A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?

Answer:

Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.

Explanation:

If the acceleration on this vehicle is constant, the SUVAT equations would apply:

[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].

Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:

[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].

Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.

If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:

[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].

Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

Pressure is related to Force, Volume and Density thus :

[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]

Using dimensional analysis :

Substituting the dimension into the relation :

[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]

[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

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The representation of pressure is:

[tex]P=FV^{-\frac{2}{3} }[/tex]

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]

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Explanation:

The speedometer of a motor car showed the following speeds in km per hour at the ends of successive intervals of 3 secs. 38.9, 52.8, 64.4. 73.6, 80.9, 86.1, 90.0, 92.5 Plot the velocity – time graph in convenient units and find from the graph, (a) The distance covered while the speed increased from 80

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

[tex]dl=\frac{Flo}{yA}[/tex]

[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=1.19064778*10^-^4[/tex]

Generally the equation for brass cylinder   is mathematically given as

[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=2.43*10^{-4}[/tex]

Therefore Total change in length

[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]

[tex]dl'=3.621*10^{-4}m[/tex]

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The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N

A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.

According  to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.

The centripetal force is the external force at work here and  It's the net force that propels the object in a circular motion.

Using the formula for calculating centripetal force:

[tex]\mathbf{F_c = mass (m) \times acceleration (a)}[/tex]

[tex]\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}[/tex]

[tex]\mathbf{F_c = 27 \ N}[/tex]

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Answer:

Explanation:

A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere

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[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]

[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]

[tex] \sf \huge \red {\dag} Given[/tex]

[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]

[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]

We know that the formula of Pressure is

[tex]\sf \longmapsto \: Force/Area[/tex]

Let's start.

[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]

[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]

[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]

Answer:

0n

Explanation:

Answer:

a. 6

b. 6 m/s²

c. 300 m to the right

d. 30 secs

Explanation:

slope = rise /run

60-0/10-0

= 6

b. slope = acceleration = 6 m/s²

c. d=ut+1/2at²

t=10 (segment A last for 10 secs)

u - initial velocity = 0

so d = 0(10)+1/2*6*10²

=300 m

Answer:

unfortunately we have not received a reply to the park yet but

Explanation:

mohamedz and he had killed him

Answer:

Conduction

Explanation:

Because when a molecule is transferred to another molecule then this in going into direct contact

For example if we have a pan and it is boiling well the heat that is on the pan holder that stays in place and it won`t move anywhere else like there is Radiation and Convection but for this question the answer would be Conduction

Answer:

element ammmkkkv was a very good

Answer:

B

Explanation:

I don't know but its b

The density of the object is 5911.94 kg/m³

An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.

The buoyancy = weight of the object - weight in water

= 15 N - 13N

= 2 N

The buoyancy force can also be determined by using the expressed:

[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]

[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]

[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]

volume (v) = 2.589 × 10⁻⁴m³

Recall that:

The mass of an object can be estimated by using the formula:

Weight = mass × gravity

mass = Weight / gravity

mass = 15/9.8

mass = 1.5306 kg

The density of the object can now be calculated using the relation

Density = mass/volume

Density = 1.5306 kg / 2.589 × 10⁻⁴m³

Density = 5911.94 kg/m³

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The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.

The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.

The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.

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Answer:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

Explanation:

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Answer:

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]

We have the final answer as

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9) a) formula = h(ρ)g by default g=9.8m/s²

Pressure = 2×1000×9.8 = 19600Pa

b)

Answer:

it prevents slipping on the grass while playing

Answer:

to keep their grip on the ground so they won't fall

We have that the the minimum coefficient of static friction  is mathematically given as

[tex]\mu= 0.235[/tex]

Generally the equation for the Force   is mathematically given as

[tex]F=n\mu\\\\Where\\\\n = mg\\\\Given\\\\Fc = m(vt2/R)\\\\Therefore\\\\\mu = vt2/gR\\\\\mu = 2.22/(9.8(2.1)) \\\\[/tex]

[tex]\mu= 0.235[/tex]

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Answer:

potentiometer is a device used to measure potential difference across the circuit

Answer:

Explanation:

Use simplified formula:

Answer: Juvenile fish go through various stages between birth and adulthood. When they have developed to the point where they are capable of feeding themselves, the fish are called fry. When, in addition, they have developed scales and working fins, the transition to a juvenile fish is complete and it is called a fingerling.

Answer

Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.

Explanation:

Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

According to the Question:

[tex]\footnotesize\implies F \propto [m]^x [v]^y [r]^z[/tex]

[tex]\footnotesize\implies F =k [m]^x [v]^y [r]^z \:...(i)[/tex]

Now, substituting Dimensions of each physical quantity in equation (I):

[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M^1L^0T^0]^x [M^0L^1T^{-1}]^y [M^0L^1T^0]^z[/tex]

[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M]^x [L]^{y + z} [T]^{ - y}[/tex]

On comparing the powers of LHS and RHS:

[tex]\implies \bf x = 1[/tex]

[tex]\implies - y = - 2[/tex]

[tex] \implies \bf y = 2[/tex]

[tex]\implies y + z = 1[/tex]

[tex]\implies z = 1 - 2[/tex]

[tex]\implies \bf z = - 1[/tex]

[tex]\footnotesize\implies F = [m]^x [v]^y [r]^z[/tex]

[tex]\footnotesize\implies F = [m]^1 [v]^2 [r]^{ - 1}[/tex]

[tex]\implies\footnotesize \underline{ \boxed{ \bf \red{ F = \frac{m {v}^{2} }{r} }}}[/tex]

Answer:

Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.

Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s

Explanation:

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