A jar has 2 pennies, 5 nickels, 3 dimes, and 2 quarters. What is the probability of drawing a penny,
replacing it, and drawing another penny?

Answer:90

Step-by-step explanation:

Answer:

Solution: y=2

Answer:

20 days

Step-by-step explanation:

Because to find the number of days that Sonia will have you have to divide total money ($40) by money each day ($2). And $40 divided by $2 is 20, so 20 days is the answer.

Have a most wonderfull day, and I hope you likeee the answer....so yep.

Answer:

66 pounds of tomatoes

Step-by-step explanation:

A recipe code lasagna calls for 3 pounds of tomatoes to serve 5 people. A caterer wants to make enough lasagna to serve 110 people. How many pounds of tomatoes does he neeed

From the above question:

5 people = 3 pounds of tomatoes

110 people = x pounds of tomatoes

Cross Multiply

5 people × x pounds = 110 people × 3 pounds

x pounds = 110 people × 3 pounds/5 people

x pounds = 66 pounds of tomatoes

Answer:

77 us dollar

Step-by-step explanation:

because I used a calculator

Answer:

77

Step-by-step explanation:

9514 1404 393

Answer:

  2. chord theorem; t = 10.5

  3. chord theorem; x = 5

Step-by-step explanation:

For both of these problems, the relevant theorem is the "intersecting chord theorem", also referred to as the "chord theorem." It tells you the product of the lengths of the parts of one chord is equal to the product of the lengths of the parts of the other chord.

2. 20t = 10·21

  t = 210/20 . . . . divide by 20

  t = 10.5 . . . . . . . simplify

__

3. 10(x +4) = 15(x +1)

  10x +40 = 15x +15 . . . . . eliminate parentheses

  25 = 5x . . . . . . . . . . . . . subtract 10x+15

  5 = x . . . . . . . divide by 5

Answer:

subtracting both equations

3x-10y=14

3x-9y=15

- - =-

_________

0-y=-1

y=1

then putting the value of y in first eqn

3x-10×1=14

3x=24

x=8

so x is 8and y is 1

Answer:no hablo espanol

Step-by-step explanation:

Answer:

If you are looking for the answer it is.... y=-12x+180

Step-by-step explanation:

Given:

The expression is

[tex]13\sqrt {22b}-10\sqrt{22b}, b>0[/tex]

To find:

The equivalent expression.

Solution:

We have,

[tex]13\sqrt {22b}-10\sqrt{22b}[/tex]

Taking out common factors.

[tex]=(13-10)\sqrt {22b}[/tex]

[tex]=(3)\sqrt {22b}[/tex]

[tex]=3\sqrt {22b}[/tex]

The expression [tex]3\sqrt {22b}[/tex] is equivalent to the given expression.

Therefore, the correct option is D.

Answer:

14

Step-by-step explanation:

40-26=14 so therefore 14% of the books are non-fiction

Answer:

AB = 8 and AD = 5

Ad=BC ( given in fig or as its is rectangle and sides of rectangle are equal )

so BC = 5

Answer:

33

Step-by-step explanation:

-5(-4)= 20

20+13=33

Answer:

The solution is (-6,2)

Step-by-step explanation:

Answer:

Fr

Step-by-step explanation:

Answer:

A. 0

B. 7

C. 3

D. 9

E.9

F.3

G.1

H.5

J.7

K.5

L.1

It's just a lot of reversing operations and seeing what fits, but if you have more you want to try, just make sure you remember borrowing and carrying numbers because they make a big difference.

Answer:

4 more students

Step-by-step explanation:

10% of 40 is 4, since the membership went up by 10% it is clear that there are 4 more students that joined the chess club.

Answer:

10/100*40

=4 more students joined the club

Step-by-step explanation:

Answer:

7)x=11

8)x=16

9)n=12

10)m=13

11)n=8

12)m=3

Step-by-step explanation:

Answer:

7= 11. 8=16. 9=12. 10=13 11=8. 12=3

Step-by-step explanation:

7= 9+2=11

8=12+4=16

9=9+3=12

10=8+5=14

11=7+1=8

12=3+0=3

Answer:

z (the arrow with teh line is pinting to the z) -4

Step-by-step explanation:

Answer:

[tex]\displaystyle \frac{d}{dx} \Big [ \frac{3}{x^2} \Big ]=-\frac{6}{x^3}[/tex]

Step-by-step explanation:

We can use either the Power Rule or the Quotient Rule to find the derivative of 3/x².

Rewrite [tex]\displaystyle \frac{3}{x^2}[/tex] as [tex]\displaystyle 3\cdot \frac{1}{x^2}[/tex] which is equivalent to [tex]3\cdot x^-^2[/tex].

Now we can apply the power rule to 3x⁻². Subtract 1 from the exponent and multiply the coefficient by -2.

This can be rewritten as [tex]\displaystyle -\frac{6}{x^3}[/tex].

Substituting 3 for f(x) and x² for g(x), we get:

Simplify.

Using exponent rules, we can rewrite this as:

This can be rewritten as [tex]\displaystyle -\frac{6}{x^3}[/tex], which is the same as what we got using the product rule.

Answer:

[tex]\displaystyle \frac{d}{d x}\left[\frac{3}{x^2}\right] = -\frac{6}{x^{3}}[/tex].

Step-by-step explanation:

Let [tex]f(x)[/tex] and [tex]g(x)[/tex] denote two functions of [tex]x[/tex]. Assume that [tex]g(x) \ne 0[/tex]. The quotient rule states that:

[tex]\displaystyle \frac{d}{d x}\left[\frac{f(x)}{g(x)}\right] = \frac{{f}^\prime(x) \cdot g(x) - f(x) \cdot g^{\prime}(x)}{{(g(x))}^2}[/tex].

In this question:

Find [tex]{f}^{\prime}(x)[/tex] and [tex]{g}^{\prime}(x)[/tex].

Notice that the value of [tex]f(x)[/tex] is constantly [tex]3[/tex] regardless of the value of [tex]x[/tex]. By the constant rule, [tex]{f}^{\prime}(x) = 0[/tex].

For [tex]{g}^{\prime}(x)[/tex], consider the power rule:

if [tex]m[/tex] represents a rational number (such as [tex]2[/tex],) then by the power rule, [tex]\displaystyle \frac{d}{d x}\left[{x}^{m}\right] = m\, {x}^{m-1}[/tex].

Apply this rule to find [tex]{g}^{\prime}(x)[/tex].

[tex]\begin{aligned}{g}^{\prime}(x) &= \frac{d}{d x} \left[x^{2}\right] \\ &= 2\, x^{2 - 1} \\ &= 2\, x\end{aligned}[/tex].

Substitute [tex]f(x) = 3[/tex], [tex]{f}^{\prime}(x) = 0[/tex], [tex]g(x) = x^{2}[/tex], and [tex]{g}^{\prime}(x) = 2\, x[/tex] into the quotient rule expression to find [tex]\displaystyle \frac{d}{d x}\left[\frac{3}{{x}^{2}}\right][/tex]:

[tex]\begin{aligned}&\; \frac{d}{d x}\left[\frac{3}{{x}^{2}}\right] \quad \genfrac{}{}{0em}{}{\leftarrow f(x) = 3}{\leftarrow g(x) = {x}^{2}} \\ =&\; \frac{d}{d x}\left[\frac{f(x)}{g(x)}\right]\\ =&\; \frac{{f}^\prime(x) \cdot g(x) - f(x) \cdot g^{\prime}(x)}{{(g(x))}^2} \\ =& \; \frac{0 \, x^2 - 3\, (2\, x)}{\left({x}^{2}\right)} \\ =&\; -\frac{6}{x^{3}}\end{aligned}[/tex].

Therefore, [tex]\displaystyle \frac{d}{d x}\left[\frac{3}{{x}^{2}}\right] = -\frac{6}{x^{3}}[/tex].

Answer:

B

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

It would be negative (-)62

Answer:

3.75

Step-by-step explanation:

Answer:

5/6 divided by 6 = 5/48 or 0.1041666666 repeating

Answer:

it is the first answer because it want you to roll 5 first try

Answer:

Option A

Step-by-step explanation:

x : y = 1 : 3

This can be also written as

[tex] \frac{x}{y} = \frac{1}{3} [/tex]

Multiplying y on both the sides

[tex] = > \frac{x}{y} \times y = \frac{1}{3} \times y[/tex]

[tex] = > x = \frac{1}{3} \times y[/tex]

Hence , x is one-third of y

Answer:

A and B

x is [tex]\frac{1}{3}[/tex] of y

AND

y is [tex]\frac{3}{4}[/tex] of (x+y)

Step-by-step explanation:

x:y is 1:3

=>  y is bigger than x

=>  y is 3x bigger than x

=>  y = 3 lots of x

=>  [tex]y =[/tex] [tex]3x[/tex]

=>  [tex]\frac{y}{3}[/tex] [tex]= x[/tex]

=>  [tex]\frac{1}{3} y[/tex] [tex]= x[/tex]

So x is [tex]\frac{1}{3}[/tex] of y

y is [tex]\frac{3}{4}[/tex] of (x+y)

If x = 1 and y = 3 (substitute in values)

=>  3 is [tex]\frac{3}{4}[/tex] of (4)

=>  3 is [tex]\frac{3}{4}[/tex](4)

=>  3 is ([tex]\frac{3}{4}[/tex]x4)

=>  3 = 3

Therefore, y is [tex]\frac{3}{4}[/tex] of (x+y) is true

So the answers are:

x is [tex]\frac{1}{3}[/tex] of y

AND

y is [tex]\frac{3}{4}[/tex] of (x+y)

Answer:

2

Explanation:

I'll explain later, it has to do with prime factors, and perfect cubes.

The two values of y that work are 18, and 144.

³√(144/18) = ³√(8) = 2 [whole number]

³√(144/144) = ³√(1) = 1 [whole number]

Answer:

[tex]-\frac{8}{x-a}[/tex]

Step-by-step explanation:

[tex]\frac{8}{a-x}[/tex]

we can take common factor of -1 in the denominator

[tex]\frac{8}{-(-a+x)}=\frac{8}{-(x-a)}[/tex]

and now multiply and divide by -1

[tex]\frac{8}{-(x-a)}\cdot \frac{-1}{-1}=\frac{-8}{x-a}=-\frac{8}{x-a}[/tex]