Answer:
3743.489 kg
Explanation:
F_g = 591 N
G = 6.674x10^-11 constant of gravity
m_1 = 95 kg
m_2 = unknown
r = 4990*1000 =
F_g = G[(m_1*m_2)/r^2]
591 N = 6.674x10^-11[(95*m_2)/4990^2]
8.855 = [(95*m_2)/4990^2]
355631.472 = 95*m_2
m_2 = 3743.489 kg
The mass of the planet, which has a radius of 4990 km, is 1.81×10²³kg.
What is Newton's law of universal gravitation ?Newton's law of universal gravitation states that
The force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.
Given parameters:
Mass of the object: m = 95 kg
Radius of the planet: r = 4990 km = 4990 × 1000 m.
Weight f the object: F= 591 N
We know that: universal gravitational constant: G = 6.674x10^-11 SI unit.
We have to find: mass of the planet: M = ?
Now, F= GMm/r^2
591 N = 6.674x10^-11[(95×M)/(4990×1000)^2]
⇒ M =1.81×10²³kg
Hence, mass of the planet is 1.81×10²³kg.
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A local FM radio station broadcasts at a frequency of 97.3 MHz. Calculate the energy of the frequency at which they are broadcasting. Energy
Answer:
6.45×10¯²⁶ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 97.3 MHz
Energy (E) =?
Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:
1 MHz = 1×10⁶ Hz
Therefore,
97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz
97.3 MHz = 9.73×10⁷ Hz
Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.
Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:
Frequency (f) = 9.73×10⁷ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 9.73×10⁷
E = 6.45×10¯²⁶ J
Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J
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Estimate the weight of a 1000-kg car that is accelerating at 3m/s/s.
(Use g=10m/s/s)
Answer:
10000N
Explanation:
Given parameters:
Mass of the car = 1000kg
Acceleration = 3m/s²
g = 10m/s²
Unknown:
Weight of the car = ?
Solution:
To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.
Weight = mass x acceleration due to gravity
So;
Weight = 1000 x 10 = 10000N
During the study of the objects,What we can observe
A 2kg object is tied to the end of a cord and whirled in a horizontal circle of radius 2 m. If the body makes three complete revolutions every second,
what is its linear speed?
And what is its centripetal acceleration?
Answer:
a) 37.70 m/s
b)710.6 m/s²
Explanation:
Given that ;
Mass of object = 2 kg
Radius of the motion = 2m
Frequency of motion = 3 rev/s
The formula to apply is;
v= 2πrf where v is linear speed
v = 2×π×2×3 =12π = 37.70 m/s
Centripetal acceleration is given as;
a= 4×π²×r×f²
a= 4×π²×2×3²
a=710.6 m/s²
Which type of telescope is best used to detect distant planets?
Are the coils in an electric heater blackbody radiators? Why?
A. No, because they do not emit different wavelengths of light
B. Yes, because they glow more brightly as they increase in
temperature
O C. No, because they absorb no energy and emit no light
D. Yes, because they reflect most of the energy they receive
Answer:
B. Yes, because they glow more brightly as they increase in
temperature
Explanation:
Did the test !!
The coils in an electric heater blackbody are not radiators. Because, they absorb no energy and emit no light. Thus, the correct option is C.
What is an electric heater?Electric heating is a process in which the electrical energy is converted directly into the heat energy at around about 100% efficiency, using rather the cheap devices. Common applications which are included are space heating, cooking, water heating and industrial processes.
A radiator is the key component of the engine's cooling system. Radiator has the main role to disperse a mix of antifreeze and water molecules throughout the fins, which releases some of the engine's heat energy while taking in the cool air before continuing to pass the rest of the electric engine.
Therefore, the correct option is C.
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Calculate the density of water in kg/m3. Express your answer in kilograms per cubic meter using three significant figures.
Answer:
This question appear incomplete
Explanation:
This question appear incomplete. However, the density of water is generally known to be 997 kg/m³. The formula used to determine density is mass ÷ volume. In the case of the density of water, the mass is measured in kilograms (kg) while the volume is measured in cubic meter (m³).
Using a pulley, you apply a force of 10 Newtons to life an object that weighs 100 Newtons. What is the mechanical advantage of that pulley?
Answer: 10
Explanation:
The mechanical advantage of that pulley is 10.
What is mechanical advantage?The force amplified by utilizing a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the gadget trades off input forces against movement. The law of the lever serves as a paradigm for this.
Mechanisms are machine parts made to control forces and motion in this way.
Given that: the weighs of the object: W = 100 Newton.
Applied force: F = 10 N.
For using a pulley, you have to apply a force of 10 Newtons to lift an object that weighs 100 Newtons.
Hence, the mechanical advantage of the pulley is
= Weighs of the object/applied force
= 100 Newton / 10 Newton.
= 10.
The mechanical advantage of it is 10.
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Show how multiplying both sides of the acceleration equation a equals F net over in Byam results in the net force equation F net equals MA
In order to find the formula for net force, multiply both sides by mass.
What is Newton's Second law of motion?Newton's second law of motion states that the rate of change of momentum is directly proportional to the force applied.
Given is the acceleration as the ratio of net force and mass.
We can write acceleration as -
a = F[net]/m
If we have to find the formula for net force, we will multiply both sides by mass (m). Therefore -
a x m = (F[net]/m) x m
am = F[net]
or
F[net] = ma
Therefore, in order to find the formula for net force, multiply both sides by mass.
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Use the graph and the table above to complete the table by estimating the amount of energy transferred near location B.
A.
1600 kilojoules
B.
300 kilojoules
C.
800 kilojoules
D.
400 kilojoules
E.
3200 kilojoules
Answer:
A. 1600 kilojoules
Explanation:
Looking at the graph, at 4 meters, we can guess the energy transferred would be around 1500 kilojoules. 1600 kilojoules is the closest to that value, so A would be the best choice.
A2 kg object moves at a constant 5 m/s across a level surface. Determine its kinetic energy.
Answer right I will cashapp $5
Someone made a copy of an analog wave and a digital wave. Compare the copies
with the original waves. Then, explain which type of wave is a more reliable way to
encode and transmit information.
Answer:
The original analog sound waves are perfect but the copy is not because most analog waves have wavelengths that are too long to reproduce in copies
The original digital waves and the copy are perfect because with digital waves no information gets lost in the transfer of data, and there is no additional noise added to the copy.
Analog refers to audio recorded using methods that replicate the original sound waves. Digital audio is recorded by taking samples of the original sound wave at a specified rate.
Explanation:
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i wrote this using information from go ogle and some from brai nly. I hope it helps.
Two inductors are connected in parallel to a 120 volt, 60 Hz line. The values are 5 H and 2 H. The total inductive reactance is
Answer:Total Inductive reactance XL =538.63 Ω
Explanation:
Parallel combination for Effective inductance is calculated as
L total = [tex]\frac{1}{1/L1 + 1/L2 + ... 1/Ln}[/tex]
=[tex]\frac{1}{1/5 + 1/2}[/tex]
[tex]\frac{1}{0.2 + 0.5 \\}[/tex]
=[tex]\frac{1}{0.7}[/tex]
=1.42857H
Inductive reactance XL = 2 πFL
where f= frequency= 60Hz
L= Effective inductance=1.42857H
Inductive reactance , XL = 2 X 3.142 X 60 X 1.42857
=538.63Ω
what medical uses does radiation have?
Answer:
Radiation is used in monitoring the response of tumors to treatment and in distinguishing malignant tumors from benign ones. Bone and liver scans can detect cancers that have spread to these organs. Half of all people with cancer are treated with radiation, and the number of those who have been cured continues to rise.
Explanation:
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The football team is selling mulch as a fundraiser. Which two options are
advantages of putting the order form online?
A. This information is transmitted using analog signals, so more
information can be sent.
B. This information is transmitted digitally, making it more reliable.
C. Any noise affecting the analog signal can be easily interpreted
correctly.
O D. Noise does not affect the digital signal, making it more reliable.
Answer:
Noise does not affect the digital signal, making it more reliable. This information is transmitted digitally, making it more reliable
Explanation:
Just did it on Ape.x
This information is transmitted digitally, making it more reliable. Noise does not affect the digital signal, making it more reliable. The correct options are B and D.
What is digital transmission?The transfer and reception of data in the form of a digital bitstream or a digitized analogue signal transmitted through a point-to-point or point-to-multipoint communication channel is known as data transmission and reception, or, more broadly, data communication or digital communications.
Because digital switching systems are substantially less expensive than analogue switching systems, digital transmission is used to achieve high reliability.
However, the analogue signals that make up the majority of speech, radio, and television must be used for digital transmission.
This information is more dependable because it is conveyed digitally. The digital signal is unaffected by noise, increasing its dependability.
Thus, B and D are the correct options.
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If a 1000kg car is accelerating at 3m/s/s for 4 seconds how far will it travel
A concave lens can be used to produce an enlarged and erect image. True or False?
Answer:
False
Explanation:
A single concave lens has the opposite effect of a magnifying glass.
Marvin the Martian needs to get back home. Marvin is 321,770 m from his home on Mars. He decides the quickest way to get home is to use his canon to fire himself into flight. He aims the the canon at an angle of 25 degrees. When the canon is fired Marvin the Martian is launched into flight at an initial velocity of 1250 m/s. The question is will his plan work
Answer:
y = 14238 m. the height of the rocket is much less than this distance therefore the plan will not work.
Explanation:
Let's analyze this exercise, so that the Martian's plan works, the vertical height of the body must be zero when it is more than half of the way to the planet Mars, this is so that Mars attracts it and can arrive.
Let's calculate the maximum height of the launch
[tex]v_{y} ^2 = v_{oy}^2 - 2 g y[/tex]
at the highest point [tex]v_{y}[/tex] = 0
y = v_{oy}² / 2g
y = (v₀ sin θ)² / 2g
let's calculate
y = (1250 sin 25)² /2 9.8
y = 14238 m
In the exercise, indicate that the distance to Mars is h = 321770 m, half of this distance is
h / 2 = 160885 m
therefore the height of the rocket is much less than this distance therefore the plan will not work.
The height reached is low, so it is not necessary to take into account the variation of g with height
How much power is generated if a person applies 220 N of force to move a bicycle 5 min 10 s?
Complete question :
How much power is generated if a person applies 220 N of force to move a bicycle 5m in 10 s?
Answer:
Explanation:
Given that :
Force = 220N
Time = 10 seconds
Distance = 5 m
Power = Workdone / time
A Nov-Dec power bill shows that a home uses 1355 kwh over a 30-day period. Find the energy used (in kJ) for the 30-day period.
Answer:
The energy used for the 30-day period is 4878000 kilojoules.
Explanation:
According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:
[tex]E = 1355\,kWh\times \frac{3600\,kJ}{1\,kWh}[/tex]
[tex]E = 4878000\,kJ[/tex]
The energy used for the 30-day period is 4878000 kilojoules.
A 3.8kw elective motor powers an inclined conveyer belt. It is designed to lift heavy boxes from the warehouse floor to loading bay. Answer the following:
a)State the energy conversion performed by the motor
b) Calculate the work done by the motor in 14 s
c) If the conveyer belt takes 14 to lift its load vertically by 5.3m, calculate the maximum mass that can carried by the conveyer belt maximum mass that can be carried by the conveyer belt
d) If a small box were to fall off the conveyer belt and hit the floor, calculate the speed at which it would hit the ground if falls from a vertical height of 4.7m
Answer:
See the answer below
Explanation:
To solve this problem we must use the definition of power and work in physics.
a)
The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.
Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.
b)
Power is defined as the relationship of work over time. Therefore we have:
[tex]P=W/t[/tex]
where:
P = power = 3.8 [kW] = 3800 [W]
W = work [J]
t = time = 14 [s]
[tex]W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ][/tex]
c)
Since the given time is equal to the given time at Point b, we can use the same work calculated.
We know that work is defined as the product of force by the distance traveled.
[tex]W =F*d[/tex]
So, the force is equal to:
[tex]F=W/d\\F=53200/5.3\\F=10037.73[N][/tex]
Now we know that force is defined as the product of mass by gravitation acceleration.
[tex]F =m*g[/tex]
where:
F = force or weight = 10037.73 [N]
g = gravity acceleration = 9.81 [m/s²]
m = mass [kg]
[tex]m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg][/tex]
d)
This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.
[tex]E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}[/tex]
where:
h = elevation = 4.7 [m]
v = velocity [m/s]
[tex]m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} } \\v = 9.6 [m/s][/tex]
A car stopped at a red light, begins to accelerate with a constant acceleration of 7.4 m/s^2 during a
time of 2.4 seconds. If the speed limit of the road is 35 mph (about 15.64 m/s), is the car
considered to be speeding at any point?
Answer:
The car is considered to be speeding
Explanation:
The following data were obtained from the question:
Constant acceleration (a) = 7.4 m/s²
Time (t) = 2.4 s
Speed limit = 15.64 m/s
To know if the car speeding at any point, we shall determine the velocity of the car.
This can be obtained as follow:
Constant acceleration (a) = 7.4 m/s²
Time (t) = 2.4 s
Constant velocity (v) =?
a = v/t
7.4 = v / 2.4
Cross multiply
v = 7.4 × 2.4
v = 17.76 m/s
Thus, the velocity of the car is 17.76 m/s.
Comparing the velocity of the car (i.e 17.76 m/s) with the speed limit (i.e 15.64 m/s), we can see that the velocity of the car is higher than the speed limit. Therefore, the car is considered to be speeding.
How will a metal container full of hot water in vaccum lose heat?
Identify one major challenge of conducting developmental research and provide an example of how a researcher can overcome it.
Answer: pointing back
Explanation:
A football player kicks a ball with a mass of 0.5 kg. The average acceleration of the football was 15 m/s/s. How much force did the kicker apply to the football?
Answer:
i think its 8.2
Explanation:
what is the electrical potential at the surface of gold nucleus? The radius of a gold atom is 6.6*10
Complete question is;
What is the electrical potential at the surface of gold nucleus? The radius of a gold atom is 6.6 × 10^(-5) m and atomic number z = 79.
Answer:
172.36 × 10^(-5) V
Explanation:
We are given;
Radius; r = 6.6 × 10^(-5) m
Atomic number; Z = 79
Formula for Electric potential here is;
V = kZe/r
Where;
e is charge on proton = 1.6 × 10^(-19) C
k has a constant value of 9 × 10^(9) N⋅m²/C²,
Thus;
V = (79 × 1.6 × 10^(-19) × 9 × 10^(9))/(6.6 × 10^(-5))
V = 172.36 × 10^(-5) V
Anthony is standing on the top of a building 10 m high holding a 7 kg
bowling ball. Mildred dug a 2-m-deep hole next to the base of the
building. What is the gravitational potential energy of the bowling ball
relative to the bottom of the hole?
I reallly need help!!
Answer:
548.8 J
Explanation:
How fast is a 30 kg child runnning if her kinetic energy is 500 J?
[tex]\displaystyle v = 5.7735 \ m/s[/tex]
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Physics
SI Units
Speed is m/s (meters per second)Energy is J (Joules), equal to 1 N/m (newton per meter)Mass is kg (kilograms)Energy
Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2} mv^2[/tex]
KE is Kinetic Energy (in J)m is mass (in kg)v is velocity (in m/s)Explanation:Step 1: Define
Mass m = 30 kg
Kinetic Energy KE = 500 J
Step 2: Solve for v
Substitute [KEF]: [tex]\displaystyle 500 = \frac{1}{2}(30)v^2[/tex]Multiply: [tex]\displaystyle 500 = 15v^2[/tex]Isolate v term: [tex]\displaystyle \frac{100}{3} = v^2[/tex] Isolate v: [tex]\displaystyle \frac{10\sqrt{3} }{3} = v[/tex]Rewrite: [tex]\displaystyle v = \frac{10\sqrt{3} }{3} \ m/s[/tex]Evaluate: [tex]\displaystyle v = 5.7735 \ m/s[/tex]You throw a baseball straight up in the air with an initial velocity of 41 m/s What is the maximum height the baseball reaches above your hand?
Answer:
85.77 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 41 m/s
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =?
The maximum height reached by the ball can be obtained as follow:
v² = u² – 2gh (since the ball is going against gravity)
0² = 41² – (2 × 9.8 × h)
0 = 1681 – 19.6h
Collect like terms
0 – 1681 = –19.6h
–1681 = –19.6h
Divide both side by –19.6
h = –1681 / –19.6
h = 85.77 m
Thus, the maximum height reached by the ball is 85.77 m
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