The magnitude of the induced electric field at a point near the center of the solenoid and 0.500 cm from the axis of the solenoid is 1.07 × 10⁻⁴ V/m,
The magnitude of the induced electric field at a point near the center of the solenoid and 1.00 cm from the axis of the solenoid is 4.284 × 10⁻⁴ V/m.
Total no. of turns on the solenoid = 900 turns/m
Radius of solenoid = 2.50 cm = 0.025m
Rate of increase in current = 48.0 A/s
The magnetic field inside the solenoid,
B = μ₀nI
Where,
n = no. of turns per unit length
n = 900 turns/m
I = current flowing through the solenoid= 0 + 48t= 48t
T = 0s → I = 0
T = ∞ → I = 48
T = t
B = 4π × 10⁻⁷ × 900 × 48t
B = 1.363 T
The induced electric field at a point near the center of the solenoid.
(a) 0.500 cm from the axis of the solenoid
Area of the loop,
A = πr²
= π(0.005)²
A = 7.85 × 10⁻⁵m²
Enclosed current,
I = nA × I
= 900 × 7.85 × 10⁻⁵ × 48tI
= 0.3396t
Magnetic flux,
Φ = BA = 1.363 × 7.85 × 10⁻⁵
Φ = 1.070 × 10⁻⁴ Wb
Induced electric field
E = - (dΦ/dt)
E = -d/dt (1.070 × 10⁻⁴)
E = - (-1.070 × 10⁻⁴)/dt
E = 1.07 × 10⁻⁴V/m(
b) 1.00 cm from the axis of the solenoid
Area of the loop,
A = πr² = π(0.01)²
A = 3.14 × 10⁻⁴m²
Enclosed current
I = nA × I
= 900 × 3.14 × 10⁻⁴ × 48t
I = 1.36224t
Magnetic flux,
Φ = BA = 1.363 × 3.14 × 10⁻⁴
Φ = 4.284 × 10⁻⁴ Wb
Induced electric field,
E = - (dΦ/dt)
E = -d/dt (4.284 × 10⁻⁴)
E = - (-4.284 × 10⁻⁴)/dt
E = 4.284 × 10⁻⁴V/m
Hence,
the magnitude of the induced electric field at a point near the center of the solenoid and 0.500 cm from the axis of the solenoid is 1.07 × 10⁻⁴ V/m,
and
the magnitude of the induced electric field at a point near the center of the solenoid and 1.00 cm from the axis of the solenoid is 4.284 × 10⁻⁴ V/m.
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What is happening to the ATOMS INSIDE of a magnet that gives the
material its magnetic properties?
Answer:
The atoms are aligned in a particular direction
Explanation:
The atoms become aligned in a particular direction in regions called domains, thus resulting in an overall resultant magnetism due to the spin of the electrons.
If a 65-kilogram astronaut exerts a voce with a magnitude of 50 newtons on a satellite that she is repairing, the magnitude of the force that the satellite exerts on her is.
1. 0N
2. 50 N less than her weight
3. 50 N more than her weight
4. 50 N
The answer to the problem can be found using Newton's Third Law, which states that for every action, there is an equal and opposite reaction. When an object exerts a force on a second object, the second object exerts an equal and opposite force on the first object.
Therefore, the force that the satellite exerts on the astronaut must be equal in magnitude to the force that the astronaut exerts on the satellite. However, the direction of the force is opposite, i.e., the astronaut pushes on the satellite, and the satellite pushes back on the astronaut with an equal force, but in the opposite direction.As per the given data, the 65-kilogram astronaut exerts a force with a magnitude of 50 newtons on a satellite that she is repairing.
The magnitude of the force that the satellite exerts on her is also 50N. Therefore, the correct answer is 4. 50 N.Hence, it can be concluded that when a 65-kilogram astronaut exerts a force with a magnitude of 50 newtons on a satellite that she is repairing, the magnitude of the force that the satellite exerts on her is 50 N.
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refer to the above graph. the firm will earn maximum total profits if it produces and sells quantity: 0k 0b 0a 0c
The firm will earn maximum total profits if it produces and sells quantity 0b. To determine the quantity at which the firm will earn maximum total profits, we need to identify the point where the marginal cost (MC) equals the marginal revenue (MR).
In the given graph, the MC curve intersects the MR curve at quantity 0b. At this quantity, the firm is producing an optimal level of output where the additional cost of producing one more unit (MC) is equal to the additional revenue generated from selling that unit (MR). This represents the point of profit maximization. Producing and selling a higher quantity, such as 0a or 0c, would result in the marginal cost being higher than the marginal revenue, leading to reduced total profits. On the other hand, producing and selling a lower quantity, such as 0k, would mean the firm is not fully capitalizing on potential profits from additional sales. Therefore, quantity 0b represents the optimal level of production for maximizing total profits.
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What are four reasons why it is important to apply for entry at tertiary institutions while you are still at grade 11
Answer:
Explanation:
The main reason for doing this is to get the attention of the tertiary institutions early. There are thousands of students that apply to these institutions every year, depending on the strictness of the acceptance of these institutions it may or may not be difficult for you to enter. Applying while at grade 11 gives you more chances of getting in as you are catching the attention of the institution and showing a high level of interest. This also allows you more chances to enter, since if you are denied you can try again next year. Aside from this, some institutions have specific requirements, applying early can allow you to know what you are missing as they will tell you if you get denied. You can then work towards obtaining these requirements and apply next year.
n a certain series rlc circuit, irms = 9.00 a, δvrms = 190 v, and the current leads the voltage by 38.0°. (a) what is the total resistance (in ω) of the circuit?
The total resistance of the circuit is approximately 21.11 Ω. To determine the total resistance (R) of the series RLC circuit, we can use the relationship between the current (I), voltage (V), and resistance.
To determine the total resistance (R) of the series RLC circuit, we can use the relationship between the current (I), voltage (V), and resistance:
V = I * R
Given:
Irms = 9.00 A (root mean square value of current)
δvrms = 190 V (root mean square value of voltage)
The current leads the voltage by 38.0°
First, we need to find the peak values of current (I_peak) and voltage (V_peak). Since the root mean square (rms) values are given, we can use the following relationship:
I_peak = Irms
V_peak = δvrms
Now, we can calculate the total resistance (R) using the peak values:
R = V_peak / I_peak
R = 190 V / 9.00 A
R ≈ 21.11 Ω
Therefore, the total resistance of the circuit is approximately 21.11 Ω.
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What unit is kinetic energy measured in?
Explanation:
jouleeeee is the unit kinetic energy is measured in and kinetic energy formula is 1/2mv (square)
a container of mass 200kg contains 160cm
of liquid. The total mass of the container and liquid is 520g. what is the density of the liquid?
Answer:
mass of liquid = total mass - mass of container
m = 52000kg - 200kg
m = 519800
D = m/v
D = 519800/160
D = 3,248.75 kgm-³
An athletes heart beats 62 times per minute. What is the frequency of her heart beat?
Answer:
22
Explanation:
bc it just is
Find solutions for your homework
sciencephysicsphysics questions and answersa 6.50 μf capacitor that is initially uncharged isconnected in series with a 4500 ω resistor and a503 v emf source with negligible internal resistance.a)just after the circuit is completed, what is the voltagedrop across the capacitor? vc= vb)just after the circuit is completed, what is the voltagedrop across the resistor?
Question: A 6.50 ΜF Capacitor That Is Initially Uncharged Isconnected In Series With A 4500 Ω Resistor And A503 V Emf Source With Negligible Internal Resistance.A)Just After The Circuit Is Completed, What Is The Voltagedrop Across The Capacitor? Vc= Vb)Just After The Circuit Is Completed, What Is The Voltagedrop Across The Resistor?
A 6.50 μF capacitor that is initially uncharged isconnected in series with a 4500 Ω resistor and a503 V emf source with negligible internal resistance.
a)Just after the circuit is completed, what is the voltagedrop across the capacitor?
Vc= V
b)Just after the circuit is completed, what is the voltagedrop across the resistor?
VR = V
c)Just after the circuit is completed, whatis the charge on the capacitor?
Qo= C
d)Just after the circuit is completed, whatis the current through the resistor?
IR= A
e)A long time after the circuit is completed(after many time constants), what are the values of the precedingfour quantities?
Vc, V R, I,Q= V, V, A, C
The voltage across the capacitor (Vc) will be equal to the emf of the source (V) which is 503 V, the voltage drop across the resistor ([tex]V_R[/tex]) will be zero, the current through the resistor ([tex]I_R[/tex]) will be 0.112 A, and the charge on the capacitor (Q) will be at its maximum value (Q = CV).
a) Just after the circuit is completed, the voltage drop across the capacitor (Vc) is equal to the emf of the source (V). Therefore, Vc = V = 503 V.
b) Just after the circuit is completed, the voltage drop across the resistor ([tex]V_R[/tex]) is zero since the capacitor is initially uncharged and behaves like a open circuit. Therefore, [tex]V_R = 0 V[/tex].
c) Just after the circuit is completed, the charge on the capacitor (Q₀) is zero since the capacitor is initially uncharged. Therefore, Q₀ = 0 C.
d) Just after the circuit is completed, the current through the resistor ([tex]I_R[/tex]) can be calculated using Ohm's Law:
[tex]I_R[/tex] = V / R = 503 V / 4500 Ω ≈ 0.112 A
e) A long time after the circuit is completed (after many time constants), the capacitor will be fully charged and behave like an open circuit. The charge on the capacitor (Q) will be at its maximum value (Q = CV).
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Suppose that you hear a clap of thunder 16.2s after seeing the associated lightning stroke. The speed of sound waves in air is 343 m/s and speed of light in air is 3×10^(8) ms^(-1). How far you are from the lightning stroke?
You are approximately 5550.6 meters away from the lightning stroke.
To calculate the distance between you and the lightning stroke, we can use the fact that the time it takes for light and sound to reach you is related to their respective speeds.
In this case:
Time for sound to reach you (t_sound) = 16.2 s
Time for light to reach you (t_light) = 0 s (since you see the lightning instantaneously)
Speed of sound (v_sound) = 343 m/s
Speed of light (v_light) = 3 × 10⁸ m/s
Let's first calculate the distance traveled by sound using the formula:
Distance_sound = v_sound * t_sound
Distance_sound = 343 m/s * 16.2 s
Distance_sound = 5550.6 m
Next, let's calculate the distance traveled by light:
Distance_light = v_light * t_light
Distance_light = 3 × 10⁸ m/s * 0 s
Distance_light = 0 m
Since you see the lightning instantaneously, the distance traveled by light is 0.
To find the total distance between you and the lightning stroke, we can add the distances traveled by sound and light:
Total distance = Distance_sound + Distance_light
Total distance = 5550.6 m + 0 m
Total distance = 5550.6 m
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role of school to protect child rights
Answer:
The Right to Protection: According to the Convention, this right includes freedom from all forms of exploitation, abuse and inhuman or degrading treatment.
Explanation:
They by law have to uphold the standards
A group of students are doing a reading activity in their classroom. They suddenly hear the noise of a truck in the parking lot of their school. They can hear it but cannot see it. Which of the following explains why they can hear the truck, but cannot see it?
Answer:
The answer is the sound waves can travel through some material (not all) and visible light cannot.
Explanation:
I did this question on study island so I know the answer.
Answer:
the answer is: sound can be transmitted through the walls, but visible light cannot.
Explanation:
An object accelerates uniformly from 3. 0 meters per second east to 8. 0 meters per second east in 2. 0 seconds. What is the magnitude of the acceleration of the object ?
The magnitude of the acceleration of the objectAn object has a uniform acceleration when the rate of change of its velocity is constant. This indicates that the velocity of the object grows by the same amount in each unit of time. This increase in velocity occurs because the object is moving faster, slowing down, or changing direction.
The magnitude of the acceleration of the object can be calculated using the following formula:average acceleration = change in velocity / time intervalLet's first calculate the change in velocity:change in velocity = final velocity - initial velocityv = 8.0 m/s (final velocity)east - 3.0 m/s (initial velocity)eastchange in velocity = 8.0 m/s - 3.0 m/s = 5.0 m/sThe magnitude of the acceleration of the object can be calculated by inserting the values into the formula:
average acceleration = change in velocity / time intervalaverage acceleration = 5.0 m/s / 2.0 s = 2.5 m/s²Therefore, the magnitude of the acceleration of the object is 2.5 m/s². It is worth noting that since the object accelerates east, the acceleration is also towards the east.
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Four children are playing on a slide at a park. They take turns going down the slide. The table below shows how much each child weighs. Child Weight (lbs) 1 50 2 45 3 40 4 35 Based on the information in the table, which child has the greatest potential energy at the top of the slide? A. child 1 B. child 2 C. child 3 D. child 4
Answer:
a. 50
Explanation:
constants, as appropriate. (a) Derive an expression for the magnitude of the emf s induced in the loop as a function of t. (b) Derive an expression for the power P dissipated in the loop as a function of t. (c) Determine the net force on the loop. Justify your answer. (d) On the axes, sketch a graph of the magnitude of the current I induced in the loop as a function of t for the first cycle. The time T for the first cycle is labeled on the horizontal axis. (e) At time t=41T, is the current in the loop clockwise or counterclockwise? Clockwise Counterclockwise Justify your answer. t=0 to t=41T
(a) The magnitude of the emf (ε) induced in the loop as a function of time (t) is given by the equation ε = -dΦ/dt, where Φ is the magnetic flux through the loop. The negative sign indicates that the emf opposes the change in magnetic flux.
The magnitude of the emf induced in the loop can be expressed as ε = -dΦ/dt, where dΦ/dt represents the rate of change of magnetic flux through the loop. The value of dΦ/dt depends on the specific scenario or setup.
(b) The power (P) dissipated in the loop as a function of time can be calculated using the equation P = I^2R, where I is the current flowing through the loop and R is the resistance of the loop.
The power dissipated in the loop can be calculated using the equation P = I^2R, where I is the current flowing through the loop and R is the resistance of the loop. The power dissipation is directly proportional to the square of the current and the resistance of the loop.
(c) The net force on the loop is zero. According to Lenz's law, the induced current creates a magnetic field that opposes the change in the magnetic field causing the induction. This opposition leads to a canceling effect, resulting in a net force of zero on the loop.
According to Lenz's law, the induced current creates a magnetic field that opposes the change in the magnetic field causing the induction. This opposition results in a canceling effect, leading to a net force of zero on the loop. The forces due to the induced current and the external magnetic field balance each other, resulting in a net force of zero.
(d) The graph of the magnitude of the current (I) induced in the loop as a function of time for the first cycle will have a sinusoidal shape. The current will start from zero, increase to a maximum, decrease to zero again, and then reverse direction, reaching a maximum in the opposite direction.
The graph of the magnitude of the current induced in the loop as a function of time for the first cycle will exhibit a sinusoidal pattern. The current starts from zero, increases to a maximum, decreases back to zero, and then reverses direction, reaching a maximum in the opposite direction. The shape of the graph resembles a sine wave.
(e) At time t = 41T, the current in the loop is counterclockwise. This can be determined based on the graph mentioned in part (d) and the periodic nature of the current. Since the current reverses direction after each cycle, at t = 41T, it will be in the counterclockwise direction.
Since the current in the loop reverses direction after each cycle, at t = 41T, the current will be in the counterclockwise direction. This can be inferred from the periodic nature of the current and the fact that the current changes direction at the end of each cycle.
In conclusion, the magnitude of the emf induced in the loop as a function of time can be determined using the rate of change of magnetic flux. The power dissipated in the loop depends on the current and resistance. The net force on the loop is zero due to Lenz's law. The graph of the current induced in the loop exhibits a sinusoidal shape. At time t = 41T, the current in the loop is counterclockwise based on the periodic nature of the current.
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an airplane is flying south going 440 mph when it hits a crosswind going west at 35 mph. What is the
it velocity? (Round to the nearest mph.)
a) 405 mph southwest
b) 439 mph southwest
c) 441 mph southwest
d) 475 mph southwest
An airplane is flying south going 440 mph when it hits a crosswind going west at 35 mph, the resultant velocity of the airplane is approximately 439 mph southwest.
Hence, the correct option is B.
To find the resultant velocity of the airplane, we can use vector addition. The airplane's velocity in the south direction is 440 mph, and the crosswind's velocity in the west direction is 35 mph.
To find the resultant velocity, we can treat the velocities as vectors and add them together. Since the airplane is flying in the south direction and the crosswind is in the west direction, we can consider these vectors as negative in the corresponding directions.
Using the Pythagorean theorem, the magnitude of the resultant velocity can be calculated as follows
Resultant velocity = [tex]\sqrt{440^{2} }[/tex] + ([tex]-35^{2}[/tex]))
Resultant velocity = 439.66 mph
Since the resultant velocity is directed to the southwest, we can round the magnitude to the nearest mph and the direction to the nearest cardinal direction. Therefore, the resultant velocity of the airplane is approximately 439 mph southwest.
Hence, the correct option is B.
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Which of the following is the best description of the first law of thermodynamics? The entropy of an isolated system increases until the system reaches thermal equilibriunm Thermal energy flows from the colder object to the warmer object. outside force. The change in thermal energy ofa systemis equal to the energy transferred into An objet will maintain its current state of motion unless acted upon by an or out of the system as work, heat, or both.
The change in thermal energy of a system is equal to the energy transferred into or out of the system as work, heat, or both.
The first law of thermodynamics, also known as the law of energy conservation, states that energy cannot be created or destroyed in an isolated system.
Instead, it can only be transferred or converted from one form to another. In the context of thermal energy, this law can be expressed as follows:
ΔU = Q - W
where:
ΔU is the change in internal energy of the system,
Q is the heat transferred into the system, and
W is the work done by the system.
This equation shows that the change in thermal energy of a system is equal to the energy transferred into the system as heat (Q) minus the work done by the system (W).
The first law of thermodynamics is a fundamental principle that describes the conservation of energy in a thermodynamic system.
It states that the change in thermal energy of a system is determined by the net transfer of energy into or out of the system as heat and work.
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Who sponsored Felix Baumgartner in the second space jump that took placed in
2008?
Alban Geissler, who developed the SKYRAY carbon fiber wing with Christoph Aarns, suggested after Baumgartner's jump that the wing he used was a copy of two prototype SKYRAY wings sold to Red Bull (Baumgartner's sponsor) two years earlier. - wiki
a transparent object with an isosceles right triangular cross-section has an index of refraction n2 = 1.2, as shown in the diagram below. A light beam in air is incident on this object, making an angle ?in = 75? with respect to the x-axis, as shown. At what angle (with respect to the x-axis), ?out, does the observer see the light beam exit the object?
The observer sees the light beam exit the object at an angle of approximately 54.74° with respect to the x-axis.
What is x-axis and what is denoted on that axis?
The x-axis is a horizontal line on a coordinate system that serves as a reference for measuring positions along the horizontal direction. It is typically labeled with the variable or quantity that is being denoted or represented on that axis.
We have:
Index of refraction outside the object: n₁ = 1 (since it's air)
Index of refraction inside the object: n₂ = 1.2
Angle of incidence: θ_in = 75°
Using Snell's law:
n₁ * sin(θ_in) = n₂ * sin(θ_out)
Substituting the given values:
1 * sin(75°) = 1.2 * sin(θ_out)
To find θ_out, we can isolate it by dividing both sides by 1.2:
sin(θ_out) = (1 * sin(75°)) / 1.2
Using the property that sin(45°) = 1 / √2, we can simplify further:
sin(θ_out) = (1 / √2) / 1.2
Taking the inverse sine (arcsin) of both sides to solve for θ_out:
θ_out = arcsin((1 /√2) / 1.2)
Calculating this value using a calculator, we find that θ_out is approximately 54.74°.
Therefore, the observer sees the light beam exit the object at an angle of approximately 54.74° with respect to the x-axis.
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If you move the north pole of a permanent magnet toward the surface of an aluminum pot, a current will flow through that pot and the pot will become magnetic, repelling your permanent magnet. If you stop the permanent magnet just before it touches the pot and then hold the permanent magnet stationary, the repulsive force between the pot and the permanent magnet will gradually disappear. The repulsive force disappears because the electric current in the pot a) becomes non-magnetic once the permanent magnet stops moving. b) stops increasing and becomes steady once the permanent magnet stops moving. c) becomes an alternating current once the permanent magnet stops moving and the pot’s magnetic poles then flip back and forth rapidly. d) stops flowing
Answer:
the correct one is d
Explanation:
Let's analyze the situation before reviewing the answers.
When the magnet moves towards the pot, an electromotive force is induced by Faraday's law
fem = [tex]- \frac{d \Phi_B }{dt}[/tex] - dfi / dt
[tex]\Phi_B[/tex] = B . A
In the pot, because it is metallic, a current is created and it is in the opposite direction to the variation of magnetic flux.
By stopping the magnet the flux becomes constant and therefore its derivative is zero, therefore there is no electromotive force and consequently no current.
When reviewing the answers, the correct one is d
A flat (unbanked) curve on a highway has a radius of 240 m . A car successfully rounds the curve at a speed of 40 m/s but is on the verge of skidding out.
Part A
If the coefficient of static friction between the car’s tires and the road surface were reduced by a factor of 2, with what maximum speed could the car round the curve?
Express your answer in meters per second to two significant figures.
Part B
Suppose the coefficient of friction were increased by a factor of 2; what would be the maximum speed?
Express your answer in meters per second to two significant figures.
The maximum speed the car could round the curve with a reduced coefficient of static friction is approximately 19.8 times the square root of the original coefficient of static friction.
Part A:
The maximum speed at which the car can round the curve without skidding can be determined using the centripetal force equation:
F = (mv^2) / r
Where:
F is the centripetal force,
m is the mass of the car,
v is the velocity of the car, and
r is the radius of the curve.
Since the car is on the verge of skidding out, the centripetal force is equal to the maximum static friction force:
F_friction = μ_s * m * g
Where:
μ_s is the coefficient of static friction,
m is the mass of the car, and
g is the acceleration due to gravity.
Setting these two forces equal, we can solve for the maximum velocity:
(μ_s * m * g) = (m * v²) / r
Rearranging the equation, we can solve for v:
v² = (μ_s * g * r)
Taking the square root of both sides, we find:
v = √(μ_s * g * r)
To find the maximum speed with a reduced coefficient of static friction (μ_s/2), we substitute this value into the equation:
v_max = √((μ_s/2) * g * r)
Calculating the value:
v_max = √((0.5 * μ_s) * g * r)
v_max = √(0.5 * μ_s * 9.8 * 240)
v_max ≈ 19.8 * √(μ_s)
Considering two significant figures, the maximum speed with the reduced coefficient of static friction is approximately 19.8 times the square root of μ_s.
Part B:
Similarly, we can find the maximum speed with an increased coefficient of static friction (2μ_s) using the same equation:
v_max = √((2μ_s) * g * r)
Calculating the value:
v_max = √(2 * μ_s * 9.8 * 240)
v_max ≈ 44.3 * √(μ_s)
Considering two significant figures, the maximum speed with the increased coefficient of static friction is approximately 44.3 times the square root of μ_s.
The maximum speed the car could round the curve with an increased coefficient of static friction is approximately 44.3 times the square root of the original coefficient of static friction.
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In terms of the wavelength of the sound wave, how far apart are the first two resonant positions in the resonance tube?
A.Three quarters of the wavelength
B.One quarter of the wavelength
C.One half of the wavelength
D.One wavelength
The distance between the first two resonant positions in a resonance tube is One half of the wavelength of the sound wave. Option C
How did we determine the distance between the first two resonant positions?In a resonance tube experiment, the first two resonant positions occur when the length of the tube equals one quarter of the wavelength and then three quarters of the wavelength.
These positions correspond to the first and second resonant frequencies, or harmonics.
Therefore, the distance between these two positions, in other words, the length of the tube at the second resonant position minus the length of the tube at the first resonant position, equals three quarters of the wavelength minus one quarter of the wavelength, which is half a wavelength.
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What is the wavelength of a sound wave
with a speed of 331 m/s and a frequency
of 500 Hz?
Answer:
0.777m
Explanation:
The sound wave has a wavelength of 0.773m.
Explanation:
To solve this problem we have to use the wave equation that is given below:
We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for
λ :
λ = v f
Let's plug in our given values and see what we get!
λ = 340 m s
440 s − 1
λ = 0.773 m
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The wavelength of the sound wave is 0.662 m.
Explanation:
Given that,
The speed of a sound wave, v = 331 m/s
The frequency of the wave, f = 500 Hz
To find,
The wavelength of the sound wave.
Solution,
The speed of wave in terms of wavelength and frequency is given by :
[tex]v=f\lambda[/tex]
Where
[tex]\lambda[/tex] is the wavelength
Rearranging for [tex]\lambda[/tex],
[tex]\lambda=\dfrac{v}{f}[/tex]
Put all the values,
[tex]\lambda=\dfrac{331}{500}\\\\\lambda=0.662\ m[/tex]
So, the wavelength of the sound wave is 0.662 m.
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What is competition?
Answer:
two team in a conflict
Explanation:
Competition arises whenever two or more parties strive for a common goal which cannot be shared: where one's gain is the other's loss. Competition includes rivalry between entities such as organisms, individuals, economic and social groups, etc.
If there is a ball sitting on top of a hill with 100J of GPE. How much KE should there be at the bottom of the hill if there is no friction?
PLS HELP MEEEE (NO LINKS PLEASE)
The difference between visible light and gamma rays is that
a.
the amplitude of visible light is greater.
c.
they travel through a different medium.
b.
the speed of gamma rays is greater.
d.
the frequency of gamma rays is greater.
Answer:
Gamma rays occupy the short-wavelength end of the spectrum; they can have wavelengths smaller than the nucleus of an atom. Visible light wavesare one-thousandths the width of human hair--about a million times longer than gamma rays. Radio waves, at the long-wavelength end of the spectrum, can be many meters long.
Answer:D "the frequency of gamma rays is greater."
Explanation:Trust
being the adventurous person that you are (you are in this class after all), you have made the choice to bungee jump off of a bridge. as you near the bottom of your fall, the bungee cord begins to tighten and your rate of downward acceleration decreases from free-fall to 7.35 m/s2. at this moment, your apparent weight is?
When the bungee cord begins to tighten and your rate of downward acceleration decreases from free-fall to 7.35 m/s², your apparent weight will be greater than your actual weight.
To understand this, let's consider the forces acting on you at that moment. Initially, when you were in free-fall, the only force acting on you was gravity, which caused you to accelerate downward at approximately 9.8 m/s² (acceleration due to gravity on Earth).
However, when the bungee cord starts to tighten, an upward force from the bungee cord comes into play. This force counteracts the downward force of gravity and causes your downward acceleration to decrease.
Apparent weight is the force experienced by an object due to the supporting surface or structure. In this case, your apparent weight is the force exerted on you by the bungee cord, which counteracts the force of gravity and reduces your acceleration.
To calculate your apparent weight, we can use Newton's second law of motion
F_net = m * a
where F_net is the net force, m is your mass, and a is your acceleration.
In this case, the net force is the difference between the downward force of gravity and the upward force from the bungee cord. So we can rewrite the equation as:
F_apparent - m * g = m * a
where F_apparent is your apparent weight, g is the acceleration due to gravity, and a is your reduced downward acceleration.
Solving for F_apparent:
F_apparent = m * (g + a)
Substituting the given values, where a = 7.35 m/s² and g = 9.8 m/s²:
F_apparent = m * (9.8 + 7.35) = m * 17.15
Therefore, at the moment your downward acceleration decreases to 7.35 m/s², your apparent weight will be 17.15 times your actual weight (mg).
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the position of a particle moving along a coordinate line is s = √ 6 3 t , with s in meters and t in seconds. find the particle’s velocity at t = 10 seconds.
Given that the position of a particle moving along a coordinate line is s = √6 3 t, with s in meters and t in seconds. Therefore, the velocity of the particle at t = 10 seconds is 0.
We need to find the particle’s velocity at t = 10 seconds. Here, we need to find the first derivative of s with respect to t, that is velocity.
The derivative of s is given as follows:
s = √6 3 t
∴ ds/dt = d/dt (√6 3 t)
ds/dt= √6 3
d/dt(t) = √6 3 velocity,
Velocity of particle at t = 10 seconds is obtained by substituting t = 10 in the expression of velocity.
Velocity of particle at t = 10 seconds = ds/dt (at t = 10)
velocity of a particle at t = √6 3 (d/dt (10))
velocity of a particle at t= √6 3 (0)= 0
Therefore, the velocity of the particle at t = 10 seconds is 0.
A concise answer to the given problem can be as follows:
The position of a particle moving along a coordinate line is given by
s = √63t.
We can find the particle's velocity at t = 10 seconds by taking the derivative of s with respect to t, which is the velocity.
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Identify the electromagnets with poles that are reversed from the electromagnet shown above
I've attached a picture of the 3 electromagnets options below the main electromagnet.
Answer:
The third electromagnet is correct.
Explanation:
From the attached image, in the electromagnet above the 3, we can see that the positive terminal comes before the negative terminal at the bottom left.
Now, when it is reversed, they will both move to the bottom right but their position will change with the negative coming before the positive.
Also, the electric current arrow inside the circle points in the north west direction but when it is reversed, it will point in the north east direction.
Also, the winded coil over the pole remains the same.
Thus, the only option that fulfills this reversed positions is the 3rd electromagnet
Answer:
Explanation:
Its B and C, I got a 5/5 on my test with these answers.
an open plastic soda bottle with an opening diameter of 3.0 cmcm is placed on a table. a uniform 1.50 tt magnetic field directed upward and oriented 30 ∘∘ from vertical encompasses the bottle.What is the total magnetic flux through the plastic of the soda bottle?
Express your answer using two significant figures. (φ= ? Wb)
The total magnetic flux through the plastic of the soda bottle is approximately 0.036 Wb.
To calculate the total magnetic flux through the plastic soda bottle, we need to consider the magnetic field passing through the area of the bottle opening.
The formula for magnetic flux (Φ) is given by
Φ = B * A * cos(θ),
Where B is the magnetic field strength, A is the area, and θ is the angle between the magnetic field and the surface normal.
Given:
B = 1.50 T (magnetic field strength)
d = 3.0 cm (diameter of the bottle opening)
First, we need to calculate the area of the bottle opening. Since the opening is circular, the area can be determined using the formula
A = π * ([tex]r^{2}[/tex]),
Where r is the radius.
r = d/2 = 3.0 cm / 2 = 1.5 cm = 0.015 m
A = π * ([tex]0.015^{2}[/tex]) = 0.00070686 [tex]m^{2}[/tex]
Next, we can calculate the total magnetic flux through the plastic of the soda bottle
Φ = B * A * cos(θ)
θ = 30°
Φ = (1.50 T) * (0.00070686 [tex]m^{2}[/tex]) * cos(30°)
Using a calculator
Φ = 0.036 Wb
Rounded to two significant figures, the total magnetic flux through the plastic of the soda bottle is approximately 0.036 Wb.
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