By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s
Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:
mass m = 0.170 kg
initial speed u = 6 m/s.
Distance covered s = 61 m
To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V
To do this, let us first calculate the kinetic energy at which the ball move.
K.E = 1/2m[tex]U^{2}[/tex]
K.E = 1/2 x 0.17 x [tex]6^{2}[/tex]
K.E = 3.06 J
The work done on the ball is equal to the kinetic energy. That is,
W = K.E
But work done = Force x distance
F x S = K.E
F x 61 = 3.06
F = 3.06/61
F = 0.05 N
From here, we can calculate the acceleration of the ball from Newton second law
F = ma
0.05 = 0.17a
a = 0.05/0.17
a = 0.3 m/[tex]s^{2}[/tex]
To calculate the final velocity, let us use third equation of motion.
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2as
[tex]V^{2}[/tex] = [tex]6^{2}[/tex] + 2 x 0.3 x 61
[tex]V^{2}[/tex] = 36 + 36
[tex]V^{2}[/tex] = 72
V = [tex]\sqrt{72}[/tex]
V = 8.485 m/s
Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.
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What event will produce the greatest increase in the gravitational force between the two masses?
Question 5 options:
Doubling the distance between the masses
Reducing the small mass by half
Doubling the large mass
Reducing the distance between the masses by half
Answer:
Doubling the large mass
Explanation:
By doubling the mass you will get more gravational force
45. 3. (III) A 7.26 kg bowling ball hangs from the end of a 2.5 m rope. The ball is pulled back until the rope makes an angle of 45 with the vertical. a. What is the increase in the ball’s potential energy when it is lifted? b. If the ball is released from rest and swings downward like a pendulum, how much kinetic energy will the ball have at the bottom of its swing? c. How fast will the ball be moving at the bottom of its swing?
Explanation:
For the first question look at the picture. It should be pretty clear. Remember that cos45° = sqrt2 / 2.
2) We calculate it thanks to the conservation of mechanical energy:
Em1 = Em2
U1 + K1 = U2 + K2
K1 = 0J
U2 = 0j
U1 = K2
3) mgh = 1/2mv^2
v = sqrt(2gh)
is atom on the offficial repository of ubuntu ?
Answer:
Atom, the cross-platform, open source code editor developed by Github, has become quite popular thanks to its plug-ins and embedded Git Control. ... There are, however, official Atom repositories for some Linux distributions, like Ubuntu, Debian, Fedora, Red Hat, CentOS, and open.
Can someone help me with this physics question? I don't know which answer is correct.
3. Distance is a quantity that is always a vector.
B.
a boulder sitting on a 45 m tall cliff has a potential energy of 7,100 J. the acceleration due to gravity is 9.8 m/s^2. what is the mass of the boulder
The mass of the boulder is equal to 16.10 kilograms.
Given the following data:
Height of cliff = 45 mPotential energy = 7,100 JoulesAcceleration due to gravity = 9.8 [tex]m/s^2[/tex]To determine the mass of the boulder:
Mathematically, potential energy (P.E) is calculated by using the following formula:
[tex]P.E = mgh[/tex]
Where:
m is the mass of object. g is the acceleration due to gravity. h is the height of an object.Making m the subject of formula, we have:
[tex]m = \frac{P.E}{gh}[/tex]
Substituting the given parameters into the formula, we have;
[tex]m=\frac{7100}{9.8 \times 45} \\\\m=\frac{7100}{441}[/tex]
Mass, m = 16.10 kg
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please help me with this
Answer:
>400N is needed to balance that lever
What is the half-life of an isotope if after 30 days you have 31.25 g remaining from a 250 g beginning sample size?
The half-life of the given isotope will be 10 days, if after 30 days only 31.25 grams are remaining from a sample of 250 grams of the sample size taken in the beginning.
What is Half-life of an element?
The Half-life is the time which is required for a quantity to reduce the content to half of the amount present as its initial value. The term is used in nuclear physics to describe how quickly an unstable atom undergo radioactive decay or how long does stable atoms survive. The term is also used generally to characterize any type of exponential decay.
The half-life of the isotope can be calculated by the formula:
FR = 0.5n
FR = Fraction Remaining = 31.25 g / 250.0 g = 0.1250
n = number of half lives elapsed = ?
0.125 = 0.5n
log 0.125 = n log 0.5
-0.9031 = -0.3010 n
n = 3.000 half lives have elapsed
3 half lives = 30 days
1 half live = 10 days
Therefore, the half-life of the isotope will be 10 days.
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A billiard ball with a speed of 5 m/s strikes another stationary billiard ball in a perfectly elastic collision.
After the collision, the first ball has a speed of 4.35 m/s and is traveling at an angle of 30° below its original line of motion.
Find the speed and angle of the second ball, with respect to the initial line of motion, after the collision.
Assuming both billiard balls have the same mass, conservation of momentum says
[tex]m\vec v_1 + m\vec v_2 = m{\vec v_1}\,' + m{\vec v_2}\,'[/tex]
where m = mass of both billiard balls, and v₁ and v₂ = their initial velocities, and v₁' and v₂' = their final velocities. The masses are the same so the exact value of m is irrelevant. The first ball has initial speed 5 m/s and the second is at rest, so
[tex]\left(5 \dfrac{\rm m}{\rm s}\right) \, \vec\imath = {\vec v_1}\,' + {\vec v_2}\,'[/tex]
After the collision, the first ball has speed 4.35 m/s and is moving at angle of 30° below the original path, so
[tex]{\vec v_1}\,' = \left(4.35\dfrac{\rm m}{\rm s}\right)\left(\cos(30^\circ) \, \vec\imath + \sin(30^\circ) \, \vec\jmath\right) \approx \left(3.77 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(-2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]
Then the second ball has final velocity vector
[tex]{\vec v_2}\,' \approx \left(1.23 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]
so it moves with speed
[tex]\left\|{\vec v_2}\,'\right\| \approx \sqrt{\left(1.23\dfrac{\rm m}{\rm s}\right)^2 + \left(2.18\dfrac{\rm m}{\rm s}\right)^2} \approx \boxed{2.50 \dfrac{\rm m}{\rm s}}[/tex]
at an angle of
[tex]\theta \approx \tan^{-1}\left(\dfrac{2.18}{1.23}\right) \approx \boxed{60.5^\circ}[/tex]
or about 60.5° above the original line of motion.
If the energy in a mechanical wave increases or decreases, what is also going to increase or decrease? A wavelength B amplitude с frequency d refraction
Answer:
i think wave lengh not 100% sure tho
If the energy of the mechanical wave will increase or decrease, then the wavelength will also change accordingly. Hence, option A is correct.
What is Wavelength?The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms, which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation.
Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.
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What is the net force on a car with a mass of 1000 kg if its
acceleration is 35 m/s^2?
Answer:
3000N
Explanation:
divided to get answer
the force needed to accelerate the 1000kg car by 3m/s2 is 3000N
Depth perception is also known as ___________ vision.
Answer:
depth from optical expansion
Explanation:
what role does gravity have in the motion of planets around the sun?
Answer:
The gravity helps the planets stay together near the Sun, without it Earth would be floating away with the planet eventually becoming frozen up, thus the role gravity have in the motion of planets around the sun is by keeping them together.
Explanation:
Hope this helps!
If a rock weighing 3.5 newtons is resting on cliff's ledge 12 meters from the canyon floor, what is its potential energy?
Group of answer choices
87 joules
4.5 joules
42 joules
142 joules
Answer:
42 Joules
Explanation:
Potential energy
= weight × height
= (3.5)(12)
= 42 joules
A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?
Have a great day!
Answer:
1176.798 J
Explanation:
[] Use the following equation:
U = mgh
m - mass
g - gravitational field
h - height
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
The slope of position-time graph represents
Answer:
The speed.
Explanation:
The slope of a line is that line's rate of change. If a car is travelling at 20 km/hr and we plot distance vs time graph, the slope of that line will be 20.
What ions are produced from acids and bases?
Answer:
Give person above me brainliest
Explanation:
One ball of mass 0.600kg travelling 9.00m/s to the right collides head on elastically with a second ball of mass 0.300kg travelling 8.00m/s to the left.what are their velocities after collisions?
Let m₁ and v₁ denote the mass and initial velocity of the first ball, and m₂ and v₂ the same quantities for the second ball. Momentum is conserved throughout the collision, so
m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'
where v₁' and v₂' are the balls' respective velocities after the collision.
Kinetic energy is also conserved, so
1/2 m₁ v₁² + 1/2 m₂ v₂² = 1/2 m₁ (v₁')² + 1/2 m₂ (v₂')²
or
m₁ v₁² + m₂ v₂² = m₁ (v₁')² + m₂ (v₂')²
From the momentum equation, we have
(0.600 kg) (9.00 m/s) + (0.300 kg) (-8.00 m/s) = (0.600 kg) v₁' + (0.300 kg) v₂'
which simplifies to
10.0 m/s = 2 v₁' + v₂'
so that
v₂' = 10.0 m/s - 2 v₁'
From the energy equation, we have
(0.600 kg) (9.00 m/s)² + (0.300 kg) (-8.00 m/s)² = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²
which simplifies to
67.8 J = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²
or
226 m²/s² = 2 (v₁')² + (v₂')²
Substituting v₂' yields
226 m²/s² = 2 (v₁')² + (10.0 m/s - 2 v₁')²
which simplifies to
3 (v₁')² - (20.0 m/s) v₁' - 63.0 m²/s² = 0
Solving for v₁' using the quadratic formula gives two solutions,
v₁' ≈ -2.33 m/s or v₁' = 9.00 m/s
but the second solution corresponds to the initial conditions, so we omit that one.
Then the second ball has velocity
v₂' = 10.0 m/s - 2 (-2.33 m/s)
v₂' ≈ 14.7 m/s
60W of power is taken by a small electrical heater from a 12V supply Determine the current flowing through the heater
Answer:
5 amps
Explanation:
I = P/V
I = current (amps)
P = power (watts)
V = voltage (volts)
I = 60/12
I = 5
what is a joule in physics?
Explanation:
Joule is unit of work or energy in the International System of Units (SI)
[tex] \large \mathfrak {Formula}[/tex]
work (joules) = force (newtons) x distance (meters)
[tex] \large\mathfrak{Invented \: by} [/tex]
James Prescott Joule
29) A cheetah can accelerate from rest to 25
m/s in 6 s. Assuming that the cheetah moves
with constant acceleration, what distance does
it cover in the first 3 s
Answer:
[tex]\huge\boxed{\sf S = 18.75 \ meters}[/tex]
Explanation:
Given Data:
Initial Velocity = Vi = 0 m/s (rest)
Final Velocity for 6 seconds = Vf = 25 m/s
Time (1) = T1 = 6 seconds
Time (2) = T2 = 3 seconds
Required:
Distance for 3 seconds = S = ?
Solution:
For 6 seconds, the acceleration will be:
[tex]\displaystyle a = \frac{Vf-Vi}{t} \\\\a = \frac{25 - 0}{6} \\\\a = 25 / 6\\\\\boxed{a = 4.167 \ m/s^2}[/tex]
Since, acceleration is constant, it will be the same at 3 seconds as well.
Using second equation of motion to find Distance (S) with time being 3 seconds:
[tex]\displaystyle S= Vit+\frac{1}{2} at^2\\\\S = (0)(3)+ \frac{1}{2} (4.167)(3)^2\\\\S = \frac{1}{2} (4.167)(9)\\\\S = \frac{37.5}{2} \\\\\boxed{S = 18.75 \ meters}\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Which electromagnetic wave has a lowest frequency?
Group of answer choices
A) x-rays
B) ultraviolet light
C) microwaves
D) infrared light
E) visible light
Answer:
E.visible lights
Explanation:
llll
hope its attachments
A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is no net force on the system, what is the velocity of the pitcher? â’0. 1 m/s â’0. 2 m/s â’0. 7 m/s â’1. 4 m/s.
The velocity of the pitcher at the given mass is 0.1 m/s.
The given parameters:
Mass of the pitcher, m₁ = 50 kgMass of the baseball, m₂ = 0.15 kgVelocity of the ball, u₂ = 35 m/sLet the velocity of the pitcher = u₁
Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;
m₁u₁ = m₂u₂
[tex]u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s[/tex]
Thus, the velocity of the pitcher at the given mass is 0.1 m/s.
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A geothermal plant has been built in a location. Which of these is the most likely benefit of the geothermal plant in this location?
A. Decrease in geothermal fuels consumption
B. Improvement to hot springs and geysers
C. Long-term cost savings for energy users
D. Increase in emission of greenhouse gases
Answer:
C
Explanation:
A and B are not true and D is a disadvantage
Answer:
C. Long-term cost savings for energy users.
Explanation:
C is correct because the first option is a drawback that is unlikely. B is a good answer but not the best. It's a likely benefit, but C is a more likely benefit. D is a drawback. C is correct. I also got this right on my quiz.
Hope this helps!
find u + (3v - w)
u =-4i-8j
v= -11i -3j
w=5i+7j
Answer:
gunrun
Explanation:
3. A(n)______ is someone who travels to new places or does new things. A. explorer B. thrill C. expedition D. research
Answer:
explorer
Explanation:
Answer:
a) EXPLORER
Explanation:
An explorer is someone who travels to new places or does new things.
ignoring air resistance, an object falling toward the surface of the earth has a velocity that is
If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50 km/h?
Answer:
This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h
24.29m/s or 87.4km/h
Explanation:
Let's find the acceleration of the car:
let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s
a = (vf-vi)/Δt
a = (16.67m/s-0)/8.0
a = 2.08m/s^2
Now we can use this acceleration to find vf in the second part:
50km/h is 13.89m/s
a = (vf-vi)Δt
vf = aΔt + vi
vf = 2.08m/s^2*5.0+13.89m/s
vf = 24.29m/s (87.4km/h)
What happens to the gravity force if the mass of the planet is increased?
Answer:
The more mass an object has, the greater its gravitational field and gravity force will be.
Explanation:
gravity force = mass × gravitational field strength (g)
The more mass, the more g-force.
what led scientists to the discovery of the strong nuclear force?
Answer:
Explanation:
The concept of a new strong nuclear force was introduced. In 1935, the first theory for this new force was developed by the Japanese physicist Hideki Yukawa, who suggested that the nucleons would exchange particles between each other and this mechanism would create the force.
What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg • m/s 4. 2 kg • m/s 6. 0 kg • m/s 6. 2 kg • m/s.
Answer:
6 kg.m/s
Explanation:
Momentum is the product of mass and velocity. So,
p = mvHere,
p denotes momentum [?]m denotes mass [5kg]v denotes velocity [1.2 m/s]→ p = 5 kg × 1.2 m/s
→ p = (5 × 1.2) kg.m/s
→ p = (5 × 12/10) kg.m/s
→ p = 12/2 kg.m/s
→ p = 6 kg.m/s
Therefore, momentum of the object is 6 kg.m/s.
The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
MOMENTUM:Momentum of a substance is the product of its mass and velocity. That is;
Momentum (p) = mass (m) × velocity (v)
According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:
Momentum = 5kg × 1.2m/s
Momentum = 6kgm/s.
Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
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