A man can jump 2 m on the surface of the earth, calculate the height that he can jump on the surface of the moon?​

Answer:

the angle of incident is 40°

Explanation:

NQ is the normal to the mirror, therefore

angle NQA =90°

PQA = 50°

incident angle = NQA - PQA

90°- 50° = 40°

note that the angle of reflection is equal to the angle of incident

Answer:

b

Explanation:

Answer:

a. 86.80 m

b. i. The mass of the bob

ii. The length of the pendulum

Explanation:

a. Determine the height of the smokestack.

Using T = 2π√(L/g) where T = period of pendulum = 18.7 s, L = length of pendulum = height of smokestack and g = acceleration due to gravity = 9.8 m/s².

So, making L subject of the formula, we have

T = 2π√(L/g)

T/2π = √(L/g)

squaring both sides, we have

(T/2π)² = L/g

L = (T/2π)²g

Substituting the values of the variables into the equation, we have

L = (T/2π)²g

L = (18.7 s/2π)²(9.8 m/s²)

L = (2.976 s)²(9.8 m/s²)

L = 8.857 s² × 9.8 m/s²

L = 86.796 m

L ≅ 86.80 m

b. What factors influence the period of a simple pendulum

The factors that influence the period of a simple pendulum are

i. The mass of the bob

ii. The length of the pendulum

Answer:

Explanation:

Kinematic equation: Final velocity^2 = Initial velocity^2 + 2*acceleration*displacement

As the ball is dropped from rest, initial velocity = 0.

Acceleration = gravity = 9.8m/s^2

Displacement = 7m

So velocity just before it hits ground

= sqrt( 2*9.8*7)

= 11.71m/s

Answer:

KE = 308642.02469136 J

Answer:

Velocity is the displacement (change In position of an an object it is similar to distance ) divided by the time taken. SI unit m/s (metre per second)

Answer: A.

Explanation:

Máquina térmica tem como função, manter a temperatura de um dado fluído, então, a quantidade de calor desse mesmo fluído ao entrar na máquina, será igual á quantidade de calor desse fluido saindo.

Qin - Qout describes the work done by a heat engine. Hence option A is correct.

A heat engine is a system which converts heat into useful work. Carnot engine is  an ideal engine which has maximum efficiency than any other engines. Carnot has showed that "no engine can be more efficient than Carnot engine and the 100% efficient engine can not be existed". It takes heat from the reservoir to do some work and it discharges some amount of heat to the sink. Reservoir is know as hot body and sink is know as cold body.

Efficiency of the Carnot's heat engine is given by,

Efficiency, η = Work done / Heat input

Work done, W = Q1 – Q2

Heat input = Q1

Efficiency,

η = W / Q1

= (Q1 – Q2) / Q1

=1 – (Q2 / Q1).

To have engine with 100% efficiency, Q2 must be zero and it is not possible.

Hence work done by a heat engine is Qin - Qout.

To know more about heat engine, click :

https://brainly.com/question/28034387

#SPJ7.

Answer:

The man's total displacement is equal to 0.

Explanation:

Given that,

A man ran a 5 mile race. The race looped around a city park and back  to the starting line.

We need to find the total displacement of the man.

We know that,

Displacement = shortest path covered

Also,

Displacement = final position - initial position

As it reaches back to its starting line, it means, the displacement is equal to 0.

Hence, the man's total displacement is equal to 0.

Answer:

With the help of formula.

Explanation:

We can calculate the electric potential of any point through the formula of electric potential which is given below.

Electric potential =  Coulomb constant x charge/ distance of separation.

Symbolically it can be written as,  V = k q/ r where

V = electric potential  

k = Coulomb constant

q = charge

r = distance of separation

If we have all these data, we can simply put the data in the formula and we will get the value of electric potential.

Question

A radio station transmitted a radio wave with frequency of 25MHz the value of the frequency is equivalent to? Leave answer in Hz and in standard form.

Answer:

2.5 x 10⁷Hz

Explanation:

The measured frequency is 25MHz

To convert this to Hz, we simply change the M, which means mega, to its equivalent value which is 10⁶.

Therefore, we have;

25MHz = 25(10⁶) Hz

=> 25MHz = 25 x 10⁶ Hz  

Now express this value in standard form as follows;

25 x 10⁶ Hz = 2.5 x 10¹ x 10⁶

=> 25 x 10⁶ Hz = 2.5 x 10⁷ Hz

Therefore, the value of 25MHz is equivalent to 2.5 x 10⁷Hz

The value of the frequency of the radio wave is equivalent to 2.5 × 10⁷ Hertz.

Given the data in the question;

Frequency of radio wave; [tex]f = 25MHz[/tex]

Frequency is the number of occurrences of a repeating event per unit of time. The SI unit for frequency is the hertz (Hz)

We know that;

[tex]1MHz\ ( Megahertz) = 1000000 Hz\ ( Hertz )[/tex]

so

[tex]25MHz = x[/tex]

We cross multiply

[tex]x = \frac{25MHz\ *\ 1000000Hz}{1MHz} \\\\x = 2.5 * 10^7 Hz[/tex]

Therefore, the value of the frequency of the radio wave is equivalent to 2.5 × 10⁷ Hertz.

Learn more: https://brainly.com/question/67787

Answer:

Notice that for all substances, the heat of vaporization is substantially higher than the heat of fusion. Much more energy is required to change the state from a liquid to a gas than from a solid to a liquid.

Gaseous water would require the most heat to produce a temperature change.

Intermolecular force is defined as the force of attraction existing between the neighboring molecules in a container that holds the together.

Here,

Evaporation is the process of conversion of liquid water into gaseous water vapor.

Condensation is the process of conversion of gaseous water vapor into liquid water.

Condensation occurs under higher temperature than that of evaporation. Condensation requires more temperature because the energy for separating the molecules in the gaseous state is comparatively higher. In order to convert the gaseous state into liquid state, it requires a greater intermolecular forces so that the gaseous molecules are brought more closer. The intermolecular force needed for the process of evaporation is lesser when compared to condensation. So, the heat required in evaporation is comparatively less.

Hence,

Gaseous water would require the most heat to produce a temperature change.

To learn more about intermolecular forces, click:

https://brainly.com/question/9007693

#SPJ2

Answer:

120,000seconds

Explanation:

400 minutes x 5= 2000minutes (2000minutes x 60)seconds =120,000seconds.

btw :

stay safe! :3

Answer:

12000

Explanation:

5 x 400 = 2000, 2000 x 60 = 12000

Answer:

SO

Explanation:

SI

Answer:

Explanation:

dynamic equilibrium

Answer:

Explanation:

The frequency is 16.0 Hz. That means that 16 of these waves can pass a single point in 1 second. We are given frequency and wavelength. The equation that relates them is

[tex]f=\frac{v}{\lambda}[/tex] where f is frequency, v is velocity, and λ is wavelength. Putting all this together:

[tex]16.0=\frac{v}{97.5}[/tex] and solving for velocity,

v = 16.0(97.5) so

v = 1560 m/s. This wave can travel 1560 meters in a single second!!! Now that we know this velocity, we can use it in a proportion to find our unknown, which is how long, t, it will take to hear this sound 11000m away. (11 km is 11000m):

[tex]\frac{1560m}{1s}=\frac{11000}{t}[/tex] and cross multiply to get

1560t = 11000 so

t = 7.1 seconds

Explanation:

Sound travels from the tour guide to the other of the canyon and then back, thus hearing the echo. The time of 2.0 s represents the time it takes the sound to make a round trip, therefore it takes 1.0 s for the tour guide's voice to reach the other side of the canyon. At 20°C, the speed of sound is 343 m/s therefore the width of the canyon is

[tex]x = vt = (343\:m/s)(1.0\:s) = 343\:m[/tex]

The canyon in the given question is 340 m wide.

Echo is a reflection of sound that comes to the listener after the direct sound, but with a delay. The delay is inversely proportional to the separation between the source and the listener of the reflecting surface.

To hear the echo, the following conditions must be met:

There must be a minimum of 17 meters between the sound source and the reflecting surface, and there must be at least 0.1 seconds between the original sound and its echo.

Given parameters:

When a tour guide shouts across a canyon, her echo is heard 2.00 s later. That means, in two seconds the sound goes to other wall of canyon and reflected back.

At a temperature of 20 °C, velocity of sound is 340 m/s.

So, the wide is the canyon be = velocity of sound × time/2

= 340 m/s ×2 s/2s = 340 m.

Hence, the wide is the canyon be 340 m.

Learn more about echo here:

https://brainly.com/question/26833784

#SPJ2

Answer:

W = 24 J

Explanation:

Given that,

Applied force, F = 60 N

Distance moved, d = 40 cm = 0.4 m

We need to find the work done by the carpenter. We know that,

Work done, W = Fd

Put all the values,

W = 60 N × 0.4 m

= 24 J

Hence, the required work done is equal to 24 J.

Answer:

2Ω

Explanation:

If a 18Ω resistance is cut into three equal parts each of the resistance will be 18Ω/3 = 6Ω

Equivalent ratio in parallel is expressed as:

1/R = 1/6 + 1/6 + 1/6

1/R = 3/6

Cross multiply

3R = 6

R = 6/3

R = 2Ω

Hence the required equivalent resistance is 2Ω

Answer:

When the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off, this is an example of resistance, which provides light and heat.  

Explanation:

Opening or closing a circuit.

Answer:

V is changing

[tex]as \: skater \: moves : \: there \: is \: displacement \\ from \: third \: equation \: of \: motion \\ {v}^{2} = {u}^{2} + 2as \\ {( \delta \: V})^{2} = 2as \\ V \: \alpha \: s[/tex]

Answer:

0.2 Hz

Explanation:

Frequency: This can be defined as the number of circles completed by a wave in one seconds. The s.i unit is hertz.

From the question,

If 4 Waves arrives on the shore every 20 seconds,

Then,

x waves will arrives on the shore in one seconds

Solving for x

x = (4×1)/20

x = 0.2 Hz

Hence the frequency of the wave is 0.2 Hz

Answer:

The weight of the person decreases.

Explanation:

Weight of person at sea level = 700 N

height = 10000m

We know that the weight is given by product of mass and the acceleration due to gravity.

The acceleration due to gravity at height is given by

[tex]g' =g\times \left ( \frac{R}{R+h} \right )^2[/tex]

Where, R is the radius of earth and h is the height.

Now, as we go on heights , the acceleration due to gravity decreases, so the weight also decreases as we go on heights.

Answer:

The electromagnetic theory of light , that's the answer

Answer:

the electromagnetic theory of light

Explanation:

got it right on o.w

Answer:

Explanation:

Refer to the pic below that I attached as we talk through these answers.

The amplitude is shown as the height from the top of one wave (called the crest) to the midline. If the whole vertical height from crest to trough is 32 cm, then the amplitude is half of that at

A = 16 cm

The wavelength, or λ, is the horizontal distance from crest to crest or trough to trough. Therefore, our wavelength is 48 cm + 48 cm which is

λ = 96 cm

The speed of the wave is the same thing as the velocity of the wave which can be found in the equation

[tex]f=\frac{v}{\lambda}[/tex] where f is the frequency of the wave and lambda is the wavelength. Filling in:

[tex]2.4=\frac{v}{96}[/tex] and

2.4(96) = v so

v = 230 m/s to the correct number of sig fig's

Answer:

Explanation:

The equation you need for this is a one-dimensional:

[tex]v_f^2=v_0^2 +2a[/tex]Δx (sorry that looks weird. It is all one equation, even though it's "crooked"!)

We have final velocity, acceleration, and the displacement, and we are looking for initial velocity. I see after working this out that you don't use the die-hard rules for significant digits, so I adapted to get an answer that matches exactly what one of your choices is. Filling in:

[tex](13.5)^2=v_0^2+2(.50)(49.3)[/tex] and

[tex](13.5)^2-2(1.50)(49.3)=v_0^2[/tex] and

[tex]\sqrt{(13.5)^2-2(1.50)(49.3)}=v_0[/tex] so

v₀ = 5.86 m/s

Answer:

A

Explanation:

Wavelength is represented by lambda

Answer:

kinetic energy of 16 J. Determine the velocity of the first toy, and the mass of the ... distance of 12 cm into the tree. ... b) the average force exerted on the bullet while slowing down to a stop.

14 pages·317 KB