Answer:
0n
Explanation:
Déterminer la charge de noyau d’atome d’oxygène en coulomb C
Answer:
determine a large mam I have no idea
A 34. 8 n object is in free fall. What is the magnitude of the net force which acts on the object? answer in units of n.
Answer:
-34.8n
Explanation:
when object in free fall, only force is the Force by weight,
which is 34.8 and direction is down.
what kind of frog species is this
Answer: i think its a bullfrog forgive me if im wrong i dont exactly know
Explanation:
Answer:
that is an African bullfrog
A bus slams on its breaks and goes from 30km/hr to 15km/hr in 4 seconds. What is its acceleration?
Answer:
− 2.08
Explanation:
When did the objects that we now see as asteroids and comets form in the solar system?.
Answer:
After solid particles condensed from the gas but before the planets finished forming
See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in motion. They are:
**a person standing on the ground **the car **the seat
**another person on the ride **the track **the sun
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
1. According to person standing on ground ~
The person is in motion2. According to The car ~
The person is not in motion3. According to the Seat ~
The person is not in motion4. According to another person on ride ~
The person is not in motion5. According to the track ~
The person is in motion6. According to the Sun ~
The person is in motionI hope that's what you were looking for, goodluck for your assignment ~
A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to determine the amount of power used?
Answer:
time
Explanation:
power = work done ÷ time
what is the formula for calculating potentiometer
1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)
The force diagram on the desk consists of normal reaction and weight of the pencil.
The net force on the desk in vertical direction is 1 N.
The net force on the desk in horizontal direction is 0.
The given parameters;
weight of the pencil, W = 1 NThe force diagram of the desk is sketched as follows;
↑ N
⊕
↓ W
Where;
N is the normal reaction on the deskW is the weight of the ballThe net force on the desk in vertical direction = 1 N
The net force on the desk in horizontal direction = 0
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an astronomer looking out into space will observe that
Answer:
The farther out a galaxy is from Earth, the faster it is moving away.
Explanation:
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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someone throws a rubber ball vertically upward from the roof of a building 8.2m in height. the ball rises, then falls.it just misses the edge of the roof, and strikes the ground.if the ball is in the air for 6.2s, what was its initial velocity?(disregard air resistance. a=-g=-10m/s²
Answer:
H = V t - 1/2 g t^2 V and g are in different directions
-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2
V = 184 / 6.2 = 29.7 m/s
Check: find time for ball to return to zero height
0 = 29.7 T - 5 T^2
T = 29.7 / 5 = 5.94 sec
The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec
S = 29.7 * .26 + 5 * .26^2 = 8.1
This should be pretty easy i think.
Describe the components within the system involved in the collision between pilot and landing zone.
Answer:
its a sure for not but i think its a 192583
How do atoms join together?
Answer:
Atoms can be joined together by chemical bonds.
Explanation:
When atoms form bonds, they can achieve a stable electron arrangement. To achieve a stable electron arrangement atoms can lose, gain or share electrons. There are many different types of bonds that hold atoms together.
Answer:
Atoms come together to form molecules because of their electrons. Electrons can join (or bond) atoms together in two main ways. When two atoms share electrons between them, they are locked together (bonded) by that sharing. These are called covalent bonds.
Explanation:
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s[/tex]
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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what metaphor most closely describes the nature of space-time?
a. chemistry formula
b.fabric
c. sine wave
d. moebius strip
Answer:
b.fabric
Explanation:
Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.
Answer:
B. fabric
Explanation:
How to find angular velocity of an object traveling at a constant speed.
I only know the formula which is ω = 2πf
1. Look at this data table
What data seems to be inconsistent with the rest? What are 2 different explanations for this data?
Using visual inspection and knowledge of linear regression , the inconsistent input is the last data point (30, 12.0).
Looking at the data, there is a negative relationship between the depth of water sample and the amount of dissolved oxygen. As the depth increases, the amount of dissolved oxygen decreases. However, the last data point does not concur with this trend. This might have been caused by imputation error or error in the measuring device used.Therefore, the inconsistent data point is (30, 12.0)
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Which of the following processes generated heat during earths formation that is still a source of heat in earths interior
Answer:
There are three main sources of heat in the deep earth: (1) heat from when the planet formed and accreted, which has not yet been lost; (2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elementsInterpreting Graphics
11. Look at the model of an atom below. Does the
model represent a metal atom or a nonmetal
atom? Explain your answer.
ng
By looking at the model shown in the problem one can clearly say that this model represents the metal because there are a total of 12 electrons revolving around the nucleus which clearly represents the Magnesium metal.
What are metalloids?The elements of the periodic tables that behave as metals, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.
As given in the problem, there is a graphical representation of the model of an atom,
One can see that the model in the problem accurately depicts the metal by looking at the total of 12 electrons circulating around the nucleus, which is a clear representation of the magnesium metal.
To learn more about metalloids here, refer to the link given below
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#SPJ5
What is gibbs free energy.
Answer:
It’s a
Explanation:
What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
Find the displacement in the time interval 3 seconds to 4 seconds
A. 1m
B.3m
C.7m
D.9m
Answer:
B. 3m
Explanation:
Took the quiz.
Hope this helps!!
Which of the following is NOT a part of Earth’s atmosphere?
1. mesosphere
2. troposphere
3. asthenosphere
4. stratosphere
Answer:
3
Explanation:
It is part of the Earth's mantle
Answer:
it is the astenospere number 3
People who drink coffee are more likely to develop cancer
Answer:
The answer is False
Why are people so rude???
Answer:
It could be low self-esteem
Explanation:
There probably insecure have problems and issues of their own could be that were abused growing up and weren’t treated right who knows.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Medicine in Western cultures has not focused on the energy in the body as much as cultures in Asia have.
A.
True
B.
False
PLEASE NO LINKS
Answer:
A
Explanation:
This is true because culture in Asia focus more on energy that is why we see kung fu and taekwondo etc.
Answer:
A
Explanation:
Got it right.
Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2
The magnitude of the acceleration of the box is 2 m/s².
The given parameters;
mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 eastThe resultant of the two given forces is calculated as follows;
[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]
The magnitude of the acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]
Thus, the magnitude of the acceleration of the box is 2 m/s².
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What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a pressure of 35 lb/in2 Assume that the distance between each floors is 10ft.
The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ftThe vertical pressure of the water is calculated as follows;
[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
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a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?
The work done on the given gas in one cycle is -405.3 kJ.
The given parameters;
initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³Convert the pressure to Pascal (N/m²);
1 atm = 101325
The work done in one cycle is the area of the triangle and it is calculated as follows
[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]
the net work done on the gas = - 405.3 kJ
Thus, the work done on the given gas in one cycle is -405.3 kJ.
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