5. A 5.00 g sample of an unknown substance was heated from 25.2 C to 55.1 degrees * C , and it required 133 to do so. Identify the unknown substance using the chart above.

show work please

ur best try is to copy and paste and change some words.

Answer: I think it would be -23

Explanation:

Answer:

1. (a) delivered volume, (b) to reach, (a) moles

2. (c) molar ratio

3. (b) acid solution before.

Explanation:

1. You must titrate the acid with a base solution of known concentration, and use the (a) delivered volume. At the endpoint, the moles of acid and base in the titration follows the chemical equation, thus, you need (b) to reach the endpoint. With volume and concentration of the base we can find its (a) moles

2. With the (c) molar ratio, we can relate the moles of base with the moles of acid

3. When we have the moles of acid, we just need the volume of (b) acid solution before the titration to find molarity of the acid.

Answer:

Explanation:

The answer is C Enthaply and entropy because temperature plays a big role in reactions

Answer:

c

Explanation:

a p e x :)

Answer: There are [tex]12.71 \times 10^{-9}[/tex] moles present in [tex]2.11 \times 10^{14}[/tex] molecules of LiBr.

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] molecules present in 1 mole of a substance.

Hence, moles in [tex]2.11 \times 10^{14}[/tex] molecules of LiBr are calculated as follows.

[tex]Moles = \frac{2.11 \times 10^{14}}{6.022 \times 10^{23}}\\= 12.71 \times 10^{-9}[/tex]

Thus, we can conclude that there are [tex]12.71 \times 10^{-9}[/tex] moles present in [tex]2.11 \times 10^{14}[/tex] molecules of LiBr.

Answer:

7

Explanation:

took test

Answer:

Percentage of copper in sample = 60%

Explanation:

Given:

Mass of copper = 150 gram

Mass of brass = 250 gram

Find:

Percentage of copper in sample

Computation:

Percentage of copper in sample = [Mass of copper / Mass of brass]100

Percentage of copper in sample = [150/250]100

Percentage of copper in sample = [0.6]100

Percentage of copper in sample = 60%

Answer:

2 moles of ammonia gas (NH₃) reacts with 5/2 moles of oxygen gas (O₂) to produce 2 moles of nitrogen monoxide gas (NO) and 3 moles of liquid water (H₂O)

Explanation:

The chemical equation is:

NH₃(g) + O₂(g)⇒ NO(g) + H₂O(I)

First, we have to distinguish which are reactants and which are products.

Reactants ⇒ left side: NH₃ (ammonia gas) and O₂ (oxygen gas)

Products ⇒ right side: NO (nitrogen monoxide) and H₂O (water)

Thus, ammonia gas reacts with oxygen gas to produce nitrogen monoxide gas and liquid water.

The reaction is not balanced, because it does not has the same number of atoms of each chemical element in both sides. To balance, we have to write a coefficient of 3 for H₂O, then a coefficient of 2 for NH₃ (to balance H atoms), then a coefficient of 2 for NO, and finally a coefficient of 5/2 for O₂ (to obtain 5 atoms of O in both sides):

2 NH₃(g) + 5/2 O₂(g)⇒ 2 NO(g) + 3 H₂O(I)

According to the balanced equation, 2 moles of ammonia gas (NH₃) reacts with 5/2 moles of oxygen gas (O₂) to produce 2 moles of nitrogen monoxide gas (NO) and 3 moles of liquid water (H₂O).

Answer:

Explanation:

It can be determined by measuring the Ph. D is incorrect.

C: is wrong because if you are making something acidic, you are increasing the H+

B: is the correct answer.

A: pH decreases. H+ increases which makes the Ph decrease. It is an oddity of the formula that makes this happen.

Answer:

Passage?

Explanation:

Answer:

hi!

Explanation:

Well, some things I would do is to know the Periodic Table font and back. Know they elements and their class and atomic number and weight. Know how many atoms make up each element and how many protons, neutrons, and elements are in each atom.

Answer:

5 moles

Explanation:

First, write out the balanced equation:

2Al + Fe₂O₃ → Al₂O₃ + 2Fe

Reaction ratio of Al to Fe₂O₃ is:

2 : 1

This means 2 moles of Al will react with 1 mole of Fe₂O₃

Al: 5 mol

Fe₂O₃: 3 mol

Multiply the reaction to get moles of both reactants you have:

2 : 1 (×⁵/₂) = 5 : ⁵/₂

2 : 1 (×3) = 6 : 3

In other words, 5 moles of Al will react with ⁵/₂ moles of Fe₂O₃;

And 3 moles of Fe₂O₃ will react with 6 moles of Al;

But, we do not have 6 moles of Al, therefore only the 5 moles of Al available will react;

5 moles of Al reacts with ⁵/₂ moles of Fe₂O₃, as we can see from the ratios we calculated above, the remaining ¹/₂ mole of Fe₂O₃ will not react;

We say that Al is the limiting reactant because all the Al will react but all the Fe₂O₃ does not (i.e. it is in excess);

Next and last, the reaction ratio of Al to Fe is:

2 : 2 or, more simply 1 : 1

This means the moles of Al that reacts is the equal to the moles of Fe produced from the reaction;

We've established that 5 moles of Al will react with ⁵/₂ moles of Fe₂O₃, so 5 moles of Fe will also be produced (since the ratio is 1 : 1);

You could also work this out using the moles of Fe₂O₃ that react;

The reaction ratio of Fe₂O₃ to Fe:

1 : 2

So the moles of Fe produced is 2× the moles of Fe₂O₃;

If ⁵/₂ moles of Fe₂O₃ reacts, then simply multiply this by 2 which is 5 moles

Answer:

Volume; high temperature and pressure

Explanation:

In an explosive combustion the rapid expansion of the volume causes explosion and the production of high temperature and pressure.

The substance is usually in a confined place and the expansion usually reaches a breaking point in which it is expelled from the space usually accompanied with a loud noise and high amount of temperature and pressure change thereby releasing its gas constituents.

Answer:

12

Explanation:

there are 12 because of the desnity

Answer:

The temperature on the graph is higher at point 5 than at point 1.  The correct answer is the last answer choice that you showed.

Explanation:

The temperature at point 1 is -10 degrees Celsius, while the temperature at  point 5 is 120 degrees Celsius. This is a 1300% increase.

See the calculation here: https://www.calculatorsoup.com/calculators/algebra/percent-change-calculator.php?v_1=-10&v_2=120&action=solve

I hope this helps.  

Answer: cuhh

Explanation:

__________________________________________________________

Which equation should you use?

B. P₁V₁=P₂V₂

What is the new pressure?  

✔ 5000  kPa

__________________________________________________________

The problem gives initial volume (2.00 L), final volume (20.0 mL), and initial pressure (50.0 kPa). Then it asks to find the final pressure. Answer B has all these variables, with P₁=initial pressure, P₂=final pressure, V₁=initial volume, and V₂=final volume. Plug the given values into the equation and then solve for the unknown value, which is P₂, final pressure.

When plugging in the values, use consistent units. 2L=2000 mL, I chose to make the consistent unit in mL. You'll get the same answer if you choose to use L as the consistent unit.

[tex]2000*50=20*P2[/tex]

[tex]100000=20*P2[/tex]

Divide both sides by 20

[tex]100000/20=(20*P2)/20[/tex]

[tex]5000=P2[/tex]

Here's a photo of Edge just incase.

Answer:

k = 1.26 x 10^-12

Its extremely small.

It follows that when k is small... The equilibrium concentration of Reactant is large and More than Product.

Option C should be your answer

Answer:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)X

Explanation:

¡Hola!

En este caso, de acuerdo con el concepto de sal, la cual está generalmente dada por la presencia de al menos un metal y un no metal, es posible encontrar cuatro tipos de estas; hidrácidas, oxácidas, básicas y ácidas, en las que las primeras dos son neutras pero la segunda tiene presencia de oxígeno, la tercera tiene iones hidróxido adicionales y la cuarta iones hidrógeno de más.

Debido a la anterior, es posible relacionar cada pareja de la siguiente manera:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)XO

En las que M se refiere a un metal, X a un no metal, H a hidrógeno y O a oxígeno.

¡Saludos!

Answer:

Elementos.

Explicación:

Los elementos son las sustancias puras que están formadas por el mismo tipo de átomos, es homogéneo y no se puede descomponer por medios químicos. El elemento tiene el mismo tipo de átomos que son similares en tamaño y forma. Es un tipo de materia pura que tiene solo un tipo de átomos y no se puede descomponer más porque no está hecha de dos sustancias, es solo una sustancia, por eso no se puede descomponer por medios químicos.

Answer:

It should have about 70-80 pounds of air pressure.

Answer:

5 lbs is what I read on the internetluv </3

Answer: hello your question has some missing details attached below is the missing details

answer : 25.5%  ( B )

Explanation:

Determine percentage yield

molar mass = 35 g/mol

mass of Li₃N(s) = 70 g

product  LiH(s) = 8.0 g ( actual yield )

theoretical yield ( LiH ) =  4 * 7.95  = 31.8 g

percentage yield = actual yield * 100 / theoretical yield

                            = 8 * 100/31.8

                            = 25.5%

Answer:

7800 cells

Explanation:

The number of Escherichia coli cells N after n generations is given by

N = 2ⁿ × N₀ where N₀ = initial population

Now making N₀ subject of the formula, we have

N₀ = N/2ⁿ

Since n = 8 and N = 1,996,800 cells, substituting the values of the variables into the equation, we have

N₀ = N/2ⁿ

N₀ = 1,996,800 cells/2⁸

N₀ = 1,996,800 cells/256

N₀ = 7800 cells

So, the initial population of Escherichia coli cells is 7800 cells.

Answer:

may be the answer is Heat and pressure - melting - cooling

Answer:

97200 J

Explanation:

Applying,

K.E = mv²/2.................. Equation 1

Where K.E = Kinetic Energy, m = mass of the roller coaster car, v = velociety of the roller coaster car.

From the question,

Given: m = 600 kg, v = 18 m/s

Substitute these values into equation 1

K.E = (600×18²)/2

K.E = 97200 J.

Hence the kinetic energy of the car is 97200 J

[tex]1 \text{ mol of H}_2 \text{O} \equiv 18 \text{ g} \implies 0.251 \text{ moles of H}_2 \text{O} \equiv 4.518 \text{ g}[/tex]

Answer:

1/....

Explanation:

If we say acceleration 'a' is inversely proportional to mass 'm', then

a=1/m.

Answer:

the correct answer is gravity

Answer:

the gravitational pull so gravity (b)