1.54 is the acceleration of the crate. The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.
Acceleration is proportional to the net force.That acceleration is proportional to the net force and inversely proportional to the mass of the object. It can be expressed with the formula: Where, Fn = Net force, m = mass. The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes the motion and a horizontal net force appears causing the acceleration.
Forces in the vertical direction?The forces in the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal: N = W = mg, The friction force can be calculated by using the coefficient of friction μ: μ*n. Calculating the normal force: N = 200 * 9.8 = 1,960 N. The friction force is f=0.2*1960, f=392. The horizontal net force is 308. Finally, the acceleration is computed: m/s^2
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You bought a can of apricot jam. The contents marked as: net weight: 500g and volume: 400ml is the statement correct?why? and what is the mass of the jam you bought? calculate the density of jam in g/cm
The statement is not correct the mass of the jam is 500g and the density of the jam is 0.125gm/cm³
How to calculate the density?The statement is not correct because mass and volume cannot be used together to describe the contents of a can. Mass is a measure of how much matter is in an object and volume is a measure of the amount of space taken up by an object. So, in this case, the can of apricot jam should just be marked with the net weight in grams.The mass of the jam you bought is 500g.To calculate the density of the jam, we need to divide the mass by the volume. The density of the jam is 500g/400ml = 1.25g/ml. To put this in g/cm3, we need to divide the density by 1000, which gives us 1.25g/ml = 0.125g/cm3.To learn more about density refer to:
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A block is resting on an slope. (Figure 3) Which of the following forces act on the block? Check all that apply. O weight O static friction O normal force O kinetic friction O force of push
The correct option is A, B, and C. A block resting on a slope is Weight, static friction, and Normal force.
Static friction is a force that continues an item at relaxation. Static friction definition can be written as: The friction skilled while individuals try to move a desk-bound object on a surface, without surely triggering any relative movement between the frame and the surface on which it's miles.
Static friction is a form of friction force that acts on a body when there's no relative motion between the object and the surface. So, it can act even if the frame is in motion however there should be no relative motion.
A pressure acting on an item is said to be a static force if it no longer exchanges the scale, function, or route of that precise object. The pressure implemented to a structure acts as a load to that precise structure, that is why static force is likewise called a static load.
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Complete Question:
A block is resting on a slope. (Figure 3) Which of the following forces act on the block?
Check all that apply.
A). Weight
B). Static friction
C). Normal force
D). Kinetic friction
E). Force of push
humans taste food mostly because of:
Answer:
taste buds
Explanation:
very sensitive microscopic hairs called microvilli. The tiny hairs send messages to the brain about how something tastes, so you know if it's sweet, sour, bitter, or salty
A voltage vL(t)=10cos(2000πt) is applied to a 100-mH inductance.
A)Find the complex impedance of the inductance.
The complex impedance of the 100 mH inductance when a voltage vL(t) = 10cos(2000πt) is applied to it is: j200Ω.
What is inductance?
Inductance is a property of an electrical component that describes the ability of the component to store energy in a magnetic field when electric current passes through it.
Inductance is measured in units of henrys (H). When current flows through a component with inductance, it creates a magnetic field around the component that resists changes to the current. This resistance to changes in current is called inductive reactance and is measured in units of ohms.
The complex impedance of an inductor is given by Z = jωL, where ω is the angular frequency and L is the inductance.
Therefore, the complex impedance of the 100 mH inductance when a voltage vL(t) = 10cos(2000πt) is applied to it is:
Z = j(2000π) (100 x 10-3) = j(2π) (100 x 10-3) = j200Ω
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How are static and passive stretching similar?
Static stretching and passive stretching are very similar in that they both involve moving the limbs into and holding the stretch posture.
Static stretching involves the individual holding their own limbs in place, while passive stretching involves a partner assisting with the movement and holding of limbs. When you stretch to your limit and hold that position, you are engaging in a form of stretching known as static stretching. Passive stretching, on the other hand, is also a form of static stretching; however, during this technique, you remain relaxed and do not actively participate in increasing your range of motion.
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Why are dynamic flexibility tests not used as often as?
Dynamic flexibility tests are not used as often as static flexibility tests because dynamic flexibility tests involve more subjective measurements.
Static flexibility tests are more common in comparison to dynamic tests because static flexibility tests are easier to replicate. It is difficult to standardize motion-based tests such as dynamic flexibility tests between various subjects, while static flexibility tests are simple and easy to standardize it is because the metrics are fixed and not open to interpretation.
Since, dynamic flexibility tests are hard to perform because they measure the amount of stress on a muscle that is in motion. And it is difficult to assess this among multiple people and to get an accurate picture. That is why these tests are not used as often as static flexibility tests.
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Complete question
Why are dynamic flexibility tests not used as often as static flexibility tests?
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Describe how you would find absolute pressure in a car tire if you had a barometer and a tire pump with an air
pressure gauge
The absolute pressure in a car tire can found by following method:
Pressure is the force per unit area applied toward a course perpendicular to the outer layer of an item. To keep it precise, it is an amount of force following up on a unit area. The SI unit for pressure is measured in Pascals (Pa). Other non-SI units are bar and PSI. There are two types of references to quantify pressure,
Gauge Pressure
Absolute Pressure
The most well-known pressure reference is Gauge Pressure which is connoted by a ‘g’ after the pressure unit, for example, 33 psi g. It is the pressure relative to barometric or atmospheric pressure; it is positive for pressures above atmospheric pressure and negative for pressures that are below atmospheric pressure. An Absolute pressure estimation is one that is alluded to as a perfect or an ideal vacuum. The best illustration of an absolute referenced pressure is the calculation of Barometric pressure. To deliver an absolute pressure sensor, one strategy is for a maker to seal a high vacuum behind the detecting diaphragm.Formula of Absolute pressure is given by:
p(a) = p(g) + p(atm)
Where ,
p(a) is absolute pressure,
p(g) is gauge pressure and
P(atm) is atmospheric pressure
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Two unequal masses are dropped simultaneously from the same height. The two masses will experience the same change in
(A) acceleration
(B) kinetic energy
(C) potential energy
(D) velocity
When two unequal masses are dropped simultaneously from the same height, then both masses will experience the same change in D: velocity.
Velocity is the prime indicator of the position and the rapidity of the object. It can be described as the distance covered by an object in a unit of time. It means that velocity is the displacement of the object in unit time. When in the case where two objects with unequal masses are dropped simultaneously from the same height, both masses will attain the same change in velocity.
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How much work is done by gravity to cause a 12.0 kg stone to drop from a height of 22.0 m to a height of 3.00 m?
Answer:
Work done is 2280 Joules.
Explanation:
Work done can be found using the formula
[tex]W=Fs\\[/tex]
where:
W is work done ( in Joules)
F is force ( in Newtons)
s is displacement ( in Meters)
Assuming we are on Earth, we can find the force acting on the object using the mass with the following:
Mass × 10 = Force
12.0 × 10 = 120N
Moreover, we can find displacement by simply subtracting the final distance from the starting distance:
22.0m - 3.00m = 19.0m
Therefore,
[tex]W = Fs[/tex]
[tex]W = 120N[/tex] × [tex]19m[/tex]
[tex]W= 2280J[/tex]
Why is i0 10 12 W m2 used as a reference intensity for intensity level?
Since I0 is the lowest sound intensity that a person with normal hearing can detect, it is chosen as the reference point. Given that log10 1 = 0, the decibel level of a sound with an intensity of 10–12 W/m2 is = 0 dB. In other words, the human hearing threshold is zero decibels.
The reference value I0 is 10–12 W/m2, which corresponds to the threshold of hearing intensity at 1000 Hz. The Sound Intensity Level, or SIL for short, is the intensity decibel scale. The related sign, like in our text, is LI.
Much more frequently than sound intensities in watts per square meter, sound intensity levels are expressed in decibels (dB). Both the scientific literature and the public media use decibels as their preferred measurement unit. The rationale behind this decision of units has to do with how we hear. There is a reference intensity, I0 = 1012 W/m2. The lowest or threshold intensity of sound that a person with normal hearing can perceive at a frequency of 1000 Hz is specifically known as I0. The degree of sound intensity is not the same as the intensity. is a unitless quantity that informs you of the sound level in relation to a predefined standard (1012 W/m2, in this case), as it is defined in terms of a ratio.
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3. An air bubble of radius r rises steadily through
a liquid of density p at the rate of v. Neglecting
density of air, find the coefficient of viscosity of
liquid.
The coefficient of viscosity of a liquid can be determined from the motion of a bubble rising or falling through the liquid.
What is viscosity?
Viscosity basically is the measure of a fluid's resistance to flow. It is a measure of a fluid's internal friction, which is caused by the attraction of molecules in the fluid. Viscosity is an important physical property of fluids, as it affects the fluid's flow characteristics.
The equation for the coefficient of viscosity is given by:
2/9 r2 ρg/v.
where,
r = radius of bubble
ρ = density of liquid
g = acceleration due to gravity
v = velocity of bubble
Therefore, to calculate the coefficient of viscosity of a liquid, we need to know the radius of the bubble, the density of the liquid, the acceleration due to gravity, and the velocity of the bubble.
Hence, the coefficient of viscosity of liquid is 2/9 r2 ρg/v.
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The speed of light is approximately $3\times10^5$ kilometers per second. How long does it take sunlight to reach Jupiter
it takes about 26 seconds for speed of light with approximate speed of 3\times10^5 kilometers per second to reach Jupiter.
To calculate the time it takes light to reach Jupiter, we need to know the distance between the Sun and Jupiter. The average distance between the Sun and Jupiter is approximately 778 million kilometers. We can use the formula distance = speed x time to calculate the time it takes for sunlight to reach Jupiter. We know that the speed of light is approximately 3x10^5 kilometers per second and the distance between the Sun and Jupiter is 778 million kilometers.time = distance / speed
time = (77810^6 km) / (310^5 km/s)
time = 26 sec (approximately)
Therefore, it takes about 26 seconds for light to reach Jupiter.
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Will day and night on Earth be different if the planet did not rotate?
A typical spectrophotometer has a path length (the distance light travels through a sample) of 1 cm. Light travels at approximately 3.0 x 108 m/s in vacuum. How long does it take (in ns) for light to travel 1.0 cm
The time taken is 3.33 ns for light to travel 1.0 cm in a spectrophotometer.
What is time?
Time is defined as a scalar quantity that describes the progression of events in the universe. It is often considered to be the fourth dimension of spacetime, along with the three dimensions of space. Time is closely related to the concepts of causality, or the relationship between cause and effect, and is considered to be a fundamental aspect of the physical universe.
The distance light travels in 1 cm is equal to 1 cm x 10^-2 m. To find out how long it takes for light to travel this distance, we can use the formula:
time = distance / speed
Where distance is the distance light travels (1.0 cm x 10^-2 m), and speed is the speed of light in vacuum (3.0 x 108 m/s).
time = (1.0 cm x 10^-2 m) / (3.0 x 108 m/s)
time = 3.33 x 10^-10 s
To convert this time to nanoseconds (ns), we can multiply the time in seconds by 1 billion (10^9):
time = 3.33 x 10^-10 s x 10^9 ns/s
time = 3.33 ns
Therefore, the time taken is approximately 3.33 ns for light to travel 1.0 cm in a spectrophotometer.
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A passenger elevator operates at an average speed of 8 m/s. if the 60th floor is 219 m above the first floor,how long does it take the elevator to go from the first floor to the 60th floor?
Answer:
27s
Explanation:
Time = distance/speed
Time = 219/8
Time = 27.375 s
Anxiety disorders can become a pathological disorder when feelings of apprehension and fear __________.
a. are recurrent for less than six months
b. are inherited due to genetics
c. become excessive, uncontrollable, and affect daily life
d. are controllable but excessive
please select the best answer from the choices provided a b c d
When feelings of anxiety and worry become excessive, out of control, and interfere with daily life, they can develop into pathological diseases called anxiety disorders. So the correct option is (c).
Anxiety disorders are characterized by feelings of apprehension and fear, which are normal human emotions. However, when these feelings become excessive, uncontrollable, and affect daily life, they can be considered a pathological disorder. Anxiety disorders can affect a person's ability to perform daily activities, such as work or school, and can also cause physical symptoms such as insomnia, muscle tension, and fatigue. These disorders can be recurrent, but they need to be excessive, uncontrollable, and affect daily life in order to be considered pathological.
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What is the shape of a baseball field called?
Each base is at the intersection of a square-shaped infield in baseball. 8100 square feet, 900 square yards, or 90 × 90 square feet make up the space.
How would you describe a baseball field?Nine players occupy the diamond-shaped field that is used for baseball. There are two main areas of the field: the infield and the outfield. Four infielders and two core players cover the infield. Three outfielders cover the outfield.
In a letter dated May 26, James Cannon expressed shock that the "diamond" form is referred to as a rhombus. A baseball diamond, he pointed out, is essentially a square.
The elevated dirt area in the middle of the infield known as the hill—also known as the pitcher's mound—is where the pitcher throws. The pitcher's rubber is located directly behind the middle of the mound and is what they use to prepare and throw the ball.
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An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5. 0 m. What is its velocity?
The velocity of the object is 7.74m/s
Though it may sound sophisticated, velocity is simply the rate at which an object's location changes with regard to a frame of reference and time. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction.
We are given that,
Acceleration = 12m/s²
Radius = r = 5.0m
Velocity = v = ?
The velocity of the object can be calculated by the formula ,
a = v²/r
v = √ar
v = √12m/s²× 5m
v = √60m²/s²
v= 7.74m/s
Thus , the velocity of the object would be 7.74m/s.
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Particles q1 = -8.99 uC, q2 = +5.16 uC, and q3 = -89.9 uC are in a line. Particles q1 and q2 are separated by 0.220m and particles q2 and q3 are separated by 0.330m. What is the net force on particle q1?
Answer: -39200.45 Nm^2/C^2 This is rough work
Explanation:
So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.
IntroductionHi! Here I will explain the net force of three charges that interacts. Remember that this question can be solved using Coulomb's Law. Coulomb's Law states that the interaction force between two interacted charges will be proportional to the magnitude of the charges that have specific interaction but inversely proportional to the square of the value of the distance between each other. So, with this concept, we can calculate the magnitude of coulomb force with this equation:
[tex] \boxed{\sf{\bold{F = k \cdot \frac{q_1 \cdot q_2}{(r_{12})^2}}}} [/tex]
Formula UsedOn this condition, the net force will be felt only by the first charge, so we must define the position of the first charge as a fixed one. So, we can calculate the magnitude of coulomb force concerning the first charge with this equation:
[tex] \boxed{\sf{\bold{\sum F_{q1} = k \cdot (\frac{q_1 \cdot q_2}{(r_{12})^2} + \frac{q_1 \cdot q_3}{(r_{13})^2})}}} [/tex]
With the following condition:
[tex] \sf{\sum F_{q1}}[/tex] = the net force will be felt by the first charge (N)k = constant of coulomb ≈ [tex] \sf{9 \times 10^{9}}[/tex] N.m²/C².[tex] \sf{q_1}[/tex] = first charge (C)[tex] \sf{q_2}[/tex] = second charge (C)[tex] \sf{q_3}[/tex] = third charge (C)[tex] \sf{r_{12}}[/tex] = the distance between first and second charge (m)[tex] \sf{r_{13}}[/tex] = the distance between first and third charge (m)Problem SolvingWe know that:[tex] \sf{q_1}[/tex]= first charge = -8.99 [tex] \sf{\mu C}[/tex] = [tex] \sf{-8.99 \times 10^{-6}}[/tex] C.[tex] \sf{q_2}[/tex]= second charge = +5.16 [tex] \sf{\mu C}[/tex] = [tex] \sf{+5.16 \times 10^{-6}}[/tex] C.[tex] \sf{q_3}[/tex]= third charge = -89.9 [tex] \sf{\mu C}[/tex] = [tex] \sf{-8.99 \times 10^{-5}}[/tex] C.[tex] \sf{r_{12}}[/tex] = the distance between first and second charge = 0.220 m = [tex] \sf{2.2 \times 10^{-1}}[/tex] m.[tex] \sf{r_{13}}[/tex] = the distance between first and third charge = 0.220 + 0.550 m = [tex] \sf{5.5 \times 10^{-1}}[/tex] m.What was asked?[tex] \sf{\sum F_{q1}}[/tex] = the net force will be felt by the first charge = ... NStep by Step:[See the attached image to know how to solve this problem]
Conclusion:So, the net force will be felt on particle [tex]\sf{q_1}[/tex] approximately 15.39 N to the right.
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Caffeine dosage causes a change in the time to finish a maze and it isn't possible for that the time to finish a maze could cause a change in
caffeine dosage.
Caffeine dosage and time to finish a maze are independent variables, meaning that a change in one does not cause a change in the other. It is possible that caffeine dosage may have an effect on the time it takes to finish a maze, but the time it takes to finish a maze would not cause a change in caffeine dosage.
Caffeine Maze Time ImpactCaffeine is a stimulant that can affect the central nervous system and can have a range of effects on the body, including increased alertness, focus, and energy. When it comes to completing a maze, the time it takes to finish it could be affected by the person's level of alertness, focus, and energy. Therefore, if a person ingests a certain dosage of caffeine, it could affect the time it takes for them to finish the maze because of the effect caffeine has on the body.
On the other hand, the time it takes to finish a maze does not affect the caffeine dosage, in other words, caffeine dosage is an independent variable, it does not depend on other variables, and does not change based on the time it takes to complete a maze. It is determined by the amount of caffeine consumed.
So, in short, caffeine dosage can have an effect on the time it takes to finish a maze, but the time it takes to finish a maze does not have an effect on caffeine dosage.
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A truck with mass of 3,250 kg traveling with a velocity of 25.0 m/s hits a car at rest. After the collision, the truck moves with a velocity of 19.0 m/s. The car has a mass of 2,820 kg. If the two vehicles do not stick together, how fast is the car moving after the collision?
Answer:
6.9 m/s
Explanation:
This is a conservation of momentum problem, so the total momentum before the collision must equal the total momentum after the collision.
P = mv
m1v1 + m2v2 (before) = m1v1 + m2v2 (after)
(3250kg)(25.0 m/s) + (2820 kg)(0m/s) = (3250 kg)(19.0 m/s) + (2820 kg)(v2)
Now you can solve for the v of the car after the collision:
81250 kg·m/s + 0 = 61750 kg·m/s + (2820 kg)v2
19500 kg·m/s = (2820 kg)v2
v2 = 19500 kg·m/s / 2820 kg = 6.9 m/s
A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision.
The final velocity of the red-blue carts system is 5 cm/s.
What is the final speed of the two carts after collision?
The final speed of the two carts, that is the red cart and the blue cart system after the collision is calculated by applying the principle of conservation of linear momentum.
Pi = Pf
m₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is mass of the red cartm₂ is the mass of the blue cartu₁ is initial velocity of the red cartu₂ is the initial velocity of the blue cartv is the final velocity of the two carts after the collisionm₁u₁ + 0 = v ( m₁ + m₂ )
m₁u₁ = v ( m₁ + m₂ )
v = ( m₁u₁ ) / ( m₁ + m₂ )
The final velocity of the red-blue carts system is calculated as;
v = ( 50 kg cm/s ) / ( 5 kg + 5kg )
v = 5 cm/s
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The complete question is below:
A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision. What is the final velocity of the two carts system after the collision if the mass of the blue cart is 5 kg.
Mechanical energy starts the Ferris wheel, charging the lights along the seats, showing Choose energy. The full Ferris wheel begins to move going from Choose to Choose energy.
Mechanical energy is used to start the Ferris wheel, providing the initial rotation and motion to the wheel.
The motion of the wheel then causes the lights along the seats to be powered, allowing them to light up as the wheel turns. The wheel is then able to generate kinetic energy as it moves, which it then uses to continue turning.
As the wheel turns, it transfers its energy from mechanical to kinetic, and this energy is used to keep the wheel moving from start to finish. Kinetic energy is also used to power the centrifugal force which keeps the riders in their seats as the wheel turns, allowing them to enjoy the ride.
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A car is travelling along a horizontal road in an easterly direction. The car has a mass of 2300 kg and the drag force (friction) acting on the car is a constant 5000 N to the west.
The car is initially travelling at a speed of 10 m s‒1 and 20 s later is travelling at a speed of 14 m s‒1.
What is the gravitational force on the car?
What is the vertical normal (support/reaction) force acting on the car?
What is the horizontal force on the cars tyres from the road?
The gravitational force on the car is 23000 N, the vertical normal (support/reaction) force acting on the car is 0 N, and the horizontal force on the car's tyres from the road is 5460 N.
Mass of the car, m = 2300 kg
Force acting on the car, F = 5000 N
The initial speed of the car, u = 10 m/s
The final speed of the car, v = 14 m/s
Time, t = 20 s
The gravitational force on the car is calculated by the formula given as
F = mg
F = 2300 × 10
F = 23000 N
Now, as there is no vertical movement in the car therefore the vertical force acting on the car is 0 N.
The horizontal force on the car's tyres from the road
= force acting on the car + net force on the car
= 5000 + ma
= 5000 + 2300 × (v-u)/t
= 5000 + 2300 × (14 - 10)/20
= 5000 + 2300 × 4/20
= 5000 + 460
= 5460 N
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if a bullet has a mass of 0.013 (13 gram) and moves at 1800 m/s what is it's momentum
Answer:
23.4 kg m/s
Explanation:
p = mv = 0.013kg × 1800m/s = 23.4 Kg.m/s
Is acceleration greater going up or down a ramp?
The acceleration which is acting on the object which is moving on the ramp is same for both the motion whether is going upwards or moving downwards.
Rolling motion happens when an object roll over from a ramp or any other sloppy surface whether it is rough or smooth. many forces act on it at the same moment. also in many forces rolling tangential force and gravitational force is also acting on it at the same moment. in which the gravitational force is acting on it at a bigger pace and plays an important role in rolling of the object from the ramp or any other sloppy surface. here we can see that the only force that is making impact on the object is the gravitational force. Hence, by this information we consider that the acceleration which is acting on the object which is moving on the ramp is same for both the motion whether is going upwards or moving downwards.
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A boy exerts a force of 225 N on a lever (Links to an external site.) to raise a 1250 N rock a distance (Links to an external site.) of 0.13 m. If the lever is frictionless, how far did the boy have to move his end of the lever
If the lever is frictionless, to raise the rock a distance of 0.13 m, then the boy has to move the lever to 0.72 m.
An external force that acts upon an object results in a motion of the object, then it is called a work done upon the object by that force.
Given that the external force on a lever is 225 N and on a rock is 1250 N. The distance of motion by the rock is 0.13 m.
Hence the work done by the lever will be equivalent to the work done by the rock to move a particular distance.
Work (Lever) = Work (Rock)
F(lever) x D (lever) = F (rock) x D (rock)
225x D(lever)= 1250 x0.13
D(lever) is 0.72 m
Hence we can conclude that the distance of the motion by the lever is 0.72 m.
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Bird bones have air pockets in them to reduce their weight. This also gives them an average density significantly less than that of the bones of other animals. Suppose an ornithologist weighs a bird bone in air and in water and finds its mass is 47.0 g47.0 g and its apparent mass when submerged is 3.60 g3.60 g (the bone is watertight). What mass of water is displaced
The mass of water displaced when the mass of bird bone in water and air is given, is calculated to be 43.4 g.
Given that,
Weight of bird bone in air = True weight = 47 g
Apparent weight of the bird bone when submerged = 3.6 g
The equation for apparent weight is known to be,
Apparent weight = True weight - Buoyant force
Making Buoyant force as subject, we have,
Buoyant force = 47 g - 3.6 g = 43.4 g
F b = mw × g = (m wat - m air)× g
mw = m wat - m air = 47 g - 3.6 g = 43.4 g
Thus, the mass of the water displaced is 43.4 g.
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The seatback must be adjusted far enough for your __________ to rest on the top of the steering wheel when your arm is comfortably extended.
The seatback must be adjusted far enough for your wrist to rest on the top of the steering wheel when your arm is comfortably extended.
What is the motion of steering wheel?The majority of modern automobiles, compact trucks, and SUVs have a rack and pinion steering. This transforms the steering wheel's rotational action into the linear motion which rotates the wheels and directs your course. A steering pinion, a circular gear, is used in the system to lock teeth on a rod (the rack).
What kind of basic device is a steering wheel?The basic device at work in steering, doorknobs, turbines, and bicycle wheels is a wheel and axle. An inclined plane wound around a cylinder is known as a screw.
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A cylindrical bucket of liquid (density rho) is rotated about its symmetry axis, which is vertical. If the angular velocity is ω, show that the pressure at a distance r from the rotation axis is P=P 0+ 21rhoω 2r 2where P 0 is the pressure at r=0,
Answer:
To derive the formula for the pressure at a distance r from the rotation axis, you can use the principle of hydrostatic equilibrium. This states that the pressure at a point in a fluid is equal in all directions and the net force on a fluid element is equal to zero.
Consider a small cylindrical element of fluid at a distance r from the rotation axis, as shown in the diagram below. The dimensions of the element are dr in the radial direction, 2πr in the circumferential direction, and h in the vertical direction. The weight of the element is equal to the product of its volume, density, and the acceleration due to gravity: W = (2πr)(dr)(h)(ρ)(g). The pressure at the top and bottom faces of the element is P + dP, where P is the pressure at the point and dP is a small change in pressure. The forces acting on the element are the weight of the element, the pressure force at the top face, and the pressure force at the bottom face.
[asy]
unitsize(2cm);
pair P1, P2, P3, P4;
P1 = (0,0);
P2 = (1,0);
P3 = (1,1);
P4 = (0,1);
draw((-0.5,0)--(1.5,0));
draw((0,-0.5)--(0,1.5));
draw(P1--P2--P3--P4--cycle);
draw((0.5,0)--(0.5,1));
draw((0.25,0)--(0.25,1));
draw((0.75,0)--(0.75,1));
label("$r$", (0.5,1.5), red);
label("$