number of cubes needed with an edge length of 1/3  inches is needed to build a cube with an edge length of 1 inch is 27.

We have,

the edge length of smaller cube, a = 1/3 inches

the edge length of the cube to be built, S = 1/3 inches

Now, Volume of cube = a³

= (1/3)³

= 1/27 in³

Volume of the cube to be build =   S³

                                                   =   1³

                                                   =   1 in.³

Thus, Cubes of smaller length are needed for the larger cube

= 1/ (1/27)

= 27

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Answer:

  y = 4x² -8x +10

Step-by-step explanation:

You want to write the equation y = 4(x -1)² +6 in standard form.

The distributive property is used to eliminate parentheses.

  y = 4(x -1)² +6 . . . . . . given equation

  y = 4(x -1)(x -1) +6 . . . . . the meaning of the exponent of 2

  y = 4((x(x -1) -1(x -1)) +6 . . . . . distributive property applied once

  y = 4(x² -x -x +1) +6 . . . . . . . . . . distributive property applied again

  y = 4(x² -2x +1) +6 . . . . . . collect terms inside parentheses

  y = 4x² -8x +4 +6 . . . . . . . distributive property applied

  y = 4x² -8x +10 . . . . . . . . . collect terms

The angles of the triangle are:

A =  95.7°, B = 33.6°, C = 50.7°.

What are the angles of the triangle?

The area created between two of a triangle's side lengths is known as the angle. Both internal and external angles are present in a triangle. In a triangle, there are three interior angles. When the sides of a triangle are stretched to infinity, exterior angles are created.

Here, we have

Given: a = 9, b= 5, c = 7

We have to find all angles in degrees.

Using law of cosines,  a² = b²+c² - 2bc cos(A),

9² = 5²+7² - 2(5)(7) cos(A)

81 = 25 + 49 - 70 cos(A)

7 = -70 cos(A)

cos(A) = -7/70

cos(A) = -1/10

A = cos⁻¹(-1/10)

A = 95.7°

Now, using the law of sines,  

[sin (A)]/(a) =  [sin (C)]/(c)

[sin (95.7°)]/(9) =  [sin (C)]/(7)

0.9955/9 = sin (C)/(7)

0.7742 = sinC

C = sin⁻¹(0.7742)

C = 50.7°

The sum of all the angles of a triangle= 180°

A + B + C = 180°

95.7° + B + 50.7° =  180°

B = 33.6°

Hence, the angles of the triangle are:

A =  95.7°, B = 33.6°, C = 50.7°.

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The quadrilateral ABCD is trapezoid.

What is trapezoid?

A quadrilateral with one set of parallel opposite sides is referred to as a trapezium. It can have congruent sides (isosceles) and right angles (a right trapezium), but neither is necessary.

Here in the given figure ,

[tex]\overline{AD}=\overline{BC}[/tex] are parallel to each other.

We can make right angle using ABC.

Hence the given quadrilateral ABCD is trapezoid.

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Answer:

Step-by-step explanation:

...

...

..

..

......

Answer:

84 degrees for number 6

Step-by-step explanation:

the area of a circle is 360 degrees, so just subtract the other angles by 360 i think that's how you do it

The surface area of the rectangular prism is 502 mm²

An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.

The area of a figure is the amount of space it occupies in its two dimensional state.

The surface area of the prism = 2(8 mm * 13 mm) + 2(8 mm * 7 mm) + 2(7 mm * 13 mm) = 502 mm²

The surface area is 502 mm²

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