1. Norah uses an ounce of butter to bake 13 cookies. How many cookies can she bake with 89 ounces of butter?​

Sebastian uses the method of similar triangles to find the distance across the river, and the distance across the river is 372 foot.

A triangle is a polygon with three sides and three vertices.

The triangle's total number of angles comes to 180°.

The distances between the formed the sight-lines are;

RB = 210 feet

OC = 275 feet

The distance between the point close to the river and the next point further from the river = 115 feet

In triangles ΔPRB and ΔPOC,

we have;

∠PRE = ∠POC = 90°

Given;

∠PER ≅ ∠PCO

By corresponding angle formed between two parallel lines and a common transversal.

Using angle-angle similarity theorem;

∴ ΔPRE is similar to ΔPOC Which gives;

PR / PO = RE / OC

Let x represent the distance across the river,

we have;

PR = x

PO = 115 + x

Which gives;

x / (115+x) = 210 / 275

275x = 210 × (115 + x)

275x = 24150 + 210x

275x - 210x = 24150

65x = 24150

x = 371. 54

Therefore, the distance across the river is 372 foot.

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The value of 1204.2 + 4.72613 is 1208.92613.

What is meaning of significant figures of a number?

Significant figures are the number of digits that add to the correctness of a value, frequently a measurement. The first non-zero digit is where we start counting significant figures. Determine how many significant digits there are given a range of numbers.

Given number is 1204.2 and  4.72613.

If add zeros after the last digit of the decimal number, then the number will remains same.

The rewrite form of 1204.2 is 1204.20000.

Before combining two decimal integers, make sure they both have the same number of digits after the decimal point. If they don't, move a number's right by a number of zeros until they do.

Then, place the decimal points vertically and write one number on top of the other. Bring the decimal point directly below the decimal point and add as you would with full numbers.

The sum of 1204.20000 and 4.72613

1204.20000

    +4.72613

__________

1208.92613

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The time that is left before the fossil fuel reserves run out would be= 2000 years.

A fossil fuel is defined as the type of fuel that is gotten from dead and decayed organic matter that has been buried for years underneath the earth surface.

The quantity of usable fossil fuel existing on earth = 2.1 x 10⁸metric tonnes.

The rate of fossil fuel used per year = 1 x 10⁵

Mathematically,

If 1 year = 1 x 10⁵

X years = 2.1 x 108

make X years the subject of formula;

X years = 2.1× 10⁸/1× 10⁵

X years = 2.1 × 10³ or 2100

X year = 2000( to one significant figure)

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Answer:

$44,334.34

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{8.5 cm}\underline{Continuous Compounding Formula}\\\\$ A=Pe^{rt}$\\\\where:\\\\ \phantom{ww}$\bullet$ $A =$ final amount \\\phantom{ww}$\bullet$ $P =$ principal amount \\\phantom{ww}$\bullet$ $e =$ Euler's number (constant) \\\phantom{ww}$\bullet$ $r =$ annual interest rate (in decimal form) \\\phantom{ww}$\bullet$ $t =$ time (in years) \\\end{minipage}}[/tex]

Given:

Substitute the given values into the continuous compounding formula and solve for A:

[tex]\implies A=6000e^{0.05 \times40}[/tex]

[tex]\implies A=6000e^2[/tex]

[tex]\implies A=6000(7.3890560...)[/tex]

[tex]\implies A=44334.33659...[/tex]

Therefore, the balance of the account after 40 years will be $44,334.34 (nearest cent).

The correct hypotheses for this test are:

Null hypothesis (H0): The standard deviation of the mutual fund's monthly rate of return is greater than or equal to 3%.

Alternative hypothesis (H1): The standard deviation of the mutual fund's monthly rate of return is less than 3%.

To determine if there is sufficient evidence to reject the null hypothesis and conclude that the fund has moderate risk, you would need to perform a hypothesis test. In this case, since you have a sample of 27 monthly rates of return and the normal probability plot indicates that the data is normally distributed, you can use a z-test for the population standard deviation.

To perform the test, you would need to calculate the test statistic and the p-value. The test statistic is calculated as follows:

test statistic = (sample standard deviation - population standard deviation) / (standard error)

where the sample standard deviation is 2.55%, the population standard deviation is 3%, and the standard error is calculated as:

standard error = sample standard deviation / sqrt(sample size)

Plugging in the values, the test statistic is:

test statistic = (2.55 - 3) / (2.55 / sqrt(27)) = -0.44

The p-value is the probability of observing a test statistic at least as extreme as the one calculated, given that the null hypothesis is true. To calculate the p-value, you can use a z-table or a statistical software package.

If the p-value is less than the chosen level of significance (a=0.05 in this case), you can reject the null hypothesis and conclude that the fund has moderate risk. If the p-value is greater than the level of significance, you cannot reject the null hypothesis and cannot conclude that the fund has moderate risk.

The solution is once more 1.28 since a combined area of 0.10416 to the right implies that it must also have an area of 0.90 to the left.

Since each normally distributed random variable has a slightly different distribution shape, standardizing the variable to give it a mean of 0 and a standard deviation of 1 is the only method to determine regions using a table. How do we go about doing that? Employ the z-score!

Z = ( x - μ)/σ

If a mean and standard deviation are present for the random variable X,

Then a random variable with a mean of 0 and a standard deviation of 1 is produced by converting X using the z-score!

With that in mind, all that remains is to understand how to find areas under the standard normal curve, which can then be applied to any random variable with a normal distribution.

Since an area of 0.10416 to the right means that it must have an area of 0.90 to the left, the answer is once again 1.28.

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Part A:

The graph of the line intersects the x-axis at the point (4, 0).

Part B:

The point represents the distance of Shari from the home.

After 4 minutes, Shari rushed past her house.

A function graph is a visual representation of a relation. A function is actually equal to its graph in set theory and current mathematical foundations. For instance, when deciding whether or not a function is onto (surjective), a codomain should be taken into account. The graph of a function alone does not reveal the codomain. Although they relate to the same thing, the terms "function" and "graph of a function" communicate different perspectives on it, which is why they are commonly employed.

The line's x-intercept is 4 minutes.

The time Shari will arrive at her house is indicated by the 4 minutes.

Shari's distance from home on her run across town is represented by the line 6x - 3y = 24......... (1), where y stands for blocks, and x for minutes.

Therefore, when y = 0, we obtain 6x - 0 = 24, which equals x = 4, from equation (1) above.

As a result, 4 minutes is the x-intercept of the line (1).

It is stated that Shari will get at her house in 4 minutes, and there are no blocks between them.

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The area of rectangle with has its vertices defined on parabola is 32 square units.

An example of a quadrilateral with equal and parallel opposite sides is a rectangle. It is a polygon with four sides and four angles that are each 90 degrees. A rectangle is a shape with only two dimensions.

Square, figure, oblong, parallelogram, plane a.re terms to describe rectangle

Equation of Parabola is y = 12 - x^2 is an even function.

Therefore, its rectangle form also is even at the origin.

We know area of rectangle = length × width

Here,

length = 2x, width = y

Area, A = 2x(12 - x2)

⇒ A = 24x - 2x^3

Take derivative of A with respect to x

⇒ A' = 24 - 6x^2

The area is largest when A' = 0

⇒ 24 - 6x^2 = 0

⇒ x^2 = 4

⇒ x = 2

Put the value of x in y = 12 - x^2

⇒ y = 12 - 4

⇒ y = 8

Area = 2(2)(8) = 32

Therefore, the largest area of a rectangle is 32 square units.

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The rate per student for the gym is given as $5.

The arithmetic operations are the fundamentals of all mathematical operations. The example of these operators are addition, subtraction, multiplication and division.

The rent of gym for 30 students is $150.

And, for 70 students it is $350.

The rate of rent in both the cases can be found by taking the ratio as follows,

The unit cost in the first case = Total rent ÷ Number of students

                                                 =  150 ÷ 30 = $5  

And, the unit cost in the second case = 350 ÷ 70 = $5

Hence, the required rate is obtained as $5 per student for both the cases.

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The height of the cliff in terms of A, B and h are 40 meters.

A triangle is said to be right-angled if one of its inner angles is 90 degrees, or if any one of its angles is a right angle.

A man standing on the deck of a ship.

Let C be the position of man.

And the angles of elevation and depression of the top and the bottom of a cliff are A and B respectively 60° and 30°.

That means, ∠DCH = 60° and  ∠BCD = 30°.

The diagram is given in the attached image.

HD = x And BD = 10 meters.

In right-triangle ΔCDH,

we have,

tan60° = HD / CD

√3 = x / CD

CD = x/√3

In right-triangle  ΔCDB,

we have,

tan30° = BD/CD

CD = 10√3

So, the distance of the ship from the cliff is 10√3 meters.

Comparing, the both values of CD,

 10√3 =  x/√3

x  =  10√3 × √3

x = 10 × 3

x = 30 meters.

Now, the total height of cliff  = BD + DH

= 10 + 30

= 40 meters.

Therefore, the height of the cliff is 40 meters.

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By definition, perpendicular strains are strains intersecting at a proper attitude. The letters T and L are examples of perpendicular strains. By definition, parallel strains are strains at the equal aircraft that in no way intersect.

The letters N and Z include pairs of parallel linetwo non-vertical strains which are withinside the equal aircraft has the equal slope, then they may be stated to be parallel. Two parallel strains might not ever intersect. If non-vertical strains withinside the equal aircraft intersect at a proper attitude then they may be stated to be perpendicular.

We can decide from their equations whether or not strains are parallel with the aid of using evaluating their slopes. If the slopes are the equal and the y-intercepts are different, the strains are parallel. If the slopes are different, the strains aren't parallel. Unlike parallel strains, perpendicular strains do intersect.

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Answer:

r = 2/ r = -2/3

Step-by-step explanation:

so you move the terms to the left side

6r^2 - 8r = 8

6r^2 -8r - 8 = 0

the common factor

6r^2 - 8r -8 = 0

2(3r^2 - 4r - 4) = 0

then you divideboth side by the same factor

2(3r^2 - 4r - 4) = 0

3r^2 - 4r - 4 = 0

use the quadratic formula

you would get 2.3

then you simplify

r = 4+8 over 6

seperate the equations

r = 4+8 over 6 change the plus into a minus

after that rearrange and issolate variable

r = 2

r = -2/3

therfore your answer is -2/3

The least to greatest of the ratio is 18 : 32, 5 : 8, and 11 : 16

Least to greatest arrangement can also be referred to as ascending order. Ascending order is the order such that each element is greater than or equal to the previous element.

5 : 8

= 5/8

= 0.625

11 : 16

= 11/16

= 0.6875

18 : 32

= 18/32

= 0.5625

Therefore, the ratio can be arranged as 18 : 32, 5 : 8, and 11 : 16 in ascending order.

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Answer:

It can be any number.

Step-by-step explanation:

The x xalue is an independent variable, which means its value does not depend on that of another variable (y)

The solution for the given inequality is -6 < x < 9.

What is linear equality?

In mathematics a linear inequality is an inequality that involves a linear function. A linear inequality contains one of the symbols of inequality. It shows the data which is not equal in graph form.

The given inequality is:

         -7 < x - 1 < 8

       −7 + 1 < x − 1 + 1 < 8 + 1 -------- (Add 1 to all parts)

             -6 < x < 9

Hence, the solution for the given inequality is -6 < x < 9.

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We can write an equation to represent the relationship between the three integers n - 1, n, and n + 1 by multiplying these three numbers together:

We can then solve this equation to find the value of n.

To solve the equation, we can first factor the left-hand side to get (n - 1) * (n + 1) * n = 210. This expression can be further simplified to n^2 - 1 = 210. We can then solve this equation by adding 1 to both sides to get n^2 = 211, and then taking the square root of both sides to get n = sqrt(211).

The value of n must be an integer, so the only possible value for n is 14. This means that the three consecutive integers are 13, 14, and 15.

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g is continuous for all x in the interval [0,7] is correct statement that would be sufficient to conclude that there exists a number c in the interval [0,7] such that g (c) = 50.

Here the given function g(x) gives values for selected values of x.

Now we are to find a condition which will conclude that there exist a number 'c' in the interval [0,7] such that g(c)=50

If a function f : a, b [tex]\rightarrow[/tex] R be continuous on R with [tex]$\mathrm{f}(\mathrm{a}) \neq \mathrm{f}(\mathrm{b})$[/tex]  then the function f(x) attains every value between f(a) and f(b) at least once in the interval [a, b]

I. The option is false.

Because if the function is defined in the interval [0,7] then it is not necessary that there exist a point in this interval, where the function will attain the value 50.

II. The given option is false.

Because if the function is increasing in the interval [0,7] then it is not necessary that there exist a point in this interval, where the function will attain the value 50.

III. This option is correct.

Since g(0) = 24 and g(7) =  68 and 'g' is continuous on the interval [0,7] , so the function g(x) attains every value between 24 and 68 at least once in the interval [0,7].

That is there must be a point 'c' in the interval [0,7] such that g(c)=50.

Therefore option (B) is correct.

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Answer:

Step-by-step explanation:

To find the equation of the tangent to the circle 4x^2 + 4y^2 = 25 that is parallel to the line 3x + 5y + 7 = 0, we can use the following steps:

Rewrite the equation of the circle in standard form: (x - a)^2 + (y - b)^2 = r^2, where (a, b) is the center of the circle and r is the radius.

In this case, the equation of the circle is already in standard form, so we can skip this step.

Find the slope of the line 3x + 5y + 7 = 0. The slope is -3/5.

Find the slope of the tangent to the circle. The slope of the tangent will be equal to the slope of the line, which is -3/5.

Substitute the slope of the tangent and the coordinates of a point on the circle into the point-slope form of the equation of a line: y - y1 = m(x - x1), where (x1, y1) is a point on the circle and m is the slope.

In this case, we can substitute the coordinates of the center of the circle (which is (0, 0)) and the slope of the tangent (-3/5) into the point-slope form to get:

y - 0 = (-3/5)(x - 0)

Simplify to get the equation of the tangent: y = -3/5x.

Therefore, the equation of the tangent to the circle 4x^2 + 4y^2 = 25 that is parallel to the line 3x + 5y + 7 = 0 is y = -3/5x.

The relationship's slope and common difference are both 70 and constant.

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

here,
As the  relationship given in the table is linear,
The slope of the relationship is given as,
M = (y₂ - y₁) /  (x₂ - x₁)
Now, putting values from the table,
m = 140 - 70 / 2 - 1
m = 70 jumps per minute

Now,
The common difference between the consecutive minutes of jumping,
d = 140 - 70 = 210 - 140
d = 70 = 70

From the above evaluation, it can be said that the common difference and rate are constant.

Thus, the slope of the relationship and the common difference is 70, as well as constant.

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to estimate the average coffee intake of Coursera students, measured in cups of coffee. C) μ=0.55, σ=1 is not necessarily true.

Given that survey is of 1000 students so n = 1000, average is 0.55 cups per day  i.e. mean (x bar) = 0.55 and standard deviation is of 1 cup per day ,i.e. S.D (s) = 1 .

First, determine the mean. Step 2: Calculate the square of each data point's variance from the mean. Add the values from Step 2 in Step 3. Divide by the total number of data points in step 4.

Just because the sample statistics are these values doesn't mean the population values will be exactly equal to them, therefore it's not necessarily true μ=0.55, σ=1 .

C) μ=0.55, σ=1 is not necessarily true.

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The value of c(7) = 78 and 78 represents the monthly cost of visiting the gym 7 times.

To find p(a) for a given polynomial p(x) we need to substitute x = a in the given polynomial i.e in place of x.

Here we have

Function c is defined by the equation c(n) = 50 + 4n.

It gives the monthly cost, in dollars, of visiting a gym as a function of the number of visits n.  

Activity 1 of 2

Find the value of c(7).

=> c(7) = 50 + 4(7)

=> c(7) = 50 + 28

=> c(7) = 78

Activity 2 of 2

Explain what the value of c(7) you found means in this situation.

In c(n) = 50 + 4n, n represents the number of visits in a month and 50+4n will represent the monthly cost in dollars

If we apply the above statement to c(7) = 78

then 7 represents the number of visits and 78 represents the monthly cost of visiting the gym 7 times

Therefore,

The value of c(7) = 78 and 78 represents the monthly cost of visiting the gym 7 times.

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Answer:

  a.  k = -8/3 = -2 2/3

  b.  k = 32/5 = 6.4

Step-by-step explanation:

You want to find the values of k that place the point (k, 1) on the line through the point (4, -3) when that line is (a) parallel to 3x +5y = 10, and (b) perpendicular to 3x +5y = 10.

The equation of the parallel line will have the same x- and y-coefficients, but will have a constant that make the equation true at the point (4, -3).

  3x +5y = 3(4) +5(-3) = 12 -15 = -3

The equation of the parallel line is

  3x +5y = -3

When y=1, the value of k is ...

  3k +5(1) = -3

  3k = -8

  k = -8/3 = -2 2/3 . . . . . . on line parallel to 3x+5y=10

The equation of the perpendicular line will have swapped x- and y-coefficients, with one of them negated. The constant will be chosen to make the equation true at the point (4, -3).

  5x -3y = 5(4) -3(-3) = 20 +9 = 29

The equation of the perpendicular line is

  5x -3y = 29

When y=1, the value of k is ...

  5k -3(1) = 29

  5k = 32

  k = 32/5 = 6.4 . . . . . . on th eline perpendicular to 3x+5y=10

Answer: 224 pens more sold in 2nd shop

Step-by-step explanation:

Given,    

1st shop, 6 pens are sold more than previous day,

      1st day : 60

      2nd day : 60+6 =66

      3rd day : 66+6 =72

      4th day : 72+6 =78

      5th day : 78+6 =84

      6th day : 84+6 =90

      7th  day : 90+6 =96  

Then,

2nd shop, each day doubles the previous sold,

      1st day: 5

      2nd day:5*2 =10

      3rd day:10*2 =20

      4th day:20*2 =40

      5th day:40*2 =80

      6th day:80*2 =160

      7th day:160*2 =320

Therefore, second shop sells more in a week which is calculated by 320-96=224 more sold than the 1st shop.

The colony will reach a population of 2000 in time -

t = - {log(2000 - c) - log(a) + log(c)}/b.

Given is that a colony of bacteria grows according to the law of inhibited growth. If there were 200 bacteria at noon, and 550 at 2 pm.

The logistic model is given as -

y(t) = {c/(1 + a[tex]e^{-bt}[/tex])}

For y(t) = 2000

2000 = {c/(1 + a[tex]e^{-bt}[/tex])}

(2000/c) = 1/(1 + a[tex]e^{-bt}[/tex])

(1 + a[tex]e^{-bt}[/tex]) = (2000/c)

a[tex]e^{-bt}[/tex] = (2000/c) - 1

a[tex]e^{-bt}[/tex] = (2000 - c)/c

[tex]e^{-bt}[/tex] = (2000 - c)/(ac)

(-bt)log{e} = log {(2000 - c)/(ac)}

- bt = log(2000 - c) - log(ac)

- bt = log(2000 - c) - log(a) + log(c)

t = - {log(2000 - c) - log(a) + log(c)}/b

Therefore, the colony will reach a population of 2000 in time -

t = - {log(2000 - c) - log(a) + log(c)}/b.

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Answer:

7

Step-by-step explanation:

54 - 3 = 51

51 divided by 7 is 7 with 2 left over

Function notation, such as f(x) = 3x + 5, can be interpreted by plugging in different values for x and evaluating the resulting expression.

For example, if we plug in 2 for x, we get f(2) = 3(2) + 5 = 11. This means that the value of the function at x = 2 is 11. By plugging in different values for x, we can evaluate the function at any point on its domain.

A connection between two variables can be expressed using function notation. We are accustomed to writing straight-line equations in the form y = m x + c .

We can express this in function notation as f (x) = m x + c by substituting y with f (x).

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Part 1) The rule of the translation is    (x,y) ------> (x+4,y+5) ,Part 2) B'(4,8) Part 3) C'(3,3)

Find out the rule of the translation

we know that

The transformation of the point A to A' is equal to

A(-4,1) ------> A'(0,6)

so

The rule of the translation is equal to

(x,y) ------> (x + a ,y + b)

(-4,1) ------> (-4 + a, 1 + b)

Find the value of a

-4 + a = 0 -----> a = 4

Find the value of b

1 + b = 6 -----> b = 5

substitute the values of a and b

(x,y) ------> (x+4,y+5)

That means -----> The translation is 4 units at right and 5 units up

Find out the coordinates of B'

Applying the rule of the translation

(x,y) ------> (x+4,y+5)

so

B(0,3) ------> B'(0+4,3+5)

B(0,3) ------> B'(4,8)

Find out the coordinates of C'

Applying the rule of the translation

(x,y) ------> (x+4,y+5)

so

C(-1,-2) ------> C'(-1+4,-2+5)

C(-1,-2) ------> C'(3,3)

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