1.Why do you think the agricultural revolution led to more population growth?

Decreasing sunlight will decrease the amount of energy storage molecules in an ecosystem.

This is the process in which green plants manufacture food in the presence of sunlight. Primary producers are involved in this process of providing energy to the ecosystem.

This therefore means that a decrease in sunlight means a decrease in photosynthesis and energy production.

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Answer:

d.7 is the correct answer

Answer:

D). NADH

Explanation:

Answer:

F' = 3 N

Explanation:

Given that,

Two objects of equal mass have a force of gravity of 6 N between them.

If the mass of one is cut in half and the other stays the same such that,

m₁' = m₁ and m₂' = (m₂/2)

We need to find the new force. The gravitational force between two objects is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]

We have, F = 6 N

New force,

[tex]F'=G\dfrac{m_1'm_2'}{r^2}\\\\F'=\dfrac{Gm_1\times \dfrac{m_1}{2}}{r^2}\\\\=\dfrac{1}{2}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{2}\\\\F'=\dfrac{6}{2}\\\\F'=3\ N[/tex]

So, the new force becomes 3 N.

Complete Question

You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accu­rately (to four significant figures). You use a simple metric ruler to measure its dimensions and obtain the results for Method A. Your partner uses a precision micrometer and obtains the results for Method B.

Method A (g/cm3) 2.2,2.3,2.7,2.4 Method B (g/cm3) 2.703 2.701 2.705 5.811

The accepted density of aluminum is 2.702 g/cm 3 .

(a) Calculate the average density for each method.

Should all the experimental results be included in your calculations? If not, justify any omissions.

(b) Calculate the percent error for each method’s average value.

(c) Calculate the standard deviation for each set of data.

(d) Which method’s average value is more precise? Which method is more accurate?

Answer:

a)[tex]Ma_{avg}= 2.4g/cm^3[/tex]

   [tex]Mb_{avg}=2701g/cm^3[/tex]

b)[tex]PE_a=7.5\%[/tex]

  [tex]P.E_b=28.8 \%[/tex]

c) [tex]\sigma_A=0.35[/tex]

   [tex]\sigma_B=0.0545[/tex]

d)Method A

Explanation:

From the question we are told that:

Method A Density values

2.7

Method B Density values

2.703,2.701,2.705,5.811

Density of aluminium [tex]p_d=2.702 g/cm^3[/tex].

a)  

Generally the average density for each method is mathematically given by

Method A

[tex]Ma_{avg}= \frac{2.2+2.3+2.7+2.4}{4}[/tex]

[tex]Ma_{avg}= 2.4g/cm^3[/tex]

Method B

[tex]Mb_{avg}=\frac{2.703+2.701+2.705}{3}[/tex]

[tex]Mb_{avg}=2701g/cm^3[/tex]

b)

Generally the equation for percentage error [tex]PE[/tex] is is mathematically given by

percent error = (measured- real)/real *100

Given real = 2.702 g/ cm​​​3

Method A =

[tex]PE_a=(2.5- 2.702)* \frac{100}{2.702}[/tex]

[tex]PE_a=7.5\%[/tex]

Method B =

[tex]PE_b=( 3.481- 2.702)*\frac{100}{2.702}[/tex]

[tex]P.E_b=28.8 \%[/tex]

c)

Generally the standard deviation [tex]\sigma[/tex] for each method is mathematically given by

Method A

[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]

[tex]\sigma=\sqrt{\frac{0.25+0.16+0+0.09}{4} }[/tex]

[tex]\sigma_A=0.35[/tex]

Method B

[tex]\sigma=\sqrt{\frac{\sum(x-a)^2}{N} }[/tex]

[tex]\sigma=\sqrt{\frac{0.000001+0.00000+0.000009+0.011881}{4} }[/tex]

[tex]\sigma_B=0.0545[/tex]

d)

Therefore with lower percentage error the method who's average value is more precise is

Method A

Answer:

23,600 collisions.

Explanation:

Hello there!

In this case, according to the Avogadro's law, which help us to understand the molecules-volume relationship as directly proportional:

[tex]\frac{molecules_2}{V_2}=\frac{molecules_1}{V_1}[/tex]

It is possible for us to compute the collisions once the volume is increased as shown below:

[tex]molecules_2=\frac{molecules_1V_2}{V_1}\\\\molecules_2=\frac{2950*46.4L}{5.80L}\\\\molecules_2=23600[/tex]

Which means 23,600 collisions will occur per square centimeter.

Regards!

Answer:

Calm down is this what you need?

Answer:

calm down, what kind of container and things do you need?

Explanation:

Answer:

The process you are referrring to is erosion.

Explanation:

Weathering would be the breaking down of rock/other land debris. Its more active counterpart would be erosion, wherein the process transports the bits of rock and minerals away. Hope it helps!

Answer:

170.38g is the mass of 1 mole of C₁₂H₂₆

Explanation:

To solve this question we must find the molar mass of the alkane C₁₂H₂₆. The molar mass is defined as the mass of one mole of a substance.

In 1 mole of C₁₂H₂₆ we have 12  moles of Carbon and 26 moles of Hydrogen. With the periodic table of elements we can know the molar mass of 1 mole of Carbon and 1 mole of hydrogen, and, thus, the molar mass of the alkane (Molar mass C = 12.01g/mol, H = 1.01g/mol)

Molar mass C₁₂H₂₆:

12C = 12*12.01g/mol = 144.12g/mol

26H = 26*1.01g/mol = 26.26g/mol

144.12g/mol + 26.26g/mol =

Answer:

1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.

2. False

3. True

Explanation:

In chromatography, there is a stationary phase and a mobile phase. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).

Since silica gel is a polar solvent, it will retain the more polar product methyl m-nitrobenzoate compared to the methyl benzoate starting material.

In comparing the electrophillic aromatic substitution of m-nitrobenzoate  and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition

The final result has a higher Rf value because the TLC plate has more polarity than the other compound.

The answer to the following question is as follows:-

In chromatography, it is a process that is used to separate the different components on the basis of their votality. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).

In comparing the electrophilic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron-withdrawing groups on the aromatic compound deactivates.

The compound towards electrophilic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substitution and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substitution.  

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Answer:

8.5 mol H₂SO₄

Explanation:

It seems the balanced reaction the problem is referring to is absent, however the description matches the following balanced reaction:

Now we can convert 8.5 moles of SO₂ into moles of H₂SO₄, using the stoichiometric coefficients of the balanced reaction:

Answer:TRUE

Explanation:

A hydrogen bond is the electromagnetic attraction created between a partially positively charged hydrogen atom attached to a highly electronegative atom and another nearby electronegative atom. A hydrogen bond is a type of dipole-dipole interaction; it is not a true chemical bond.

Answer:

HCO₂

Explanation:

From the information given:

The mass of the elements are:

Carbon C = 26.7 g;     Hydrogen H = 2.24 g     Oxygen O = 71.1 g

To determine the empirical formula;

First thing is to find the numbers of moles of each atom.

For Carbon:

[tex]=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon[/tex]

For Hydrogen:

[tex]=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen[/tex]

For Oxygen:

[tex]=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen[/tex]

Now; we use the smallest no of moles to divide the respective moles from above.

For carbon:

[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon[/tex]

For Hydrogen:

[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen[/tex]

For Oxygen:

[tex]\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen[/tex]

Thus, the empirical formula is HCO₂

Answer:

14

Explanation:

Step 1: Calculate the moles corresponding to 25 g of Ba(OH)₂

The molar mass of Ba(OH)₂ is 171.34 g/mol.

25 g × 1 mol/171.34 g = 0.15 mol

Step 2: Calculate the molar concentration of Ba(OH)₂

Molarity is equal to the moles of solute divided by the liters of solution.

[Ba(OH)₂] = 0.15 mol/0.250 L = 0.60 M

Step 3: Calculate the molar concentration of OH⁻

Ba(OH)₂ is a strong base according to the following equation.

Ba(OH)₂ ⇒ Ba²⁺ + 2 OH⁻

The molar ratio of Ba(OH)₂ to OH⁻ is 1:2. The molar concentration of OH⁻ is 2/1 × 0.60 M = 1.2 M.

Step 4: Calculate the concentration of H⁺

We will use the ionic product of water expression.

Kw = 1.0 × 10⁻¹⁴ = [H⁺] × [OH⁻]

[H⁺] = 1.0 × 10⁻¹⁴/[OH⁻] = 1.0 × 10⁻¹⁴/1.2 = 8.3 × 10⁻¹⁵ M

Step 5: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 8.3 × 10⁻¹⁵ = 14

Answer:

The correct answer is - 0.0173888 moles.

Explanation:

Aspirin,  C 9 H 8 O 4 , the atomic mass rounded to the nearest whole number, so: c- 12 h- 1 o - 16

now multiply these number by how many of each there are in the formula:

c - 12 x 9 = 108

h - 1 x 8 = 8

0 - 16 x 4 = 64

add these numbers up 108 + 8 + 64 = 180

aspirin has a molar mass of  

180.g mol ^− 1 . This means that one mole of aspirin will have a mass of 180 g .

You're dealing with 3.13 g  of aspirin, which will be equivalent to

3.13 g  /180g

=  0.0173888 moles aspirin

Answer:

D. Speed up and spread out

Answer:

Waterrrr

Explanation:

H2O

Answer:

Muscle contraction

Explanation:

According to the new study, exercise improves muscle health by renewing its cellular powerhouse: the mitochondria. Mitochondria are crucial to the good functioning of our bodies, as well as to our overall health and longevity. These tiny parts of the cell turn the food we eat into energy.

Answer:

Explanation:

july

Answer:

Container 1 I think.

The containers have the same number of molecules and temperature. The container 1.

Collision is the encounter between two particles or object. There are three type of collision: perfectly elastic collision, inelastic collision, perfectly inelastic collision.

Container 1 is smallest, so there will be less distance between the molecules, so they will collide most.

Thus, the containers have the same number of molecules and temperature. The container 1.

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Answer:

b

Explanation:

one clue is the double bond at 4 carbon c=c

The correct structure that corresponds to the name.

3-bromo-6-methyl-4-octene is   [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] .

The molecule in which bromine is attached with C-3 carbon and double present at C-4 carbon containing total number of 8 carbon atom can be considered as 3-bromo-6-methyl-4-octene.

A chemist specifies the molecular geometry and, where possible and required, the electronic structure of such given molecule as well as other solid during a chemical structure determination.

It can be seen that in molecule [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex] bromine is attached with C-3 carbona and double bond exist at C-4 carbon. the total number of carbon atom is 8.

therefore, the structure of the compound will be [tex]$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBrCH}=\mathrm{CHCH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3}$[/tex].

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Answer:

False i think

Answer:

Do you mean Esterification experiment?

Explanation:

Answer:

Experiment 8 E Data Table 3 fl Data Table 4 fl Data Table 5 fl Data Table 6 Data Table 3: Polystyrene Test Tube, 12x75mm Volume of water at room temperature (V1 in mL) Volume of gas in polystyrene tube at boil (V2 in mL) Temperature of gas at boil inside polystyrene tube (°C) Volume of gas in polystyrenetube at room temperature (V3 in mL) Temperature of gas.

Explanation:

Hope this helps

Mark as Brainliest please

Answer:

Explanation:

A1. Chemical indicator, any substance that gives a visible sign, usually by a colour change, of the presence or absence of a threshold concentration of a chemical species, such as an acid or an alkali in a solution. An example is the substance called methyl yellow, which imparts a yellow colour to an alkaline solution.

A2. The reaction of an acid with a base is called a neutralization reaction. The products of this reaction are a salt and water. ... For example, the reaction of hydrochloric acid, HCl, with sodium hydroxide, NaOH, solutions produces a solution of sodium chloride, NaCl, and some additional water molecules

A3. Methyl orange has the property to color alkaline and neutral water yellow. If the water becomes acidic, it turns red immediately.

Answer:

the correct answere to that is q

Answer:

D.

Explanation:

Answer: The mass of sodium acetate anhydrous required is 0.820 g

The mass of sodium acetate trihydrate required is 1.36 g

The mass of Iron (III) chloride required is 2.70 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

= volume of solution in ml

1. moles of =

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{82.03\times 100.0}[/tex]

[tex]x=0.820g[/tex]

Therefore, the mass of sodium acetate anhydrous required is 0.820 g

2.   moles of [tex]CH_3COONa.3H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136.08g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{136.08\times 100.0}[/tex]

[tex]x=1.36[/tex]

Therefore, the mass of sodium acetate trihydrate required is 1.36 g

3. moles of [tex]FeCl_3.6H_2O[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{g/mol}[/tex]

Now put all the given values in the formula of molarity, we get

[tex]0.100=\frac{x\times 1000}{270.33\times 100.0}[/tex]

[tex]x=2.70g[/tex]

Therefore, the mass of Iron (III) chloride required is 2.70 g