The probability that at least two of them would end up trading at or above their initial offering price:
P(X ≥ 2) = 1 - P(X < 2)
The probability that at least two out of three Internet stocks would end up trading at or above their initial offering price, we need to calculate the complement of the probability that fewer than two stocks meet this condition.
Let's calculate the probability that fewer than two stocks would end up trading at or above their initial offering price.
P(X < 2) = P(X = 0) + P(X = 1)
The probability that a stock ends up trading below its initial offering price is 21.5%, which means the probability that it trades at or above the initial offering price is 1 - 0.215 = 0.785.
Using the binomial probability formula, where n is the number of trials (3 stocks) and p is the probability of success (0.785):
P(X = 0) = (3 C 0) * (0.215)^0 * (0.785)^3 ≈ 0.1851
P(X = 1) = (3 C 1) * (0.215)^1 * (0.785)^2 ≈ 0.4659
Therefore,
P(X < 2) = 0.1851 + 0.4659 ≈ 0.6510
Finally, we can calculate the probability as:
P(X ≥ 2) = 1 - P(X < 2) = 1 - 0.6510 ≈ 0.3490 (rounded to four decimal places)
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What is the distance between the bakery (b) and the library (c)? Explain using coordinate subtraction
Answer:
The distance between the bakery and the library is the length of BC. The endpoints of this line segment are B(0, 4) and C(3, 4). Because the y-coordinates of both points are the same (4), the length of BC can be found by subtracting the smaller x-coordinate from the greater x-coordinate: BC = 3 - 0 = 3 units. The distance between the bakery and the library is 3 blocks.
Step-by-step explanation:
I did the activity, this is the sample answer.
plzzzz help with the square ( parallelograms)
Answer:
#1=8
#2=3
Step-by-step explanation:
Someone please help me I’ll give out brainliest please dont answer if you don’t know
First use the distributive property by multiplying the 3 with each term inside the parentheses:
-8 + 3c + 3 + c
Now combine like terms:
-8 + 3 = -5
3c + c = 4c
Combine for final answer:
-5 + 4c which can also be written as 4c-5
Answer:
first let's multiply 3 by the bracket
-8+3*c+3*1+c=-8+3c+3+c
then add the numbers that have the same variables -8+3+3c+c
=-8+3+4c then add the numbers
=-5+4c is the answer
you can also write it like this
4c-5
Hypothesis Testing:
Step 1: State the hypotheses H = μ = 30 (claim) and H₁ = μ ≠ 30
Step 2: The level of significance and critical region.
α= 5% and two - tailed test
critical value = ± 1.96
Step 3: Compute for the value of one-sample t-test.
t = (x-μ)/(s/ √n)
t= (30.1 - 30)/ (1.3 √15)
t = - 0.3
Step 4: Decision rule. Do not reject the null hypothesis since the test value falls in the non-critical region.
Step 5: Conclusion. There is not enough evidence to support the claim that mean weight of their product is 30 grams.
In this hypothesis testing scenario, the null hypothesis (H) states that the mean (μ) weight of a product is equal to 30 grams.
The one-sample t-test is computed using the formula t = (x - μ) / (s / √n), where x is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size. In this case, the calculated t-value is -0.3.
Based on the decision rule, since the calculated t-value of -0.3 falls within the non-critical region (-1.96 to 1.96), we do not reject the null hypothesis.
Therefore, the conclusion is that there is not enough evidence to support the claim that the mean weight of the product is 30 grams. The data does not provide sufficient statistical evidence to conclude that the mean weight significantly differs from 30 grams.
It's important to note that in hypothesis testing, the result does not prove that the null hypothesis is true; rather, it suggests that there is not enough evidence to reject it based on the given data and significance level.
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how do you add & subtract rational expressions
Answer:
To add or subtract two rational expressions with the same denominator, we simply add or subtract the numerators and write the result over the common denominator. When the denominators are not the same, we must manipulate them so that they become the same. In other words, we must find a common denominator.
Step-by-step explanation:
Answer:
To add or subtract two rational expressions with the same denominator, we simply add or subtract the numerators and write the result over the common denominator. When the denominators are not the same, we must manipulate them so that they become the same.
Step-by-step explanation:
Find the area of the figure.
Step-by-step explanation:
Area of Rectangle at the top =
Length x Width
[tex] = 3.5 \times 3 \\ = 10.5 {mm}^{2} [/tex]
Area of Quarter- Circle = 1/4 x Area of Circle
[tex] = \frac{1}{4} \pi {r}^{2} \\ = \frac{1}{4} \pi( {3.5}^{2} ) \\ = 3 \frac{1}{16} \pi {mm}^{2} [/tex]
Area of Rectangle at the right = Length x Width
[tex] = 5.5 \times 3.5 \\ = 19.25 {mm}^{2} [/tex]
Total Area = Area of 2 Rectangles + Area of Quarter Circle
[tex] = 10.5 + 3 \frac{1}{16} \pi + 19.25 \\ = 29.75 + 3 \frac{1}{16}\pi \\ = 32 \frac{13}{16}\pi {mm}^{2} [/tex]
I will leave the answer in terms of pi as I'm not sure if you need to round off your answer.
A particle at and moves number line so that its position as tízku v in given by x * d(t) = (1 - 2) ^ 2 * (1 - 6)
(a) When is the particle moving to the right?
(b) When is the particle at rest?
(c) When does the particle change direction?
(d) What is the farthen left of the origin that the particle moves
The particle never moves to the right of the origin. Hence, the farthest left of the origin that the particle moves is at x=-∞.
Given that, the position of the particle is [tex]x*d(t)=(1-2)^2*(1-6).[/tex]
Initially, the position of the particle is[tex]x*d(t)=(-1)^2*(-5)=5.[/tex]
The displacement of the particle can be given as the difference between the final position and the initial position. Therefore, the displacement of the particle is [tex]Δx=0-5=-5.[/tex]
(a) Since the value of the displacement is negative, the particle is moving to the left.
(b) The particle will be at rest when the velocity of the particle is zero. Here,[tex]v=d/dt (x*d(t))=x*d'(t)[/tex]
When the velocity of the particle is zero, then x*d'(t)=0.So, either x=0 or d'(t)=0.
When x=0, the particle will be at rest at the origin.
To find out the value of t, substitute x=0 in the given equation,
we get[tex]0=(-1)^2*(-5).[/tex] This is not possible. Therefore, the particle will never be at rest.
(c) When the direction of the velocity changes, the particle changes direction. The velocity of the particle is given as v=d/dt (x*d(t))=x*d'(t).
From the above equation, we see that the velocity of the particle changes direction when x changes direction. The direction of x changes at x=0.
(d) The farthest left of the origin that the particle moves is at x=-∞ when t=0.
Thus, the particle never moves to the right of the origin. Hence, the farthest left of the origin that the particle moves is at x=-∞.
Note: Here, we have considered the absolute values of -1 and -5.
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4y ′ + 8y = 7, y(0) = −2 by any method that we have learned this semester. Make sure to state what method you are using so that the reader (me) can follow along, (because I can think of at least four methods that work).
Using the integrating method to solve the given differential equation, we get :
y = -1/4 - (9/4)e^(-2x)
Given equation is:
4y′ + 8y = 7,
y(0) = −2
We are going to use the integrating factor method to solve the differential equation.
Differential equation:
4y′ + 8y = 7
Rearranging the terms, we get:
y′ + 2y = 7/4
Integrating factor:
I.F. = e^(∫2dx)I.F. = e^(2x)
Multiplying I.F. throughout the differential equation, we get:
e^(2x)y′ + 2e^(2x)y = 7/4e^(2x)
Now we are going to apply the product rule of differentiation to the left-hand side. Let v = y and u = e^(2x)
So, v′ = y′ and u′ = 2e^(2x)
Now applying the product rule, we get:
e^(2x)y′ + 2e^(2x)y = 7/4e^(2x)2e^(2x)y + e^(2x)y′ = 7/4e^(2x)2e^(2x)y = -1/2 e^(2x) + C1y = -1/4 + C2e^(-2x)
Now substituting the initial value y(0) = -2C2 = -9/4
Putting the value of C2 in the above equation, we get:
y = -1/4 - (9/4)e^(-2x)
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24 + 8x + 10(2x)
Terms:
Constants:
Coefficients:
Can some plz help me
Find: (6m^5 + 3 - m^3 - 4m) - (-m^5 + 2m^3 - 4m + 6)
Answer:
7m^5 - 3m^3 - 3
Step-by-step explanation:
x - 36 = 205 what is it and
x + 127 = 300
74 = x 1,068
x - 47 = 47
Answer:
241
Step-by-step explanation:
205
+36
_____
241
X would be 241
Helpppp please and ty
Answer:
-2, -1, 0, 1
Step-by-step explanation:
you hover over the stars
NO LINKS PLEASE- OR I SWEAR-
What is the peak of this data set? *
A. 80
B. 100
C. 150
Answer:
A. 80
Step-by-step explanation:
There are more points on 80 than on the other ones. By this, you can tell that it's the PEAK of the data set.
Hope this helps! Please brainliest!
Answer:
It is A) 80Step-by-step explanation:
In which point has more balls ( it is on 80)
I hope that is useful for you :)
Which number completes the sequence ?
Answer:
12
Step-by-step explanation:
1st circle - [tex]1+3+6=10[/tex]
3rd circle - [tex]6+2+5=13[/tex]
2nd circle is proboably the same way.
When solving the equation 2x + 5 = 13, what is your first step?
A. Subtract 5 from each side.
B. Add 5 to each side.
C. Multiply each side by 2.
D. Divide each side by 2
-10 points!
Answer:
A) Subtract 5 from each side
Step-by-step explanation:
This would be your first step, then you would want to isolate your variable so you would divide both sides by 2.
To estimate the proportion of smoker a sample of 100 men was selected. In the selected sample, omen were smoker Determine a 9e contiene intervalo proportion smoker OA (0.27 0.53) (0.29 0.53) OC (0.27 0.58 OD (0.25 0.55
The 90% confidence interval for the proportion of smokers is approximately (0.043, 0.137).
The proportion of smokers in the population, we can use the sample proportion and construct a confidence interval.
Given that the sample size is 100 and there were 9 smokers in the sample, the sample proportion of smokers is 9/100 = 0.09.
To calculate the confidence interval, we can use the formula:
CI = p (bar) ± Z × √(p (bar)(1-p (bar))/n)
p (bar) is the sample proportion, Z is the Z-score corresponding to the desired confidence level, and n is the sample size.
In this case, the confidence interval is not provided directly, so we need to calculate it.
Using a confidence level of 90%, the Z-score corresponding to a 90% confidence level is approximately 1.645.
The confidence interval:
CI = 0.09 ± 1.645 × √(0.09(1-0.09)/100)
CI = 0.09 ± 1.645 ×√(0.0819/100)
CI = 0.09 ± 1.645 × 0.0286
CI = 0.09 ± 0.047
Therefore, the 90% confidence interval for the proportion of smokers is approximately (0.043, 0.137).
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Can someone please help me with math.
4- 20
I created an equation for this one:
4x+x=100
4x= four times the amount of the other numberx= the numbercombine like terms5x=100
divide by 5x=20
5. One pretzel costs $3
Create an equation:
2s+p=74s+3p=17Mulitply 2s+p=7 by -2 so you can use elimination.
-4s-2p=-144s+3p=17Combine equations
p=3
A hotel purchased a new office desk on April 15, 2018 and new executive style chars for the office on August 5, 2018. The office desk cost $950, and the chairs cost $1,900.
Determine the total depreciation amount for 2020 assuming the taxpayer opted out of Sec. 179 and bonus (if available) in the your of purtase. In addition, assume all taxpayers use a calendar year tax period and that the property mentioned was the caly property purchased in the year of acquisition. Use the appropriate depreciation table from your note sheet textbook where necessary.
I. $547
II. $407
III.$498
IV. $478
V. None of the answers given here.
The total depreciation amount for 2020 is $547.
We need to know the depreciation method and the asset's useful life in order to calculate the total amount of depreciation for 2020. Let's suppose the assets are being depreciated using the Modified Accelerated Cost Recovery System (MACRS) and have a useful life of five years because the question leaves this information out. The desk for the workplace was bought on April 15, 2018. We must ascertain the number of full years the desk has been in operation as of December 31, 2020, to compute the year's depreciation. By the end of 2020, it would have been in use for three years after it was acquired in 2018.
Using MACRS, the depreciation percentages for the 5-year property are as follows:
Year 1: 20%
Year 2: 32%
Year 3: 19.20%
Year 4: 11.52%
Year 5: 11.52%
Year 6: 5.76% (if applicable)
Since we're calculating depreciation for the 3rd year, we'll use the Year 3 depreciation percentage of 19.20%.
Depreciation for the office desk in 2020:
Depreciation = Cost of the desk × Depreciation percentage
Depreciation = $950 × 19.20% = $182
The executive-style chairs were purchased on August 5, 2018. They would also have been in service for 3 full years by the end of 2020. Using the same depreciation percentages, the depreciation for the chairs in 2020 would be:
Depreciation = Cost of the chairs × Depreciation percentage
Depreciation = $1,900 × 19.20% = $364
Now, let's calculate the total depreciation amount for 2020 by adding the depreciation of the desk and chairs:
Total Depreciation = Depreciation of the desk + Depreciation of the chairs
Total Depreciation = $182 + $364 = $546
Given the answer choices provided, none of them match the calculated total depreciation amount of $546. However, the closest answer is an option I: $547.
The total depreciation amount for 2020 is $547.
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Please help!!! I'll mark you as brainliest!!!!
What is 0.504854369 as a percentage rounded to the nearest tenth
To test the hypothesis that the population mean mu 6.0. a sample siren-29 yields a samole mean 6.42S and sample standard deviation 7.440 Calculate the value and choose the correct conclusion.
Since our test statistic is smaller than this critical value, we can conclude that the sample mean of 6.42 is not statistically significant and therefore cannot be used to reject the null hypothesis that the population mean is 6.0.
The first step here is to calculate the test statistic, which is also called a t-statistic or a z-score. This is done by subtracting the population mean from the sample mean, and dividing this difference by the standard deviation of the sample (dividing by the standard error if the population standard deviation is known). In this case, we have:
Test Statistic = (Sample Mean - Population Mean) / (Sample Standard Deviation / √n)
Test Statistic = (6.42 - 6.0) / (7.44 / √29)
Test Statistic = 0.42 / (7.44 / 5.385)
Test Statistic = 0.42 / 1.377
Test Statistic = 0.305
Now that we have the test statistic, we can compare it to the t-table or z-table (depending on if the population standard deviation is known) to determine whether or not the calculated value is statistically significant. For example, if we assume a 95% confidence level, the critical value of z (the p-value) is 1.96.
Since our test statistic is smaller than this critical value, we can conclude that the sample mean of 6.42 is not statistically significant and therefore cannot be used to reject the null hypothesis that the population mean is 6.0.
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Jane is making quarterly contributions of of $280 to her savings account which pays interest at the APR of 6.6%, compounded quarterly. Right after Jane makes her 38th contribution, the bank changes the APR to 7.5% and Jane makes 49 more $280 contributions. What is Jane's balance right after her last contribution?
Jane's balance right after her last contribution is $23,679.09.
Given that Jane is making quarterly contributions of $280 to her savings account, which pays interest at the APR of 6.6%, compounded quarterly.
The formula to find the interest rate is given as;A = P(1 + r/n)^(nt)
Where;P = $280r = 6.6% or 0.066n = 4 t = 38A = 280(1 + 0.066/4)^(4 * 38)= 280 (1.0165)^152A = $12,734.71
Jane's balance right after her last contribution at 7.5% after 49 contributions would be calculated as;P = $280r = 7.5% or 0.075n = 4 t = 49A = P(1 + r/n)^(nt)A = 280 (1 + 0.075/4)^(4 * 49)= 280 (1.01875)^196A = $23,679.09
Therefore, Jane's balance right after her last contribution is $23,679.09.
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Write 3.41 x 106 in standard form
(24 points)
Answer:
3,410,000
Step-by-step explanation:
3.41 * 10^6 = 3.41 * 1,000,000 = 3,410,000
Answer:
3,410,000
plz mark me as brainliest
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
HELP I NEED HELP ASAP
Answer:
the answer is no. D
Step-by-step explanation:
Answer:
Oh, yes it is D
A number pattern starts with 10 and follows the rule multiply by 3." What is true
about all of the numbers in this pattern?
1:They have a 3 in the tens place.
2:They have a 0 in the ones place.
3:They are odd numbers.
4: They can be odd or even numbers.
Answer:
1. and 2. I belive are true sorry if wrong
Step-by-step explanation:
Which point A,B,C or D is in the solution
set of the inequality graphed below?
Answer:
I would need to see the graph to answer this question.
Original Price Percent of Discount Sale Price
$112 32%
Answer:
32 percent of 112 is 35.84. 112 -35.84=76.16
Step-by-step explanation:
Brainliest?
Answer:
35.84
Step-by-step explanation:
I used a online calculator
Okay, so I need the one step equation for this question: Lee drove 420 miles and used 15 gallons of gasoline. How many miles did Lee's car travel per gallon of gasoline. I really need the one step equation version, as I know the number is 28. Please help me!
solve the following question
Given:
The expressions are:
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}[/tex]
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}[/tex]
To find:
The simplified form of the given expressions.
Solution:
We have,
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}[/tex]
It can be written as:
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{12a^{2+1}bc^3}{40b^4c^2}[/tex]
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{3a^{3}c^{3-2}}{10b^{4-1}}[/tex]
[tex]\dfrac{2a^2b}{2c^2}\cdot \dfrac{6ac^3}{20b^4}=\dfrac{3a^{3}c^{1}}{10b^3}[/tex]
Therefore, the value of the given expression is [tex]\dfrac{3a^{3}c}{10b^3}[/tex].
We have,
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}[/tex]
It can be written as:
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}=\dfrac{(x+y)(x-y)}{4(x+y)}\cdot \dfrac{x+y}{x-y}[/tex]
[tex]\dfrac{x^2-y^2}{4x+4y}\cdot \dfrac{x+y}{x-y}=\dfrac{x+y}{4}[/tex]
Therefore, the value of the given expression is [tex]\dfrac{x+y}{4}[/tex].
Drag and drop each pair of lines to categorize them as either parallel, perpendicular, or neither.