3x-y=2
x+2y=3

elimination method

Answer:

1 1/2

Step-by-step explanation:

1 1/2 + 3 1/2 = 5

6 1/2 - 5 =1 1/2

Answer:

A.

Step-by-step explanation:

The estimated simple linear regression equation is y = 46.2 + 589.2x, with a coefficient of determination (r^2) of 0.7523.

The coefficient of determination (r^2) measures the proportion of the total variation in the dependent variable (y) that can be explained by the independent variable (x) in a linear regression model. In this case, the coefficient of determination is 0.7523, indicating that approximately 75.23% of the variation in the dependent variable (y) can be explained by the independent variable (x) using the given regression equation. This means that the linear relationship between x and y accounts for 75.23% of the variability observed in y. The remaining 24.77% of the variation is attributed to other factors not included in the model. A higher value of r^2 indicates a stronger relationship between the variables.

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Answer:

$17.5

Step-by-step explanation:

Answer:

26.25

Step-by-step explanation:

I took the test

Step-by-step explanation:

X=40/8

X=5 Answer

hope it helps

Answer:

X= 5

Step-by-step explanation:

NOTE: DIVIDE 8 IN BOTH SIDE

8X/8 = X

40/8 = 5

SO X = 5

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Have a great day, be safe and healthy  

Thank u  

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Answer:

a. ∆ABC ~ ∆A'B'C'

b. Enlargement

c. Scale factor = 4

Step-by-step explanation:

a. <A corresponds to <A'

<B corresponds to <B'

<C corresponds to <C',

Therefore, the similarity statement would be: ∆ABC ~ ∆A'B'C'

b. The image of the dilation is an enlargement of the original figure because the side lengths of ∆A'B'C are larger than the corresponding side lengths of ∆ABC.

c. Scale factor = the ratio of the corresponding sides

Thus:

Scale factor = A'B'/AB = B'C'/BC = A'C'/AC

Scale factor = 24/6 = 48/12 = 60/15 = 4

Scale factor = 4

Option C is correct: A one-unit increase in x1 will lead to a 0.5906 unit increase in y, when x2 is held constant. A one-unit increase in x2 will lead to a 0.498 unit increase in y, when x1 is held constant.

The estimated regression equation for a model involving two independent variables and 10 observations follows. Here SST = 6,724.125,

SSE = 507.75,

Sb1 = 0.0813, and

Sb2 = 0.0567.

ŷ = 29.1270 +0.5906x1 + 0.4980x2

Interpretation of Regression Coefficients:

Below are the explanations of the regression coefficients in the estimated regression equation:

1. The regression coefficient for x1 is 0.5906. A one-unit increase in x1 will lead to a 0.5906 unit increase in y, when x2 is held constant.

2. The regression coefficient for x2 is 0.4980. A one-unit increase in x2 will lead to a 0.498 unit increase in y, when x1 is held constant.

Therefore, Option C is correct: A one-unit increase in x1 will lead to a 0.5906 unit increase in y, when x2 is held constant. A one-unit increase in x2 will lead to a 0.498 unit increase in y, when x1 is held constant.

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Answer:

An expression for this would be 3y as length * breadth is the area of a rectangle.

Answer:

you will need to wait 3 hours and 30 mins

Step-by-step explanation:

Answer:

Hello There!!

Step-by-step explanation:

It is 3 hours and 30 minutes which is 210 minutes altogether.

hope this helps,have a great day!!

~Pinky~

Answer:

Step-by-step explanation:

17*8= the entire rectangle which is 136

Area of triangle=(base*height)divided by 2

The base of the white triangle is 4 because 8-4=4 and the height is 17

17*4=68

68/2=34

34= the area of the triangle

Area of the rectangle-area of the triangle=102

102 is your answer.

hopefully i did this right:)

Answer:

hi

Step-by-step explanation:

Answer:

The selection of the schools is done by random sampling, the remaining schools are considered as the control and stratified sampling for the selection of students for analysis is considered

Step-by-step explanation:

Based on the scenario, the following key highlights are presented:

This indicates that the selection of the schools is done by random sampling, the remaining schools are considered as the control and stratified sampling for the selection of students for analysis is considered.

Answer:

48

Step-by-step explanation:

60 students X 80%=48

20% is 12 students

40% is 24 students

60% is 36 students

so on and so forth.

Answer:

48.

Step-by-step explanation:

.80 x 60 = 48

Answer:

114cm

Step-by-step explanation:

When you're in a situation like this, you use ratios!

If the father's height is 5cm, and actually 185cm, the ratio of photo height and actual height is 1:57.

When we use this, the father is 57 times taller than him inside the photo, so since the daughter (in photo) is 2 cm, her height should be 2*57 cm.

2*57 = 114, which concludes to 114 cm.

:)

Answer:

(8,9)

Step-by-step explanation:

<|--------------------|--------------------------|>

(-2,-5)               (3,2)

-2-3 = -5 = | -5 | = 5

-5-2=-7 = | -7 | = 7

3+5=8

2+7=9

(8,9)

Answer:

Need to add picture

Step-by-step explanation:

Answer:

x = 35

m<PQR = 70

Step-by-step explanation:

This is an isoceles triangle so the base angles are the same and they all add up to 180 so:

2x + 2x + 40 = 180

4x + 40 = 180

4x = 140

x = 35

m<PQR:

2x

2(35)

70

Answer:

40 + 25 = 65

49 + 63 = 112

63 + 15 = 78

7×16 =112

26 × 3 =78

5×13=65

so the answer is

40 + 25 -------- 5 × 13

49 + 63 -------- 7 × 16

63 + 15 --------- 26 × 3

i hope this help you

If a translation of the figure above is plotted 7 units to the right and 2 units up, the (12,3) point A' will be located on the new figure.

The process of changing the location of the image on the coordinate system will be known as the translation. Here the image is translated as;

The given coordinate of the point is:- (7, 2)

Then it is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s range(involving values of y) or in it’s domain(involving values of x  because we  just count 7 units to the right and then 2 units up.

Hence If a translation of the figure above is plotted 7 units to the right and 2 units up, the (12,3) point A' will be located on the new figure.

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Answer:

-53

Step-by-step explanation:

The formula of the iteration function for Newton's method is given by g(x) = x - f(x) / f'(x).

The graph of g(x) and g'(x) shows convergence of Newton's method on [-1, 0] as a Fixed-Point Iteration technique. Applying Newton's method to find an approximation of the root of the equation x + e^(-0.812x) = 0 in [-1, 0], with an initial approximation of p0 = -1, gives an approximation of p_n = -0.567143. The standard output table for this method is: TLP_nP_n-1RE(P_nP_n-1) 0-1.00000000000.1559875219 1-0.4801700174-1.00000000000.4801700174 2-0.5889524214-0.4801700174 0.1087824049 3-0.5671941668-0.5889524214 0.0217582546 4-0.5671432850-0.5671941668 0.0000508818. The conclusion is that the Newton's method converges to a root of the equation x + e^(-0.812x) = 0 in [-1, 0] with a tolerance of 10^-5.

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Answer:

C

Step-by-step explanation:

No soil bag weighs A or B and D is too much unless she has many acres.

Answer  The guy Above  is right

Answer:

0.4c

Step-by-step explanation:

Given that :

Price of mp3 is reduced by 60%

Let initial price of mp3 = c

Discount on price = 60% = 0.6

Discounted price = initial price - discount on price

Discounted price = c - 0.6c

Discounted price = 0.4c

Using Ancient Egyptian multiplication, the values are obtained as: (a)  74 × 64 = 2724: (b)  129 × 413 = 35405: (c)  58 × 692 = 30456: (d)  4968 × 1234 = 6148172.

Ancient Egyptian multiplication, also known as Egyptian multiplication or the method of multiplication through doubling and halving, is a method used by ancient Egyptians to multiply two numbers.

It involves breaking down one of the numbers into a sum of powers of two and then adding the corresponding multiples of the other number. Here's how you can compute the given multiplications using ancient Egyptian multiplication:

(a) 74 × 64:

We start with the number 1 and keep doubling it until we reach a number greater than or equal to 74. We then create a column for each power of 2 that was used, and write the corresponding multiple of 64 in each column. Finally, we add the numbers in the columns corresponding to the powers of 2 that make up 74.

1  ×  64 =  64

2  ×  64 = 128

4  ×  64 = 256

8  ×  64 = 512

16 ×  64 = 1024

32 ×  64 = 2048

Adding the numbers corresponding to powers of 2 that make up 74:

64 + 0 + 0 + 512 + 0 + 2048 = 2724

Therefore, 74 × 64 = 2724.

(b) 129 × 413:

1  ×  413 =  413

2  ×  413 =  826

4  ×  413 = 1652

8  ×  413 = 3304

16 ×  413 = 6608

32 ×  413 = 13216

64 ×  413 = 26432

Adding the numbers corresponding to powers of 2 that make up 129:

413 + 0 + 1652 + 0 + 6608 + 0 + 26432 = 35405

Therefore, 129 × 413 = 35405.

(c) 58 × 692:

1  ×  692 =  692

2  ×  692 = 1384

4  ×  692 = 2768

8  ×  692 = 5536

16 ×  692 = 11072

32 ×  692 = 22144

Adding the numbers corresponding to powers of 2 that make up 58:

692 + 1384 + 0 + 5536 + 0 + 22144 = 30456

Therefore, 58 × 692 = 30456.

(d) 4968 × 1234:

1   ×  1234 =   1234

2   ×  1234 =   2468

4   ×  1234 =   4936

8   ×  1234 =   9868

16  ×  1234 =  19668

32  ×  1234 =  39468

64  ×  1234 =  78936

128 ×  1234 = 157872

256 ×  1234 = 315744

512 ×  1234 = 631488

1024 × 1234 = 1262976

Adding the numbers corresponding to powers of 2 that make up 4968:

1234 + 2468 + 4936 + 0 + 19668 + 39468 + 78936 + 157872 + 315744 + 0 + 1262976 = 6148172

Therefore, 4968 × 1234 = 6148172.

Using the ancient Egyptian multiplication method, we have computed the products for the given multiplications.

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The entry to record the payment of salaries and wages on July 2 is a debit to Salaries and Wages Payable and a credit to Cash.

1. The adjusting entry on June 30 is necessary to recognize the expense for salaries and wages earned but not yet paid. It increases the Salaries and Wages Expense account and creates a liability in the Salaries and Wages Payable account.

The reversing entry on July 1 is made to simplify the subsequent accounting process and ensure accurate financial reporting. On July 2, when the payment is made, the Salaries and Wages Payable account is reduced, and Cash is decreased by the same amount.

2. Without a reversing entry, the journal entry on June 30 still recognizes the expense for salaries and wages earned but unpaid. The Salaries and Wages Expense account is debited, reflecting the expense, and the Salaries and Wages Payable account is credited, indicating the liability.

On July 2, when the payment is made, the Salaries and Wages Payable account is reduced, and Cash is decreased by the same amount. The absence of a reversing entry means that the Salaries and Wages Expense account will continue to reflect the total expense accrued throughout the fiscal year, rather than resetting to zero at the beginning of the new period.

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Answer:

30 blue pins

Step-by-step explanation:

30% is the same as 30 out of 100, so this can be written in this fraction: [tex]\frac{30}{100}[/tex]

now, you should multiply this fraction by the total number of pins she ordered:

100 x [tex]\frac{30}{100}[/tex]

to solve this, you can simplify by dividing 100 by 100, this equals 1

30 times 1 is 30

there are 30 blue pins

Answer:

30 hair pins were blue

Step-by-step explanation:

100 x 0.3 =  30

Answer:

C) Line A does not intersect Line B.

Step-by-step explanation:

Line A passes through (6 ,-30) & (-2 , 10)

Line B passes through (-4 , 28) & (2 , -2)

Find the slopes for each line. To find the slope, use the slope formula:

slope (m) = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]

Line 1:

Let:

[tex](x_1 , y_1) = (6 , -30) \\(x_2 , y_2) = (-2 , 10)[/tex]

Plug in the corresponding numbers to the corresponding variables:

m = [tex]\frac{10 - (-30)}{-2 - 6} = \frac{10 + 30}{-8} = \frac{40}{-8} = \frac{-5}{1}[/tex]

Line 2:

Let:

[tex](x_1 , y_1) = (2 , -2)\\(x_2 , y_2) = (-4 , 28)[/tex]

Plug in the corresponding numbers to the corresponding variables:

m = [tex]\frac{28 - (-2)}{-4 - (2)} = \frac{28 + 2}{-4 - 2} = \frac{30}{-6} = \frac{-5}{1}[/tex]

The two lines share the same slope, therefore, they are parallel to each other. This means that they do not intersect at any given point.