1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.
How far will it go before it is moving at 20 m/s?
A) 83
B) 43
C) 39
D) 94
E) 20

Answer:

[tex]10.54\ \text{rad/s}[/tex]

Explanation:

[tex]\omega_i[/tex] = Initial angular velocity = 500 rpm = [tex]500\times \dfrac{2\pi}{60}\ \text{rad/s}[/tex]

[tex]\omega_f[/tex] = Final angular velocity

t = Time = 34 s

[tex]\theta[/tex] = Angular displacement = 170 revs = [tex]170\times 2\pi\ \text{rad}[/tex]

[tex]\alpha[/tex] = Angulr acceleration

From the kinematic equations of angular motion we have

[tex]\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \alpha=\dfrac{\theta-\omega_it}{\dfrac{1}{2}t^2}\\\Rightarrow \alpha=\dfrac{170\times 2\pi-500\times \dfrac{2\pi}{60}\times 34}{\dfrac{1}{2}\times 34^2}\\\Rightarrow \alpha=-1.23\ \text{rad/s}^2[/tex]

[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=500\times \dfrac{2\pi}{60}+(-1.23)\times 34\\\Rightarrow \omega_f=10.54\ \text{rad/s}[/tex]

The rate at which the wheel is spinning when the power comes back on is [tex]10.54\ \text{rad/s}[/tex].

The answer is A. velocity .

Velocity is a vector quantity because it need magnitude as well as direction to be defined.

Answer:

number 1

Explanation:

they have common ancestors

Answer:

1. b. The door is exerting a centripetal force on you that balances the centrifugal force of the turn.

2. b. There is no net force acting on the object.

Explanation:

1. This is because as you move to the right due to the centrifugal force of the turn, a corresponding centripetal force acts on you due to the door which does not allow you fall out of the car since, the door is exerting a centripetal force on you that balances the centrifugal force of the turn.

So, the answer is b

2. This is because, since the object moves at a constant speed and thus does not accelerate, no net force can act on it since, a net force would imply that the object accelerates. Note that a constant speed does not imply that no force acts on it. It only shows that the resultant or net force is zero since the object does not accelerate.

So, there is no net force acting on the object.

So, b is the answer.

Answer:

the answer is b!!!!

Explanation:

just took the test

The best labeling for the chart would be Title 1 is "Transverse Waves," and Title 2 is "Longitudinal Waves." Therefore, the correct option is B.

The two types of waves that are the subject of the chart under consideration are transverse waves and longitudinal waves. While longitudinal waves have vibrations parallel to the path of wave travel, transverse waves have vibrations perpendicular to the direction of wave propagation.

The graphic distinguishes between these wave types by designating title 1 as "transverse wave" and title 2 as "longitudinal wave". Using this labeling, viewers can understand and differentiate the two wave ranges based on their unique characteristics.

So, the correct option is B.

Learn more about longitudinal wave, here:

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Answer:

Explanation:

From the question we are told that:

Plant Generates [tex]P=3GW[/tex]

Efficiency [tex]\eta =33\%[/tex]

Recoverable energy per fission [tex]\mu=210MeV \approx 336.42*18^{-7}J[/tex]

Fission Power [tex]F_p=235U[/tex] [tex](65\% of Plant\ power)[/tex]

Fission in plutonium [tex]F_{pl}=239Pu[/tex]

a)

Generally the equation for net electric power output [tex]P_o[/tex] is mathematically given by

[tex]P_o=P*\frac{1}{\eta}[/tex]

[tex]P_o=3*\frac{100}{3}[/tex]

[tex]P_o=9.0GW[/tex]

b)

Generally the equation for Rate of Fission [tex]F_{rate}[/tex] is mathematically given by

[tex]F_{rate}=\frac{P_o}{\mu}}[/tex]

[tex]F_{rate}=\frac{9*10^{9}}{336.42*18^{-7}}}[/tex]

[tex]F_{rate}=27.02*10^{13}[/tex]

c)

Generally the equation for  Mass of [tex]^{235} U[/tex] used in a yr [tex]M_{U/yr}[/tex] is mathematically given by

[tex]M_{U/yr}=P_o*\frac{65}{100}[/tex]

[tex]M_{U/yr}=5.91GW[/tex]

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒  [tex]V=f\times \lambda[/tex]

or,

⇒  [tex]f=\frac{V}{\lambda}[/tex]

On substituting the values, we get

⇒      [tex]=\frac{2}{1.5}[/tex]

⇒      [tex]=1.33 \ Hz[/tex]

hence,

⇒  [tex]\lambda_1=\frac{V_1}{f}[/tex]

On substituting the values, we get

⇒       [tex]=\frac{1.6}{1.33}[/tex]

⇒       [tex]=1.2 \ m[/tex]

Answer:

Distance A:11km

B:10km

Explanation:

Displacement A and B is 9km

Answer:

The solubility of KNO3 at 50 degrees C is 83 g/100 g water.

Explanation:

when u see the graph and by using graph reading techniques then u find the solubility.

Answer:

1. Positive

2. Negative

3. induction

4. Insulator

5. Voltage

6. Static energy

7. Positive, Negative

8. Resistance

9. Increase

Would appreciate if you mark me as brainliest answer

1. Protons have positive electric charge and electrons have negative electric charge.

2. Opposite charges attract and like charges repel.

3. Charging by induction is the rearrangement of electrons on a neutral object caused by a nearby charged object.

4. Insulator are materials that do not allow electric current to pass through easily.

5. Voltage is the accumulation of electrical charges on on object.

6.Current is usually the flow of static electricity.

7. Charges flow from positive voltage to negative voltage.

8. The tendency of material to oppose the flow of electron is called resistance.

9. Making wires thinner, longer or hotter Increase the resistance.

The current is the stream of charges which flow from positive to negative terminal of voltage source.  

Voltage is the collection or storage of charges. Resistance of the circuit is the opposition to the flow of current.

Charging a neutral object is done by induction. Like charges repel each other and unlike charges attract each other. The electron are positive charged and proton are positive charged.

Learn more about current.

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Answer:

This is because of friction and heat lost.

Explanation:

Answer:

A local tsunami is one that originates from within about 100 km or less than 1 hour tsunami travel time from the impacted coastline. Local tsunamis can result in a significant number of casualties since authorities have little time to warn/evacuate the population.

Explanation:

Hope this helps

Answer:

6.75 v

Explanation:

Answer:

 θ = 32.4º

Explanation:

For this exercise let's use Malus's law

         I = Io cos² θ

in this case it indicates that the incident intensity is 370 W/m², when the first polarization passes, only the radiation with the same polarization of the polarizer emerges, that is, vertical

         I₀ = 370/2 = 185 W / m²

this is the radiation that affects the second polarizer, let's apply the expression of Maluz

         θ = cos⁻¹ ([tex]\sqrt{\frac{I}{I_o} }[/tex])

         θ = cos⁻¹ ([tex]\sqrt{132/185}[/tex])

         θ = cos⁻¹ (0.844697)

         θ = 32.4º

Answer:

1. B. The person and the Earth

2. This is because the energy gained by the person equals the energy lost by the earth,

Explanation:

1.

B. The person and the Earth

This is because the person and the earth both represent a system. A system consists of more than one item. A system consists of two or more items interacting with each other.

2. This is because, the energy of an isolated system is conserved according to the second law of thermodynamics which states that in an isolated system, energy can neither be created nor destroyed. So, there is an exchange of energy between the person and the Earth. So, the energy gained by the person at the new height equals the energy lost by the earth. And thus, the total energy of the system remains constant.

Answer:

[tex]0.261\ \text{m}[/tex]

Explanation:

[tex]\Delta f[/tex] = Change in frequency = 2.1 Hz

[tex]f[/tex] = Frequency of source of sound = 440 Hz

[tex]v_m[/tex]= Maximum of the microphone

[tex]v[/tex] = Speed of sound = 343 m/s

[tex]T[/tex] = Time period = 2 s

We have the relation

[tex]\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}[/tex]

Amplitude is given by

[tex]A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}[/tex]

The amplitude of the simple harmonic motion is [tex]0.261\ \text{m}[/tex].

Answer:

Acceleration of the car = 5.51 m/s²

Explanation:

Given:

Initial speed of car = 0 m/s

Final speed of car = 27 m/s

Time taken by car = 4.9 seconds

Find:

Acceleration of the car

Computation:

Using first equation of motion

v = u + at

Where

v = Final velocity

u = Initial velocity

t = Time taken

a = Acceleration

So,

v = u + at

27 = 0 + a(4.9)

a(4.9) = 27

a = 5.51 m/s²

Acceleration of the car = 5.51 m/s²

Answer:

becouse most of nuclear elements are heave

Explanation:

Answer:

5.45 moles

Explanation:

The chemical balanced equation of this reaction is;

3Si + 2N2 → Si3N4

From the balanced equation, we can see that that 3 moles of Si reacts with 2 moles of N2 to produce 1 mole of Si3N4.

Thus imies that the molar ration of Si to N2 is 3:2.

Now, we are told that 16.35 moles of Si reacts with 11.26 moles of N2.

16.35

Thus, using the ratio 3:2, we can say that moles of 16.35 miles of Si will react completely with (16.35 × ⅔) = 10.9 moles of N2.

Remaining N2 = 11.26 - 10.9 = 0.36 will be the excess.

From our balanced chemical equation, we saw that;

3 moles of Si produced 1 mole of Si3N4.

Thus; 16.35 moles of Si will produce;

no. of moles of Si3N4 produced = (1 × 16.35)/(3.0) = 5.45 moles

Answer:

WATER TO A VAPOR

Explanation:

Explanation:

During transpiration, water goes from a root to a stomata.

Explanation:

I couldn't have information on this question.

Mimicry. This is when oraganisms imitate another oraganism whether it be physical or behavoioral.

Answer:

the correct result is L = 0.319 m

Explanation:

This system is a physical pendulum whose angular velocity is

         w² = [tex]\frac{M \ g \ d}{I}[/tex]

where d is the distance from the center of mass to the point of rotation and I is the moment of inertia of the system

The Moment of Inertia is a scalar, therefore an additive quantity

          I = I_bar + I_disk

the moment of inertia of each element with respect to the pivot point can be found with the parallel axes theorem

let's use M for the mass of the bar and m for the mass of the disk

Bar

          I_bar = I_{cm} + Md²

the moment of inertia of the center of mass is

          I_{cm} = [tex]\frac{1}{12}[/tex] M L²

the distance from the center of mass

           d = L / 2

we substitute

         I_bar = [tex]\frac{1}{12}[/tex] M L² + M ([tex]\frac{L^2}{4}[/tex])

Disk

          I_disk = I_{cm} + m d²

moment of inertia of the center of mass

          I_{cm} = ½ m R²

the distance d is

         d = L

we substitute

          I_disk = 1/2 m R² + m L²

the total moment of inertia is

          I = [tex]\frac{1}{12}[/tex] M L² +[tex]\frac{1}{4}[/tex] M L² + [tex]\frac{1}{2}[/tex] m r² + m L²

          I = [tex]\frac{1}{4}[/tex] M L² + m L² + ½ m r²

          I = L² (m + [tex]\frac{1}{4}[/tex] M) + ½ m r²

The position of the center of mass of the system can be found with the expressions

         d_{cm} = [tex]\frac{1}{M} \sum r_i m_i[/tex]

         d_{cm} = [tex]\frac{1}{m+M} \ ( M \frac{L}{2} + m L)[/tex]

         d_{cm} = [tex]L \frac{m + M/2}{m +M }[/tex]

now we can substitute in the expression for the angular velocity

         w² = (m + M) g  L  [tex]\frac{m + \frac{M}{2} }{m+M}[/tex]   [tex]\frac{1}{L^2 (m+ \frac{M}{4} ) + \frac{1}{2} m r^2 }[/tex]

         w² = g (m + [tex]\frac{1}{2}[/tex] M)   [tex]\frac{L}{ L^2 ( m +\frac{1}{4} M ) + \frac{1}{2} m r^2}[/tex]

angular velocity and period are related

         w = 2π/T

sustitute

        4π²/T² =   g (m + [tex]\frac{1}{2}[/tex] M)   [tex]\frac{L}{ L^2 ( m +\frac{1}{4} M ) + \frac{1}{2} m r^2}[/tex]  

         L² (m + [tex]\frac{1}{4}[/tex] M)  + ½ m r² =  [tex]\frac{T^2}{4 \pi ^2 } \ g ( m + \frac{1}{2} M ) \ \ L[/tex]

we substitute the values ​​and solve the second grade equation

          L² (0.1 + [tex]\frac{1}{4}[/tex] 0.3) - [[tex]\frac{1^2}{4\pi ^2}[/tex]  9.8 (0.1 + 0.3/2) ]  L + ½ 0.1 0.2² = 0

          L² 0.175 - 0.06206 L + 0.002 = 0

the equation remains after simplifying

          L² - 0.3546 La + 0.01143 = 0

solve us

           L = [tex]\frac{0.3546 \ \pm \sqrt{ 0.3546^2 - 4 \ 0.01143 }}{2}[/tex]

           L = [tex]\frac{0.3546 \ \pm \ 0.28288 }{2}[/tex]

           L₁ = 0.319 m

           L₂ = 0.036m

the correct result must have a value greater than the radius of the disk.  The correct result is L = 0.319 m