11. Twelve samples of water form a particular source have an average lead concentration of 12.5µg/L with a standard deviation of 2.0µg/L. 1 (a) Find a 95% confidence interval for the lead concentration in water from this source. (b) Can you conclude that the lead concentration is less than 14µg/L?

Answers

Answer 1

Answer:

a) The 95% confidence interval for the lead concentration in water from this source is between 11.23 µg/L and 13.77 µg/L.

b) The upper bound of the confidence interval is less than 14 µg/L, which means that yes, we can conclude that the lead concentration is less than 14µg/L.

Step-by-step explanation:

We have the standard deviation for the samples, which mean that the t-distribution will be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 12 - 1 = 11

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 11 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.201

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.201\frac{2}{\sqrt{12}} = 1.27[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12.5 - 1.27 = 11.23 µg/L.

The upper end of the interval is the sample mean added to M. So it is 12.5 + 1.27 = 13.77 µg/L.

The 95% confidence interval for the lead concentration in water from this source is between 11.23 µg/L and 13.77 µg/L.

(b) Can you conclude that the lead concentration is less than 14µg/L?

The upper bound of the confidence interval is less than 14 µg/L, which means that yes, we can conclude that the lead concentration is less than 14µg/L.


Related Questions

What is the simplified value of the expression below?

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21.38
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Answers

Answer:

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Step-by-step explanation:

The simplification form of the provided expression is 18.25 option (A) is correct.

What is an expression?

It is defined as the combination of constants and variables with mathematical operators.

We have a mathematical expression:

[tex]= \rm \dfrac{7\times8+20(4.5)}{16\times0.5}[/tex]

= (56 + 90)/8

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= 18.25

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Step-by-step explanation:

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Answer:

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------------------

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer/Step-by-step explanation:

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https://www.calculator.net/volume-calculator.html

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9514 1404 393

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Answer:

165 centimeters

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Answers

Answer:

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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yes
no

Answers

Answer:

no

Step-by-step explanation:

7x+5y=15

(x,y)

(4,3)

put in 4 for x and 3 for y

7(4)+5(3)=15

43=15

This equation is impossible

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Step-by-step explanation:

7x+5y=15 (x=4,y=3)

7(4)+5(3)=15

28+15=15

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Answer:

14

Step-by-step explanation:

Because right angles are 90 degrees, we need to subtract 34 from 90 which gets us 56. That means 56 = 4x, so 56/4 = 14, therefore X = 14.

Hope this helps!

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Angle 2 would equal 90 degrees - angle 1

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So now we know 4x = 56

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Answers

Answer:

Could you add more info?

Step-by-step explanation:

For each of the following studies, say whether you would use a t test for dependent means or a t test for independent means.

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Answers

Answer:

1. T test for independent means

2. T test for dependent means

3. T test for dependent means

Step-by-step explanation:

In number 1, the two groups are unrelated. The first group has 25 subjects and they're all unemployed. The second group has 24 subjects and their employment status is not stated and might not be the same all through. Also, the first group is receiving a new type of job skills program while the second group is taking the standard job skills program.

- The groups in the experiment are unrelated

- The tests in the research are unrelated

- The purpose of the research is unreasonable - the researcher seeks to measure how well all 49 subjects perform on 'a' job skills test! No comparison between the scores or mean scores of the two groups.

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