A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The defender catches the ball carrier in a completely inelastic collision. What was the kinetic energy of the ball carrier/defender system BEFORE the tackle?

Answer:

Hypertonic, isotonic, and hypotonic solutions and their effect on cells. ... There are some different explanations out there. ... Tonicity is a concern for all living things, particularly those that lack rigid cell walls and live in ...

Answer:

1m/s

Explanation:

D = 22m

T = 22s

S = 22÷22

= 1 m/s

Answer:

C = - 1.625 i + 6.06 j

Explanation:

Positive angles are measured counterclockwise.

Positive angles are measured counterclockwise. To determine the component on the x axis we use the cosine of the angle while to determine the component on the y axis we use the sine of the angle.

[tex]C_{x}=6.28*cos(105)=-1.625\\C_{y}=6.28*sin(105)=6.06\\[/tex]

C = - 1.625 i + 6.06 j

Explanation:

1.Seeds have endosperm which provides nourishment for a new plant, but spores do not have any stored food supplies.

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Answer:

a. Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.

b. -2.81 m/s²

c. 3.78 s

d. -351.25 N

Explanation:

a. After landing on the flat land above, each block of ice travels 20 meters while slowing to a stop.

For the block of ice to reach the top of the cliff, its maximum height, h should be greater than or equal to 5.7 m. That is, h ≥ 5.7 m.

The maximum height of a projection h, projected with an initial velocity v at an angle Ф is h = v²sin²Ф/2g where g = acceleration due to gravity = 9.8 m/s².

For the block of ice, v = 15 m/s and Ф = 45°. So,

h = v²sin²Ф/2g

= (15 m/s)²sin²45/(2 × 9.8 m/s²)

= 225 (m/s)²(1/√2)²/19.6 m/s²

= 225 (m/s)²(1/2)/19.6 m/s²

= 112.5 (m/s)²/19.6 m/s²

= 5.74 m

Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.

The graph is in the attachment.

b. What is the rate of acceleration while the blocks slow to a stop?

Using v² = u² + 2as where u = initial horizontal velocity of block = 15m/scos45° = 10.61 m/s, v = final velocity of block = 0 m/s since it stops, a = acceleration and s = distance block moves = 20 m

So, a =  (v² - u²)/2s

substituting the variables into the equation, we have

a =  ((0 m/s)² - (10.61 m/s)²)/2(20 m)

= - 112.57 (m/s)²)/40 m

= -2.81 m/s²

c. How long do the blocks take to slow to a stop?

Using v = u + at where u = initial horizontal velocity of block = 10.61 m/s v = final velocity of block = 0 m/s since it stops, a = acceleration = -2.81 m/s² and t = time it takes block of ice to stop

So, making t subject of the formula,

t = (v - u)/a

substituting the values of the variables, we have

t = ( 0 m/s - 10.61 m/s)/-2.81 m/s²

= -10.61 m/s/-2.81 m/s²

= 3.78 s

d.  What is the amount of friction between the ice and the snowy ground?

The frictional force, f = net force on block of ice

f = ma where  m = mass of bock = 125 kg and a = acceleration of block = -2.81 m/s²

f = ma

= 125 kg(2.81 m/s²)

= -351.25 N

Answer:

B. 1200

Explanation:

60 sec in one min in 2 min there will be 120 sec. 10x120=1200

Answer:mechanical waves.

Explanation:

Mechanical waves require the particles of the medium to vibrate in order for energy to be transferred. For example, water waves, earthquake/seismic waves, sound waves, and the waves that travel down a rope or spring are also mechanical waves.

Answer:two terabyte external hard drive for $100

Explanation:

Answer:

3.77202

Explanation:81.9 kg×9.8N/kg÷0.0021 Pa ×(1atm/101325)=3.77202

The pressure exerted between her toes and the ground is 3.77 atm.

The stress at a location within a confined fluid or the perpendicular force per unit area are the two definitions of pressure used in the physical sciences. A 42-pound box with an area of 84 square inches at the bottom will apply pressure on a surface equal to the force divided by the surface area.

Given:

An 81.9 kg person stands on her toes. The surface area of her toes in contact with the ground is only 0.00210 m²,

Calculate the pressure on the toe as shown below,

The pressure on the toe = Force of man / area of toe

The pressure on the toe = mass of man × 9.8 / 0.00210

The pressure on the toe = 81.9 × 9.8 / 0.00210

The pressure on the toe = 802.62 / 0.00210

The pressure on the toe = 382200 N/m²

The pressure on the toe = 382200 / 101325 (1 atm = 101325 N / m²)

The pressure on the toe = 3.77 atm,

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Answer:

Kinetic energy.

Explanation:

This is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy.

Explanation:

distance=16km=16000m

time=0.25hours=1/4hr=15min=900sec

speed=dist./time

=16000/900=160/9=17.777m/s

speed=17.78m/s (rounded)

Answer:

64

Explanation:

Avg. speed = total distance/total time

Avg. speed= 16km/0.25h

Avg. speed= 64km/h

Answer:

Acceleration of the car = 2 m/s²

Average velocity of the car =28 m/s

Explanation:

Initial velocity = 20 m/s

Final velocity = 36 m/s

Time taken = 8 s

Acceleration = Δ velocity / time taken

Acceleration = 36-20 / 8 = 16/8 = 2 m/s²

Average velocity of the car =[ Initial velocity + Final velocity ] /2

Average velocity of the car = [ 20+36] / 2 = 28 m/s

Answer:

electrons are transferred from the lithium atom to the chlorine atom

Answer:

D

Explanation:

I just took the test :)

Question:

At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2.  Calculate the distance travelled by car.

Answer:

62.5 metres

Explanation:

Given

[tex]u = 0[/tex] -- Initial Velocity

[tex]a = 5.0m/s^2[/tex] --- acceleration

[tex]t =5.0s[/tex] -- time

Required

Calculate the distance

This question will be solved using the following equation of motion

[tex]S = ut + \frac{1}{2}at^2[/tex]

Where S represents the distance

Substitute values for u, t and a

[tex]S = 0 * 5.0 + \frac{1}{2} * 5.0 * 5.0^2[/tex]

[tex]S = 0 + \frac{1}{2} * 5.0 * 25.0[/tex]

[tex]S = \frac{1}{2} * 5.0 * 25.0[/tex]

[tex]S = \frac{1}{2} * 125.0[/tex]

[tex]S = 62.5m[/tex]

Hence, the distance travelled is 62.5m

If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.

Question:

The flow of air caused by _____ and the Coriolis effect creates distinct _____ on Earth's surface.

Answer:

Explanation:

The flow of air caused by variations in the rate at which the different parts are heated up as well as the Coriolis effect combine to create distinct wind patterns on Earth's surface.

The Coriolis Effect is used to describe a "force" that causes things (like objects, planes, air currents) traveling long distances around the Earth to appear to bend as they move rather than in a straight line.

Cheers

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

Hope this helps you

Answer:

Coulomb's law.

Explanation:

If the distance between two particles is doubled and the force between them is quartered, this is known as Coulomb's law. Coulomb presented a law in which he states that when there is increase occur in distance between two objects, the force between them is decreases so if the distance between two particles or objects is doubled so the force between them is also quartered.

Answer:

Explanation:

time =d/s

therefore, t =8.5/2.8

t=3.02s

Answer:

500x

Explanation:

A microscope had an eyepiece magnification of 10x

The objective lens magnification is 50x

Therefore the total magnification can be calculated as follows

= 10 × 50

= 500x

Hence the total Magnificattion is 500x

Answer:

All you need is golfing equipment make a small hole in the ground and have like something to cover the sun off of you and boom you got a golfing spot and a golf club no skills needed. Oh and you need a small flag for your gold hole but then your good and you can have fun

Explanation:

Answer:

You have to answer this in your opinion!

Anyways, A time I took a big risk was when I decided to talk to strangers online. It was risky because the stranger was harrasing me and doing bad stuff to me online. I learned about online safety and I learned to be careful who I talk to online! :)

Explanation:

Answer:

The net and only force acting on the ball thrown up into the air at half of its maximum height is the weight  of the ball

Explanation:

When the ball is rising in the air, the force, F, acting on it is given by the product of the mass, m × acceleration, a

The acceleration of a body thrown in the air = Gravitational acceleration = g = Constant

Therefore;

The force acting on the body thrown in the air F = Constant = m × g (downwards)

The force acting on the ball thrown up into the air at half of its maximum height = The mass of the ball × The acceleration due to gravity = The weight  of the ball.

Answer:

Time Saved = 0.374 h = 22.4 min

Explanation:

First we calculate the time required at old speed limit:

s = v₁t₁

where,

s = distance from Portland to Bangor = 215 km

v₁ = old speed limit = 88.5 km/h

t₁ = time taken with old speed limit = ?

Therefore,

215 km = 88.5 km/h (t₁)

t₁ = (215 km)/(88.5 km/h)

t₁ = 2.429 h

Now, we calculate the time taken at the new speed limit:

s = v₂t₂

where,

s = distance from Portland to Bangor = 215 km

v₂ = new speed limit = 104.6 km/h

t₂ = time taken with new speed limit = ?

Therefore,

215 km = 104.6 km/h (t₂)

t₂ = (215 km)/(104.6 km/h)

t₂ = 2.055 h

So, the time saved will be:

Time Saved = t₁ - t₂ = 2.429 h - 2.055 h

Time Saved = 0.374 h = 22.4 min

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.

Answer:

The value is  [tex]u = 27.93 \ m/s[/tex]

Explanation:

From the question we are told that

   The  mass of the ball is [tex]m = 0.250 \ kg[/tex]

    The radius of the circle is  [tex]r = 0.5 \ m[/tex]

    The force exerted is  [tex]F = 33 \ N[/tex]

    The  speed of the ball on top of the circle is  [tex]v = 13.0 \ m/s[/tex]

Gnerally from the law of energy conservation we have that

     [tex]PE + W = \Delta KE[/tex]

Here PE  is the potential energy of the pitcher which is mathematically represented as

      [tex]PE = m * g * (2 r )[/tex]

=>   [tex]PE = 0.250 * 9.8 * (2 * 0.5 )[/tex]  

=>   [tex]PE = 24.5\ J[/tex]

And  W  is the workdone by the force applied which is mathematically represented as

       [tex]W = F * \pi * r[/tex]

=>    [tex]W = 33 * 3.142 * 0.5[/tex]

=>    [tex]W = 51.84 \ J[/tex]

And   [tex]\Delta KE[/tex] is the change in kinetic energy which is mathematically represented as

       [tex]\Delta KE = \frac{1}{2} * m * (v^2 - u^2 )[/tex]

=>    [tex]\Delta KE = \frac{1}{2} * 0.250 * ( 13^2 - u^2 )[/tex]

=>    [tex]\Delta KE = 0.125 * ( 13^2 - u^2 )[/tex]

=>    [tex]\Delta KE = 21.125 - 0.125u^2[/tex]

So

      [tex]24.5 + 51.84 = 21.125 - 0.125u^2[/tex]

=>    [tex]u = 27.93 \ m/s[/tex]

The velocity of the ball released at the bottom is required.

The velocity of the ball released at the bottom is 24.56 m/s

F = Force = 33 N

r = Radius of loop = 0.5 m

m = Mass of ball = 0.25 kg

u = Initial velocity of ball = 13 m/s

v = Final velocity

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

The energy balance of the system is given by

[tex]F\pi r+mg2r=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow v=\sqrt{\dfrac{2}{m}(F\pi r+mg2r)+u^2}\\\Rightarrow v=\sqrt{\dfrac{2}{0.25}(33\times \pi\times 0.5+0.25\times 9.81\times 2\times 0.5)+13^2}\\\Rightarrow v=24.56\ \text{m/s}[/tex]

The velocity of the ball released at the bottom is 24.56 m/s.

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Answer: 9.05 s

v = 3 m/s

u = 22 m/s

Deceleration = 2.1 m/s^2

∴ 3 = 22 - 2.1 ( t )

∴ t = 9 .05 s