-ww.A
m = 15.0 kg
The block at Position A is released from the spring with 100 J of elastic potential energy. How
much kinetic energy does the block have at Position B? Explain how you know.
Answer:
v = 3.65 m / s
Explanation:
In this exercise we use the conservation of mechanical energy
starting point. Point A compressed spring
Em₀ = 100 J
final point. Point B uncompressed spring
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em₀_f
100 = ½ m v²
v = [tex]\sqrt{ \frac{2 \ 100 }{m} }[/tex]
v = [tex]\sqrt {200/15}[/tex]
v = 3.65 m / s
Steph uses 18 Newtons of force to push a piano up a ramp. She uses a total of 900 Joules getting this piano into the moving truck. Calculate the
distance of the ramp.
[tex]\huge{ \mathcal{ \underline{ Answer }: }}[/tex]
[tex] \boxed{ \mathrm{Work done = Force × displacement}}[/tex]
[tex]900 = 18 \times d[/tex][tex]d = \dfrac{900}{18} [/tex][tex]d = 50[/tex]Therefore the distance covered :
[tex] \large \boxed{50 \: m}[/tex]
_____________________________
[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]
plsss plsss plsss helppppp ASAP thank u ❤️
Answer:
7. (D) uniformly accelerated vertical motion
8. (A) zero
9. (A) zero
10. (C) parabolic
Answer:
7.Uniformly accelerated vertical motion
8.0m/s²
9.9.8m/s
10.parabolic
11.vertical component.
Questions
1. Why does pressure on a diver increase with
depth?
Answer:
The weight of the water above a diver exerts pressure on their body. The deeper a diver descends, the more water they have above them, and the more pressure it exerts on their body
What is the period of a sound wave with a frequency of 20Hz?
Physics class, need hell
Answer:
325.76 revolutions
Explanation:
The tire radius is diameter/2: 42/2 = 21
And now we can discover the lenght of the tire circumference. The lenght of a circumference is given by 2×radius×π, and let's consider π=3.14, and let's use the radius in meter (21 cm = 0.21 m):
2•0.21•3.14 = 1.32 m of lenght
Now, you divide the distance the car moved by the lenght of the tire circumference and you will find how many revolutions the tire makes:
420/1.32 = 325.76
When an object is moving towards us the waves compresses in a way that it has
Answer: The waves are compressed as the item moves closer to you, so their wavelength is shorter.
Explanation:
Drag each tile to the correct box a chemical reaction takes place in which energy is released arrange the reactions characteristics in order from start to finish
You accidentally slide a glass of iced tea off a table that is 0.75 m tall. How
long does it take the tea to hit the ground?
A. 0.54 s
B. 0.39 s
C. 0.23 s
D. 0.47 s
Answer:
0.39 seconds
Explanation:
Given:
Distance, S = 0.75 m
Acceleration due to gravity, g = 9.81 m/s^2
Initial (vertical) velocity, u = 0 m/s
Final velocity,
S = ut + (1/2)gt^2
0.75 = 0(t) + (1/2)(9.81)t^2
t^2 = 0.75/(9.81/2) = 0.1529 s^2
t = sqrt(0.1529) s.
= 0.391 s.
The time it takes an object to fall a certain distance is 0.39 s. Therefore, option (B) is correct.
What is kinematioc equation?To determine how long it takes for the glass of iced tea to hit the ground, we can use the kinematic equation that relates the distance, time, initial velocity, and acceleration of an object under free fall.
Assuming the glass is dropped from rest, its initial velocity is zero, and the acceleration due to gravity is[tex]-9.8 m/s^2[/tex] (negative because it is acting in the opposite direction to the motion).
Using the equation:
[tex]d = 1/2 * a * t^2[/tex]
where d is the distance, a is the acceleration due to gravity, and t is the time, we can solve for t:
[tex]0.75 m = 1/2 * (-9.8 m/s^2) * t^2[/tex]
Simplifying this equation gives:
[tex]t^2 = 0.75 m / (1/2 * 9.8 m/s^2) = 0.153[/tex]
Taking the square root of both sides gives:
[tex]t = sqrt(0.153) = 0.39 s[/tex]
Therefore, the correct option is B. It takes approximately 0.39 seconds for the glass of iced tea to hit the ground.
Learn more about acceleration, here:
https://brainly.com/question/12550364
#SPJ7
Please hurry Describe why electric currents can be dangerous. ***what causes it to happen in the circuit not biology****
Answer:
Basically, the main risk is cardiac arrest, caused by the electric current interfering with the normal operation of the heart muscle. Other possible damages are burns due to the electric energy vaporizing the water inside the cells, and nerve damage caused by excessive current through the nerves.
The main hazards of working with electricity are:
Electric shock and burns from contact with live parts.Injury from exposure to arcing, fire from faulty electrical equipment or installations.Explanation:
How old are the hydrogen atoms in water?
Answer: 4.5 billion years
Explanation:
Some of the water molecules in your drinking glass were created more than 4.5 billion years ago, according to new research.
That makes them older than the Earth, older than the solar system — even older than the sun itself.
If you have a frequency of 99Hz what is your period?
Answer:
frequency=1/time period
99HZ*time period=1
time period=1/99HZ
=0.01 second
Explanation:
The blank
is the organ responsible for cleaning a person's blood.
What would the axes be labelled on a graph that allows you to calculate VELOCITY?
Una lámpara requiere 5 A y presenta una resistencia de 20 Ω, cuando está
encendida.
a. ¿Cuál es la tensión?
b. ¿Qué resistencia adicional requiere si se desea operar a 120 V?
c. ¿Y 110 V?
Answer:
a. V = 100 voltios
b. Para 120 V → [tex]R_{2} = 4 \Omega[/tex]
c. Para 110 V → [tex]R_{2} = 2 \Omega[/tex]
Explanation:
a. La tensión se puede calcular mediante la ley de Ohm:
[tex] V = IR [/tex]
V: es el voltaje o tensión =?
I: es la corriente = 5 A
R: es la resistencia = 20 Ω
Entonces, la tensión es:
[tex]V = IR = 5 A*20 \Omega = 100 V[/tex]
b. La resistencia adicional es la siguiente:
[tex] R_{2} + R_{1} = \frac{V}{I} [/tex]
[tex]R_{2} = \frac{V}{I} - R_{1} = \frac{120 V}{5 A} - 20 \Omega = 4 \Omega[/tex]
c. La resistencia adicional para operar a 110 voltios es:
[tex]R_{2} = \frac{V}{I} - R_{1} = \frac{110 V}{5 A} - 20 \Omega = 2 \Omega[/tex]
Espero que te sea de utilidad!
What Do Alien Civilizations Look Like?
Answer:
We dont know. It can look like anything
Explanation:
Although it's thought to be highly probable, we have no reliable evidence that aliens exist.
Using organisms such as fungi to detoxify a polluted area is called
A. sustainable use
B. bioremediation
C. endemic treatment
D. edge effect
Answer:
bioremediation :)
Explanation:
If a red star and a blue star both have the same radius and both are the same distance from Earth, which one looks brighter in the night sky? Explain why.
Answer:
The blue one.
Explanation:
Im pretty sure its because the blue is hotter.
A 5 kg ball is thrown at 4 m/s. What is the ball’s momentum
Answer:
20kgm/s
Explanation:
p=mv
p=5*4
p=20kgm/s
What is the kinetic energy of an a 7.1 kg sled with a velocity of 5.7 m/s?
Answer:
115.3395 j
Explanation:
K= 1/2mv²= (7.1/2)*5.7² = 115.3395 j
Answer:
115.34 J
General Formulas and Concepts:
Energy
Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]
m is mass (in kg)v is velocity (in m/s)Explanation:
Step 1: Define
Identify variables
[Given] m = 7.1 kg
[Given] v = 5.7 m/s
[Solve] KE
Step 2: Solve for KE
Substitute in variables [Kinetic Energy Formula]: [tex]\displaystyle KE = \frac{1}{2}(7.1 \ kg)(5.7 \ m/s)^2[/tex]Evaluate exponents: [tex]\displaystyle KE = \frac{1}{2}(7.1 \ kg)(32.49 \ m^2/s^2)[/tex]Multiply: [tex]\displaystyle KE = (3.55 \ kg)(32.49 \ m^2/s^2)[/tex]Multiply: [tex]\displaystyle KE = 115.34 \ J[/tex]Topic: AP Physics 1 - Algebra Based
Unit: Energy
Book: College Physics
In regard to the Compton scattering experiment with x-rays incident upon a carbon block, as the scattering angle becomes larger, what happens to the magnitude of difference between the incident and scattered wavelengths
Answer:
Increases
Explanation:
In the Compton scattering experiment with x-rays,
The change in operation
[tex]\Delta \lambda = \frac{h}{m_oc} [1-cos\theta][/tex]
Now rest being constant, as \theta increases, cos\theta decreases
Hence, The change in wavelength will increase with the increase in \theta.
Hence, wavelength increases with an increase in the angle of scatttering.
Please help with this question
Answer:
This unbalanced force causes her to change in direction.
If the forces on an object are unbalanced, this is what happens:
a stationary object starts to move in the direction of the resultant force
a moving object changes speed and/or direction in the direction of the resultant force
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
A skier is at the top of the mountain facing east. The skier then decides to skis to the westward side of the mountains and pushes off .The unbalanced for causes her to change in Direction.
If you shine a light of frequency 375hz on a double slit setup , and you measure the slit separation to be 950 nm and the screen distance to be 4030 nm away , what is the distance from the zero order fringe to the first order fringe ?
Answer:
y = 33.93 10⁵ m
Explanation:
This is an interference exercise, for the contributory interference is described by the expression
d sin θ = m λ
let's use trigonometry for the angle
tan θ = y / L
how the angles are small
tan θ = sin θ / cos tea = sin θ
we substitute
sin θ = y / L
d y / L = m λ
y = m λ L / d
the light fulfills the relation of the waves
c = λ f
λ = c / f
λ = 3 10⁸ /375
λ = 8 10⁵ m
first order m = 1
let's calculate
y = 1 8 10⁵ 4030 10-9 / 950 10-9
y = 33.93 10⁵ m
defination of formula bar
The Formula Bar is where data or formulas you enter into a worksheet appear for the active cell. The Formula Bar can also be used to edit data or formula in the active cell. The active cell displays the results of its formula while we see the formula itself in the Formula Bar.
mark me brainliestt :))
what is the lowest frequency of a standing wave that has the fewest number nodes and antinodes
Answer:
Fundamental frequency
A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist's acceleration?Felipe drives his car at a velocity of 28 m/s. He applies the brake, which slows the vehicle down at a rate of 6.4 m/s2 and causes it to slow to a stop. How long does it take for the car to stop? Round your answer to the nearest tenth.
Answer:
a) a = - 0.0833 m / s², b) t = 4.4 s
Explanation:
a) this is a kinematics exercise where the acceleration is along the inclined plane
v = v₀ - a t
a = v₀ - v / t
a = 3 - 8/60
a = - 0.0833 m / s²
b) in this case the final velocity is zero
v = v₀ - a t
0 = v₀ - at
t = v₀ / a
t = 28 / 6.4
t = 4.375 s
t = 4.4 s
If a positively charged rod is brought near the knob of a positively charged electroscope, the leaves of the electroscope will...
A) converge, only
B) diverge, only
C) first diverge, then converge
D) first converge, then diverge
Answer:
B
Explanation:
if a positively charged rod is brought near the knob of a neutral electroscope, it will attract some electrons up from the leaves onto the knob. That process causes both of the leaves to be positively charged (excess protons), and the leaves will diverge.
Which example below is the most complex component of a multicellular organism?
Question 20 options:
Skin cell
Heart
Muscle Tissue
Reproductive System
A flywheel slows from 600. to 416 rev/min while rotating through 34.0 revolutions. What is the angular acceleration of the flywheel
Answer: [tex]\alpha=4.798\ rad/s^2\quad [\text{deceleration}][/tex]
Explanation:
Given
Initial revolution of flywheel [tex]N_1=600\ rpm[/tex]
(Initial angular velocity [tex]\omega_i=\dfrac{2\pi N_1}{60}[/tex])
Final revolution of flywheel [tex]N_2=600\ rpm[/tex]
(Final angular velocity [tex]\omega_f=\dfrac{2\pi N_1}{60}[/tex])
Revolution turned [tex]34[/tex]
So, angle turned is [tex]\theta =2\pi \times 34\\[/tex]
Using equation of angular motion i.e. [tex]\omega_f^2-\omega_i^2=2\cdot \alpha \cdot \theta[/tex]
[tex]\Rightarrow \left(\dfrac{2\pi \times 416}{60}\right)^2-\left(\dfrac{2\pi \times 416}{60}\right)^2=2\alpha \times (68\pi )\\\\\Rightarrow \alpha=\dfrac{1898.344-3948.86}{427.312}\\\\\Rightarrow \alpha =-4.798\ rad/s^2\\\Rightarrow \alpha =4.798\ rad/s^2\quad [\text{deceleration}][/tex]
A rookie quarter back throws a football with an initial upward velocity component of 12.0 m/s and a horizontal velocity component of 20.0 m/s. Ignore resistance. How much time is required for the football to reach the highest point of the trajectory
Answer:
t = 1.22 s
Explanation:
Given that,
The initial upward velocity component of a football = 12 m/s
The horizontal velocity component is 20 m/s
We need to find the time required for the football to reach the highest point of the trajectory. Let the time is t.
Using first equation of motion to solve it such that,
[tex]v=u+at[/tex]
u is initial velocity
v is final velocity
a = -g
so,
[tex]t=\dfrac{u}{g}\\\\t=\dfrac{12}{9.8}\\\\t=1.22\ s[/tex]
So, the required time taken by the football to reach the highest point is 1.22 seconds.