18. At my son's birthday party, we had a piñata that we filled with 140 pieces of candy. If there were 42 Hershey
chocolate bars, what percent of the candy was Hershey chocolate bars?
19. On a recent test, there were 15 multiple-choice questions and 25 fill-in-the-blank problems. What percent of
the problems were fill-in-the-blank problems? (Hint: How many problems were on the entire test.)

Answer:

70 yd²

Step-by-step explanation:

Area of triangle = (1/2)(base)(perpendicular height)

= (1/2)(20)(7)

= 70 yd²

Answer:

Answer B will be the best answer for your question.

Step-by-step explanation:

Polygons usually have straight sides, but this one does not.

There is 1820 ways of teams of 4 can she make without repetition using combination formula.

What is combination?

  Selections are another name for combinations. The choice of items from a predetermined group of items corresponds to combinations. We don't want to organise anything here. We are going to choose them. We use the notation nCr to indicate how many distinct r-selections or combinations there are among a set of n objects. A combination is distinct from an arrangement or a permutation. No matter how the objects are arranged, combinations are produced by choosing some or all of them.

Here There are 16 total swim team members and 4 swimmers that will be chosen for each relay team.

So, n=16 and r=4. Then

=> nCr =  [tex]\frac{n!}{r!(n-r)!}[/tex]

=> 16C4 = [tex]\frac{16!}{4!(16-4)!}[/tex]

=> 16C4 = [tex]\frac{16!}{4!*12!}[/tex]

=> 16C4 = [tex]\frac{16*15*14*13}{4*3*2*1}[/tex]

=>16C4 = 4*5*7*13 = 1820

Hence there is 1820 ways  of teams of 4 can she make without repetition.

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Answer:

Alli khanaw .................

Answer:

8x^36

Step-by-step explanation:

first term (a) = [tex]8x^{8}[/tex]

Second term (t2)= [tex]8x^{12}[/tex]

common ratio (r)

= [tex]\frac{8x^{12} }{8x^{8} }[/tex]

= [tex]x^{4}[/tex]

now the 8th term of the G.S is

t8 = [tex]ar^{n-1}[/tex]

  = [tex]8x^8 * (x^4)^8^-^1[/tex]

  = [tex]8x^8 * (x^4)^7\\[/tex]

  = [tex]8x^8 *x^2^8\\= 8x^3^6[/tex]

hope it will help

Answer:

NO

Step-by-step explanation:

The sum of the lengths of any two sides of a triangle is greater than the length of the third side. And this MUST true for ALL combinations

12 +8    IS NOT greater than 20

4x +2x+2 +x+3 = 40

7x +5=40

7x =3 5

x=5

side 4x  =  20

side x+3 = 8

side 2x+2 = 12

            20 +8 is bigger than 12

             20+12 is   bigger than 8

             12 + 8  IS NOT BIGGER than 20  (it's just the same)

Answer:

x = 6

Step-by-step explanation:

3x - 6 = 12

3x = 18

x = [tex]\frac{18}{3}[/tex]

x = 6

Answer:

length =  18yd

Width = 10yd

Step-by-step explanation:

Complete question

A rectangular parking lot has a length that is 8 yards greater than the width. The area of the parking lot is 180 square yards. Find the length and the width.

Area of the parking lot - length * width

A = LW

Given

Area = 180sq. yd

If the parking lot has a length that is 8 yards greater than the width, then;

L = 8 + W

The area becomes;

A = (8+W)W

180 = 8W+W²

W²+8W - 180 = 0

W²+18W-10W - 180 = 0

W(W+18)-10(W+18) = 0

(W-10)(W+18) = 0

W-10 = 0

W = 10yd

Since L = 8 + W

L = 8 + 10

L = 18yd

Hence the length and the width area 18yd and 10yd respectively

Answer:

96

Step-by-step explanation:

Its a pattern :) BTW can you help with mine please

Answer:

okAy

Step-by-step explanation:

hypo(square) = altitude(square)+base,(square)

so hypo(square) =300(square)+400(square)

Answer:

500

Step-by-step explanation:

300² + 400² = 500²

pythagorean theorem

Answer:

NK=12

Step-by-step explanation:

x^2 +9^2=15^2

x^2+81=225

subtract 81

x^2=144

x=12

(This is only for number 13, I don't know the answer to 14-16)

Using the Pythagoras theorem, the value of NK is 12.

The sum of the squares of the lengths of the other two sides of a right triangle equals the square of the hypotenuse's length.

It is given that, NL=9, and KL=15.

Use the Pythagoras theorem,

[tex]& \Rightarrow {{15}^{2}}=N{{K}^{2}}+{{9}^{2}} \\ & \Rightarrow 225-81=N{{K}^{2}} \\ & \Rightarrow NK=\sqrt{144} \\ & \Rightarrow NK=12 \\[/tex]

Therefore, the value of NK is 12.

Learn more about the Pythagoras theorem, here

https://brainly.com/question/343682

Answer:

-6

Step-by-step explanation:

you should add two sums to get higher equation that means he took 45 minutes last year that is

42+3=45

Answer:

364yd^2

Step-by-step explanation:

LxWxH

Answer:

its 364

Step-by-step explanation:

you do length times width times height

Answer:

Step-by-step explanation:

17 meters because 5^2+12^2=17 meaning the answer must be d

Answer:

yes you are right! the answer is c

Step-by-step explanation:

**reminder: the hypotnuse is always your longest side**

first do 5 square = 25

then do 12 squared = 144

now add 25+144= 169

and finally you do 169 square root which equals 13

Hope this helped!

Answer:

673.8

Step-by-step explanation:

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z)  is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant  ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

Answer:wheres the question

sadStep-by-step explanation:

sadsadsa

the answer would be 0.9583

Answer:

C.

Step-by-step explanation:

Answer:

A.) Function one has a larger maximum at (4,1)

Step-by-step explanation:

The function f(x) = -x² + 8x - 15 will have larger maximum at ( 4,1 ) so option (B) will be correct.

A certain kind of relationship called a function binds inputs to essentially one output.

In other words, the function is a relationship between variables, and the nature of the relationship defines the function for example y = sinx and y = x +6 like that.

A function can be regarded as a computer, which is helpful.

Given 1 function,

f(x) = -x² + 8x - 15  

f(x) = -(x² - 8x + 15 )

f(x) = - [(x - 4)² - 16 + 15 ]

f(x) = -(x-4)² + 1

So vertex will at ( 4,1 )

In function 2,

f(x) =  −x² + 2x − 3

f(x) = - [ x² - 2x + 3 ]

f(x) = -[ (x-1)² - 1 + 3 ]

f(x) = - (x-1)² - 2

So vertex will at ( 1, -2 )

Since in function(1) maximum is at y = 1 while in function (2) maximus is at y = -2

Hence Function 1 has the larger maximum at (4, 1).

For more about the function

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Answer:

30 degrees

Step-by-step explanation:

<ACB is a central angle while <ADB is an inscribed angle.

Central angles are twice the size of inscribed angles.

Therefore, <ADB*2 = <ACB . 15*2=30

Answer:

217945728000 ways

Step-by-step explanation:

Given

[tex]Books = 12[/tex] --- 1 dozen

[tex]Shelf = 4[/tex]

The given condition implies that;

[tex]Book\ 1 = 4[/tex] ---- any of the 4 shelves

[tex]Book\ 2 = 5[/tex] --- any of the 4 shelves and either ways of book 1

[tex]Book\ 3 = 6[/tex]  --- any of the 4 shelves and either ways of book 1 and 2

-----------------------

----------------

----------

So, the number of ways is:

[tex]Ways = 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11 * 12 * 13 * 14 * 15[/tex]

[tex]Ways = 217945728000[/tex]

Answer:

Once Kenny gets 6 hats sold, he could gain the $3 he spent back, and once Ben sells 4 hats, he could gain the $1 he spent back.

Step-by-step explanation:

The limit as g(x) approaches 11 doesn't exist.

[tex]\lim_{x \to 11} g(x) = DNE[/tex]

It looks like you are working with the following piecewise defined function:

[tex]g(x)=\left \{ {{-9;x<11} \atop {7;x\geq11}} \right.[/tex]

There is a rule in calculus that tells us that for a limit to exist, both lateral limits must be the same as x approaches a given value. This is:

[tex]\lim_{x \to a^{-}} f(x)=\lim_{x \to a^{+}} f(x)[/tex]

if and only if this is true, then:

[tex]\lim_{x \to a^{-}} f(x)=\lim_{x \to a^{+}} f(x)=\lim_{x \to a} f(x)[/tex]

if that condition isn't met, then the limit doesn't exist.

So let's calculate the lateral limits for this function:

[tex]\lim_{x \to 11^{-}} g(x) = -9[/tex]

This means that as x approaches 11 from the left, the function will return a value close to -9

Now, let's calculate the lateral limits for this function:

[tex]\lim_{x \to 11^{+}} g(x) = 7[/tex]

This means that as x approaches 11 from the right, the function will return a value close to 7

You can better visualize this in the graph of the function which I attached to this answer.

Notice that both lateral limits are different, from the left you got a -9 and from the right you got a 7. Therefore, according to the rule I wrote above, the limit does not exist.

For more information on this topic, you can go to the following link:

https://brainly.com/question/17334531?referrer=searchResults

Answer:

D) DNE

Step-by-step explanation:

edge 2021

Answer:

need points

Step-by-step explanation: