7. Two people are pushing a 40.0kg table across the floor. Person 1 pushes with a force of 490N
[W], and person 2 pushes with a force of 565N (N). If the coefficient of kinetic friction between
the table and the floor is 0.613, determine the acceleration of the table.(12.7m/s2 [49.1° Nofw])
Answers
Answer:
20.4 [tex]m/s^{2}[/tex]
Explanation:
To start doing this problem, first draw a free body diagram of the table. My teacher always tells us to do this, and I find that it is very helpful. I have attached a free body diagram to this answer- take a look at it.
First, let us see if Net force = MA. To do that, we need to determine whether the object is at equilibrium horizontally. For an object to be at equilibrium, it either needs to be moving at a constant velocity or not moving at all. Also, if an object is at equilibrium, there will not be any acceleration. But we know that there IS acceleration horizontally, so it cannot be in equilibrium. If it is not in equilibrium, we can use the formula ∑F= ma.
Let us determine the net force. Since the object is moving horizontally, we can ignore the weight and normal force, because they are vertical forces. The only horizontal forces we need to worry about are the applied force and force of friction.
Applied force = 1055 N (490 + 565)
Friction force= Unknown
To find the friction force, use the kinetic friction formula, Friction = μkN
μk is the coefficient, which the problem includes- it is 0.613.
N is the normal force, which we have to find.
*To find the normal force, we have to determine if the object is at equilibrium VERTICALLY. Since it has no acceleration vertically (it's not moving up/down), it is at equilibrium. Now, when an object is at equilibrium in one direction, it means that all the forces in that direction are equal. What are our vertical forces? Weight (mg) and Normal force (N). So it means that the Normal force is equal to the Weight.
Weight = mg = (40)(9.8) = 392 N
Normal force = 392 N
Now, plug it back into the formula (μkN): (0.613)(392) = 240.296 N
Friction = 240.296 N
Now that we know the friction, we can find the horizontal net force. Just subtract the friction force, 240.296 from the applied force, 1055 N
Horizontal Net Force: 814.704 N
Now that we know the net force, plug in the numbers for the formula
∑F= ma.
814.704 = (40.0)(a)
*Divide on both sides)
a = 20.3676 m/s^2
Round it to 3 significant figures, to get:
20.4 [tex]m/s^{2}[/tex]
![7. Two People Are Pushing A 40.0kg Table Across The Floor. Person 1 Pushes With A Force Of 490N[W], And](https://brainimage.s3.us-east-005.backblazeb2.com/answers/attachments/4o1TYoulvk3kY2RItUgSqdwdgIkc8iPM.png)
Related Questions
What are Alpha rays
please its aurgent
Answers
Answer:
An alpha ray is a stream of alpha particles. An alpha particle consists of two protons and two neutrons bound together into a particle identical to a helium nucleus.
Use a ballistic cart to shoot a small ball into the air. Push the cart along a track, allowing it
to release the ball. What explains why the cart always catches the ball, and the ball doesn't
fall behind the moving cart?
Answers
Answer:
Explained below.
Explanation:
The ball doesn't fall behind the moving cart because the horizontal motion of the ballistic cart is not affected by the forces that act in the vertical direction. Therefore, when the cart is pushed, it means that the ball will shoot up and then it will land right back in the barrel.
Rex scored the following marks in 6 subjects:
English - 88
Hindi - 64
Sanskrit - 89
Maths - 96
Science - 87
Social Studies - 80
Find his average score in 6 subjects.
Answers
A current of 8 A flows through a conductor. The number of electrons passing through the conductor in each second will be
Answers
Answer:
8=3×1019 electrons per second.
Explanation:
Answer:
here
Explanation:8=3×1019 electrons per second.
A 1 kg box is sitting on a flat horizontal surface that has a coefficient of static friction value of 0.8. What answer best states the minimum force required to move the box in the horizontal direction?
A. >-9.8N
B. >9.8N
C. >7.84N
D. >9N
Answers
The normal force felt by the box has magnitude
F[normal] = (1 kg) g = 9.8 N
so that the maximum magnitude of static friction is
F[s. friction] = 0.8 F[normal] = 7.84 N
In order to get the box to move, (C) a minimum force of 7.84 N is required.
Who would like to be my girlfiend ?
Answers
nobody this is a app to help others
Answer:
I bet my great grandmother would
They confessed their guilt.
Answers
Answer:
heyyy
May I Know the full question
How much gravitational potential energy does a 1.0 kg hammer have on a shelf 1.5 m above the ground?
Answers
Answer:
14.7 J
Explanation:
PE=MGH
PE= 1.0 x 9.8 x 1.5 = 14.7 J
identify the types of simple machine given below .
a)scissors b)axe c)driller
Answers
Answer:
there should some picture to identify right?
pls edit your question and insert the picture..
Answer:
Well it depends Because An axe Would be A Simple machine well as a drill is
An electric motor transforms potential energy into mechanical energy.
Please select the best answer from the choices provided
T
F
Answers
Answer:
t
Explanation:
Answer:
False
Explanation:
how can an object travel 6 meters if it ends up at -2 on the number line?)
Answers
Answer: Distance is a scalar quantity and direction is not applicable. We can use graphs to depict an object's change in position over time. Create a large number line in the classroom by taping index cards on the floor or wall 1 meter apart.
Explanation: I really hope that was helpful.
What is the density of a box measuring 100 grams and 10 ml?
Answers
Answer:
In order to convert density to grams, you have to put the mass on one side of the equation, and the density and the volume on the other. Therefore, d * v = m. Multiply the density by the volume. Using the example in step 1, you would multiply 2 g/mL by 4mL.
Explanation:
ok
A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?
A. 2.2 ɥC
B. 680 ɥC
C. 2.2 C
D. 680 C
can someone explain this in detail because im having a hard time understanding these type questions...thank you!!
Answers
Answer:
A. 2.2 ɥC
Explanation:
Given;
electric field strength, E = 1236 N/C
distance of the source charge, r = 4 m
Electric field strength is calculated as;
[tex]E = \frac{kQ}{r^2}[/tex]
where;
Q is the magnitude of the source charge
k is Coulomb's constant = 9 x 10⁹ Nm²/C²
[tex]E = \frac{kQ}{r^2} \\\\kQ = Er^2\\\\Q = \frac{Er^2}{k} \\\\Q = \frac{(1236)(4^2)}{9 \ \times \ 10^9} \\\\Q = 2.197 \ \times \ 10^{-6} \ C\\\\Q = 2.197 \ \mu \ C[/tex]
Therefore, the correct option is A. 2.2 ɥC
Which of the following can sometimes be zero for a moving body i average velocity ii distance travelled iii average speed iv displacement
Answers
Answer:
displacement can be zero...because it only care about initial and final positionsPlease helpp !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
A 1000 kg car’s velocity increases from 5 m/s to 10 m/s. What is the change to the car’s kinetic energy? Show your work.
Answers
Answer:
k. e. = 1/2 mv^2
1/2 * 1000 * (5)^2
1/2 * 1000 * 25
12500 joules
k. e. = 1/2 mv^2
1/2 * 1000 * (10)^2
1/2 * 1000 * 100
50000
change in k. e. = final - initial
50000 - 12500
= 37500 joules
hope it helps you
if a ball is thrown up from the ground and takes 2.30 seconds before it hits the ground. A) what was its initial velocity b) what was its max velocity
Answers
Answer:
A) The initial velocity is 11.27 m/s
B) The maximum velocity is 11.27 m/s
Explanation:
A) The question is with regards to kinematic motion under gravity
The the time it takes the ball to travel up and return back to the ground = 2.30 seconds
Therefore, from the kinematic equation of motion of the ball, under gravity, v = u - g·t, we have;
t = (v - u)/g
Where;
t = The total time of the motion of the ball = 2.30 seconds
v = The final velocity of the ball = 0 m/as at the maximum height
u = The initial velocity of the ball
g = The acceleration due to gravity = 9.8 m/s²
Therefore, given that we have;
The time it takes the ball to ascend = The time it takes the ball to descend
The time it takes the ball to ascend to maximum height = 2.30 second/2 = 1.15 seconds
Substituting the parameter values of the motion to maximum height, we get;
1.15 = (0 - u)/(-9.8)
-9.8 × 1.15 = -u
11.27 = u
The initial velocity, u = 11.27 m/s
B) Given that the ball experiences a deceleration on the way up, and that the motion of a parabola is symmetrical about the vertex, which is the maximum height, where the velocity is zero, we have that the initial velocity is equal to the final velocity which are both equal to the maximum velocity
Therefore, the initial velocity = The maximum velocity = 11.27 m/s.
The international space station travels 110,304 km in 4 hours. What is
speed of the ISS in Meters per second. (3600 seconds = 1 hour)
Answers
Answer:
7660 m/s
Explanation:
multiply 110304 x 1000 to turn it into meters then turn 4 hours into seconds making it 14400 seconds. Then divide 11030400 by 14400
What is the acceleration of an object that has a mass of 10kg and is pushed with a force of 50n
Answers
Answer:
5m/s/s
Explanation:
force = mass x acceleration
50 = 10a
a=5m/s/s
A 120 Ω resistor, a 60 Ω resistor, and a 40 Ω resistor are connected in parallel and placed across a potential difference of 12.0 V. What is the equivalent resistance of the parallel circuit?
Answers
Answer:
The equivalent resistance of the parallel circuit would be 20 Ω
Explanation:
To calculate the resistance of resistors connected in parallel, the formula to be used is
1/R = 1/R₁ + R₂ + R₃ + R₄...
1/R = 1/120 + 1/60 + 1/40
1/R = (1 + 2 + 3)/120
1/R = 6/120
1/R = 1/20 Ω
This can be rewritten or cross-multiplied to be
R × 1 = 20 × 1
R = 20 Ω
The equivalent resistance (R) would then be 20 Ω
Waves move fastest in
low-temperature gases.
low-temperature solids.
high-temperature gases.
high-temperature solids.
Answers
AGREE OR DISAGREE: All light can be seen.
Answers
Answer:
Disagree
Explanation:
We cannot see infared lights.
PHYSICS PLEASE HELP
a. Draw a force diagram
b. The skier has a mass of 76.6 kg and the coefficient of kinetic friction between the skier and the snow is 0.15. The angle the hill makes to the horizontal is 38 degrees and the distance the skier glides down the hill is 40.5 m. Answer the following questions based on this information.
What is the magnitude of the normal force on the skier as they glide down the hill? Show your work.
c. What is the magnitude of the force of friction on the skier as they glide down the hill? Show your work.
d. What is the acceleration of the skier as they glide down the hill? Show your work.
e. What is the speed of the skier when they reach the end of the straight section of the hill? Show your work.
f. How many seconds does the skier take to reach the end of the straight section of the hill? Show your work.
Answers
Answer:
Explanation:
b )
Normal force R = mgcosθ
= 76.6 x 9.8 x cos 38
R = 591.5 N
c )
Force of friction
= μ R
μ is coefficient of friction .
= .15 x 591.5
= 88.73 N
d )
Net force
= mg sinθ - friction
= 76.6 x 9.8 x sin 38 - 88.73
= 462.16 - 88.73
= 373.43 N
Acceleration = 373.43 / 76.6
a = 4.87 m / s²
e )
v² = u² + 2 a s
s = 40.5 m
a = 4.87
u = 0
v² = 0 +2 x 4.87 x 40.5
= 394.5
v = 19.86 m /s
f )
v = u + a t
19.86 = 0 + 4.87 t
t = 4 .07 s
How would you measure the volume of an oddly shaped object
By breaking the object into tiny pieces and placing them in a beaker
By placing it on a triple beam balance
By placing it in a room without gravity
By placing it in water and measuring how high the water rises
Answers
Answer:
By placing it in water and measuring how high the water rises
Explanation:
You can place the object in a can filled with water. You'll then see that as it sits there, the water level rises. You would then measure that to find the volume.
The diagram below shows an electric circuit with a battery and a bulb.
What energy transformations would occur when the bulb lights?
B. chemical to electrical to light
C. electrical to mechanical to light
D. chemical to electrical to solar
A. light to electrical to chemical
(First answer gets brainliest)
Answers
Answer:
B. chemical to electrical to light
The battery holds chemical energy, which is transformed to electrical energy due to flow of electrons.
The electrons due to their drift velocity which heats up the bulb filament hence producing light.
Answer:
B
Explanation:
because i learned in 5th grade
a pulley is used to lift a 2000 N safe over frosty's head. the safe is lifted 6m in 4s by Rudolph. how much power did Rudolph use?
Answers
Answer:
3000W
Explanation:
Given parameter:
Weight of safe = 2000N
Height of lift = 6m
Time = 4s
Unknown:
Power used by Rudolph = ?
Solution:
Power is the rate at which work is being done. It is expressed as:
Power = [tex]\frac{Work done }{Time taken}[/tex]
Work done = Weight x height = 2000 x 6 = 12000J
Power = [tex]\frac{12000}{4}[/tex] = 3000W
You look at yourself in the mirror and notice many of your physical features: your hair color, eye color, your height, dimples, etc. How does DNA relate to the way you look the way you do?
Answers
well, you get some DNA from both of your parents, so when you hear the phrase, "You have your mother's eyes!" That means you have some of your mother's DNA that gave you her eye color. The DNA you get from your parents help determine how you look today
If you and your friend are playing tug of war and both are you are pulling with the same amount of force. What will happen?
Answers
Answer:
Nothin will move, it will stay the same since no force is greater than the other. it's "the same amount of force" which also means an equal amount of force
Explanation:
The forces are only equal if there is no acceleration (which in the game of tug of war, accelerating yourself and your opponent is the idea). If the force on the rope and the ground are both equal either nothing moves or some other force is being applied in the system.
Hope this helped!
If a net horizontal force of 0.8 N is applied to a toy whose mass is 1.2 kg what acceleration is produced?
Answers
Answer:
0.67 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{0.8}{1.2} \\ = 0.666666...[/tex]
We have the final answer as
0.67 m/s²Hope this helps you
A term used to describe a critical assessment of how an athlete acts and what they achieve either during a match or while training is known as:
A. SMART Target
B. Area of improvement
C. Performance analysis
D. Measurement of success
Answers
Answer:
I believe D
Explanation:
I'm not for sure but I think it is D