A different bullet has a mass of 0.09 kg. Starting from rest, after its gun's trigger is pulled, a constant force acts on the bullet for the next 0.025 seconds until the bullet leaves the barrel of the gun with a speed of 1,346 m/s.

What force acts on this bullet?

Time required : 25.876 s

Given

A car weight = 25000 N

Brake force = 628 N

vo= 6.5 m/s

vt = 0(stop)

Required

time to stop

Solution

W = m . g

25000 = m.10

m=2500 kg

Newton's second law

F = m . a

628 = 2500 . a

[tex]\tt a=\dfrac{628}{2500}=0.2512~m/s^2[/tex]

vt=vo-at(deceleration a=-)

0=6.5-0.2512.t

0.2512.t=6.5

t=25.876 s

Answer:

100kgms⁻¹

Explanation:

Given parameters:

Mass of the sled  = 20kg

Velocity of the sled  = 5m/s

Unknown:

Momentum of the sled = ?

Solution:

The momentum of a body is the quantity of motion such a body possesses. Due to this;

    Momentum  = mass x velocity

Now insert the parameters and solve;

      Momentum  = 20 x 5  = 100kgms⁻¹

Answer:

F=84.0 Hz

Explanation:

Using the equation f= n (v/2L),  frequency equals number of loops times velocity over 2 times the length, in order to get 60.0 Hz of frequency from 5 loops, v/2L would have to equal 12. (12*5=60) v/2L is constant, so to find the frequency of 7 loops you would times 7 by 12 to get 84.0.

Hope this helped! :)

Answer:

Explanation:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects

so a option is correct

Answer:

The answer would be 11.6 g/m^3

Explanation:

Knowing that vapor's density at 100% humidity is 20g/m^3 we can calculate the answer using the following math:

0.58 * 20 = 11.6 grams per cubic meter

the units can also be written as g/m^3

The density of water vapor is 11.6 grams/cubic meter.

The quantity of atmospheric moisture that is present compared to the amount that would be there if the air were saturated is known as relative humidity, and it is stated as a percentage. Relative humidity depends on both moisture content and temperature because the latter quantity is temperature-dependent. The related temperature and dew point for the specified hour are used to calculate relative humidity. it is expresses as %.

Now given that the maximum water vapor in air at this temperature is 20 grams/cubic meter at 22°C, that is, density of vapor at 100% humidity is 20g/[tex]m^3[/tex]  at 22°C.

And, The device showing that at 22 degrees Celsius the relative humidity is 58%

So, water vapor density at that moment is = 20g/[tex]m^3[/tex] × 58%

= 11.6 g/[tex]m^3[/tex] .

= 11.6 grams/cubic meter.

Hence, according to the measurement of device, the water vapor density is 11.6 grams/cubic meter.

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Answer:

=101343.62N/m^2

Explanation:

absolute pressure on the bottom of a swimming pool= atmospheric pressure +( 2 ×ρ ×g)

( 2 ×ρ ×g)= guage pressure

atmospheric pressure= 101325pa

h= height= 1.9 mm = 1.9×10^-3m

ρ = density of water

= 1000kg/m^3

g= acceleration due to gravity= 9.8m/s^2

Then substitute, we have

absolute pressure on the bottom of a swimming pool= 101325+ [0.0019 ×1000 × 9.8)]

=101343.62N/m^2

Hence, the absolute pressure on the bottom of a swimming pool is =101343.62N/m^2

Answer: B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.

Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.

As the Heat of vaporization for methyl alcohol  (1100) is almost half as that of Heat of vaporization for water (2257) , it means  Methyl alcohol requires less than half as much energy per kg to evaporate than water does.

Answer:

Explanation:

Step one:

Given data

work-done in dragging the trash= 236J

applied force= 18.9N

distance moved= 24.4m

Required

The angle of the applied force

Step two:

We know that work done is

WD= F * distance

The work is the product of the horizontal component of the force and the distance.

Horizontal force = 236 ÷ 24.4

= 9.67 N

Cos θ = Horizontal force ÷ Actual force

Cos θ = (236 ÷ 24.4) ÷ 18.9 = 236 ÷ 461.16

The angle is approximately 59˚

Answer:True

Explanation:

Answer:

I am going to say true not too sure

Answer:

centripital acceleration= v^2/r

r = v^2/a

r=31.8×31.8/29

r=34.8703m

Explanation:

the maximum acceleration is obtained with minimum radius.

The efficiency of the leaf blow is 48%.

         Here, E = Energy transferred

                   m = Mass

                   Ф = Temperature change

            Here, E = Energy transferred

                      P = Power

                      t = time

        Here, v = speed

                   f = frequency

                  ∧ = wavelength

       Efficiency =  (Useful power out / Total power in ) = 360/750 = 0.48

So, the efficiency of the leaf blower is 48%.

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Answer:

3743.489 kg

Explanation:

F_g = 591 N

G = 6.674x10^-11 constant of gravity

m_1 = 95 kg

m_2 = unknown

r = 4990*1000 =

F_g = G[(m_1*m_2)/r^2]

591 N = 6.674x10^-11[(95*m_2)/4990^2]

8.855 = [(95*m_2)/4990^2]

355631.472 = 95*m_2

m_2 = 3743.489 kg

The  mass of the planet, which has a radius of 4990 km, is  1.81×10²³kg.

Newton's law of universal gravitation states that

The force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

Given parameters:

Mass of the object: m = 95 kg

Radius of the planet: r = 4990 km = 4990 × 1000 m.

Weight f the object: F= 591 N

We know that: universal gravitational constant: G = 6.674x10^-11 SI unit.

We have to find: mass of the planet: M = ?

Now, F= GMm/r^2

591 N = 6.674x10^-11[(95×M)/(4990×1000)^2]

⇒ M =1.81×10²³kg

Hence, mass of the planet is  1.81×10²³kg.

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The change in momentum of the bullet : 59.52 kg m/s

Given

m=0.06 kg

Δt=0.025 s

vo=0(from rest)

vt= 992 m/s

Required

The change in momentum

Solution

The change in momentum  = ΔP

ΔP  =m(vt-vo)

ΔP =0.06(992-0)

ΔP =59.52 kg m/s

Answer:

Electric field will be greater when the battery is connected by the factor of 2.

Explanation:

Solution:

I will be doing some algebraic calculations to answer this question:

As we know that,

Q = CV

and

C = [tex]\frac{AE_{0} }{d}[/tex]

So, when separation = d/2, then,

[tex]C^{'}[/tex] = [tex]\frac{AE_{0} }{d/2}[/tex] by rearranging we get

So,

[tex]C^{'}[/tex]  = 2C

We further know that, Voltage will remain same if the battery is  connected.

This further implies that,

Q = CV

So,

[tex]Q^{'}[/tex] = [tex]C^{'}[/tex]V

[tex]Q^{'}[/tex]  = 2CV

[tex]Q^{'}[/tex] = 2Q

and we also know that,

Electric field E = [tex]\frac{Q}{AE_{0} }[/tex]

So, the new E or [tex]E^{'}[/tex] = [tex]\frac{Q^{'} }{AE_{0} }[/tex]

Hence,

[tex]E^{'}[/tex] = [tex]\frac{2Q}{AE_{0} }[/tex] = 2E

[tex]E^{'}[/tex] = 2E

when battery is disconnected, Q remain the same.

So,

When disconnected

E = E

E = [tex]\frac{Q}{AE_{0} }[/tex]  = Same

Hence, we can see that the magnitude of the electric does not depend upon the distance of separation. Instead it does depend upon the magnitude of charge.

So, when battery is disconnected, Q is same, so the Electric field.

But when it is connected, [tex]Q^{'}[/tex] = 2Q and the [tex]E^{'}[/tex] = 2E

So,

[tex]\frac{E connected}{E disconnected} = \frac{E^{'} }{E}[/tex] = [tex]\frac{2E}{E}[/tex] = 2

Electric field will be greater when the battery is connected by the factor of 2.

Answer and Explanation:

The computation is shown below:

As we know that

Frequency = Speed ÷ wavelength

= (3 × 10^8 )÷ (632.8 × 10^-9)

= 4.74 × 10^14 Hz

Speed in flourite is

= Vaccum speed ÷ refraction index

= 3 × 10^8 ÷ 1.434

= 2.092 × 10^8 m/s

wavelength is

= Speed in flourite ÷ frequency

= (3 × 10^8 × 632.8 × 10^-9) ÷ (1.434 × 3 × 10^8)

= 441.28nm

Answer:

both

Explanation:

Answer:

I actually have 20000 arena points thank you very much

Answer: Caca means in French lol.

Answer:

electrical

Explanation:

the TV needs electrical energy to power on

Answer:

electrical energy powers your TV, computer, microwave and toaster.

Answer:

true

Explanation:

I believe the answer i chose because the earths atmosphere is mostly made up of different things that causes the earth to interact with human life and also interacts with what's in the atmosphere like energy oxygen carbon dioxide and all the stuff like that i hope its right.

Answer:

There are many kinds of waves all around us. There are waves in the ocean and in lakes. Did you also know that there are also waves in the air? Sound travels through the air in waves and light is made up of waves of electromagnetic energy.

The wavelength of a wave describes how long the wave is. The distance from the "crest" (top) of one wave to the crest of the next wave is the wavelength. Alternately, we can measure from the "trough" (bottom) of one wave to the trough of the next wave and get the same value for the wavelength.

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength.

Light waves have very, very short wavelengths. Red light waves have wavelengths around 700 nanometers (nm), while blue and purple light have even shorter waves with wavelengths around 400 or 500 nm. Some radio waves, another type of electromagnetic radiation, have much longer waves than light, with wavelengths ranging from millimeters to kilometers.

Sound waves traveling through air have wavelengths from millimeters to meters. Low-pitch bass notes that humans can barely hear have huge wavelengths around 17 meters and frequencies around 20 hertz (Hz). Extremely high-pitched sounds that are on the other edge of the range that humans can hear have smaller wavelengths around 17 mm and frequencies around 20 kHz (kilohertz, or thousands of Hertz).

Explanation:

Explanation:

Hope This Helped U

Brqinliest

Answer:

False

Explanation:

A contact force is any force that requires contact to occur. Contact forces are ubiquitous and are responsible for most visible interactions between macroscopic collections of matter. Pushing a car up a hill or kicking a ball across a room are some of the everyday examples where contact forces are at work. 

Answer:

false

Explanation:

Answer:

7. d. England during the Age of Enlightenment

8. a. State governments do not usually act together

Explanation:

The Age of Enlightenment occurred in the 18th century and at this time England was a Constitutional monarchy with a monarch and parliament ruling the country with different powers.

The third and fourth methods of amending the Constitution will be much harder to use because state governments simply do not usually act together as they most times have ideological differences. The sheer number of states it would take to unite for these methods to be used makes this impractical.

Answer:

VAB = 20km/hr

Explanation:

Given the following data;

Velocity of car A, VA = 60km/hr

Velocity of car B, VB = 80km/hr

To find the relative velocity of B w.r.t A, VAB;

Since the two cars are moving in the same direction, we have;

VAB = VB - VA

Substituting into the equation, we have;

VAB = 80 - 60

VAB = 20km/hr

Therefore, the relative velocity of car B with respect to car A is 20 kilometers per hour.

Answer:-The formula of to calculate  KE = 1/2 m v^2

so we,

           KE = 1/2 (450kg)(23m/s)^2

           KE = 1/2 ×238050

            KE = 119025

Explanation: In Physics Formulas mean everything.

Answer: The level of CO2 has risen.

Explanation:

From the table shown, we can see that the quantity of CO₂ in the atmosphere has steadily risen since the year 1960 going from 317 CO₂PPM in that year to 390 CO₂PPM in 2010.

This is a cause for alarm because with so much carbon dioxide in the atmosphere, there will be an even greater greenhouse effect that will contribute to global warming.

Answer:

[tex]D= -0.42km[/tex]

Explanation:

From the question we are told that

Drifting right with speed 5.0m/s

The motor runs for 6.0 seconds

Leftward acceleration of magnitude 4.0 m/s squared

Generally the equation [tex]V=ut+1/2at^2[/tex] can be used here

[tex]V=ut+1/2at^2[/tex]

Mathematically solving with the newton equation above we have that

   [tex]D=5*6 + \frac{1}{2} (-4)*6^2[/tex]

   [tex]D=30-72[/tex]

   [tex]D=-42m[/tex] [tex]or -0.42km[/tex]

Therefore having this the Displacement is [tex]D= -0.42km[/tex] leftward