Answer:
what is the question. . .
Answer:
see the answer above
Explanation:
during each cycle, a heat engine ejects 75 j of thermal energy for every 115 j of input thermal energy. this engine is used to lift a 375 kg load a vertical distance of 27.0 m at a steady rate of 52.5 mm/s. how many cycles of the engine are needed to accomplish this task?
Hence, 1309 cycles of the engine are needed to accomplish this task.
Given values:
Work done = Force × Distance moved = mgh,
Force = mg = 375 × 9.8 = 3675 N,
Distance moved, s = 27 m
Rate of work = Power = Work done ÷ time
Rate of work = Fs/t
rate of work = 3675 × 0.0525
rate of work = 193.69 W.
Potential energy = Work done = mgh = 375 × 9.8 × 27 = 98175 J.
Heat ejected by the engine per cycle = 75 J, Heat input to the engine per cycle = 115 J.
We can find the number of cycles of the engine needed to accomplish this task by dividing the potential energy by the amount of heat ejected per cycle.
Therefore: Number of cycles = Potential energy ÷ Heat ejected per cycle= 98175 ÷ 75 = 1309 cycles.
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what tangential speed v must the bob have so that it moves in a horizontal circle with the string making an angle 21.0 ∘ with the vertical?
To find the tangential speed required for the bob to move in a horizontal circle with the string making an angle of 21.0 degrees with the vertical, we can use the concept of centripetal force.
The centripetal force required to keep the bob moving in a circular path is provided by the tension in the string. The tension can be resolved into two components: the vertical component and the horizontal component. The vertical component of the tension balances the weight of the bob, which is given by: T * cos(21.0°) = mg. where T is the tension in the string, m is the mass of the bob, and g is the acceleration due to gravity. The horizontal component of the tension provides the centripetal force required for circular motion, and it can be expressed as: T * sin(21.0°) = mv^2 / r. where v is the tangential speed of the bob and r is the radius of the circular path. Dividing the two equations: [T * sin(21.0°)] / [T * cos(21.0°)] = (mv^2 / r) / (mg). tan(21.0°) = v^2 / (rg). Solving for v: v = √(rg * tan(21.0°)) Now, we can substitute the values of the gravitational acceleration (g) and the angle (21.0°) to calculate v. Note: It is assumed that the bob is moving in a horizontal circle without any additional external forces affecting the system.
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Please help me if you can.
I can't figure out how the answer for number 30 is C and 31 is C. My question is how did they get that answer?
Answer:
30. $3.85
31. $2.22
Explanation:
30. The time duration of the kitchen clock is left on = All day = 24 hours
The power rating of the kitchen clock, P = 4 watts
The electricity cost in Alberta, R = $0.11 per kilowatt hour
The total number of hours the kitchen clock is on during the year, 't', is given as follows;
t = Number of hours per day × Number of days per year
∴ t = 24 hours/day × 365 days/year = 8,760 hours
The energy consumption of the kitchen clock, per year, E = P × t
∴ E = 4 watts × 8,760 hours = 35,040 watts-hour = 35.040 kw·h
The cost of operating the clock in one year, C = E × R
∴ Operating cost for the kitchen clock
∴ C = 35.040 kw·h × $0.11/(kw·h) = $3.8544 ≈ $3.85
The cost of operating the clock in one year, C ≈ $3.85
31. The power rating of the ghetto blaster, P = 28 watts
The time duration the ghetto blaster was on during an average month = All day = 24 hours
The number of days during an average month, n = 30 days
The cost of electricity in Alberta, R = $0.11 per kilowatt hour
The time in hours the ghetto blaster was on, t = 30 days/month × 24 hours/day
∴ t = 720 hours per month
The cost of operating the ghetto blaster in one month, C = P × t × R
∴ C = 28 W × 720 hours × 1 kw·h/(1000 w·h)× $0.11/(kw·h) = $2.2176
∴ The cost of operating the ghetto blaster in one month, C ≈ $2.22
The distance between two cities A and B is 180 km. a car moved from the city A towards the city :
with a velocity of 25 Km/hr , at the same moment another car moved from the citv B towards the city A with a uniform velocity of 65 Km/hr. Then: when and where do the two cars meet?
The two cars will meet at a distance of 50 km from city A, and the meeting will occur 2 hours after they start moving.
To determine when and where the two cars meet, we need to calculate the time it takes for them to meet and then use that time to find the meeting location.
In this case:
Distance between cities A and B = 180 km
Velocity of the car starting from city A = 25 km/hr
Velocity of the car starting from city B = 65 km/hr
Let's assume the meeting point is at a distance of x km from city A. Since the total distance between the two cities is 180 km, the distance traveled by the car starting from city A is x km, and the distance traveled by the car starting from city B is (180 - x) km.
Using the formula:
Time = Distance / Velocity
The time taken by the car starting from city A to reach the meeting point is:
Time for car from A = x km / 25 km/hr = x/25 hr
The time taken by the car starting from city B to reach the meeting point is:
Time for car from B = (180 - x) km / 65 km/hr = (180 - x)/65 hr
Since the two cars meet at the same time, we can set their time equations equal to each other:
x/25 = (180 - x)/65
Now, we can solve this equation to find the value of x:
65x = 25(180 - x)
65x = 4500 - 25x
90x = 4500
x = 50
Therefore, the meeting point is 50 km from city A.
To find the time it takes for the cars to meet, we can substitute this value of x back into either of the time equations:
Time = Distance / Velocity
Time = 50 km / 25 km/hr
Time = 2 hours
So, the two cars will meet after 2 hours.
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The electric field strength is 5.50×10⁴ N/C inside a parallel-plate capacitor with a 2.30 mm spacing. A proton is released from rest at the positive plate.What is the proton's speed when it reaches the negative plate?
To determine the proton's speed when it reaches the negative plate, we can utilize the relationship between electric field, force, and acceleration.
The force experienced by a charged particle in an electric field is given by the equation F = qE, where F is the force, q is the charge of the particle, and E is the electric field strength. In this case, the proton has a charge of +e (1.6 × 10⁻¹⁹ C) and experiences a force in the direction of the electric field.
Using Newton's second law, F = ma, we can relate the force to the proton's acceleration (a) and mass (m). Since the proton is released from rest, its initial velocity (v₀) is zero. The distance traveled by the proton (d) is equal to the spacing of the parallel plates, which is 2.30 mm (2.30 × 10⁻³ m).
The force on the proton is F = qE = (1.6 × 10⁻¹⁹ C) × (5.50×10⁴ N/C) = 8.80 × 10⁻¹⁵ N. By equating the force to mass times acceleration, we have ma = 8.80 × 10⁻¹⁵ N.
Rearranging the equation to solve for acceleration, we get a = (8.80 × 10⁻¹⁵ N) / (m). The mass of a proton is approximately 1.67 × 10⁻²⁷ kg.
Substituting the values, we find the acceleration of the proton. Using the kinematic equation v² = v₀² + 2ad, we can find the final velocity (v) of the proton when it reaches the negative plate.
Since the initial velocity (v₀) is zero and the distance (d) is known, we can solve for the final velocity. Calculating the expression gives us the speed of the proton when it reaches the negative plate.
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a hydrogen atom in the n=4 state decays to the n=1 state. what is the wavelength of the photon that the hydrogen atom emits? use hc=1240 nm ev.
A hydrogen atom in the n=4 state decays to the n=1 state. The wavelength of the photon that the hydrogen atom emits is 97.2 nm.
To calculate the wavelength of the photon emitted when a hydrogen atom transitions from the n=4 state to the n=1 state, we can use the Rydberg formula:
1/λ = R * (1/n₁² - 1/n₂²)
Where:
λ is the wavelength of the photon
R is the Rydberg constant for hydrogen (approximately 1.097 x 10⁷ m⁻¹)
n₁ is the initial energy level (n=4)
n₂ is the final energy level (n=1)
1/λ = 1.097 x 10⁷ m⁻¹ * (1/16 - 1)
1/λ = 1.097 x 10⁷ m⁻¹ * (-15/16)
λ = -0.972×10⁷ m⁻¹
Since wavelength cannot be negative, we take the absolute value
λ ≈ 97.2 nm.
Therefore, the wavelength of the photon emitted by the hydrogen atom is approximately 97.2 nm.
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I need help with one question on my homework. This is on the Specific Heat Capacity required practical.
Sample c has no solid residue left when evaporated. Suggest why it has a boiling point 1.7 degrees Celsius lower than distilled water.
Answer:
will mostly accord at the top of the boiling water my kind sir
Explanation:
Evaporation takes place only at the surface of a liquid, whereas boiling may occur throughout the liquid. In boiling, the change of state takes place at any point in the liquid where bubbles form. The bubbles then rise and break at the surface of the liquid.
Can someone pls answer
Answer:
im still in elementry so you got to do it yo self
Explanation:
so me confused
(a) Does the index of refraction vary as you change the wavelength of light. (B) What is the angle of the ray that leaves the glass square (emergent ray) relative to the ray that enters it? (c) What can you say about the path of emergent ray relative to that of the incident ray?
(a) Yes, the index of refraction varies with the wavelength. (b) The emergent ray is refracted at a different angle. (c) The path of the emergent ray deviates from the incident ray.
(a) Yes, the index of refraction varies as you change the wavelength of light.
The index of refraction (n) of a material is a measure of how much the speed of light is reduced when it passes through that material compared to its speed in a vacuum.
The index of refraction is wavelength-dependent and typically varies slightly with different wavelengths of light. This phenomenon is known as dispersion.
One way to express this variation is through the refractive index as a function of wavelength, often represented by a refractive index versus wavelength graph.
In general, different wavelengths of light are bent or refracted by different amounts when passing through a medium due to their interaction with the material's atoms or molecules.
This bending is a result of the change in the speed of light, which is dictated by the refractive index.
The index of refraction does vary as you change the wavelength of light. This variation is responsible for phenomena like dispersion, where different colors of light are separated when passing through a prism, for example.
(b) The angle of the emergent ray leaving a glass square relative to the incident ray depends on the angle of incidence and the refractive index of the glass.
According to Snell's law, the relationship between the angle of incidence (θ₁), the angle of refraction (θ₂), and the refractive indices of the two media involved can be expressed as:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
In the case of a glass square, let's assume light is incident on one of its faces. If we know the angle of incidence (θ₁) and the refractive index of the glass (n₂), we can calculate the angle of the emergent ray (θ₂) using Snell's law.
The angle of the emergent ray leaving the glass square relative to the incident ray depends on the angle of incidence and the refractive index of the glass, and it can be calculated using Snell's law.
(c) The path of the emergent ray relative to the incident ray can be different due to refraction.
When light passes from one medium to another, it changes direction due to the change in its speed caused by the change in the refractive index. This change in direction is called refraction. Therefore, the emergent ray may have a different direction compared to the incident ray.
The emergent ray will still follow the law of refraction (Snell's law) and will be bent towards or away from the normal depending on the refractive indices of the two media involved and the angle of incidence.
The amount of bending depends on the difference in refractive indices and the angle at which the light strikes the boundary between the two media.
The path of the emergent ray relative to the incident ray can be different due to refraction, as the emergent ray changes direction upon passing from one medium to another.
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a 85-power refracting telescope has an eyepiece with a focal length of 4.8 cmcm. How long is the telescope
The estimated length of the refracting telescope is approximately 412.8 cm.
The magnification (M) of a telescope is given by the formula: M = focal length of the objective lens / focal length of the eyepiece. In this case, the magnification is 85, and the focal length of the eyepiece is 4.8 cm.
Rearranging the formula, we can find the focal length of the objective lens:
focal length of the objective lens = M × focal length of the eyepiece = 85 × 4.8 cm = 408 cm.
Now, to estimate the length of the telescope, we need to consider the formula for the total length of a refracting telescope:
total length = focal length of the objective lens + focal length of the eyepiece.
Substituting the values, we have:
total length = 408 cm + 4.8 cm = 412.8 cm.
Please note that the actual length of a refracting telescope depends on various factors, such as the design, focal lengths, and positioning of the lenses, which may differ from the assumptions made in this response.
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for the truss bridge shown, a) sketch the influence lines for the force in members be, bc, and da.
a) Sketching the influence lines for the force in members BE, BC, and DA in a truss bridge requires a visual representation. Influence lines show the variation of forces in a structure due to the movement of a load.
Please refer to structural engineering resources or software for accurate sketches and graphical representations of the influence lines for these specific members in a truss bridge. These resources will provide detailed illustrations based on the structural dimensions, member properties, and load positions. Influence lines are valuable tools for structural engineers as they help identify critical load positions, assess the structural response, and determine the maximum forces experienced by different members. Please consult reliable structural engineering references, textbooks, or appropriate software that specifically address truss bridge analysis and design to obtain accurate sketches of the influence lines for members BE, BC, and DA. These resources will provide the necessary diagrams and detailed explanations based on the specific truss bridge configuration and load positions.
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True or False: A balanced force acts on different objects, and action-
eaction forces act on the same object. *
A. True
B. False
Answer:
true
Explanation:
according to the Newton's third law
derive the error propagation equation for δk (the kinetic energy).
The error propagation equation for δk (the kinetic energy) is:
δk = √((1/4v^4) * δm² + m²v² * δv²).
To derive the error propagation equation for δk (the kinetic energy), we first need to understand what error propagation is.
Error propagation is a method used to estimate the uncertainty of a quantity that is derived from several other measured quantities that have uncertainties. In other words, it is a way to determine how the errors of the input quantities affect the error of the output quantity.
Now let's derive the error propagation equation for δk (the kinetic energy):
The kinetic energy (k) of an object can be calculated using the following equation:
k = 1/2mv^2
Where m is the mass of the object and v is its velocity.
We can use the standard error propagation formula to find the uncertainty in k.
This formula is given as:
δk = √((∂k/∂m)² * δm² + (∂k/∂v)² * δv²)
where δm and δv are the uncertainties in the measured values of m and v, respectively.
To find ∂k/∂m and ∂k/∂v, we need to take the partial derivatives of k with respect to m and v.
∂k/∂m = 1/2v²
∂k/∂v = mv
Now we can substitute these values in the error propagation equation:
δk = √((1/2v²)² * δm² + (mv)² * δv²)
Therefore, the error propagation equation for δk (the kinetic energy) is:
δk = √((1/4v^4) * δm² + m²v² * δv²)
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if an object is projected vertically upward from ground level it rises to maimum height h. True or False
The statement is true. When one projects an object vertically upward from the ground, that object will reach a maximum height h before it is brought back down to earth by the force of gravity.
The laws of motion, more especially the principles of projectile motion, are the ones that rule over this behaviour. When the object is propelled forward, its initial velocity works against the gravitational pull, causing it to slow down until it reaches its highest point. This continues until the object has reached its highest position. After reaching this point, the object's velocity stops being positive and it begins a free fall towards the ground as a result of the force of gravity.
The initial velocity of the object, the angle at which it is launched, and the force of gravity all play a role in determining the maximum height h that it is possible to reach. Kinematic equations can be used to determine the answer to this question. It is essential to keep in mind, however, that the maximum height will also be determined by any external forces that are operating on the object, such as the resistance posed by the air.
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12. Which of the following statements is accurate?
A. If an object's velocity is changing, it's experiencing either acceleration or deceleration.
B. If an object's velocity decreases, then the object is accelerating
C. If an objects said to be decelerating, its velocity must be increasing,
D. If an object's velocity remains constant, its acceleration must be increasing.
Answer:
Option (a) is correct
Explanation:
The acceleration of an object is defined as the rate of change of velocity. Mathematically, it can be written as :
[tex]a=\dfrac{v-u}{t}[/tex]
Where
v and u are final and initial velocity
It is clear that if there is some change in velocity, it means the object is experiencing either acceleration or deceleration. Hence, the correct option is (a).
Answer:
a
Explanation:
How does burning wood compare to the chemical reactions in trees that make them grow?
Answer:
Log burning in a fire. Burning wood is an example of a chemical reaction in which wood in the presence of heat and oxygen is transformed into carbon dioxide, water vapor, and ash.
Explanation:
basketball center steve tootall is 7 feet 2 inches in height. what is steve’s height in inches?
Steve Tootall's height is 86 inches. To calculate his height in inches, we convert feet to inches and then add the remaining inches.
Steve Tootall's height is given as 7 feet 2 inches. To calculate his height in inches, we convert feet to inches and then add the remaining inches.
1 foot is equal to 12 inches. So, 7 feet would be 7 * 12 = 84 inches.
Adding the remaining 2 inches, Steve's height in inches would be:
84 inches + 2 inches = 86 inches.
Therefore, Steve Tootall's height is 86 inches.
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Two stars, both of which behave like ideal blackbodies, radiate the same total energy per second. The cooler one has a surface temperature T and 2.0 times the diameter of the hotter star. Part A What is the temperature of the hotter star in terms of T? VO AED h ? TT = Submit Previous Answers Request Answer Part B What is the ratio of the peak-intensity wavelength of the hot star to the peak-intensity wavelength of the cool star? VO AED ? = Submit Request Answer Provide Feedback
The temperature of the hotter star ([tex]T_h[/tex]) is equal to the square root of the surface temperature of the cooler star (T), and the ratio of the peak-intensity wavelengths is proportional to the inverse cube of the temperature ratio.
Part A: Let's denote the temperature of the hotter star as [tex]T_h[/tex]. According to the Stefan-Boltzmann law, the total energy radiated by a blackbody is proportional to the fourth power of its temperature. Since both stars radiate the same total energy per second, we can write:
[tex]T_h^4 = T^4[/tex]
Taking the fourth root of both sides, we get:
[tex]T_h = T^{(\frac {1}{4})}[/tex]
Part B: The peak intensity wavelength (λmax) of a blackbody radiation is inversely proportional to its temperature.
According to Wien's displacement law, we can express the ratio of peak-intensity wavelengths ([tex]\lambda_{max, hot}/ \lambda_{max, cool}[/tex]) as the ratio of their temperatures:
[tex]\frac{\lambda_{max, hot}}{ \lambda_{max, cool}} = \frac{T_h}{T}[/tex]
Substituting the relationship we derived in Part A, we have:
[tex]\frac{\lambda_{max, hot}}{ \lambda_{max, cool}} = \frac{T^{\frac{1}{4}} }{T}[/tex]
Simplifying, we get:
[tex]\frac{\lambda_{max, hot}}{ \lambda_{max, cool}} = T^{\frac{-3}{4}} }[/tex]
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A video game regularly costs $29.95 is on sale for 15% off. About how much is the sale price of the game is you include 8% sales tax?
Answer:
Hereeeeeeeeeeeeeeeeeee
assume+that+kish+inc.+hired+you+as+a+consultant+to+help+estimate+its+cost+of+capital.+you+have+obtained+the+following+data:+d0+=+$0.90;+p0+=+$47.50;+and+g+=+7.00%
The cost of capital is the rate of return on a firm's investments that must be earned to meet the cost of financing. The cost of capital refers to the opportunity cost of making a specific investment. This opportunity cost is the rate of return that could have been earned by placing the same capital into a different investment that has equivalent risk.
Consultant is a professional who provides expert advice in a specific area such as management, accounting, human resources, and information technology. They provide guidance to an organization to assist them in improving their performance or solving particular problems.
The components of the cost of capital are the cost of debt and the cost of equity. Cost of DebtCost of debt is the interest rate that a firm pays on its debt. It is calculated as follows: Cost of debt = (Interest rate) x (1 - Tax rate)Here, D0 = $0.90, P0 = $47.50, and G = 7.00%.The current dividend is D0.
The next dividend is calculated as follows:D1 = D0 (1 + G) = $0.90 (1 + 0.07) = $0.963Dividend yield can be calculated as follows:Dividend yield = D1 / P0= $0.963 / $47.50= 0.0203 = 2.03%.
The cost of equity can be calculated using the following formula: Cost of Equity = (Dividend Yield) + (Growth Rate of Dividends).
Cost of Equity = 2.03% + 7.00% = 9.03%.
The cost of capital for Kish Inc. is the weighted average of the cost of debt and the cost of equity.
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Two objects collide elastically. The first has a mass of 5.00kg and a
velocity of 8.00 m/s. The second has a mass of 2.50 kg and a velocity
of -4.00m/s. If the velocity of object 1 after the collision is -4.00m/s,
what is the velocity of object 2?
Answer:
Explanation:
General formula
m1 * vi + m2*v2 = m1*v3 + m2*v4
Givens
m1 = 5
m2 = 2.5
v1 = 8 m/s
v2 = - 4 m/s
v3 = -4 m/s
v4 = x
Solution
5 * 8 - 2.5 * 4 = 5 * -4 + 2.5*x
40 - 10 = -20 + 2.5x
30 = - 20 + 2.5x
50 = 2.5x
x = 50/2.5
x = 20 m/s in the positive direction
Remark
Does this answer make sense? It should. You have 5 kg moving 8m/s in the plus direction. That's a lot of momentum. In addition after the collision, it turns around which is more momentum needed.
It has to give up that extra momentum to the 2.5 kg mass.
Which graph BEST represents the relationship between the potential energy and kinetic energy of a cannon ball as it flies over the
bow of a ship and then falls onto the beach on the other side? Note that the dotted line represents potential energy while the solid
line represents kinetic energy
Answer:C
Explanation:I think sorry if it’s wrong
a light ray can change direction when going from one material into another. that phenomenon is known as __________.
A light ray can change direction when going from one material to another. That phenomenon is known as refraction.
The phenomenon you are referring to is known as refraction. Refraction occurs when a light ray transitions from one medium to another, causing a change in its direction.
This change in direction is a result of the difference in the speed of light between the two media. When light passes through a medium with a different optical density or refractive index, it experiences a change in speed, causing the light ray to bend or deviate from its original path.
Refraction can be observed in various everyday situations. For example, when light travels from air into water or glass, it undergoes refraction.
The bending of light at the interface between these media is responsible for phenomena like the apparent shift in position of objects submerged in water, the bending of a pencil when placed in a glass of water, or the formation of rainbows.
The amount of bending that occurs during refraction depends on the angle at which the light ray enters the interface and the refractive indices of the two media involved.
Snell's law, which describes the relationship between the incident angle, the refracted angle, and the refractive indices, governs the behavior of light during refraction.
Refraction plays a crucial role in various optical devices, including lenses, prisms, and fiber optics. Understanding and controlling the phenomenon of refraction is essential in fields such as optics, physics, and engineering, enabling the development of technologies and applications that rely on manipulating light for imaging, communication, and scientific research.
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2.00 × 1020electrons flow through a cross section of a 3.20-mm-diameter iron wire in 4.50 s .
part a
what is the electron drift speed?
The electron drift speed in the iron wire is approximately 4.49 mm/s. When electrons are subjected to an electric field they do move randomly, but they slowly drift in one direction, in the direction of the electric field applied. The net velocity at which these electrons drift is known as drift velocity.
The formula to calculate the electron drift speed is:
v_d = I / (n * A * q)
Where:
- v_d is the electron drift speed
- I is the electric current
- n is the number density of charge carriers (electrons)
- A is the cross-sectional area of the wire
- q is the charge of an electron
Given:
- I = 2.00 × 10^20 electrons
- Diameter of the wire = 3.20 mm
- Time = 4.50 s
First, we need to calculate the current (I) in Amperes:
I = (2.00 × 10^20 electrons) / (4.50 s)
I ≈ 4.44 × 10^19 A
Next, we need to determine the cross-sectional area (A) of the wire. The wire is cylindrical in shape, so we can use the formula for the area of a circle:
A = π * (diameter/2)^2
A = π * (3.20 mm/2)^2
A ≈ 8.03 mm^2
Converting the cross-sectional area to square meters:
A = 8.03 mm^2 * (1 m^2 / 1000 mm^2)
A ≈ 8.03 × 10^-6 m^2
The number density of charge carriers (n) is given by the ratio of the number of electrons (I) to the volume of the wire. Since we don't have the volume, we cannot calculate the exact number density. However, for a wire, the number density is typically on the order of 10^28 to 10^29 electrons per cubic meter.
Lastly, we know that the charge of an electron (q) is approximately 1.6 × 10^-19 C.
Using the formula for electron drift speed, we can calculate:
v_d = (4.44 × 10^19 A) / (10^28 electrons/m^3 * 8.03 × 10^-6 m^2 * 1.6 × 10^-19 C)
v_d ≈ 4.49 mm/s
Therefore, the electron drift speed in the iron wire is approximately 4.49 mm/s.
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an iron anchor of density 7810.00 kg/m3 appears 152 n lighter in water than in air. (a) what is the volume of the anchor? (b) how much does it weigh in air
The volume of the anchor is approximately 0.0195 m^3. The weight of the anchor in air is approximately 1492 N.
To find the volume of the anchor, we can use Archimedes' principle, which states that the buoyant force experienced by an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
Given that the anchor appears 152 N lighter in water than in air, we can equate this weight difference to the buoyant force experienced by the anchor in water.
Weight difference = Buoyant force
= Weight in air - Weight in water
Let's assume the weight of the anchor in air is W_air and the weight of the anchor in water is W_water.
W_air - W_water = 152 N
We know that weight = mass × acceleration due to gravity (W = m × g), and density is defined as mass divided by volume (ρ = m/V), where ρ is the density, m is the mass, and V is the volume.
Therefore, W_air = ρ_anchor × g × V × (1), and
W_water = ρ_water × g × V × (2).
Given that the density of water, ρ_water, is 1000 kg/m^3, and the density of the anchor, ρ_anchor, is 7810.00 kg/m^3, we can substitute these values into equations (1) and (2):
7810.00 × g × V - 1000 × g × V = 152
Simplifying the equation:
6810.00 × g × V = 152
V = 152 / (6810.00 × g)
Using the standard acceleration due to gravity, g = 9.8 m/s^2:
V = 152 / (6810.00 × 9.8)
≈ 0.0195 m^3
Therefore, the volume of the anchor is approximately 0.0195 m^3.
To calculate the weight of the anchor in air, we can use the formula:
Weight in air = ρ_anchor × g × V
Substituting the values:
Weight in air = 7810.00 × 9.8 × 0.0195
≈ 1492 N
Therefore, the weight of the anchor in air is approximately 1492 N.
The volume of the anchor is approximately 0.0195 m^3, and its weight in air is approximately 1492 N.
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the focal length of a converging lens is 0.50 meters. an object is placed 1.0 meters from the lens. the distance between the lens and the image is
The distance between the lens and the image is 1.0 meter.
To find the distance between the lens and the image formed by a converging lens, we can use the lens formula:
1/f = 1/v - 1/u
Where:
f is the focal length of the lens
v is the distance of the image from the lens (positive if the image is on the same side as the observer, negative if the image is on the opposite side)
u is the distance of the object from the lens (positive if the object is on the same side as the observer, negative if the object is on the opposite side)
In this case:
Focal length (f) = 0.50 meters
Distance of the object (u) = 1.0 meter
Let's substitute the given values into the lens formula:
1/0.50 = 1/v - 1/1.0
2 = 1/v - 1
2v = v - 1
v = 1
Therefore, the distance between the lens and the image = 1.0 m.
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A softball player is running at 4.88 m/sec when she slides into second base coming to a stop in .872 seconds. How far did she slide, and what was her acceleration?
Answer:
d=v1t - .5at^2
d=4.88 x .872 - 0.5 x (4.88/0.872) x 0.872^2
d=4.255 - 2.12
d= 2.135m
Explanation:
acceleration is negative because she is slowing down.
In its elemental state, carbon is available as:
a
Coal
b Graphite
C Diamond
All of the above
Answer: D all of the above
Explanation: Coal, Graphite, Diamond are all allotropes of Carbon. Hope this helps :)
A 29 kg child jumps to the ground from the top of a fence that is 1.8 m high. You analyze the problem using upward as the positive x direction.
A. Taking x=0 to be at the bottom of the fence, what are the initial potential energy of the child-Earth system and the chnage in the system kinetic energy during the jump? (Ui , change of U)
B.Repeat the previous part for x=0 at the top of the fence (Ui , change of U)
The initial potential energy of the child-Earth system is 509.4 J, and the change in system kinetic energy during the jump is 509.4 J.
In the first scenario, with x=0 at the bottom of the fence, we can calculate the initial potential energy (Ui) using the formula Ui = mgh, where m is the mass of the child (29 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the fence (1.8 m). Substituting the values, Ui = 29 kg × 9.8 m/s^2 × 1.8 m = 509.4 J.
Since there is no external work done on the child during the jump, the change in system kinetic energy (change of U) is equal to the negative of the initial potential energy. Therefore, the change of U = -509.4 J.
In the second scenario, with x=0 at the top of the fence, the initial potential energy (Ui) is still the same, i.e., 509.4 J. However, since the child is starting from a higher position, the change in system kinetic energy (change of U) will be different. The change of U will still be equal to -509.4 J since it depends on the initial potential energy, regardless of the reference point.
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A box m=87 kg is being pulled by a constant force F=124 N at an angle of θ =43 degrees. The initial speed of the box is zero. A 33\% Part (a) Write an expression for the work done by force F as the block moves a horizontal distance d. A3\% Part (b) How much work, in joules, was done in moving the block 4.1 m ? A 33% Part (c) What is the speed of the box at d=4.I m if the surface is frictionless?
Part (a) involves writing an expression for the work done by force F as the box moves a horizontal distance d. Part (b) requires calculating the amount of work done in moving the box 4.1 m. Part (c) asks for the speed of the box at a distance of 4.1 m, assuming a frictionless surface.
(a) The work done by a force is given by the formula W = Fd cos(θ), where W represents work, F is the force applied, d is the distance moved, and θ is the angle between the force and the displacement. In this case, since the force is applied horizontally ([tex]\theta[/tex] = 0), the expression for the work done by force F becomes W = Fd cos(0) = Fd.
(b) To calculate the work done in moving the box 4.1 m, we can substitute the given values into the equation from part (a). Thus, the work done is W = (124 N)(4.1 m)(cos 0) = 124 N * 4.1 m = 508.4 J (joules).
(c) If the surface is frictionless, the work done is converted entirely into kinetic energy. We can use the work-energy principle to find the speed of the box. The work done (508.4 J) is equal to the change in kinetic energy. Assuming the initial speed is zero, the final kinetic energy is 508.4 J. We can calculate the speed using the equation [tex]KE = (1/2)mv^2[/tex], where KE is the kinetic energy, m is the mass, and v is the speed. Rearranging the equation, [tex]v = \sqrt(2KE/m)[/tex]. Given the mass m = 87 kg, the speed at d = 4.1 m can be calculated.
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