A large tank is filled to capacity with 400 gallons of pure water. Brine containing 3 pounds of salt per gallon is pumped into the tank at a rate of 4 gal/min. The well-mixed solution is pumped out at a rate of 8 gals/min. Find the number A(t) of pounds of salt in the tank at time t.

Answers

Answer 1

Answer:

The number A(t) of pounds of salt in the tank at time t = [tex]\frac{3t(100 - t)}{25}[/tex]

Step-by-step explanation:

Given - A large tank is filled to capacity with 400 gallons of pure water. Brine containing 3 pounds of salt per gallon is pumped into the tank at a rate of 4 gal/min. The well-mixed solution is pumped out at a rate of 8 gals/min.

To find - Find the number A(t) of pounds of salt in the tank at time t.

Proof -

Given that,

Capacity of water = 400 gallons

rate in flow = 4 gal/min

rate out flow = 8 gal/min

Concentration in = 3 lbs/gal

Concentration out = (Amount of salt at time t )/ (Solution in tank at time t)

Now,

Let

A(t) = Amount of salt in the tank at time t

Now,

Initially tank has 400 gallons of water, So

A(0) = 0 ................(1)

Now,

Rate of change in the amount of salt = [tex]\frac{d}{dt} A(t)[/tex]

                                                             = (Rate in flow )( Concentration In) - (Rate out flow )( Concentration out)

                                                             = (4) (3) - (8) ([tex]\frac{A(t)}{400 - 4t)}[/tex]

                                                             = 12 - [tex]\frac{2A(t)}{100 - t)}[/tex]

⇒[tex]\frac{d}{dt} A(t)[/tex] + [tex]\frac{2A(t)}{100 - t)}[/tex] = 12

Now,

Integrating Factor, I.F = [tex]e^{\int {\frac{2}{100 - t} } \, dt }[/tex]

                                    = [tex]e^{-2ln(100 - t)}[/tex]

                                    = (100 - t)⁻²

⇒I.F = (100 - t)⁻²

The solution becomes

A (I.F) = ∫ (I.F)(12) dt + C

⇒A (100 - t)⁻² = ∫12(100 - t)⁻² dt + C

⇒A (100 - t)⁻² = -12(100 - t)⁻¹ (-1) + C

⇒A(t) = [tex]12(100 - t)+ C(100 - t)^{2}[/tex]

Now,

We have A(0) = 0

⇒C = -12/100

∴ we get

A(t) = 12(100 - t) - [tex]\frac{12}{100}[/tex] (100 - t)²

     = 12(100 - t) [ 1 - [tex]\frac{100 - t}{100}[/tex] ]

     = 12(100 - t) ([tex]\frac{t}{100}[/tex])

     = [tex]\frac{3t(100 - t)}{25}[/tex]

⇒A(t) = [tex]\frac{3t(100 - t)}{25}[/tex]

∴ we get

The number A(t) of pounds of salt in the tank at time t = [tex]\frac{3t(100 - t)}{25}[/tex]


Related Questions

shamika grew by 14 cm in the past year, and is now 1.33 meters tall. how tall in meters was shamika last year

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She was 1.19m tall last year

what is the slope of the line for 3x+ 4y = 20?

Answers

Slope is -3/4
20 characters

Answer:

[tex]-\frac{3}{4}[/tex]

Step-by-step explanation:

Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operation, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

~

First, subtract 3x from both sides of the equation:

3x (-3x) + 4y = (-3x) + 20

4y = -3x + 20

Next, divide 4 from both sides of the equation:

(4y)/4 = (-3x + 20)/4

y = (-3/4)x + 5

[tex]y = -\frac{3}{4}x + 5[/tex]

~

Note the equation.

y = mx + b

y = y

m = slope = [tex]-\frac{3}{4}[/tex]

x = x

b = y-intercept = 5

v=Xf; speed = wavelength x frequency
f= 1/T; frequency = 1/Period
Problems: 1. The frequency of a wave is 4.0 x 10 Hz. What is its wavelength?

2. A wave with a frequency of 31,200 Hz and travels at 790m/s? What is the wavelength in centimeters?

3. A wave has a wavelength of 25cm and a velocity of 630 m/s, what is the frequency?​

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I don’t understand your questions because it’s all connected together. Could you maybe separate the actual question in the comments for me to help?

Happy Tuesday! Looking for some help with my geometry.

Please only answer if you know the answer, the comment section is right below. Please don't waste my points!

Also, please show all of your work, you are trying to help me better understand the concept, not just give me the answer.

The image is down below. This is a multi step question and please answer all five. Show work! Thanks!

Answers

Answer:

Q1

cos 59° = x/16x = 16 cos 59°x = 8.24

Q2

BC is given 23 mi

Maybe AB is needed

AB = √34² + 23² = 41 (rounded)

Q3

BC² = AB² - AC²BC = √(37² - 12²) = 35

Q4

Let the angle is x

cos x = 19/20x = arccos (19/20)x = 18.2° (rounded)

Q5

See attached

Added point D and segments AD and DC to help with calculation

BC² = BD² + DC² = (AB + AD)² + DC²

Find the length of added red segments

AD = AC cos 65° = 14 cos 65° = 5.9DC = AC sin 65° = 14 sin 65° = 12.7

Now we can find the value of BC

BC² = (19 + 5.9)² + 12.7²BC = √781.3BC = 28.0 yd

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Help me solve this, it’s trig

Answers

Answer:

The answer is 6.451 or 6.5 rounded

Step-by-step explanation:

The way to solve this is to find all the degrees inside the triangle first

you have two given degrees which are 21 and 90 degrees

add those numbers up and subtract it from 180. That is the last corner degree

you then use that information to find all the side lengths using the given hypotenuse length.

Btw its geometry not really trig.

Answer: 6.45 units

Step-by-step explanation:

    To solve for x, we will set up an equation using the trigonometric functions. We are given an angle (21 degrees), the opposite side of that angle (x), and the hypotenuse (18). For this, we will use the sine function.

sin(21) = [tex]\frac{opposite}{hypotenuse }[/tex]

sin(21) = [tex]\frac{x}{18}[/tex]

18sin(21) = x

x = 18sin(21)

x = 6.4506230 ≈ 6.45 units

six people wen put to dinner, split the check, and paid $18. How much was the check

Answers

Answer:

$180

Step-by-step explanation:

$18 × 6

=$180

That's your answer

I need help with solving this​

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Answer:

x=12

.......................

suppose 11 out of 22 students said they were attending the football game. how many students out of 580 would you expect to attend the football game.

Answers

Answer: 290

Step-by-step explanation:

11/22 is half so the percentage would be 50%.

As we know it's a half you would just have to half or divide 580 by 2.

580÷2=290

Hope this helps :)

Graph the compound inequality on the number line. x> -7 and x<-3​

Answers

Answer:

Step-by-step explanation:

Mark works as a librarian and makes $16.75 per hour. He gets paid time-and-a-half for overtime. How much will he make if he works 52 hours this week?

Play media comment.

Group of answer choices

$670.00

$971.50

$1,005.00

$871.00
PLZZZ HURRY

Answers

Answer:

$871.00

Step-by-step explanation:

Simplify the expression and find its value please help i will give brainliest​

Answers

Answer:

7.5

Step-by-step explanation:

a - (2a-1)/a

--------------------

(1-a)/3a

Multiply the top and bottom by 3a

a - (2a-1)/a              3a

-------------------- * ---------------

(1-a)/3a                     3a

3a *a - (2a-1)*3a/a

------------------------

          (1-a)/3a *3a

Simplify

3a *a - (2a-1)*3

------------------------

          (1-a)

3a^2 - 6a+3

------------------------

          (1-a)

Factor

3( a^2 -2a+1)

-----------------------

-(a-1)

3(a-1)^2

---------------

-(a-1)

Cancel like terms

-3(a-1)

Letting a = -1.5

-3( -1.5-1)

-3 (-2.5)

7.5

The number of bacterial colonies of a certain type in samples of polluted water has a Poisson distribution with a mean of 3 per cubic centimeter (cm3). (a) If eight 1 cm3 samples are independently selected from this water, find the probability that at least one sample will contain one or more bacterial colonies. (Round your answer to four decimal places.) 1 Correct: Your answer is correct. seenKey 1.000 (b) How many 1 cm3 samples should be selected in order to have a probability of approximately 0.95 of seeing at least one bacterial colony

Answers

Answer:

a) 1 = 100% probability that at least one sample will contain one or more bacterial colonies.

b) 1 sample should be selected in order to have a probability of approximately 0.95 of seeing at least one bacterial colony

Step-by-step explanation:

To solve this question, we need to understand the poisson and the binomial distributions.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Probability of a single sample having at least one bacterial colonies.

Poisson distribution with a mean of 3 per cubic centimeter (cm3), which means that [tex]\mu = 3[/tex]

This is:

[tex]P(X \geq 3) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0495[/tex]

[tex]P(X \geq 3) = 1 - P(X = 0) = 1 - 0.0495 = 0.9505[/tex]

(a) If eight 1 cm3 samples are independently selected from this water, find the probability that at least one sample will contain one or more bacterial colonies.

Multiples samples means that the binomial distribution is used.

0.9505 probability of a sample having at least one colony, which means that [tex]p = 0.9505[/tex]

8 samples means that [tex]n = 8[/tex]

The desired probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{8,0}.(0.9505)^{0}.(0.0495)^{8} \approx 0[/tex]

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0 = 1[/tex]

1 = 100% probability that at least one sample will contain one or more bacterial colonies.

(b) How many 1 cm3 samples should be selected in order to have a probability of approximately 0.95 of seeing at least one bacterial colony

We have to find [tex]P(X \geq 1)[/tex] for samples of 1,2,3,..., until this probability is 0.95. So

n = 1

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{1,0}.(0.9505)^{0}.(0.0495)^{1} = 0.0495[/tex]

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0495 = 0.9505[/tex]

0.9505 > 0.95

1 sample should be selected in order to have a probability of approximately 0.95 of seeing at least one bacterial colony

i will give a crown if you are the first one to answer and if you get it right and if you just get it right then i will i give you a full star rating and a thanks

Answers

Answer:

30x+15

Step-by-step explanation:

g Based on historical data, your manager believes that 32% of the company's orders come from first-time customers. A random sample of 146 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.43

Answers

Answer:

0.0022 = 0.22% probability that the sample proportion is greater than than 0.43

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Based on historical data, your manager believes that 32% of the company's orders come from first-time customers.

This means that [tex]p = 0.32[/tex]

Mean and standard deviation:

Sample of 146 means that [tex]n = 146[/tex]

[tex]\mu = p = 0.32[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.32*0.68}{146}} = 0.0386[/tex]

What is the probability that the sample proportion is greater than than 0.43?

This is 1 subtracted by the pvalue of Z when X = 0.43. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.43 - 0.32}{0.0386}[/tex]

[tex]Z = 2.85[/tex]

[tex]Z = 2.85[/tex] has a pvalue of 0.9978

1 - 0.9978 = 0.0022

0.0022 = 0.22% probability that the sample proportion is greater than than 0.43

if 4=p (p+5)=21 find p​

Answers

Answer:

p=16?

16+5=21?

Step-by-step explanation:

16+5=21

Can someone please help with this one I will report false/fake answers please someone.
I will also give brainiest.

Answers

Answer:

I belive it is 2.9716

Step-by-step explanation:

Pls helppppppp!!!!!!!!!!!

Answers

Answer:

part of it is cutted out show a better picture please ill answer it

Step-by-step explanation:

it’s cut out silly goose

In a toy box there are 3 toy cars, 2 dolls, and 5 balls. What is he probability of choosing a toy car

Answers

3/10 , 30% , 0.3 depends what they want the answer in but they all are the same just different answer forms .

Solve three fourths times two thirds. Leave answer as improper fraction

a. 5/12
b.6/12
c.5/7
d. 6/7

Answers

B is the correct answer



3/4 times 2/3 is 0.5

6/12 is 1/2, 1/2 is 0.5

Answer:

B) [tex]\frac{6}{12}[/tex]

Step-by-step explanation:

Note that you do not need to simplify. Simply multiply straight across:

[tex]\frac{3}{4} * \frac{2}{3} = \frac{3 * 2}{4 * 3} = \frac{6}{12}[/tex]

B) [tex]\frac{6}{12}[/tex] is your answer.

`

In ΔMNO, the measure of ∠O=90°, the measure of ∠M=46°, and NO = 96 feet. Find the length of OM to the nearest tenth of a foot.

Answers

Answer:

92.7 ft

Step-by-step explanation:

Help w number 6 pls!

Answers

Answer:

Y is 66 and x is 48

Step-by-step explanation:

So, if u put together x and y, it'll make 48 because

the arranged two numbers will go to 9.

So, that's it! :)

whats 56787577765445789990 times 3695669870

Answers

Answer:

2.0986814e+29

Step-by-step explanation:

Answer:

what

Step-by-step explanation:

punch your calculator to find out

even the calculator might not give u the exact value

all muntiple of 5 is an odd number true proposition?​

Answers

The correct answer is false.

Multiples 5 include: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, etc.

Bold numbers: even

Normal numbers: odd

What are the two solutions to 2x2−x−4=0 ? Use the quadratic equation

Answers

Answer in the photo below. Good luck.

5x -30 = 3x + 60
How many solutions are there

Answers

Answer:

one solution

Step-by-step explanation:

5x - 30 = 3x + 60

2x - 30 = 60

2x = 90

x = 45

A restaurant chef has designed a new set of dishes for his menu. His set of dishes contains 10 10 main courses, and he will select a subset of them to place on the menu each night. To ensure variety of main courses for his patrons, he wants to guarantee that a night's menu is neither completely contained in nor completely contains another night's menu. What is the largest number of menus he can plan using his 10 10 main courses subject to this requirement

Answers

Answer:

252 menu

Step-by-step explanation:

Total number courses, n = 10

The largest number of menu the chef can plan using his 10 main courses.

There are various combinations of menu obtainable from the available courses :

Ranging from :

nC0 to nCn

The largest number of menu he can plan is the highest output obtainable between :

10C0 to 10C10

10C0 = 1

10C1 = 10

10C2 = 45

10C3 = 120

10C4 = 210

10C5 = 252

10C6 = 210

10C7 = 120

10C8 = 45

10C9 = 10

10C10 = 1

Hence, the largest number of menu he can plan using his 10 main courses is 252

What is the probability of flipping a coin 85 times and getting tails 30 times or
fewer?
A. 99.8%
B. 33.2%
C. 95.9%
D. 0.4%

Answers

Answer:

C

Step-by-step explanation:

Answer:

0.4

Step-by-step explanation:

2. Karen sells newspaper subscriptions. She earns $12 for each daily subscription and $4 for each Sunday- only subscription. How much will she earn if she sells 24 daily and 13 Sunday-only subscriptions in a week?​

Answers

Your Answer;

❀♡ 12 x 24 + 4 x 13 = 340 ♡❀

Answer:

340

Step-by-step explanation:

Solve this inequality for x.



A.

B.

C.

D.

Answers

Answer:

D

Step-by-step explanation:

dd

Of the pets in the pet show, 10/12 are cats. 6/10 of the cats are calico cats. What fraction of the cats are calico cats?

Answers

Answer:

6/10, simplified 3/5

Step-by-step explanation:

kinda tricky, but the fraction is stated right out.

Answer:

3/5

Step-by-step explanation:

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