1.9. determine whether or not each of the following signals is periodic. if a signal is periodic, specify its fundamental period.

True: A Chorochromatic map is a type of cartographic map that represents features depending on how they are distributed across the surface in terms of quality.`

We have,

The art and science of cartography involves visually depicting a geographic location, typically on a flat surface like a map or chart. It could include superimposing a region's depiction with non-geographical distinctions like political, cultural, or other ones.

Making and utilizing maps is the theory and application of cartography. Cartography, which combines science, aesthetics, and method, is based on the idea that reality may be described in ways that effectively convey spatial information. The same basic components are included on most maps: the main body, the legend, the title, the scale and orientation indications, the inset map, and the source notes.

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complete question:

a cartographic map style that symbolizes features based on the qualitative surface distribution of a mapped feature is called a chorochromatic map.

Answer:

f(1) = 15

f(n) = f(n-1) x n

Step-by-step explanation:

The sequence in recursive form is:

f(1) = 15

f(n) = f(n-1) x n

Using this recursive formula, we can find the value of any term in the sequence by calculating the value of the previous term and multiplying it by the index of the current term.

For example, to find the value of f(2), we would use the formula:

f(2) = f(1) x 2

f(2) = 15 x 2

f(2) = 30

Similarly, to find the value of f(3), we would use the formula:

f(3) = f(2) x 3

f(3) = 30 x 3

f(3) = 90

And to find the value of f(4), we would use the formula:

f(4) = f(3) x 4

f(4) = 90 x 4

f(4) = 360

We can continue using this formula to find the values of any term in the sequence.

Answer:

A formula that uses one or more previous terms to find the next term is a recursive formula.

Step-by-step explanation:

A recursive formula is a formula that defines any term of a sequence in terms of its preceding term(s).

Answer:

3.142 in 2 decimal is 3.100

Step-by-step explanation:

When we come to diameter of 8cm I don't know

The vertex form of the given quadratic equation is.

y = -5(x + 6)² - 356

To complete squares we need to use the perfect square trinomial:

(a + b)² = a² + 2ab +b²

Here we can rewrite our quadratic as follows:

y = -5x² - 60x - 176

y = -5*( x² + 12x) - 176

y = -5*( x² + 2*6x) - 176

Now we can add and subtract 6² = 36 then we will get:

y = -5*( x² + 2*6x + 36 - 36) - 176

y = -5*( (x + 6)² - 36) - 176

y = -5(x + 6)² - 356

Which means that the vertex is at (-6, -356)

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Answer:

The common difference is 2.

Answer:

The common difference of the arithmetic sequence 14, 16, 18 is **2**.

In any arithmetic sequence, each term is equal to the previous term plus the common difference. So, the second term is equal to the first term plus the common difference. In this case, the second term, 16, is 2 more than the first term, 14. Therefore, the common difference is 2.

We can also find the common difference by subtracting any two consecutive terms in the sequence. For example, we can subtract the second term from the third term to get 18 - 16 = 2.

The common difference of an arithmetic sequence is always constant. This means that the difference between any two consecutive terms in the sequence will always be the same. In this case, the difference between any two consecutive terms is 2.

Step-by-step explanation:

Answer:

Please leave more information regarding the question thank you

Answer:

Probability of George picking black pants and a green shirt is 2/13

Probability of George picking a green shirt is 6/7

Probability of George not choosing a blue shirt 5/7

Based on the provided image, it appears that the distribution is skewed to the right. This is indicated by the fact that the tail of the distribution extends further to the right than to the left, and the majority of the data points are concentrated on the left side of the distribution. Therefore, the answer would be B, it is skewed.

The double integral of x² 2y over the given region (bounded by y = x, y = x³, and x > 0) is 2/35.

To solve this double integral, we need to integrate the function x² 2y over the given region in the xy-plane.

The region is bounded by the curves y = x and y = x³, and the line x = 0.

First, we need to determine the limits of integration. Since x > 0,

we can integrate from x = 0 to x = 1.

For each value of x in this range, the lower bound of y is given by y = x, and the upper bound is given by y = x³.

Therefore, we need to integrate with respect to y from y = x to y = x³ for each value of x in the range [0, 1].

So, the double integral can be written as:

∫(0 to 1) ∫(x to x³) x² 2y dy dx

Integrating with respect to y first, we get:

Therefore, the double integral of x² 2y over the given region is 2/35.

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Hence,0.72 rather than to increase the radius to meet their requirements.

A cone is a three-dimensional geometric form with a plane base and a smooth tapering vertex. A cone is made up of a collection of line segments, half-lines, its  lines that connect the apex of the common point at to every point on a base that is in a flat  other than the apex. 

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using  US-standard units ,SI-derived units, as well as several imperial  Volume and the notion of length are connected.

Let the new radius x and the old radius as r. The formed volume was 175 cubic cm, and the new container height is 5 cm,

V = [tex]\frac{1}{3}\pi r^2h[/tex], where V is the volume, r is the radius, and h is the height, is the formula for a cone volume.

We can construct an equation using the previous volume:

175 =    [tex]\frac{1}{3}\pi r^2h[/tex]

the height is same for new and old container , so,:

175 =[tex]\frac{1}{3}\pi r^2*5[/tex]

175 = [tex]\frac{5}{3}\pi r^2[/tex]

By multiplying both sides by (5/3)

[tex]r^2 = \frac{175*3}{5*\pi}[/tex] ≈ 22.3 use [tex]\pi[/tex]=3.14

When both sides are square root

r ≈ 4.72

Therefore, the old container  radius is 4.72 cm.

now,We subtract the old radius from the new radius for  determine how much the radius must increase to s the new container:

x - r ≈ 4 - 4.72 ≈ -0.72

Because the new radius is lower than the old radius, the outcome is negative.

We would need to reduce the radius by roughly 0.72 cm rather than expand it to satisfy the needs of the new container.

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The result cos²(α) = -2 is not possible, as the square of cosine must be between 0 and 1. It appears there might be an error in the given information. Please double-check the values and try again.

Given that cos(2α) = -5 and that it terminates in quadrant I, we need to find the exact value of sin(α).

First, let's recall the Pythagorean identity: sin²(α) + cos²(α) = 1.

Since cos(2α) = -5, we need to find the value of cos(α). In order to do this, we'll use the double-angle formula for cosine: cos(2α) = 2cos²(α) - 1.

Now, we can plug in the given value of cos(2α) and solve for cos(α):
-5 = 2cos²(α) - 1
-4 = 2cos²(α)
cos²(α) = -2

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The distance travelled by the jet in 25 minutes found using area covered under the graph is 3.7 miles.

What is area?

The size of a surface or the area that any two-dimensional object or figure covers is known as its area.

Area of triangle = [tex]\frac{bh}{2}[/tex]

Area of rectangle=l x w

The area covered under graph= area of triangle+ area of rectangle

                                                   = [tex]\frac{bh}{2}[/tex] + l x w

Dimension of triangle:

base(time on x-axis)=5 seconds

height(speed on y-axis)= 600 miles per hour

                                      =600÷3600 miles per seconds

                                       =0.167 miles per seconds

Dimensions of rectangle:

length(time on x-axis):25-5 =20 seconds

width(speed on y-axis)= 600 miles per hour

                                      =600÷3600 miles per seconds

                                       =0.167 miles per seconds

Distance = The area covered under graph

              = area of triangle+ area of rectangle

               = [tex]\frac{bh}{2}[/tex] + l x w

               =[tex]\frac{5(0.167)}{2}[/tex] + 20(0.167)

               =0.4175 + 3.34

                =3.7575

Distance ≈3.7 miles

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The MLE for u is the sample mean and the MLE for 02 is the sample variance.

To find the maximum likelihood estimators (MLEs) for both u and 02, we need to first write down the likelihood function.

The likelihood function for a normal distribution with unknown mean u and unknown variance 02 is given by:

L(u,02|X1,X2,...,Xn) = (2π02)^(-n/2) exp[-1/(2*02) Σ(Xi-u)^2]

Taking the natural logarithm of the likelihood function, we get:

log L(u,02|X1,X2,...,Xn) = -n/2 log(2π02) - 1/(2*02) Σ(Xi-u)^2

To find the MLE for u, we differentiate the log likelihood function with respect to u and set it equal to zero:

d/d u log L(u,02|X1,X2,...,Xn) = 1/(2*02) Σ(Xi-u) = 0

Solving for u, we get:

u = ΣXi / n

Therefore, the MLE for u is simply the sample mean.

To find the MLE for 02, we differentiate the log likelihood function with respect to 02 and set it equal to zero:

d/d(02) log L(u,02|X1,X2,...,Xn) = -n/(2*02) + 1/(2*02^2) Σ(Xi-u)^2 = 0

Solving for 02, we get:

02 = Σ(Xi-u)^2 / n

Therefore, the MLE for 02 is simply the sample variance.

In summary, the MLE for u is the sample mean and the MLE for 02 is the sample variance.

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A) Length A = 5 ft and width B= 4 ft

B) Volume of the water though = 88 [tex]ft^3[/tex]

What is volume?

The space taken up by any three-dimensional solid constitutes a volume, to put it simply. A cube, cuboid, cone, cylinder, or sphere can be one of these solids. Cubic units are used to measure the volume of solids. The volume will be given in cubic metres, for instance, if the dimensions are given in metres.

Here consider the prism plane figure the dotted lines are equal to the width,

Then width B= 8-4 = 4 ft

Length A = 8-3 = 5 ft

B) Now volume of rectangular prism = lwh cubic unit.

Volume of big prism = 8*2*3=48 [tex]ft^3[/tex]

Volume of small prism = 5*4*2 = 40 [tex]ft^3[/tex]

Then Total volume = 48+40 = 88  [tex]ft^3[/tex]

Hence in the rectangular prisms,

A) Length A = 5 ft and width B= 4 ft

B) Volume of the water though = 88 [tex]ft^3[/tex]

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Answer:

3x=12

divide boths by the coefficient of x

and x= 4

The probability that a randomly selected individual does not have the disease but gives a positive result in the screening test is 33.8%.

The probability of having the disease is P(A) = 0.15, so the probability of not having the disease is P(~A) = 1 - P(A) = 0.85.

Using Bayes' theorem:

P(~A|B) = P(B|~A) * P(~A) / [P(B|A) * P(A) + P(B|~A) * P(~A)]

= 0.1 * 0.85 / [0.7 * 0.15 + 0.1 * 0.85]

= 0.338

Therefore, the probability that a randomly selected individual does not have the disease but gives a positive result in the screening test is 0.338, or about 33.8%.

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Answer:

2j - c

Step-by-step explanation:

Let's use variables to represent the number of child and adult tickets sold on Wednesday.

Let c be the number of child tickets sold, and let a be the number of adult tickets sold.

We know that the price of a child ticket is $5.60, and the price of an adult ticket is $9.40.

From the problem statement, we know that 177 tickets were sold in total, so:

c + a = 177

We also know that the total revenue from ticket sales was $1352.20, so:

5.60c + 9.40a = 1352.20

Now we have a system of two equations with two variables. We can solve for a by using the first equation to express c in terms of a, and then substituting into the second equation:

c + a = 177 --> c = 177 - a

5.60c + 9.40a = 1352.20

Substituting c = 177 - a into the second equation, we get:

5.60(177 - a) + 9.40a = 1352.20

Expanding and simplifying:

992.20 - 5.60a + 9.40a = 1352.20

3.80a = 360

a = 95

Therefore, 95 adult tickets were sold on Wednesday.

Its bugging out but I got 95 tickets I would add explanation if it didn't act out.

X=Adult tickets

Y=Child tickets

X+Y=117

Y=117-X

9.40X+5.60Y=1352.20

9.40X+5.60(117-X)=1352.20

9.40X+991.20-5.60x=1352.20

3.80X=361

X=95

The derivative of x = 2 of the given function its value is -13/4.

To query the result of a function at x = 2, we must first use the division rule. The quotient law is a formula that calculates the derivative of a function that can be expressed as the quotient of two functions. Let

f(x) = h(x) and g(x) = x. We can express the function h(x)/x as f(x)/g(x). Now we can use the quotient rule like this:

d/dx(h(x)/x)) = d/dx(f(x)/g(x))

= [( g(x) * f '(x) )) - (f(x) * g'(x))] / (g(x))^2

= [(x * h'(x)) - (h (x) * 1) ] / x ^2

Now we can put the values ​​given as x = 2 and h(2) = 9 and h'(2) = -2 into the formula:

d /dx(h(x)/ x) ) x = 2 = [ (2 * (-2)) - (9 * 1)] / 2^2

= (-4 - 9) / 4

= -13/4

Therefore, the derivative of x = 2 of the given function its value is -13/4.

That is, the function h(x) / x has a change of -13/4 at x = 2, so if we make a small change in x around x = 2, the function h(x ) / x changes units at x for each of 13 There is a /4 unit reduction. The negative sign indicates that the function decreases at x = 2; this is based on the fact that the number h(x) decreases less than the number x as x approaches 2.

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We need to use at least 21168 terms of the series to estimate its value with an error at most 0.000001.

Explanation: -

To estimate the value of the convergent series ∑n=1[infinity] 2 n^(-1.1) with an error at most 0.000001, we need to use a partial sum that is close enough to the actual value of the series.

One way to approach this is to use the error bound formula for a convergent series:

|S - Sn| ≤ a_n+1/(1 - r),

where S is the actual sum of the series, Sn is the sum of the first n terms of the series, an+1 is the (n+1)th term of the series, and r is the common ratio (in this case, r = 1/2^(1.1)).

We want to find the value of n such that the error |S - Sn| is at most 0.000001.

Plugging in the given values, we get:

0.000001 ≤ 2(n+1)^(-1.1)/(1 - 1/2^(1.1))

Solving for n using a calculator or computer algebra system, we get n ≈ 21168.

Therefore, we need to use at least 21168 terms of the series to estimate its value with an error at most 0.000001.

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The standard errors of the proportion for sample sizes of 40, 80, and 120 are 0.0733, 0.0518, and 0.0422, respectively,

How to calculate the standard error of the proportion?

To calculate the standard error of the proportion for a population with a proportion equal to 0.32 and sample sizes of 40, 80, and 120, we can use the formula:

Standard Error (SE) = √[(p * (1 - p)) / n]

where p is the proportion (0.32), and n is the sample size.

For a sample size of 40:
SE = √[(0.32 * (1 - 0.32)) / 40]
SE ≈ 0.0733 (rounded to 4 decimal places)

For a sample size of 80:
SE = √[(0.32 * (1 - 0.32)) / 80]
SE ≈ 0.0518 (rounded to 4 decimal places)

For a sample size of 120:
SE = √[(0.32 * (1 - 0.32)) / 120]
SE ≈ 0.0422 (rounded to 4 decimal places)

So, for a population with a proportion equal to 0.32, the standard errors of the proportion for sample sizes of 40, 80, and 120 are approximately 0.0733, 0.0518, and 0.0422, respectively, when rounded to 4 decimal places.

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It can be used to partition the nodes of the graph into two sets. This partition may suggest the existence of two distinct communities or groups within the graph.

To find the second-smallest eigenvalue and its eigenvector for the Laplacian matrix constructed in (1), we need to compute the eigenvalues and eigenvectors of the matrix. Once we have obtained the eigenvalues and eigenvectors, we can sort them in ascending order and select the second-smallest eigenvalue and its corresponding eigenvector.

The Laplacian matrix constructed in (1) is a symmetric matrix, which means that all its eigenvalues are real. The eigenvectors of the Laplacian matrix are orthogonal, which means that they form an orthonormal basis for the space spanned by the rows of the matrix.

Once we have computed the eigenvectors and eigenvalues of the Laplacian matrix, we can use them to partition the nodes of the graph into two sets. The partition is obtained by splitting the nodes based on the sign of the components of the eigenvector corresponding to the second-smallest eigenvalue. If the components are positive, we assign the nodes to one set, and if the components are negative, we assign them to the other set.

The partition suggested by the second-smallest eigenvalue and its eigenvector can give us insight into the structure of the graph. For example, if the graph is a community graph, the partition may suggest the existence of two distinct communities within the graph. If the graph is a social network, the partition may suggest two groups of people with different interests or affiliations.

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Factors (1) x² - 11x + 28 = (x-4)(x-7), (2) 2x² + 8x + 6 = 2(x+1)(x+3), (3) k² - 25 = (k+5)(k-5), (4) a² - 9a + 20 = (a-5)(a-4), (5) 7x² - 11x - 6 = (7x+2)(x-3) , (6) 14x² - 52x + 30 = 2(7x-3)(x-5), (7) 6n³ - 8n² + 3n - 4 = (2n-1)(3n²-2n+4), (8) 15y³ - 3v² + 20v - 4 = (5y-1)(3y²+1)(4-v)

Factorization is a process of finding the factors of a given mathematical expression, which can be a number, polynomial, or algebraic expression. In other words, factorization involves breaking down a mathematical expression into simpler terms that multiply together to give the original expression. For example, the factors of the expression x^2 - 4 are (x + 2)(x - 2).

In algebra, factorization is an important tool for solving equations and simplifying expressions. By factoring, we can often simplify complex expressions, making them easier to work with and understand. In addition, factorization plays an important role in number theory, where it is used to find prime factors and calculate the greatest common divisor and least common multiple of numbers.

(1) x² - 11x + 28 = (x-4)(x-7)

(2) 2x² + 8x + 6 = 2(x+1)(x+3)

(3) k² - 25 = (k+5)(k-5)

(4) a² - 9a + 20 = (a-5)(a-4)

(5) 7x² - 11x - 6 = (7x+2)(x-3)

(6) 14x² - 52x + 30 = 2(7x-3)(x-5)

(7) 6n³ - 8n² + 3n - 4 = (2n-1)(3n²-2n+4)

(8) 15y³ - 3v² + 20v - 4 = (5y-1)(3y²+1)(4-v)

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Based on the terms you provided, I can help you identify the true statement(s):

1. As the sample size n increases, the distribution of the sum of the observations approaches a normal distribution.
2. The sample mean varies from sample to sample.
3. If the underlying population is not normal, the Central Limit Theorem (CLT) states that the distribution of the sample mean X approaches a normal distribution as the sample size n increases.
These statements are true. Note that the statement "As the sample size n increases, the variance of the sample mean X also increases" is incorrect, as the variance of the sample mean actually decreases when the sample size increases. Additionally, the statement "The distribution of the mean X is never exactly normal" is not universally true, as the distribution of the mean can be exactly normal under specific circumstances.

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Answer:

Every day, 33% of locusts are added to the locust population

8 is the value of x in parallel lines.

With an example, what is a parallel line?

Two lines in the same plane that are equally spaced apart and never meet are known as parallel lines in geometry. They can be either vertical or horizontal.

                      Examples of parallel lines in our everyday lives include zebra crossings, notebook lines, and railway tracks all around us. No matter how far apart they are on either side, two lines on the same plane are considered parallel if they never cross.

given

      m ║n

 8x - 10 + 126 = 180°

  8x + 116 = 180°

  8x  = 180° - 116

    8x = 64

      x = 64/8

       x = 8

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Answer:

If you're asking if its possible, yes it is